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Direct Tests of Cumulative Prospect Theory⇤
B. Douglas Bernheim †
Stanford University and NBER
Charles Sprenger‡
UC San Diego
First Draft: December 1, 2014This Version: November 8, 2016
Abstract
Cumulative Prospect Theory (CPT), the leading behavioral account of decision makingunder uncertainty, assumes that the probability weight applied to a given outcome dependson its ranking. This assumption is needed to avoid the violations of dominance implied byProspect Theory (PT). We devise a simple test involving three-outcome lotteries, basedon the implication that compensating adjustments to the payo↵s in two states shoulddepend on their rankings compared with payo↵s in a third state. In an experiment, we areunable to find any support for the assumption of rank dependence. We separately elicitprobability weighting functions for the same subjects through conventional techniquesinvolving binary lotteries. These functions imply that changes in payo↵ rank shouldchange the compensating adjustments in our three-outcome lotteries by 20-40%, yet wecan rule out any change larger than 7% at standard confidence levels. Additional testsnevertheless indicate that the dominance patterns predicted by PT do not arise. Wereconcile these findings by positing a form of complexity aversion that generalizes thewell-known certainty e↵ect.
JEL classification: D81, D90
Keywords : Prospect Theory, Cumulative Prospect Theory, Rank Dependence, Certainty Equiv-alents.
⇤We are grateful to Ted O’Donoghue, Colin Camerer, Nick Barberis, Kota Saito, and seminar participantsat Cornell, Caltech, and Gary’s Conference (UC Santa Barbara) for helpful and thoughtful discussions. FulyaErsoy, Vincent Leah-Martin, Seung-Keun Martinez, and Alex Kellogg all provided valuable research assistance.
†Stanford University, Department of Economics, Landau Economics Building, 579 Serra Mall, Stanford, CA94305; [email protected].
‡University of California San Diego, Rady School of Management and Department of Economics, 9500 GilmanDrive, La Jolla, CA 92093; [email protected].
1 Introduction
Prospect Theory (PT), as formulated by Kahneman and Tversky (1979), provides a flexible
account of decision making under uncertainty that accommodates a wide variety of departures
from the Expected Utility (EU) paradigm. As a result, it has been enormously influential
throughout the social sciences. In contrast to the EU formulations of von Neumann and Mor-
genstern (1944), Savage (1954), and Samuelson (1952), a central premise of PT holds that utility
is non-linear in proabilities, with highly unlikely events receiving greater proportionate weight
than nearly certain ones. This feature reconciles PT with important behavioral puzzles such
as the famous Allais (1953) paradoxes, as well as the simultaneous purchase of lottery tickets
and insurance, as in Friedman and Savage (1948). Probability weighting is also well-supported
by simple and widely replicated laboratory experiments.1
Unfortunately, the formulation of probability weighting embedded in PT leads to conceptual
di�culties because it implies violations of first-order stochastic dominance even in relatively
simple settings. This is a serious flaw given the broad consensus that this property renders a
model of decision making unappealing on both positive and normative grounds.2 To understand
the problem, consider a lottery that pays X with probability p; for our current purpose, we
will leave other events and payo↵s unspecified. Now imagine a second lottery, identical to the
first, except that it splits the aforementioned event, paying X and X � " each with probability
p/2.3 Given the S-shape of the probability weighting function, we can choose p so that the
total weight assigned to two events occurring with probability p/2 discretely exceeds the weight
1For example, when graphing the empirical certainty equivalent, C, for a lottery that pays X with probabilityp and 0 with probability 1�p, one typically finds an inverse S-shaped pattern, with pX exceeding C for moderate-to-large values of p (as risk aversion would imply), but with the opposite relation for small p (see, e.g., Tverskyand Kahneman, 1992; Tversky and Fox, 1995).
2As noted by Quiggin (1982), “Transitivity and dominance rules command virtually unanimous assent...even from those who sometimes violate them in practice... If a theory of decision under uncertainty is to beconsistent with any of the large body of economic theory which has already been developed... it must satisfythese rules.” (p. 325).
3Kahneman and Tversky (1979) described their theory as being concerned with lotteries that have at mosttwo non-zero outcomes. Hence, to apply Prospect Theory strictly in accordance with their original intent, onewould have to assume that this lottery pays zero with probability 1�p. Kahneman and Tversky (1979) actuallyprovided two formulations of Prospect Theory; we we assume their Equation 1 for ‘regular prospects.’ Theyimplicitly invoke the same assumption when examining the Allais common consequence paradox (p. 282).
1
assigned to a single event occurring with probability p. Consequently, if X is large and/or "
is small, the first lottery will yield lower PT utility than the second even though it is clearly
preferrable based on first-order stochastic dominance.4
Ultimately, “rank-dependent” probability weighting was o↵ered as a solution to the stochas-
tic dominance problem (Quiggin, 1982), and was incorporated into a new version of PT known
as Cumulative Prospect Theory, henceforth CPT (Tversky and Kahneman, 1992). To under-
stand intuitively how CPT resolves the issue, consider a lottery L with three possible payo↵s,
X > Y > Z, occurring with probabilities p, q, and 1 � p � q. Another description of the
same lottery involves cumulative probabilities: it pays Z with probability 1, adds Y � Z with
probability p+ q, and then incrementally adds X � Y with probability p. Accordingly, within
the EU framework, one could write its expected utility as follows:
Expected Utility = u(Z) + (p+ q)(u(Y )� u(Z)) + p(u(X)� u(Y )).
CPT involves an analogous calculation, except that a reference-dependent utility function,
u(·|r) (where r is the reference point), is applied to the payo↵s, while a weighting function,
⇡(·), is applied to the cumulative probabilities:
U(L) = ⇡(1)u(Z|r) + ⇡(p+ q)[u(Y |r)� u(Z|r)] + ⇡(p)[u(X|r)� u(Y |r)].
Normally this is rewritten in a form that attaches a weight to each outcome:
U(L) = ⇡(p)u(X|r) + [⇡(p+ q)� ⇡(p)]u(Y |r) + [⇡(1)� ⇡(p+ q)]u(Z|r). (1)
4 Kahneman and Tversky appreciated this problematic implication of PT and attempted to address itthrough an “editing” assumption: “Direct violations of dominance are prevented, in the present theory, bythe assumption that dominated alternatives are detected and eliminated prior to the evaluation of prospects”(p. 284). Most economists have found this ad hoc “fix” conceptually unsatisfactory, and it is rarely invokedin applications. Kahneman and Tversky also provided a formulation for two-outcome lotteries with either allpositive or all negative outcomes that does indeed respect dominance (see e.g., Equation 2 of Kahneman andTversky, 1979). One can see in that formulation the roots of Cumulative Prospect Theory.
2
Now imagine, as before, a second lottery, identical to the first, except that it splits the event
yielding the payo↵ X into two events paying X and X � ", each with probability p/2. In that
case, the term ⇡(p/2)u(X|r)+ [⇡(p)�⇡(p/2)]u(X� "|r) replaces the term ⇡(p)u(X|r). Notice
that the total weight assigned to the two events is still ⇡(p), the same as for the original lottery.
