GRAAD 12 NATIONAL SENIOR CERTIFICATE …resources.besteducation.co.za/English/Grade-10/Exam-and-Memos/Nov...The ticker tape is analysed and the displacement ... 4.3 Draw a graph of

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This question paper consists of 15 pages, 1 data sheet, an answer sheet and graph paper.

GRAAD 12

PHYSICAL SCIENCES: PHYSICS (P1)

EXEMPLAR 2012

NATIONAL SENIOR CERTIFICATE

GRADE 10

Physical Sciences/P1 2 DBE/2012 NSC – Grade 10 Exemplar


INSTRUCTIONS AND INFORMATION 1. 2. 3. 4. 5. 6. 7.

Write your name in the appropriate space on the ANSWER BOOK. This question paper consists of TWELVE questions. Answer ALL the questions. You may use a non-programmable calculator. You may use appropriate mathematical instruments. YOU ARE ADVISED TO USE THE ATTACHED DATA SHEETS. Number the answers correctly according to the numbering system used in this question paper. Write neatly and legibly.



QUESTION 1 INSTRUCTIONS

1. Answer this question on the ANSWER SHEET. [NOTE: The ANSWER

SHEET may either be a separate sheet provided as part of your question paper, or printed as part of the ANSWER BOOK.] Write your name in the appropriate space, if a separate ANSWER SHEET is used.

2. Various options are provided as possible answers to the following questions.

Choose the answer and make a cross (X) in the block (A–D) next to the question number (1.1–1.10) on the ANSWER SHEET.

3. Do not make any other marks on the ANSWER SHEET. Any calculations or

writing that may be necessary when answering this question should be done in the ANSWER BOOK and must be deleted clearly by means of a line drawn across the page.

4. If more than ONE block is marked per question, no marks will be awarded for

that answer.

PLACE THE COMPLETED ANSWER SHEET INSIDE THE FRONT COVER OF THE ANSWER BOOK, IF A SEPARATE ANSWER SHEET HAS BEEN USED.

EXAMPLE: QUESTION: The SI unit of time is ... A

B C D

t. h. s. m.

ANSWER:

[NOTE: This layout may vary, depending on the type of ANSWER SHEET used by the province.]

A B C D



1.1 Which ONE of the following physical quantities is a vector? A

B C D

Time Speed Velocity Distance

(2) 1.2 A characteristic property of motion at constant acceleration is that the … A

B C D

change in position per unit time is constant. change in velocity per unit time is constant. velocity remains constant for the duration of the motion. change in position remains constant for the duration of the motion.

(2) 1.3 In the equation Δx = viΔt + ½aΔt2, the part ½aΔt2 represents the … A

B C D

time. velocity. acceleration. displacement.

(2) 1.4 The gravitational potential energy of an object relative to the ground is

dependent on the object's …

A

B C D

speed. position. velocity. change in velocity.

(2)



1.5 Which ONE of the following statements regarding electromagnetic waves is

CORRECT? In a vacuum all electromagnetic waves have the same …

A

B C D

speed. amplitude. frequency. wavelength.

(2) 1.6 A tuning fork is made to vibrate by striking it gently on a rubber stopper.

The sound waves produced are …

A

B C D

transverse waves and require a medium for propagation. transverse waves and require no medium for propagation. longitudinal waves and require a medium for propagation. longitudinal waves and require no medium for propagation.

(2) 1.7 Which ONE of the following statements is CORRECT?

All waves …

A

B C D

are transverse. are longitudinal. transmit energy. travel through a vacuum.

(2) 1.8 The direction of the magnetic field lines of a magnet is towards its … A

B C D

south pole. north pole. positive pole. negative pole.

(2)



1.9 An object which is charged positively has … A

B C D

lost protons. lost electrons. gained protons. gained electrons.

(2) 1.10 Which ONE of the following is the unit of measurement for the rate of flow of

charge?

