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Lecture 9 Energy Work and Kinetic Energy Kinetic and Potential Energy Kinetic and Potential Energy Physics 105 Fall 2009 Lecture 9 Andrei Sirenko, NJIT 1 Lecture 9 Andrei Sirenko, NJIT 2 Lecture 9 Andrei Sirenko, NJIT 3 Lecture 9 Andrei Sirenko, NJIT 4

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Page 1: Energy Work and Kinetic Energy Kinetic and Potential Energy - UCS Home

Lecture 9L 9Energygy

Work and Kinetic EnergyKinetic and Potential EnergyKinetic and Potential Energy

Physics 105 Fall 2009

Lecture 9 Andrei Sirenko, NJIT 1 Lecture 9 Andrei Sirenko, NJIT 2

Lecture 9 Andrei Sirenko, NJIT 3 Lecture 9 Andrei Sirenko, NJIT 4

Page 2: Energy Work and Kinetic Energy Kinetic and Potential Energy - UCS Home

Lecture 9 Andrei Sirenko, NJIT 5

Why ?

It’s good that

K ½ K = ½ …

Lecture 9 Andrei Sirenko, NJIT 6

Why ?

Lecture 9 Andrei Sirenko, NJIT 7

Energy and WorkKinetic energy

Units of Work and Energy: Joule

Work done by a constant force

Units of Work and Energy: Joule

W k ki ti thWork–kinetic energy theorem

Lecture 9 Andrei Sirenko, NJIT 8

Page 3: Energy Work and Kinetic Energy Kinetic and Potential Energy - UCS Home

Lecture 9 Andrei Sirenko, NJIT 9 Lecture 9 Andrei Sirenko, NJIT 10

Lecture 9 Andrei Sirenko, NJIT 11

(h is the vertical drop)

Lecture 9 Andrei Sirenko, NJIT 12

Page 4: Energy Work and Kinetic Energy Kinetic and Potential Energy - UCS Home

Work Done by a Gravitational ForceyWork done by gravitational force

Tomato thrown upwardWg > 0Wg < 0

Lifting/lowering an object

gg

Change in kinetic energy:

Lifting/lowering an object

Lecture 9 Andrei Sirenko, NJIT 13 Lecture 9 Andrei Sirenko, NJIT 14

F

x

Lecture 9 Andrei Sirenko, NJIT 15

Work Done by a Spring ForceHooke’s law:

Work done by a spring force:

Lecture 9 Andrei Sirenko, NJIT 16

Page 5: Energy Work and Kinetic Energy Kinetic and Potential Energy - UCS Home

Sample Problem 7-8pA block of mass A block of mass m = 0.40 kgm = 0.40 kg slides across a horizontal slides across a horizontal frictionless counter with a speed of frictionless counter with a speed of v = 0.50 m/sv = 0.50 m/s. It runs . It runs into and compresses a spring of spring constant into and compresses a spring of spring constant k 750 N/k 750 N/ Wh th bl k i t il t d bWh th bl k i t il t d bk = 750 N/mk = 750 N/m. When the block is momentarily stopped by . When the block is momentarily stopped by the spring, by what distance the spring, by what distance dd is the spring compressed?is the spring compressed?

Lecture 9 Andrei Sirenko, NJIT 17

Work Done by a General Variable Force

Work: variable forceWork: variable force

Calculus

Divide area under curve

Add increments of W (numerically)

Analytical form?

Integration!!!

Lecture 9 Andrei Sirenko, NJIT 18

½Lecture 9 Andrei Sirenko, NJIT 20

P = ½*50kg*(5m/s)2/1 s

Page 6: Energy Work and Kinetic Energy Kinetic and Potential Energy - UCS Home

PowerAverage PowerAverage Power

Sample Problem 7Sample Problem 7--1010: Two constant forces : Two constant forces FF11 and and FF22acting on a box as the box slides rightward across aacting on a box as the box slides rightward across aUnits: Watts