Consequently, the stochastic dominance problem noted above does not arise (Quiggin, 1982;
Tversky and Kahneman, 1992). CPT nevertheless accommodates the same assortment of EU
violations as PT. For these reasons, CPT has replaced PT as the leading behavioral model of
decision making under uncertainty.
To understand the sense in which CPT involves rank-dependent probability weighting, con-
sider the weight applied to the event that generates the payo↵ X as we change its value.
Initially X exceeds Y , and its weight is ⇡(p). As we reduce the value of X, the weight remains
unchanged until X passes below Y , at which point it changes discontinuously to ⇡(p+q)�⇡(q).
Thus, the weight assigned to the event depends not only on probabilities, but also on the ranking
of the event according to the size of the payo↵.
Given the central role the assumption of rank-dependent probability weighting plays in the
leading behavioral theory of decision-making under uncertainty, as well as in recent applications
of the theory,5 it has been the object of surprisingly little formal scrutiny. The prior literature’s
failure to explore and test the implications of rank dependence systematically is acknowledged
5 Barseghyan, Molinari, O’Donoghue and Teitelbaum (2015) investigate choices involving a range of insur-ance products. They demonstrate that the bracketing of risks – for example, whether people consider homeand automobile insurance together or separately – a↵ects the implications of probability weighting because itchanges the ranking of outcomes. Epper and Fehr-Duda (Forthcoming) examine the data from Andreoni andSprenger (2012) on intertemporal decision-making under various risk conditions, which exhibits deviations fromdiscounted expected utility. They argue that CPT can rationalize an apparent choice anomaly if one framestwo independent binary intertemporal lotteries as a single lottery with four possible outcomes. This alternativeframing delivers the desired prediction because it alters the rankings of the four outcomes. Barberis, Mukherjeeand Wang (Forthcoming) examine historical monthly returns at the stock level for a five year window and linkthe CPT value of the stock’s history to future returns, demonstrating a significant negative correlation. Theinterpretation for the negative relation is that investors overvalue positively skewed, lottery-like stocks. Given 60equi-probabable monthly return events, PT would equally overweight all outcomes, giving no disproportionatevalue for skewness. CPT, on the other hand, allows the highest ranked outcomes to receive higher proportionateweight. Barberis et al. (Forthcoming) show that CPT substantially outperforms EU in predicting future returns.Given that that the PT formulation (ignoring the reference point) would be collinear with the EU formulation,rank-dependence would seem critical for delivering this result.
3
in the review of Fehr-Duda and Epper (2012).6 The literature has focused instead on identi-
fying the shapes of CPT functions and associated parameter values based on choices involving
binary lotteries (Tversky and Kahneman, 1992; Tversky and Fox, 1995; Wu and Gonzalez,
1996; Gonzalez and Wu, 1999; Abdellaoui, 2000; Bleichrodt and Pinto, 2000; Booij and van de
Kuilen, 2009; Booij, van Praag and van de Kuilen, 2010; Tanaka, Camerer and Nguyen, 2010).
In cases where the experimental tasks encompass an appropriate range of binary lotteries, one
can devise and implement tests of rank dependence, conditional on maintained assumptions
about functional forms. Unfortunately, an incorrect functional specification can manifest as
spurious rank dependence. To our knowledge, in cases where such data are available, no for-
mal test of rank dependence has been performed.7 The literature does include a small number
of attempts to test the axiomatic foundations of rank-dependent models (Wu, 1994; Wakker,
Erev and Weber, 1994; Fennema and Wakker, 1996), and the findings have been on the whole
unfavorable.8 Defenses of rank dependence, such as the discussion in Diecidue and Wakker
(2001), are instead typically based on intuitive arguments and/or point to findings concerning
the psychology of decision making that arguably resonate with the premise (Lopes, 1984; Lopes
and Oden, 1999; Weber, 1994).
The current paper contributes to the literature by devising and implementing a simple,
direct, and robust test of rank-dependent probability weighting that requires no maintained
6They state “It is our impression that this feature of rank-dependent utility has often not been properlyunderstood. For example, an inverse S-shaped probability weighting function does not imply that all smallprobabilities are overweighted. Whether a small probability is overweighted or underweighted depends on therank of the outcome to which it is attached” (p. 571).
7As we explain in Appendix A, the data in Tversky and Kahneman (1992) lend themselves to such tests.Reanalyzing results from Tversky and Kahneman (1992), we find some support for rank dependence. However,as noted in the text, that finding hinges on the validity of their functional form assumptions. We show thatdepending on the assumptions for the shape of utility, probability weighting for a given chance of receiving anoutcome can either appear to be rank dependent or not.
8Wu (1994) tests the concept of ‘ordinal independence,’ which means that when two lotteries have commontails, one should be able to replace both tails without changing how anyone ranks the lotteries. The authorsobserve significant violations, which they explain by assuming that decision makers practice a form of editingprior to maximizing the CPT objective function. Wakker et al. (1994) and Fennema and Wakker (1996) providesimilar tests of comonotonic independence for both risk and ambiguity, which show more severe violations thanone would expect assuming noisy rank-dependent decision-making. They also find that a rank-dependentmodel does not meaningfully improve upon EU in terms of explanatory power. More recently, in the domain ofambiguity, L’Haridon and Placido (2010) investigate the closely related concept of ‘tail separability’, and alsodemonstrate significant violations.
4
assumptions concerning functional forms, either for utility and risk aversion, or for probability
weighting. An essential feature of our test is that it involves lotteries with three outcomes
rather than two. To understand why the presence of a third outcome facilitates a sharp and
powerful test of the premise, consider equation (1). For any small increase (m) in the value of
Y , there is a small equalizing reduction (k) in the value of Z that leaves the decision maker
indi↵erent. Both EU theory and PT imply that the magnitude of the equalizing reduction is
entirely indepedent of the value of X, regardless of functional forms. The same is true for
CPT, provided X remains within one of the following three ranges: X > Y +m, Y > X > Z,
or Z � k > X. However, as the value of X crosses from one of these ranges into another, the
ranking of the payo↵s changes, which causes the probability weights to change, thus altering
the equalizing reduction. In particular, if we increase X from a value just below Y to a value
just above Y + m, the weight on u(Y |r) changes from ⇡(q) to [⇡(p + q) � ⇡(p)] , while the
weight on u(Z|r) is una↵ected. Provided q is not too large, the shape of the standard CPT
probability weighting function implies [⇡(p + q) � ⇡(p)] < ⇡(q). Accordingly, the equalizing
reduction should decrease discontinuously when X crosses this boundary, with the magnitude
of the change reflecting the quantitative importance of rank dependence. Our strategy is to
test the weaker implication that the equalizing reduction should be smaller for X > Y + m
than for X 2 (Z, Y ).
Subjects in our experiment perform decision tasks that reveal their equalizing reductions for
three-outcome lotteries of the type described in the previous paragraph. Following previous
studies (Tversky and Kahneman, 1992; Tversky and Fox, 1995), we also elicit their certainty
equivalents for a collection of binary lotteries, which we use to derive their CPT parameters.