A

B C D

Ohm Volt Ampere Coulomb

(2) [20]

ANSWER QUESTIONS 2–12 IN THE ANSWER BOOK. ANSWER QUESTION 4.3 ON THE ATTACHED GRAPH PAPER. INSTRUCTIONS AND INFORMATION

1. 2. 3. 4. 5. 6.

Start EACH question on a NEW page in the ANSWER BOOK. Leave ONE line between two subquestions, for example between QUESTION 2.1 and QUESTION 2.2. Number the answers correctly according to the numbering system used in this question paper. Show ALL formulae and substitutions in ALL calculations. Round off your FINAL numerical answers to a minimum of TWO decimal places. Give brief motivations, discussions, et cetera where required.



QUESTION 2 (Start on a new page.) A crane lifts a crate vertically upward as shown below. The total weight lifted is 1 480 N. The crane applies an upward force of 1 550 N. A frictional force of 20 N acts on the crate during lifting.

2.1 Define the term resultant of a number of forces. (2) 2.2 Calculate the magnitude and direction of the resultant force acting on the

crate.

(3) The crate is lifted to a vertical height of 80 m above the ground and then lowered to a height of 20 m above the ground as shown in the diagram below.

2.3 Calculate the: 2.3.1 Total distance travelled by the crate (2) 2.3.2 Displacement of the crate (1)

[8]

20 m

80 m

F = 1 550 N

w = 1 480 N

f = 20 N



QUESTION 3 (Start on a new page.) A man runs from point A in a straight line along a track ABCDEFG. The velocity-time graph below represents the motion of the man.

3.1 Using the information on the graph, describe the motion of the man from: 3.1.1 A to B (3) 3.1.2 B to D (2) 3.2 WITHOUT USING EQUATIONS OF MOTION, calculate the: 3.2.1 Acceleration of the man between E and G (4) 3.2.2 Distance covered by the man in 100 s (4)

[13]

A

B C D E

F

G

time (s)

velo

city

(m∙s

-1)

2,5

0 0 25 35 50 60 80 100



QUESTION 4 (Start on a new page.) To investigate the motion of a trolley travelling at uniform acceleration, a runway is set up as shown in the sketch below. The slope of the runway is adjusted before readings are taken.

4.1 Give a reason why the slope of the runway has to be adjusted. (2) The ticker tape is analysed and the displacement (change in position) is measured after each 0,2 s. The table below shows the data obtained.

4.2 For this investigation, write down the: 4.2.1 Independent variable (1) 4.2.2 Dependent variable (1) 4.3 Draw a graph of position versus time on the attached GRAPH PAPER.

Indicate the following on your graph: • A suitable heading • Correct labels on both axes • An appropriate scale on both axes • The six plotted points

(6)

4.4 What type of motion (UNIFORM MOTION or UNIFORM ACCELERATED

MOTION) is represented by the graph drawn in QUESTION 4.3? Give a reason for the answer.

(2) [12]

Time (s) Position (m) 0,0 0 0,2 0,20 0,4 0,60 0,6 1,20 0,8 2,00 1,0 3,00

runway

trolley

ticker tape ticker timer



QUESTION 5 (Start on a new page.) A delivery van is travelling at a constant speed of 15 m∙s-1 in a 60 km∙h-1 speed zone when the driver sees people walking across a pedestrian crossing 50 m ahead of him. The driver takes exactly one second (1 s) to react before he applies brakes as hard as he can. It takes a further 3 seconds for the van to come to a stop.

5.1 Complete the following sentence:

The equations of motion are only valid for motion at constant (5.1.1) … in a (5.1.2) … line.

(2)

5.2 Did the driver of the delivery van exceed the speed limit? Show ALL

calculations.

(3) 5.3 Calculate the distance that the delivery van travels during the 1 second

reaction time.

(3) 5.4 Will the van stop before the pedestrian crossing? Show ALL calculations. (6) 5.5 Will the stopping distance of the van INCREASE or DECREASE when the

road is wet and slippery? By referring to velocity and time, briefly explain how you arrived at the answer.