Instantaneous PowerInstantaneous Power

acting on a box as the box slides rightward across a acting on a box as the box slides rightward across a frictionless floor. Force frictionless floor. Force FF11 is horizontal, with is horizontal, with magnitude magnitude 2.0 N2.0 N, force , force FF22 is angled upward by is angled upward by 6060ººto the floor and has a magnitude of to the floor and has a magnitude of 4.0 N4.0 N. The speed . The speed

Units: Watts

vv of the box at of the box at a certain instanta certain instant is is 3.0 m/s3.0 m/s..

a)a) What is the power due to each force acting What is the power due to each force acting on the box? Is the net power changing at thaton the box? Is the net power changing at thaton the box? Is the net power changing at that on the box? Is the net power changing at that instant?instant?

b)b) If the magnitude If the magnitude FF22 is, instead, is, instead, 6.0 N6.0 N, what is , what is th t d i it h i ?th t d i it h i ?

Lecture 9 Andrei Sirenko, NJIT 21

now the net power, and is it changing?now the net power, and is it changing?

P t nti l En nd C ns ti n f • Potential Energy and Conservation of Energy

F• Conservative Forces• Gravitational and Elastic Potential Energygy• Conservation of (Mechanical) Energy• Potential Energy CurvePotential Energy Curve• External and Internal Forces

Lecture 9 Andrei Sirenko, NJIT 22

Work and Potential EnergygyPotential Energy

General Form:

Gravitational Potential Energy

Elastic Potential Energy

Lecture 9 Andrei Sirenko, NJIT 23

Path Independence of Path Independence of Conservative Forces

• The work done by a conservative force on a particle moving between two points doesmoving between two points does not depend on the path taken by the particle.

• The net work done by a conservative force on a particle moving around every closed path is zero.

Lecture 9 Andrei Sirenko, NJIT 24

Page 7: Energy Work and Kinetic Energy Kinetic and Potential Energy - UCS Home

Path Independence of Path Independence of Conservative Forces

Sample Problem 8-1: A 2.0 kg block slides along a frictionless track from a to point b. The block travels through a total distance of 2.0 m,block travels through a total distance of 2.0 m, and a net vertical distance of 0.8 m. How much work is done on the block by the gravitational force?

Lecture 9 Andrei Sirenko, NJIT 25

Conservation of Mechanical EnergyMechanical Energy

Conservation of M h i l EMechanical Energy

In an isolated system where only conservative forces cause energy changes, the kinetic gy g ,and potential energy can change, but their sum, the mechanical energy Emec of the

Lecture 9 Andrei Sirenko, NJIT 26

system, cannot change.

Kinetic Energy:

Potential Energy:• Gravitation:• Gravitation:

• Elastic (due to spring force):

y1 U K

mg2

Conservation of Mechanical Energy

Lecture 9 Andrei Sirenko, NJIT 27

Kinetic Energy:

Potential Energy:• Gravitation:• Gravitation:

• Elastic (due to spring force):

K = 01

U = 02

U K

Conservation of Mechanical Energy

Lecture 9 Andrei Sirenko, NJIT 28

Page 8: Energy Work and Kinetic Energy Kinetic and Potential Energy - UCS Home

QZ#10Name, ID#, Section #Name, ID#, Section #

4 d

N F b l h d l NYC

SF 4 days

NYC – SF by train. On a regular schedule It takes 4 days for 1 way tripOne train per day; starts at 1 pm in NYC and arrives in 4 days at 1 pm to SF. Quickly unload – load and go back.(a) Calculate the work of the engine when the train of the mass 10,000 kg

l t t 72 k /h f t th d t f NYC accelerates to v = 72 km/h from zero at the departure from NYC. (b) Calculate the work done by the breaks (friction force) when the train slows

down from v = 72 km/h to v = 0 arriving to SF. ( ) How many other trains will our train meet during one way trip?

Lecture 9 Andrei Sirenko, NJIT 29

(c) How many other trains will our train meet during one way trip?

Conservation of EnergyConservation of EnergyThermal Energy/Friction

• The total energy of a system

gy

• The total energy of a system can change only by amounts of energy that are transferred to or f hfrom the system.

• The total energy E of an isolated system cannot change.isolated system cannot change.