The results are striking. Using the data from the tasks involving binary lotteries, we reproduce
standard findings regarding probability weights: subjects apparently attach disproportionately
high weight to low probabilities and disproportionately low weight to high probabilities, so
the ⇡(·) curve has the standard inverse S-shape. Moreover, our estimates of the curvature
parameters correspond closely to those reported in the prior literature. Given this finding,
5
CPT yields dramatic predictions for our three-outcome lotteries: an increase in X that changes
the ranking of X and Y should change the equalizing reductions by –20% to –37%. Contrary to
this implication, we find no evidence that equalizing reductions are even modestly sensitive to
the ranking of outcomes. The actual change in the equalizing reduction ranges from +2.87%
to -2.74%, and in no case can we reject the hypothesis of rank-independence. However, in all
cases we can reject the hypothesis that the equalizing reduction falls by more than 7%, and
the confidence intervals for actual and predicted changes are always non-overlapping. These
patterns are also apparent at the individual level, with a preponderance of subjects exhibiting
virtually no rank dependence for their equalizing reductions, despite manifesting preferences
over binary lotteries that would imply substantial rank dependence within the CPT framework.
The results are robust with respect to a variety of alternative analytic procedures, such as
using only between-subject variation and eliminating potentially confused subjects. We also
consider alternative formulations of CPT, and assess related models that posit expectations-
based reference dependence (Koszegi and Rabin, 2006, 2007; Bell, 1985; Loomes and Sugden,
1986). These models have similar predictions for equalizing reductions, and hence we reject
them as well.
It is worth emphasizing that this stunning failure of CPT to account for our data is not
a mere technical shortcoming. Our test focuses on a first-order implication of the theory –
indeed, it isolates the critical feature that distinguishes CPT from PT. To put the matter
starkly, if equalizing reductions in three-outcome lotteries are not rank-dependent, then the
CPT agenda is on the wrong track.
What type of model should behavioral economists consider in place of CPT? One possibil-
ity is that PT is correct, and that people actually exhibit the implied violations of first-order
stochastic dominance. We test this possibility by eliciting certainty equivalents for three out-
come lotteries that pay X + " with probability p/2, X � " with probability p/2, and Y with
probability 1 � p. We include the case of " = 0, which reduces to a two-outcome lottery. We
choose the parameters so that standard formulations of PT predict a sizable and discontinuous
6
drop in the certainty equivalent at " = 0. In contrast, CPT implies continuity. Contrary to
both predictions, we find a discontinuous increase in the certainty equivalent at " = 0. This
behavior implies violations of dominance, but not the type PT predicts.
A good theory of choice under uncertainty would therefore have to account for three pat-
terns: (1) the inverse S-shaped certainty equivalent profile, (2) the absence of rank-dependence
in equalizing reductions, and (3) the sharp drop in certainty equivalents that results from split-
ting an event. EU is inconsistent with (1) and (3), while CPT is inconsistent with (2) and
(3), and PT is inconsistent with (3). We hypothesize that the observed behavior results from
a combination of standard PT and a form of complexity aversion: people may prefer lotteries
with fewer outcomes because they are easier to understand. One can think of the well-known
certainty e↵ect as a special case of this more general phenomenon.
The paper proceeds as follows. Section 2 outlines the pertinent implications of CPT and
related theories. Section 3 elaborates our experimental design, while section 4 presents our main
results and robustness checks. Section 5 discusses implications, including alternative theories
and tests thereof. Section 6 concludes.
2 Theoretical Considerations
We focus on the implications of Cumulative Prospect Theory (Tversky and Kahneman, 1992)
(CPT) for three outcome lotteries. Let L = ({p, q, 1�p�q}, {X, Y, Z}) represent a lottery with
three potential outcomes, X, Y, Z, with X > Y > Z > r, paid with corresponding probabilities
p, q, 1� p� q; 0 p, q, 1� p� q 1. The CPT representation is
U(L) = ⇡(p)u(X|r) + [⇡(p+ q)� ⇡(p)]u(Y |r) + [1� ⇡(p+ q)]u(Z|r).
We first introduce the notion of an ‘equalizing reduction.’ The equalizing reduction for a given
lottery L = ({p, q, 1 � p � q}, {X, Y, Z}) is the value k that delivers indi↵erence between L
and Le = ({p, q, 1 � p � q}, {X, Y + m,Z � k}). That is, k is the equalizing reduction to
7
Z that exactly compensates the decisionmaker for increasing Y by a given m. The intuition
for why the equalizing reduction may be of interest in the analysis of CPT decisionmaking is
clear: the CPT rank-dependent weighting of q depends upon whether the outcomes are ranked
X > Y > Z > r or Y > X 0 > Z > r. As such, the equalizing reduction will depend on whether
Y is the second highest or the highest ranked outcome. In contrast, Expected Utility Theory
(EUT) and PT imply that the equalizing reduction should be entirely independent of X.9
2.1 Equalizing Reductions: X > Y > Z
We first consider equalizing reductions for a lottery such as L, above, with X > Y > Z > r.
The equalizing reduction for increasing Y to Y +m < X (i.e., without changing the ranks) is
the value
k = Z � u�1
✓u(Z|r)�
⇡(p+ q)� ⇡(p)
1� ⇡(p+ q)
�[u(Y +m|r)� u(Y |r)]
◆. (2)
The notation k represents the equalizing reduction when Y and Y +m lie below X.10 Note that
k depends upon the weighted probability ratioh⇡(p+q)�⇡(p)1�⇡(p+q)
i. For an expected utility decision
maker this ratio is q1�p�q .
11 Under PT, the ratio would be ⇡(q)1�⇡(p)�⇡(q) . For all three theories, we
have @k/@X = 0, such that equalizing reductions are constant with respect to the outcome X,
provided X > Y, Y +m.
9An alternative approach would be to assess certainty equivalents for the lottery with outcomes X, Y, andZ, varying X as in our method. Under CPT (but not PT or EUT), the certainty equivalent would changediscontinuously when X crosses Y. An important di↵erence is that the certainty equivalent would also changewith X for a fixed ranking of X and Y, whereas with our method the equivalent reduction remains constant.Consequently, with the alternative method, one would have to disentangle rank dependence from the e↵ects ofrisk aversion. Our approach avoids that potential confound.
10 Solve for k as k satisfying
⇡(p)u(X|r) + [⇡(p + q) � ⇡(p)]u(Y |r) + [1 � ⇡(p + q)]u(Z|r) =
⇡(p)u(X|r) + [⇡(p + q) � ⇡(p)]u(Y + m|r) + [1 � ⇡(p + q)]u(Z � k|r).
11For an expected utility decisionmaker, k satisfies the equation
1 � p� q[u(Z) � u(Z � k)] = q[u(Y + m) � u(Y )].
8
2.2 Equalizing Reductions: Y > X 0 > Z
We now consider equalizing reductions for a lottery, L0 , with Y > X 0 > Z > r and the same
probabilities as before. The only di↵erence between lotteries L and L0 is that X is reduced to
X 0. The values of Y and Z remain unchanged, but Y now becomes the highest ranked outcome.
Given the new configuration of ranks, the equalizing reduction for increasing Y to Y +m is
k = Z � u�1
✓u(Z|r)�
⇡(q)
1� ⇡(p+ q)
�[u(Y +m|r)� u(Y |r)]
◆. (3)
The notation k represents the equalizing reduction when Y and Y +m lie above X 0.12 Note that
k now depends upon the weighted probability ratioh
⇡(q)1�⇡(p+q)
i. Once again, the ratio would
be q1�p�q under EUT and ⇡(q)
1�⇡(p)�⇡(q) under PT. Under all three theories, @k/@X 0 = 0, so that
equalizing reductions are constant with respect to the outcome X 0, provided X 0 < Y, Y +m.