(3) [17]

60 km∙h-1

PE

DE

STR

IAN

CR

OSS

ING

15 m∙s-1

50 m

reaction time 1 s



QUESTION 6 (Start on a new page.) An object of mass 0,2 kg is released at point A and moves along the frictionless section AC of a curved track. Along section CD it experiences friction and stops at point D. The vertical height of point A above point X on the ground is 0,8 m as shown below.

6.1 Write down, in words, the principle of conservation of mechanical energy. (2) 6.2 Calculate the gravitational potential energy of the object at point A just before

it is released.

(3) 6.3 At point B the speed of the object is 3 m∙s-1. Use the principle of conservation

of mechanical energy to calculate the vertical height of point B above the ground.

(6)

6.4 The object reaches point C at a velocity of 3,96 m∙s-1. 6.4.1 Write down the energy conversion which takes place as the object

moves from point C to D.

(1) 6.4.2 Calculate the acceleration that the object experiences as it moves

from point C to D.

(5) [17]

z X

2 m

z

z

z z

A

B

C D

0 8 m



QUESTION 7 (Start on a new page.) 7.1 The diagram below shows two waves, A and B, of the same wavelength but

different amplitudes, crossing each other.

7.1.1 Define the term amplitude. (2) 7.1.2 Draw the shape of the resulting wave as the two waves (A and B)

cross. On your diagram, show the resulting amplitude.

(3) 7.1.3 Which wave property is illustrated in QUESTION 7.1.2? (1) 7.1.4 Name the principle used to answer QUESTION 7.1.2. (1) 7.2 In the sketch below, not drawn to scale, Q represents an object on the surface

of the water in a dam. A person standing on a bridge observes object Q moving up and down. Object Q rises to the top every 5 s.

7.2.1 Define the term wavelength. (2) 7.2.2 In which direction is object Q about to move? (2) Calculate the: 7.2.3 Frequency of the waves (3) 7.2.4 Speed of the waves (3)

[17]

b a

- b -a

B A

time (s)

posi

tion

(m)

1,5 m

Q position (m)

posi

tion

(m)

Direction of motion



QUESTION 8 (Start on a new page.) A sound wave produced by a vibrating musical instrument is represented in DIAGRAM 1 below.

8.1 Label the sections marked: 8.1.1 A (1) 8.1.2 B (1) 8.2 The position-time graph in DIAGRAM 2 below represents the same sound

wave produced by the musical instrument above.

8.2.1 Name the type of wave represented in DIAGRAM 2. (1) 8.2.2 Which ONE of points X, Y or Z in DIAGRAM 2 corresponds to the

section labelled A in DIAGRAM 1?

(1) 8.2.3 The same note is now played on the instrument, but much louder

than before. How will this change affect the graph in DIAGRAM 2?

(1)

8.2.4 A note of higher frequency, but of the same original loudness is

now played on the instrument. How will this change affect the graph in DIAGRAM 2?

(1) [6]

DIAGRAM 1

A A A

B

DIAGRAM 2

Y

X

Z time (s)

posi

tion

(m)



QUESTION 9 (Start on a new page.) Some electromagnetic waves are listed below.

UV-rays Infrared rays Radio waves X-rays γ-rays

9.1 How are electromagnetic waves generated? (1) 9.2 From the list above, write down the waves: 9.2.1 Used in a TV remote control (1) 9.2.2 Used to sterilise instruments in hospitals (1) 9.2.3 With the greatest penetrating ability (1) 9.2.4 Used in the treatment of cancer (1) 9.3 Ultrasound is used to obtain an image of an unborn baby. Briefly explain why

X-rays cannot be used for the same purpose.

(2) 9.4 An X-ray photon incident on a body has a wavelength of 2,1 x 10-9 m.

Calculate how much energy the photon imparts to the body.