Lecture 9 Andrei Sirenko, NJIT 30

Potential Energy Curve

1D Motion

• Turning Points• Equilibrium Points

– Neutral Equilibrium

– Unstable EquilibriumA l t f U( ) th t ti l f ti Equilibrium

– Stable EquilibriumA plot of U(x), the potential energy function of a system containing a particle confined to move along the x axis. There is no friction, so

Lecture 9 Andrei Sirenko, NJIT 31mechanical energy is conserved.

Sample Problem 8-4A 61 0 kg bungeeA 61 0 kg bungee cord jumper iscord jumper isA 61.0 kg bungeeA 61.0 kg bungee--cord jumper is cord jumper is on a 45.0 m bridge above a river. on a 45.0 m bridge above a river. The elastic bungee cord has a The elastic bungee cord has a ggrelaxed length of relaxed length of L =L = 25.0 m. 25.0 m. Assume that the cord obeys Assume that the cord obeys Hooke’s law, with a spring Hooke’s law, with a spring constant of 160 N/m. If the constant of 160 N/m. If the jumper stops before reaching thejumper stops before reaching thejumper stops before reaching the jumper stops before reaching the water, what is the height water, what is the height hh of her of her feet above the water at her lowestfeet above the water at her lowest

Lecture 9 Andrei Sirenko, NJIT 32

feet above the water at her lowest feet above the water at her lowest point?point?

Page 9: Energy Work and Kinetic Energy Kinetic and Potential Energy - UCS Home

Sample Problem 8-8A circus beagle of mass A circus beagle of mass m =m = 6 0 kg runs onto the left6 0 kg runs onto the leftm =m = 6.0 kg runs onto the left 6.0 kg runs onto the left end of a curved ramp with end of a curved ramp with speed speed vv00 == 7.8 m/s at height 7.8 m/s at height yy00 == 8.5 m above the floor. It 8.5 m above the floor. It then slides to the right and then slides to the right and comes to a momentary stop comes to a momentary stop y py pwhen it reaches a height when it reaches a height y =y = 11.1 m from the floor. 11.1 m from the floor. The ramp is not frictionlessThe ramp is not frictionlessThe ramp is not frictionless. The ramp is not frictionless. What is the increase What is the increase ∆∆EEthth in in the thermal energy of the the thermal energy of the

Lecture 9 Andrei Sirenko, NJIT 33

beagle and the ramp because beagle and the ramp because of the sliding?of the sliding?

Sample Problem 7-2Two industrial spies sliding an initially stationary Two industrial spies sliding an initially stationary 225 kg225 kg floor safe a displacement floor safe a displacement dd of magnitude of magnitude 8.50 m8.50 m, straight toward their truck. The push , straight toward their truck. The push FF11 of spy 001 is of spy 001 is 12.0 N12.0 N, directed at an angle of , directed at an angle of 3030ºº downward from the horizontal; the pull downward from the horizontal; the pull FF22 of of

002 i002 i 10 0 N10 0 N di ddi d 4040ºº b h h i l Th i d db h h i l Th i d dspy 002 is spy 002 is 10.0 N10.0 N, directed at , directed at 4040ºº above the horizontal. The magnitudes and above the horizontal. The magnitudes and directions of these forces do not change as the safe moves, and the floor and safe directions of these forces do not change as the safe moves, and the floor and safe make frictionless contact.make frictionless contact.

)) h i h k d h f b hh i h k d h f b ha)a) What is the net work done on the safe by the What is the net work done on the safe by the forces forces FF11 and and FF22 during the displacement during the displacement d d ??

b)b) During the displacement, what is the work During the displacement, what is the work WWgg)) g pg p ggdone on the safe by the gravitational force done on the safe by the gravitational force Fgand what is the work done on the safe by the and what is the work done on the safe by the normal force normal force N from the floor?from the floor?

c)c) The safe is initially stationary. What is its The safe is initially stationary. What is its speed speed vvff at the end of the at the end of the 8.50 m8.50 mdisplacement?displacement?

Lecture 9 Andrei Sirenko, NJIT 34

pp