The critical insight from examining (2) and (3) is that under CPT, k and k will generally
di↵er. This is because the relevant ratios,h
⇡(q)1�⇡(p+q)
iand
h⇡(p+q)�⇡(p)1�⇡(p+q)
i, will as a general matter
coincide only when ⇡(·) is linear.13 Hence, equalizing reductions will depend on whether the
ranks are arrayed as X > Y > Z or Y > X 0 > Z. This insight, in combination with the
observations that @k/@X = 0 and @k/@X 0 = 0, implies a distinctive relationship between k
and X: the equalizing reduction is constant as long as the fixed ranking remains, but shifts
discontinuously whenX passes across Y .14 Our strategy is to test the corresponding implication
that the equalizing reduction should be systematically di↵erent for X > Y + m than for
X 2 (Z, Y ). Critically, both EUT and PT imply that k should be invariant with respect to X.
In the next sub-section we provide a sense for the magnitude of the discontinuity implied by
CPT under standard parameterizations.
12 Solve for k as
⇡(q)u(Y |r) + [⇡(p + q) � ⇡(q)]u(X 0|r) + [1 � ⇡(p + q)]u(Z|r) =
⇡(q)u(Y + m|r) + [⇡(p + q) � ⇡(q)]u(X 0|r) + [1 � ⇡(p + q)]u(Z � k|r).
13With linearity, we have ⇡(q) = ⇡(p + q) � ⇡(p) .14Technically, the discontinuity occurs at Y in the limit as m goes to zero.
9
2.3 Simulated Equalizing Reductions under CPT Decisionmaking
In this section we derive the equalizing reductions, k and k, for given values of X,X 0, Y, Z and
m, and probabilities, p, q, and 1 � p � q. We focus on the parametric specification used in
the original formulation of CPT (Tversky and Kahneman, 1992),15 which posited probability
weighting function, ⇡(p) = p�/(p� + (1 � p)�)1/�, a reference point of r = 0, and a utility
function u(x) = x↵ for x > r = 0. The parameters identified by Tversky and Kahneman (1992)
were � = 0.61 and ↵ = 0.88.
Consider the lottery, L, with {X, Y, Z} = {$30, $24, $18} and {p, q, 1 � p � q} =
{0.4, 0.3, 0.3}. Increase Y by m = $5, from $24 to $29. For the parameters � = 0.61 and
↵ = 0.88, the equalizing reduction is k = 1.67. The CPT decision maker is indi↵erent between
the original lottery, L, and the perturbed lottery, Le, in which Y is $5 higher and Z is $1.67
lower.16
Now consider the lottery L0 with {X 0, Y, Z} = {$23, $24, $18} and {p, q, 1 � p � q} =
{0.4, 0.3, 0.3}. Increase Y by m = $5, from $24 to $29. For the same CPT parameters as
above, the equalizing reduction is k = $3.22.17 The CPT decisionmaker is indi↵erent between
the original lottery, L0, and the perturbed lottery, L0e, in which Y is $5 higher and Z is $3.22
lower.
Thus, a standard parameterization of CPT implies a sharp discontinuity in equalizing re-
ductions: moving from X 0 < Y to X > Y +m cuts the equalizing reduction roughly in half. In
Table 1, we provide further simulations with the above values of X, Y, Z, and m and di↵ering
parameter levels for �.18 Table 1 exhibits the results of analogous calculations for three di↵erent
probability vectors, {p, q, 1� p� q} = {0.6, 0.3, 0.1}, {0.4, 0.3, 0.3}, and {0.1, 0.3, 0.6}. For the
CPT parameter values of Tversky and Kahneman (1992), substantial di↵erences between k and
15Tversky and Fox (1995) and Gonzalez and Wu (1999) employ a similar two parameter ⇡(p) function. SeePrelec (1998) for alternative S -shaped specifications.
16Note that Y and Z are received with equal probability, so that a risk neutral decisionmaker would exhibitan equalizing reduction of k = $5.
17One again, note that a risk neutral decisionmaker would exhibit an equalizing reduction of k = $5.18To demonstrate the dependence of discontinuities in equalizing reduction on the extent of probability weight-
ing, we hold fixed, ↵ = 0.88 throughout.
10
k are predicted in all cases. The table also includes results for other values of the probability
weighting parameter. Even with more modest curvature of the probability weighting function
(� = 0.8), the discontinuities remain sizable. The final column of Table 1 shows that the dis-
continuities disappear when the probability weighting function becomes linear (� = 1), which
of course corresponds to the case of expected utility.19
Table 1: Cumulative Prospect Theory Simulated Equalizing Reductions
� = 0.4 � = 0.61 � = 0.8 � = 1
{p, q, 1� p� q} k k k - k k k k- k k k k - k k k k - k(% Change) (% Change) (% Change) (% Change)
{0.6, 0.3, 0.1} 1.97 1.33 -0.63 5.17 3.88 -1.29 9.21 7.84 -1.37 13.42 13.42 0(-32%) (-25%) (-15%) (0%)
{0.4, 0.3, 0.3} 1.61 0.53 -1.09 3.22 1.67 -1.56 4.29 3.13 -1.16 4.69 4.69 0(-68%) (-48%) (-27%) (0%)
{0.1, 0.3, 0.6} 1.45 0.40 -1.06 2.39 1.39 -1.00 2.60 2.08 -0.51 2.37 2.37 0(-73%) (-42%) (-20%) (0%)
Notes: Dollar values for equalizing reductions in Z for increase in Y to Y +m. k calculated with {X,Y, Z} ={$30, $24, $18}, m = $5. k calculated with {X 0
, Y, Z} = {$23, $24, $18}, m = $5. CPT calculations withu(x) = x
↵,↵ = 0.88; and ⇡(p) = p
�/(p� + (1 � p)�)1/� with � varying by column.
2.4 Reference Point Formulation and Alternative Models of Refer-
ence Dependence
Throughout the previous discussion, we implicitly assumed that the reference point, r, lay below
all potential outcomes. Though this is a natural starting point, one may imagine situations
where the reference point falls between payo↵s, which it segregates into gains and losses. CPT
treats gain and loss probabilities di↵erently, and consequently could in principle have somewhat
di↵erent implications in these settings. It is particularly important to consider the sensitivity
of the implied discontinuity to formulations that endogenize the reference point, such as Bell
(1985), Loomes and Sugden (1986), and Koszegi and Rabin (2006, 2007). In Appendices B
19Because the popularized functional form of Tversky and Kahneman (1992) features both convex and concaveregions of probability weighting, non-monotonicities in equalizing reductions with respect to the weightingparameter � can exist. One such non-monotonicity is observed for k in {0.1, 0.3, 0.6}.