(4) [11]

QUESTION 10 (Start on a new page.) 10.1 In the diagram shown below steel paper clips A and B are attached to a string

which is attached to a table. The paper clips remain suspended beneath a magnet.

10.1.1 Define the term magnetic field. (2) 10.1.2 Will the top end of paper clip A be a N pole or a S pole? (1) 10.2 Two bar magnets are placed close to one another as shown in the diagram

below.

10.2.1 Draw the magnetic field pattern between the two magnets. (3) 10.2.2 The magnets are now moved further apart. What effect will this

change have on the magnetic field pattern drawn in QUESTION 10.2.1?

(1) [7]

N S S N

A B N S

Table


Copyright reserved

QUESTION 11 (Start on a new page.) Two identical metal spheres, A and B, on an insulated surface carry charges of -2,8 x 10-6 C and +4,5 x 10-6 C respectively. The spheres are brought in contact with each other.

11.1 It is observed that the spheres move apart after contact. Briefly explain this

observation.

(3) 11.2 Calculate the new charge on each sphere after they moved apart. (3) 11.3 Calculate the number of electrons transferred from one sphere to the other

during contact.

(4) [10]

QUESTION 12 (Start on a new page.) Learners set up a circuit as shown in the diagram below. The emf of each cell is 1,5 V. Each of bulbs A and B has a resistance of 2 Ω and bulb C has a resistance of 3 Ω.

12.1 Calculate the effective resistance of bulbs A and B. (3) Switch S is now closed for a short time. 12.2 Determine the reading on: 12.2.1 Voltmeter V1 (1) 12.2.2 Voltmeter V3 (2) 12.3 Calculate the energy transferred in bulb C in 3 seconds if the current in the

circuit is 2 A.

(5) 12.4 ALL the bulbs are now connected in parallel. How will the total current in the

circuit be affected? Write down only INCREASES, DECREASES or REMAINS THE SAME.

(1) [12]

GRAND TOTAL: 150

- A B

-2,8 x 10-9 C +4,5 x 10-9 C +

A

V1

V2 V3

B

A C S

Physical Sciences/P1 DBE/2012 NSC – Grade 10 Exemplar

Copyright reserved

DATA FOR PHYSICAL SCIENCES GRADE 10 PAPER 1 (PHYSICS)

GEGEWENS VIR FISIESE WETENSKAPPE GRAAD 10

VRAESTEL 1 (FISIKA) TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES

NAME/NAAM SYMBOL/SIMBOOL VALUE/WAARDE Acceleration due to gravity Swaartekragversnelling G 9,8 m·s-2

Speed of light in a vacuum Spoed van lig in 'n vakuum C 3,0 x 108 m·s-1

Planck's constant Planck se konstante H 6,63 x 10-34 J·s

Charge on electron Lading op elektron e -1,6 x 10-19 C

Electron mass Elektronmassa me 9,11 x 10-31 kg

TABLE 2: FORMULAE/TABEL 2: FORMULES MOTION/BEWEGING

tavv if ∆+= 221

i tatvx ∆+∆=∆

xa2vv 2i

2f ∆+= t

2vvx if ∆

+=∆

WORK, ENERGY AND POWER/ARBEID, ENERGIE EN DRYWING

mghU= or/of mghEP = 2mv21K = or/of 2

k mv21E =

WAVES, SOUND AND LIGHT/GOLWE, KLANK EN LIG

λ= fv f1T =

hfE= or/of λ

=chE

ELECTRIC CIRCUITS/ELEKTRIESE STROOMBANE

I=Q ∆ t ...R1

R1

R1

21p

++=

...RRR 21s ++= qWV =


Copyright reserved

ANSWER SHEET LEARNER'S NAME: 1.1 A B C D

1.2 A B C D

1.3 A B C D

1.4 A B C D

1.5 A B C D

1.6 A B C D

1.7 A B C D

1.8 A B C D

1.9 A B C D

1.10 A B C D

(10 x 2) [20]

For the use of the marker Vir die gebruik van die nasiener

Marks obtained Punte behaal

Marker's initials Nasiener se paraaf

Marker's number Nasiener se nommer


Copyright reserved

GRAPH PAPER LERANER'S NAME: QUESTION 4.3

(6)

Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

-

MARKS/PUNTE: 150

This memorandum consists of 11 pages. Hierdie memorandum bestaan uit 11 bladsye.

PHYSICAL SCIENCES: PHYSICS (P1) FISIESE WETENSKAPPE: FISIKA (V1)

EXEMPLAR/MODEL 2012

MEMORANDUM

NATIONAL SENIOR CERTIFICATE

NASIONALE SENIOR SERTIFIKAAT

GRADE/GRAAD 10

Physical Sciences P1/Fisiese Wetenskappe V1 2 DBE/2012 NSC/NSS – Grade 10 Exemplar/Graad 10 Model – Memorandum


QUESTION 1/VRAAG 1 1.1 C 33 (2) 1.2 B 33 (2) 1.3 D 33 (2) 1.4 B 33 (2) 1.5 A 33 (2) 1.6 C 33 (2) 1.7 C 33 (2) 1.8 A 33 (2) 1.9 B 33 (2) 1.10 C 33 (2)

[20] QUESTION 2/VRAAG 2 2.1 A single force 3

having the same effect as all other forces acting together. 3 'n Enkele krag 3 wat dieselfde effek het as al die ander kragte tesame. 3

(2)

2.2 Upward positive/Opwaarts positief:

Fnet = F + w + f = 1 550 + (-1 480) + (-20) 3 = 1 550 – 1 500 = 50 ∴ Fnet = 50 N 3upwards/opwaarts 3 Upward negative/Opwaarts negatief: Fnet = F + w + f = -1 550 + (1480 + 20) 3 = -1 550 + 1 500 = -50 ∴ Fnet = 50 N 3upwards/opwaarts 3

Notes/Aantekeninge: The force of 1 550 N must have an opposite sign than the other two forces. Die krag van 1 550 N moet 'n teken hê wat die teenoorgestelde is van die ander twee kragte.

(3)

2.3 2.3.1

Distance/Afstand = 80 + 60 = 140 m 3

(1)



2.3.2 Upward positive/Opwaarts positief:

Displacement /Verplasing = +80 + (-60) = 20 m 3 upwards/opwaarts 3 Upward negative/Opwaarts negatief: Displacement /Verplasing = -80 + 60 = 20 m 3 upwards/opwaarts 3

Notes/Aantekeninge: The two displacements must have opposite signs. Die twee verplasings moet teenoorgestelde tekens hê.

(2) [8]

QUESTION 3/VRAAG 3 3.1 3.1.1

Starts from rest/0 m∙s-1 3 Velocity increases at a constant rate 3 until he reaches 2,5 m∙s-1 after 25 s. 3 Begin uit rus/0 m∙s-1 3 Snelheid vermeerder teen 'n konstante tempo 3 totdat hy 2,5 m∙s-1 bereik na 25 s. 3 OR/OF Starts from rest/0 m∙s-1 3 Constant positive acceleration 3 until he reaches 2,5 m∙s-1 after 25 s. 3 Begin uit rus/0 m∙s-1 3 Konstante positiewe versnelling 3 totdat hy 2,5 m∙s-1 bereik na 25 s. 3

(3)

3.1.2 Constant/uniform velocity 3

for another 25 s. 3 Konstante/uniforme snelheid 3 vir 'n verdere 25 s. 3 OR/OF Velocity remains 2,5 m∙s-1 in the direction of motion 3 for another 25 s. 3 Snelheid bly 2,5 m∙s-1 in die rigting van beweging 3 vir 'n verdere 25 s. 3 OR/OF Zero/No acceleration 3 for another 25 s. 3 Nul/Geen versnelling 3 vir 'n verdere 25 s. 3