11
and C, we consider these possibilities in detail, demonstrating that alternative formulations of
static reference points as well as models of expectations-based reference-dependence all exhibit
substantial sensitivity of equivalent reductions to the ranking of outcomes.20
3 Design
Our experimental design follows closely the theoretical discussion of section 2. Conditional on
various probability vectors, {p, q, 1 � p � q}, we test for di↵erences in equalizing reductions
between lotteries with ranks X > Y > Z and those with ranks Y > X 0 > Z. Subjects
also complete a battery of certainty equivalent tasks involving binary lotteries; these tasks
are commonly used to derive risk-preference parameters within the CPT framework. This
strategy allows us to compare the observed equalizing reductions to predicted values based on
elicited risk preferences for the same individuals. We divide our discussion of design into three
subsections. First we describe the elicitation of equalizing reductions; second we detail the
conventional elicitation of CPT preference parameters; third, we discuss other design details
including task orders and payment procedures.
3.1 Elicitation of Equalizing Reduction
We elicited equalizing reductions using the method of price lists. In each task, subjects made a
series of decisions between ‘Option A’ and ‘Option B’, both three outcome lotteries. Option A
was fixed throughout the task as either a lottery withX > Y > Z or a lottery with Y > X 0 > Z.
Option B was constructed by adding $5 to Y and reducing Z by $k. The value of k varied
throughout the task. The point at which an individual switched from choosing Option A to
choosing Option B places tight bounds on the equalizing reduction, either k or k. Panels A and
20A subtle feature this analysis involves the distinction between the models of Koszegi and Rabin (2006, 2007)and those of Bell (1985); Loomes and Sugden (1986). Because these models feature di↵erent formulations ofexpectations-based reference points, their predictions di↵er. Whereas Koszegi and Rabin (2006, 2007) predictchanges in equivalent reductions resulting from changes in ranks, the models of Bell (1985) and Loomes andSugden (1986) predict discontinuities as X crosses the induced lottery’s certainty equivalent. See Appendix Cfor further detail.
12
Figure 1: equalizing Reduction Tasks
Panel A : X > Y > Z Panel B : Y > X 0 > Z
k k
TASK 8On this page you will make a series of decisions between two uncertain options. Option A will be a 40
in 100 chance of receiving $30, a 30 in 100 chance of receiving $24 and 30 in 100 chance of receiving $18.Initially Option B will be a 40 in 100 chance of receiving $30, a 30 in 100 chance of receiving $29 and 30 in100 chance of receiving $18. As you proceed, Option B will change. The lowest amount you receive with30 in 100 chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B40 in 100 30 in 100 30 in 100 40 in 100 30 in 100 30 in 100Chance Chance Chance Chance Chance Chance
1) $30 $24 $18 2 or $30 $29 $18.00 22) $30 $24 $18 2 or $30 $29 $17.75 23) $30 $24 $18 2 or $30 $29 $17.50 24) $30 $24 $18 2 or $30 $29 $17.00 25) $30 $24 $18 2 or $30 $29 $16.75 26) $30 $24 $18 2 or $30 $29 $16.50 27) $30 $24 $18 2 or $30 $29 $16.25 28) $30 $24 $18 2 or $30 $29 $16.00 29) $30 $24 $18 2 or $30 $29 $15.75 210) $30 $24 $18 2 or $30 $29 $15.50 211) $30 $24 $18 2 or $30 $29 $15.25 212) $30 $24 $18 2 or $30 $29 $15.00 213) $30 $24 $18 2 or $30 $29 $14.50 214) $30 $24 $18 2 or $30 $29 $14.00 215) $30 $24 $18 2 or $30 $29 $13.50 216) $30 $24 $18 2 or $30 $29 $13.00 217) $30 $24 $18 2 or $30 $29 $12.50 218) $30 $24 $18 2 or $30 $29 $12.00 219) $30 $24 $18 2 or $30 $29 $11.50 220) $30 $24 $18 2 or $30 $29 $11.00 221) $30 $24 $18 2 or $30 $29 $10.50 222) $30 $24 $18 2 or $30 $29 $10.00 223) $30 $24 $18 2 or $30 $29 $9.50 224) $30 $24 $18 2 or $30 $29 $9.00 225) $30 $24 $18 2 or $30 $29 $8.50 226) $30 $24 $18 2 or $30 $29 $8.00 227) $30 $24 $18 2 or $30 $29 $7.50 228) $30 $24 $18 2 or $30 $29 $7.00 229) $30 $24 $18 2 or $30 $29 $6.50 230) $30 $24 $18 2 or $30 $29 $6.00 231) $30 $24 $18 2 or $30 $29 $5.50 232) $30 $24 $18 2 or $30 $29 $5.00 233) $30 $24 $18 2 or $30 $29 $4.50 234) $30 $24 $18 2 or $30 $29 $4.00 235) $30 $24 $18 2 or $30 $29 $3.50 236) $30 $24 $18 2 or $30 $29 $3.00 237) $30 $24 $18 2 or $30 $29 $2.50 238) $30 $24 $18 2 or $30 $29 $2.00 2
TASK 11On this page you will make a series of decisions between two uncertain options. Option A will be a 40
in 100 chance of receiving $23, a 30 in 100 chance of receiving $24 and 30 in 100 chance of receiving $18.Initially Option B will be a 40 in 100 chance of receiving $23, a 30 in 100 chance of receiving $29 and 30 in100 chance of receiving $18. As you proceed, Option B will change. The lowest amount you receive with30 in 100 chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B40 in 100 30 in 100 30 in 100 40 in 100 30 in 100 30 in 100Chance Chance Chance Chance Chance Chance
1) $23 $24 $18 2 or $23 $29 $18.00 22) $23 $24 $18 2 or $23 $29 $17.75 23) $23 $24 $18 2 or $23 $29 $17.50 24) $23 $24 $18 2 or $23 $29 $17.00 25) $23 $24 $18 2 or $23 $29 $16.75 26) $23 $24 $18 2 or $23 $29 $16.50 27) $23 $24 $18 2 or $23 $29 $16.25 28) $23 $24 $18 2 or $23 $29 $16.00 29) $23 $24 $18 2 or $23 $29 $15.75 210) $23 $24 $18 2 or $23 $29 $15.50 211) $23 $24 $18 2 or $23 $29 $15.25 212) $23 $24 $18 2 or $23 $29 $15.00 213) $23 $24 $18 2 or $23 $29 $14.50 214) $23 $24 $18 2 or $23 $29 $14.00 215) $23 $24 $18 2 or $23 $29 $13.50 216) $23 $24 $18 2 or $23 $29 $13.00 217) $23 $24 $18 2 or $23 $29 $12.50 218) $23 $24 $18 2 or $23 $29 $12.00 219) $23 $24 $18 2 or $23 $29 $11.50 220) $23 $24 $18 2 or $23 $29 $11.00 221) $23 $24 $18 2 or $23 $29 $10.50 222) $23 $24 $18 2 or $23 $29 $10.00 223) $23 $24 $18 2 or $23 $29 $9.50 224) $23 $24 $18 2 or $23 $29 $9.00 225) $23 $24 $18 2 or $23 $29 $8.50 226) $23 $24 $18 2 or $23 $29 $8.00 227) $23 $24 $18 2 or $23 $29 $7.50 228) $23 $24 $18 2 or $23 $29 $7.00 229) $23 $24 $18 2 or $23 $29 $6.50 230) $23 $24 $18 2 or $23 $29 $6.00 231) $23 $24 $18 2 or $23 $29 $5.50 232) $23 $24 $18 2 or $23 $29 $5.00 233) $23 $24 $18 2 or $23 $29 $4.50 234) $23 $24 $18 2 or $23 $29 $4.00 235) $23 $24 $18 2 or $23 $29 $3.50 236) $23 $24 $18 2 or $23 $29 $3.00 237) $23 $24 $18 2 or $23 $29 $2.50 238) $23 $24 $18 2 or $23 $29 $2.00 2
13
B of Figure 1 provide two tasks eliciting k and k. Appendix F provides the full instructions
given to subjects along with all tasks.