(2)



3.2 Acceleration/Versnelling = tv∆∆

= 601005,20

−−

= - 0,0625 ∴ a = 0,063 m∙s-2 3 opposite to direction of motion/teenoorgesteld aan bewegingsrigting 3

(4)

3.3 Length of track = Area between the graph and the time axis 3

Lengte van baan = Area tussen grafiek en tydas = ½(2,5) 3(35 + 100) 3 = 168,75 m 3 OR/OF Length of track/Lengte van baan = Area of trapezium/Area van trapesium = ½(2,5) 3(35 + 100) 3 = 168,75 m 3 OR/OF Length of track/Lengte van baan = ½h(sum of // sides)/½h(som van // sye) = ½(2,5) 3(35 + 100) 3 = 168,75 m 3 OR/OF Length of track = Area between the graph and the time axis 3 Lengte van baan = Area tussen grafiek en tydas = ½bh + ½bh + lb = ½(25)(2,5) + ½(40)(2,5) 3 + (35)(2,5) 3 = 31,25 + 87,5 + 50 = 168,75 m 3 OR/OF Length of track = Area of triangle + area of triangle + area of rectangle Lengte van baan = Area van driehoek + area van driehoek + area v. reghoek = ½bh + ½bh + lb = ½(25)(2,5) + ½(40)(2,5) 3 + (35)(2,5) 3 = 31,25 + 87,5 + 50 = 168,75 m 3 OR/OF Length of track/Lengte van baan = ½bh + ½bh + lb = ½(25)(2,5) + ½(40)(2,5) 3 + (35)(2,5) 3 = 31,25 + 87,5 + 50 = 168,75 m 3

(4) [13]

QUESTION 4/VRAAG 4 4.1 To compensate for friction. 33

Om vir wrywing te vergoed. 33 OR/OF To ensure that the trolley moves at constant acceleration. 33 Om te verseker dat die trollie teen konstante versnelling beweeg. 33

(2)

3 3



4.2 4.2.1

Time/Tyd 3

(1)

4.2.2 Displacement/Verplasing 3 (1) 4.3 Graph of position versus time/Grafiek van posisie teenoor tyd Criteria for graph:

• Suitable heading. 3 • Correct labels on both axes. 3 • Appropriate scale on both axes. 3 • Any three points plotted correctly. 3 • All six points plotted correctly. 3 • Curve joining the points. 3

Kriteria vir grafiek: • Geskikte opskrif. 3 • Korrekte benoemings op beide asse. 3 • Geskikte skaal op beide asse. 3 • Enige drie punte korrek gestip. 3 • Al ses punte korrek gestip. 3 • Kromme wat die punte verbind. 3

(6)

4.4 Uniformly accelerated motion. 3

The gradient of the graph increases constantly. 3 Uniform versnelde beweging. 3 Die gradiënt van die grafiek vermeerder konstant. 3 OR/OF Uniformly accelerated motion. 3 The velcoity increases constantly each 0,2 s. 3 Uniform versnelde beweging. 3 Die snelheid vermeerder konstant elke 0,2 s. 3

(2) [12]

0 0,2 0,4 0,6 0,8 1,0 Time/Tyd (s)

0

0,5

1,0

Pos

ition

/Pos

isie

(m)

2,0

2,5

3,0

1,5

•

•

•

•

•

•




Acceleration/Versnelling 3

(1)

5.1.2 Straight line/Reguitlyn 3 (1) 5.2 15 m∙s-1 = (15) )

10003600( 3 km∙h-1 = 54 km∙h-1 3 < 60 km∙h-1

No 3/He did not. Nee 3/Hy het nie. OR/OF

60 km∙h-1 = (60) )36000001( 3 m∙s-1 = 16,67 m∙s-1 3 > 15 m∙s-1

No 3/He did not. Nee 3/Hy het nie.

(3)

5.3 OPTION 1/OPSIE 1 Δx = viΔt 3 = (15)(1) 3 = 15 m 3

Notes/Aantekeninge: Accept/Aanvaar: s = vt s = ut + ½at2

s = t2

vu +

(3)

OPTION 2/OPSIE 2 Δx = viΔt + ½aΔt2 3 = (15)(1) + ½(0)(1)2 3 = 15 m 3

OPTION 3/OPSIE 3

Δx = t2

vv 1f ∆+ 3

= +2

1515 (1) 3

= 15 m 5.4 POSITIVE MARKING FROM QUESTION 5.3

POSITIEWE NASIEN VAN VRAAG 5.3

Braking distance/Remafstand:

Δx = t2

vv 1f ∆+ 3

= +2150

3 (3) 3

= 22,5 m Total stopping distance/Totale stilhouafstand = 22,5 + 15 m 3 = 37,5 m 3 Yes3/He will stop before the pedestrian crossing. Ja/Hy sal voor die voetoorgang tot stilstand kom.

(6)



5.5 Increases 3

For the same change in velocity, 3 the stopping time will increase. 3 Toeneem 3 Vir dieselfde verandering in snelheid, 3 verhoog die stilhoutyd. 3

(3) [17]

QUESTION 6/VRAAG 6 6.1 The total mechanical energy remains constant/is conserved 3

in a closed/isolated system. 3 Die totale meganiese energie bly konstant/bly behoue 3 in 'n geslote/geïsoleerde sisteem. 3

(2)

6.2 Ep = mgh 3

= (0,2)(9,8)(0,8) 3 = 1,568 J 3

(3)

6.3 EM(B) = EM(A) 3 / (Ep + Ek)B = (Ep + Ek)A / mghB + ½mv 2

B = mghA + ½mv 2A

(0,2)(9,8)h 3 + ½(0,2)(3)2 3= (0,2)(9,8)(0,8) 3 + ½(0,2)(0)2 3 ∴h = 0,34 m 3

(6)

6.4 6.4.1

Mechanical/kinetic energy converted to heat/sound/internal energy. 3 Meganiese/kinetiese energie omgeskakel na hitte-/klank-/interne energie. 3

(1)

6.4.2 vf

2 = vi2 + 2aΔx 3

(0)2 3 = (3,96)2 + 2a(2) 3 a = -3,92 m∙s-2 ∴a = 3,92 m∙s-2 3 opposite to the direction of motion 3 teenoorgesteld aan bewegingsrigting 3

(5) [17]




The maximum displacement of a particle 3 from its equilibrium position/position of rest. 3 Die maksimum verplasing van 'n deeltjie 3 van sy ewewigsposisie/posisie van rus. 3

(2) 7.1.2 Criteria for diagram:

Diagram shows two complete waves. 3 Amplitude correctly shown. 3 Correct shape. 3

Kriteria vir diagram: Diagram toon twee volledige golwe. 3 Amplitude korrek getoon. 3 Korrekte vorm. 3 (3)

7.1.3 (Constructive) interference 3

(Konstruktiewe) interferensie 3

(1) 7.1.4 Principle of superposition 3

Beginsel van superposisie 3

(1) 7.2 7.2.1

The distance between two consecutive points in phase. 33 Die afstand tussen twee opeenvolgende punte in fase. 33 OR/OF The distance between two consecutive crests/troughs. 33 Die afstand tussen twee opeenvolgende kruine/buike. 33

(2) 7.2.2 Upward/Opwaarts 33 (2) 7.2.3

f = T1

3

= 51 3

= Hz2,0 3

(3)

Time/tyd (s)

Pos

ition

/pos

isie

(m)

a + b



7.2.4 POSITIVE MARKING FROM QUESTION 7.2.3

POSITIEWE NASIEN VAN VRAAG 7.2.3 OPTION 1/OPSIE 1

v = fλ 3 = 0,2 x 1,5 3 = 0,3 ms-13

OPTION 2/OPSIE 2 Δx = vΔt 3 1,5 = v(5) 3 ∴v = 0,3 ms-13

(3) [18]