As in the simulations of section 2, our design fixes Y = $24, Z = $18, and m = $5. We
use three values of X > Y +m , {$34, $32, $30}, and three values of X 0 < Y , {$23, $21, $19}.
We use one additional value, X = $25, to check robustness; see the discussion in Appendix
E.21 This set of values allows us to investigate both rank dependence and the predictions that
@k/@X = 0 and @k/@X 0 = 0.
As in the simulations of section 2, we examine three probability vectors, {p, q, 1� p� q} =
{0.6, 0.3, 0.1}, {0.4, 0.3, 0.3}, and {0.1, 0.3, 0.6}. The cumulative probability of receiving at least
Y ranges from 0.1 + 0.3 = 0.4 to 0.6 + 0.3 = 0.9, which provides broad scope for detecting
the predicted discontinuities. Note that the design varies the relative probabilities of Y and Z
from 0.3/0.1 = 3 to 0.3/0.6 = 1/2, generating a wide range of equalizing reductions.22
With seven values of X/X 0 and three probability vectors, we have 21 equalizing reduction
tasks in total. We organize these tasks into seven blocks, each of which presents the three prob-
ability vectors for a single value of X/X 0. Hence, the tasks within each block are di↵erentiated
by the probability vector, {p, q, 1�p�q}. We distributed task blocks to subjects one at a time,
and collected responses before moving on to the next block. This feature of our design was
intended to limit any tendency to respond mechanically with the same answer as X varies, a
possibility that could artificially generate patterns consistent with @k/@X = 0 and @k/@X 0 = 0
while obscuring discontinuities.
3.2 Prospect Theory Elicitation Tasks
We generate predictions of equalizing reductions for our subjects by eliciting their risk prefer-
ence parameters using the same experimental techniques employed by Tversky and Kahneman
(1992). The approach employs seven tasks, each of which elicits the certainty equivalents for
21Note that for X = $25, adding $5 to Y induces a change of ranks. These tasks allow us to investigate thepossibility that explicit rank changes influence choice. See Appendix E for further detail.
22For example, an expected value decision maker would exhibit values of k, k between $2.50 and $15 acrossthese tasks.
14
a two-outcome lottery, (p, $25; 1 � p, 0), p 2 {0.05, 0.1, 0.25, 0.5, 0.75, 0.9, 0.95}. We grouped
these tasks in a single block. Figure 2 illustrates one of these tasks, and Appendix F describes
the full set. Although these tasks provide no information concerning rank-dependence in prob-
ability weighting, they allow us to determine whether our sample exhibits representative risk
preferences, and they permit us to generate precise sample-specific predictions for equalizing
reductions.
Figure 2: Prospect Theory Elicitation Task
TASK 22On this page you will make a series of decisions between two options. Option A will be a 50 in 100
chance of receiving $25 and a 50 in 100 chance of receiving $0. Initially Option B will be a 100 in 100chance of receiving $25. As you proceed, Option B will change. The amount you receive with 100 in 100chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B50 in 100 Chance 50 in 100 Chance 100 in 100 Chance
1) $25 $0 2 or $25.00 22) $25 $0 2 or $24.00 23) $25 $0 2 or $23.00 24) $25 $0 2 or $22.00 25) $25 $0 2 or $21.00 26) $25 $0 2 or $20.00 27) $25 $0 2 or $19.00 28) $25 $0 2 or $18.00 29) $25 $0 2 or $17.00 210) $25 $0 2 or $16.00 211) $25 $0 2 or $15.00 212) $25 $0 2 or $14.00 213) $25 $0 2 or $13.00 214) $25 $0 2 or $12.00 215) $25 $0 2 or $11.00 216) $25 $0 2 or $10.00 217) $25 $0 2 or $9.00 218) $25 $0 2 or $8.00 219) $25 $0 2 or $7.00 220) $25 $0 2 or $6.00 221) $25 $0 2 or $5.00 222) $25 $0 2 or $4.00 223) $25 $0 2 or $3.00 224) $25 $0 2 or $2.00 225) $25 $0 2 or $1.00 226) $25 $0 2 or $0.00 2
15
3.3 Design Details
One hundred fifty three subjects were recruited from the Stanford Economics Research Labo-
ratory subject pool in September, October, and November of 2014. A total of 20 sessions were
conducted with the number of subjects varying between two and sixteen. We varied the order
of the six main equalizing reduction blocks systematically across session. Subjects completed
three equalizing reduction blocks, then the CPT elicitation block, then three more equalizing
reduction blocks. The X = $25 equalizing reduction tasks were always presented last. Table 2
lists all sessions, dates, numbers of subjects and block orders.
Table 2: Experimental SessionsNumber Date Order # Obs
1 09/24/14 {34, 32, 30, CE, 23, 21, 19, 25} 162 09/24/14 {34, 21, 30, CE, 23, 32, 19, 25} 113 09/30/14 {23, 32, 19, CE, 34, 21, 30, 25} 94 09/30/14 {19, 32, 23, CE, 30, 21, 34, 25} 125 10/01/14 {30, 21, 34, CE, 19, 32, 23, 25} 126 10/02/14 {21, 30, 34, CE, 32, 19, 23, 25} 147 10/07/14 {32, 19, 23, CE, 21, 30, 34, 25} 108 10/07/14 {23, 19, 32, CE, 34, 30, 21, 25} 59 10/08/14 {34, 30, 21, CE, 23, 19, 32, 25} 1310 10/09/14 {30, 34, 21, CE, 19, 23, 32, 25} 511 10/14/14 {19, 23, 32, CE, 30, 34, 21, 25} 412 10/16/14 {32, 23, 19, CE, 21, 34, 30, 25} 613 10/26/14 {21, 34, 30, CE, 32, 23, 19, 25} 714 10/28/14 {21, 34, 30, CE, 32, 23, 19, 25} 315 10/29/14 {32, 23, 19, CE, 21, 34, 30, 25} 216 11/05/14 {23, 19, 32, CE, 34, 30, 21, 25} 217 11/07/14 {19, 23, 32, CE, 30, 34, 21, 25} 618 11/10/14 {23, 19, 32, CE, 34, 30, 21, 25} 619 11/14/14 {30, 34, 21, CE, 19, 23, 32, 25} 620 11/18/14 {32, 23, 19, CE, 21, 34, 30, 25} 4
Total 153
Notes: Session number, date, order and number of observations. Order of tasks refers to the value of X/X
0 in
each task block. CE corresponds to the block of tasks with certainty equivalent questions.