Compression/Verdigting 3

(1)

8.1.2 Wavelength/Golflengte 3 (1) 8.2 8.2.1

Longitudinal wave/Longitudinale golf 3

(1)

8.2.2 Y 3 (1) 8.2.3 Higher amplitude/Hoër amplitude 3 (1) 8.2.4 Shorter wavelength/Korter golflengte 3

OR/OF Points X, Y and Z closer together. Punte X, Y en Z sal nader aan mekaar wees.

(1) [6]

QUESTION 9/VRAAG 9 9.1 Accelerating charges/Versnelde ladings 3 (1) 9.2 9.2.1

Infrared/Infrarooi 3

(1)

9.2.2 Ultraviolet/Ultraviolet 3 (1) 9.2.3 γ rays/γ-strale 3 (1) 9.2.4 γ rays/γ-strale 3 (1) 9.3 High energy/frequency/penetrating ability. 3

Damage living cells/Cause cancer/Cause mutations 3 Hoë energie/frekwensie/deurdringingsvermoë. 3 Beskadig lewende selle./Veroorsaak kanker./Veroorsaak mutasies. 3

(2)

9.4

E = λ

hc 3

= 9-

8-34

10×1,210×3×10×63,6

= 9,47 x 10-17J 3

(4) [11]

3 3




Region in space where another magnet/ferromagnetic material will experience a magnetic force. 33 Gebied in die ruimte waar 'n ander magneet/ferromagnetiese materiaal 'n magnetiese krag sal ondervind. 33

(2) 10.1.2 S pole/S-pool 3 (1) 10.2 10.2.1

Criteria for magnetic field pattern • Correct shape. 3 • Correct direction. 3 • Filed lines do not touch/cross each other. 3

Kriteria vir magneetveldpatroon • Korrekte vorm. 3 • Korrekte rigting. 3 • Veldlyne raak/kruis nie mekaar nie. 3

(3)

10.2.2 Fewer magnetic field lines further apart./less dense. 3

Minder magneetveldlyne verder uitmekaar/minder dig. 3

(1) [7]

QUESTION 11/VRAAG 11 11.1 During contact, electrons are transferred from A to B. 3

The spheres acquire equal charges. 3 Spheres thus repel each other. 3 Tydens kontak word elektrone van A na B oorgedra. 3 Die sfere verkry gelyke ladings. Sfere stoot mekaar dus af.

(3) 11.2

Q = 2

)108,2(105,4 99 −− ×−+× = + 8,5 x 10-10 C 3

(3)

3

3


Copyright reserved/Kopiereg voorbehou

11.3 ∆QA = QA(final/finaal) – QA(initial/aanvanklik)

= 8,5 x 10-10 – (-2,8 x 10-9) 3 = 3,65 x 10-9 C 3 OR/OF ∆QB = QB(final/finaal) – QB(initial/aanvanklik) = 8,5 x 10-10 – 4,5 x 10-9 3 = 3,65 x 10-9 C 3

Number of electrons/Aantal elektrone = 19

9

106,11065,3

−

−

×× 3

= 2,28 x 1010 3

(4) [10]

QUESTION 12/VRAAG 12 12.1

21p R1

R1

R1

+= 3

= 21

21+ 3

∴Rp = 1 Ω 3

(3)

12.2 12.2.1

6 V 3

(1)

12.2.2 4,5 V 33 (2) 12.3 POSITIVE MARKING FROM QUESTION 12.2.2.

POSITIEWE NASIEN VAN VRAAG 12.2.2.

Q = I∆t 3

= (2)(3) 3 = 6 C

V = qW 3

4,5 = 6W 3

∴W = 27 J 3

(5) 12.4 Increases/Vermeerder 3 (1)

[12

GRAND TOTAL/GROOTTOTAAL: 150

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