To induce truthful revelation of equalizing reductions and certainty equivalents, we incen-
tivized subjects by paying them based on one randomly selected question in one randomly
selected task. On average, subjects earned $26.87. This random-lottery incentive mechanism
16
is widely used in experimental economics, but note that it transforms the experiment into
a single compound lottery. The literature on choice under risk, dating to Holt (1986) and
Karni and Safra (1987), suggests that random mechanisms need not be incentive compatible
in such contexts if either the Independence or Reduction of Compound Lotteries axioms are
violated. As CPT violates independence, this limitation is a potential concern. Importantly,
however, Starmer and Sugden (1991) and Cubitt, Starmer and Sugden (1998) demonstrate
that this mechanism can be used even when individuals deviate from expected utility because,
in practice, subjects appear to narrowly frame each lottery, making each decision e↵ectively
in isolation. Whether their findings apply to our setting is of course an empirical question.
Our CPT-preference elicitation tasks are especially important because they allow us to assess
the validity of the method we use. If isolation fails in this context, then our subjects would
not exhibit standard CPT probability weighting in binary tasks. Conversely, if our subjects
do exhibit standard CPT probability weighting in binary tasks, then one cannot reasonably
attribute the absence of implied discontinuities in the compensating reduction tasks to a failure
of isolation.
Ten of 153 (6.5%) subjects exhibited at least one instance of multiple switching within a
single experimental task. This figure compares favorably to other experiments employing price
lists.23 Because multiple switch points are di�cult to rationalize and may indicate subject
confusion, researchers often exclude such observations or mechanically enforce single switch
points.24 We begin by excluding all subjects exhibiting multiple switch points in any task,
leaving a sample of 143 subjects. In Appendix E we include the ten subjects with multiple
switch points, taking each subject’s first switch point as their relevant choice, and demonstrate
that the results are qualitatively unchanged.
23Around 10 percent of subjects feature multiple switch points in similar price-list experiments (Holt andLaury, 2002; Meier and Sprenger, 2010), and as many as 50 percent in some cases (Jacobson and Petrie, 2009).
24See Harrison, Lau, Rutstrom and Williams (2005) for discussion.
17
4 Results
We present our results in four subsections. We begin with the prospect theory elicitation tasks,
demonstrating the classic probability weighting found in previous studies. The correspond-
ing parameter estimates provide a segue to the second subsection, which explores equalizing
reductions. Although the estimated probability weighting function implies substantial discon-
tinuities, we show that there is no relationship between payo↵ ranks and equalizing reductions.
The third subsection focuses on results for individual subjects, and corroborates the absence
of support for rank-dependent probability weighting. The fourth subsection presents tests of
robustness focusing primarily on between-subject variation. Additional robustness exercises
beyond the results appear in Appendix E.
4.1 Certainty Equivalents: Eliciting CPT Parameters
As in the original experiments of Tversky and Kahneman (1992), we administered seven cer-
tainty equivalent tasks involving lotteries over $25 and $0, with the governing probability
p 2 {0.05, 0.10, 0.25, 0.50, 0.75, 0.90, 0.95}. Figure 3, Panel A summarizes these data. To cap-
ture average behavior, we first estimated an interval regression (Stewart, 1983) describing the
certainty equivalent, C, as a function of indicators for the experimental probabilities, p.25 Fig-
ure 3, Panel A thus presents the estimated mean certainty equivalent for each value of p along
with its 95% confidence interval.26 Following Tversky and Kahneman (1992), the data are
presented relative to a benchmark of risk neutrality so that Figure 3, Panel A would directly
reveal aggregate probability weighting, ⇡(·), if the utility function were linear.
Tversky and Kahneman (1992) and Tversky and Fox (1995) obtain probability weighting pa-
rameters from certainty equivalents by parameterizing both the utility and probability weighting
functions and assuming each observation satisfies the indi↵erence condition u(C) = ⇡(p) ·u(25).25Virtually identical results are obtained when using OLS and the midpoint of the interval.26Standard errors are estimated clustered at the individual level. Appendix Table A2, column (1) provides
corresponding estimates. Column (2) provides estimates of risk premia, demonstrating significant risk toleranceat low probabilities and significant risk aversion at high probabilities.
18
Figure 3: Certainty Equivalents and Equalizing Reductions0
510
1520
25C
erta
inty
Equ
ival
ent
0 20 40 60 80 100Chance of $25
C CPT ModelRisk Neutral 95% CI
Panel A: Certainty Equivalents
05
10Eq
ualiz
ing
Red
uctio
n: k
for X
, Y=2
4+5,
Z=1
8-k
20 25 30 35X
with Y = 24, Z = 18
p = 0.6 p = 0.4 p = 0.195% CI CPT Pred CPT 95% CI
Panel B: Equalizing Reductions
Notes: Panel A: Mean behavior for C estimated from interval regression (Stewart, 1983) of experimental re-sponse on indicators for probability vectors. Standard errors clustered at individual level to provide 95%confidence interval. Appendix Table A2, column (1) provides corresponding estimates. Dashed line correspondsto predicted CPT behavior with ↵̂ = 0.941 (s.e. = 0.019) and �̂ = 0.715 (0.015); standard errors clustered atindividual level. Panel B: Mean behavior for k estimated from interval regression of experimental response onindicators for probability vectors interacted with indicators for value of X. Standard errors clustered at indi-vidual level to provide 95% confidence interval. Appendix Table A4 provides corresponding estimates. Dashedline corresponds to predicted values of (2) and (3) for CPT decision maker with risk preference parameters↵̂ = 0.941 (s.e. = 0.019) and �̂ = 0.715 (0.015). Standard errors clustered at individual level and calculatedusing the delta method to provide 95% confidence interval.
We follow Tversky and Kahneman (1992) by assuming power utility, u(x) = x↵, and a weighting
function ⇡(p) = p�/(p� +(1�p)�)1/�. We then estimate the parameters �̂ and ↵̂ by minimizing
the sum of squared residuals for the non-linear regression equation
C = [p�/(p� + (1� p)�)1/� ⇥ 25↵]1↵ + ✏. (4)
where C is the midpoint of the certainty equivalent interval defined by experimental choice.
When conducting this analysis for our aggregate data with standard errors clustered on the
subject level, we obtain ↵̂ = 0.941 (s.e. = 0.019) and �̂ = 0.715 (0.015). The benchmark model
19
of expected utility, � = 1, is rejected at all conventional confidence levels, (F1,142 = 341.5, p <
0.01). The value of the probability weighting parameter is reasonably close to the estimate of
Tversky and Kahneman (1992) (�̂ = 0.61), and coincides with the findings of Wu and Gonzalez
(1996), who estimate �̂ = 0.71. The dashed line in Figure 3, Panel A, shows the in-sample
model fit, which closely matches actual behavior.27
The empirically parameterized probability weighting function does an impressive job of
matching the patterns exhibited by average certainty equivalents. Given this parameterization,
if the CPT framework is correct, we would expect to observe substantial discontinuities in
equalizing reductions as ranks change. We turn next to the equalizing reductions, and test the
prediction that behavior di↵ers depending on whether the ranks are arrayed as X > Y > Z or
Y > X 0 > Z.
4.2 Average Equalizing Reductions
Figure 3, Panel B presents equalizing reductions, k and k, for each value of X and X 0. We
exhibit separate results for each of the three probability vectors. To determine average behavior,
we performed an interval regression describing the equalizing reduction, k or k, as a function of
indicators for the probability vectors interacted with indicators for the value of X or X 0.28 The
figure exhibits the estimated mean equalizing reductions along with 95% confidence intervals.29
Vertical lines at Y = $24 and Y +m = $29 partition the figure into three regions, one showing
k, another showing k, and a transitional region.
Notable from Figure 3 is the consistency of the equalizing reductions, k and k, for all three
probability vectors. Corresponding statistics are provided in Table 3, Panel A. For {p, q, 1 �
p � q} = {0.6, 0.3, 0.1}, the mean value of k is 9.02 (clustered s.e. = 0.39), while the mean
27The correlation coe�cient for predicted and actual certainty equivalents is 0.93, and a regression of thetrue certainty equivalent on the model’s prediction yields a slope coe�cient of 0.998 (clustered s.e. = 0.020), aconstant of 0.102 (0.214), and an R-squared value of 0.86. The null hypothesis that the constant is 0 and thepredicted value’s true coe�cient is 1 is not rejected (F2,142 = 0.17, p = 0.84).
28Virtually identical results are obtained when using OLS and the midpoint of the interval.29Standard errors are estimated clustered at the individual level. Appendix Table A4 provides corresponding
estimates.
20
Table 3: Equalizing Reductions
Panel A: Mean Behavior Panel B: CPT Predicted Values
{p, q, 1� p� q} k k k - k % Change k k k- k % Change[95% Conf.] [95% Conf.] [95% Conf.] [95% Conf.]
{0.6, 0.3, 0.1} 9.02 (0.39) 9.28 (0.38) 0.26 (0.17) 2.87 (1.92) 7.58 (0.36) 6.06 (0.35) -1.52 (0.03) -20.04 (0.83)[-0.08,0.59] [-0.90,6.65] [-1.57,-1.47] [-21.68,-18.40]
{0.4, 0.3, 0.3} 4.31 (0.12) 4.34 (0.12) 0.04 (0.09) 0.86 (2.00) 4.01 (0.10) 2.52 (0.13) -1.49 (0.04) -37.17 (1.74)[-0.13,0.21] [-3.07,4.78] [-1.57,-1.41] [-40.61,-33.72]
{0.1, 0.3, 0.6} 2.63 (0.08) 2.56 (0.07) -0.07 (0.06) -2.74 (2.06) 2.65 (0.03) 1.87 (0.06) -0.78 (0.04) -29.34 (1.79)[-0.18,0.04] [-6.78,1.29] [-0.86,-0.69] [-32.88,-25.80]
Notes: Panel A: Mean behavior for k and k estimated from interval regression (Stewart, 1983) of experi-mental response on indicators for probability vector interacted with indicator for whether X > Y . Standarderrors clustered at individual level, in parentheses. See Appendix Table A3, column (1) and Appendix TableA4 for detail. Panel B: Predicted behavior calculated from (2) and (3) for CPT decision maker with ag-gregate parameters ↵̂ = 0.941 (s.e. = 0.019) and �̂ = 0.715 (0.015). Standard errors clustered at individuallevel and calculated using the delta method, in parentheses.
value of k is 9.28 (0.38). The di↵erence, k � k = 0.26 (0.17), is not statistically di↵erent
from zero �2(1) = 2.31, p = 0.13. Expressed as a percentage, this corresponds to 2.87%
(1.92%) change. The 95% confidence interval for k � k is [�0.08, 0.59], indicating that we can
reject discontinuities in equalizing reductions more extreme than $-0.08 (-0.90%) at the 5%
significance level. Similar results are obtained for the other probability series.30
Panel B of Figure 3 also displays the predicted values of k and k, based on our estimates
of the CPT parameters, ↵̂ = 0.941 (s.e. = 0.019) and �̂ = 0.715 (0.015). With this parameter-
ization, we obtain closed-form solutions for k and k based on (2) and (3), and derive standard
errors using the delta method. Figure 3 shows the predicted values along with 95% confidence
intervals, shown as dashed lines. Substantial discontinuities are readily apparent.
30 For {p, q, 1 � p � q} = {0.4, 0.3, 0.3}, the mean value of k is 4.31 (0.12), while the mean value of k is4.34 (0.12). The di↵erence, k � k = 0.04 (0.09), is not statistically di↵erent from zero �
2(1) = 0.18, p = 0.67.The 95% confidence interval for k� k is [�0.13, 0.21], indicating that we can reject discontinuities in equalizingreductions more extreme than $-0.13 (-3.07%). For {p, q, 1 � p� q} = {0.1, 0.3, 0.6}, the mean value of kis2.63(0.08), while the mean value of kis2.56 (0.07). The di↵erence, k� k = �0.07(0.06), is not statistically di↵erentfrom zero �
2(1) = 1.70, p = 0.19. The 95% confidence interval for k� k is [�0.18, 0.04], indicating that we canreject discontinuities in equalizing reductions more extreme than $-0.18 (-6.78%). In Appendix Table A5 andAppendix Table A3, column (2) we reproduce the analysis of Table 3, Panel A and Appendix Table A3, column(1) with individual fixed e↵ects and robust standard errors and reach identical conclusions.
21
Corresponding statistics for predicted behavior appear in Table 3, Panel B. For {p, q, 1 �
p � q} = {0.6, 0.3, 0.1}, the predicted values are k = 7.58 (clustered s.e. = 0.36) and k =
6.06 (0.35). The predicted gap, k � k = �1.52 (0.03), is significantly di↵erent from zero,
F1,142 = 3634.43, (p < 0.01). Expressed as a percentage, this discrepancy corresponds to a
20.04% (0.83%) decrease in equalizing reduction as ranks change. Predictions for the other
probability series are even more extreme.31
The contrast between our findings and the theoretical implications of CPT are striking. CPT
predicts that equalizing reductions should change significantly as ranks change, but we find no
evidence of rank dependence, and we can confidently rule out even relatively small changes.
For every probability vector we consider, the 95% confidence intervals for the predicted and
actual di↵erence in equalizing reductions, k � k, are non-overlapping.32 Given that (1) we
have estimated the CPT parameters for the same set of subjects used to study equalizing
reductions, (2) we estimate those parameters using standard methods, and (3) the resulting
parameter estimates coincide with standard findings, we view these results as striking evidence
against the empirical validity of CPT’s assumption of rank-dependent probability weighting.
In principle, the predictive failures documented above could reflect the influence of unrep-
resentative subjects. In the next section we reexamine the data at the subject level, estimating
CPT parameters and evaluating predictive accuracy separately for each individual.
31For {p, q, 1 � p � q} = {0.4, 0.3, 0.3}, the predicted values are k = 4.01 (0.10) and k = 2.52 (0.13). Thepredicted gap, k � k = �1.49 (0.04), is significantly di↵erent from zero, F1,142 = 1363.43, (p < 0.01). Thisdiscrepancy corresponds to a 37.17% (1.74%) decrease in equalizing reduction as ranks change. For {p, q, 1 �p � q} = {0.1, 0.3, 0.6}, the predicted values are k = 2.65 (0.03) and k = 1.87 (0.06). The predicted gap,k � k = �0.78 (0.04), is significantly di↵erent from zero, F1,142 = 310.44, (p < 0.01). This discrepancycorresponds to a 29.34% (1.79%) decrease in equalizing reduction as ranks change.
32With mean estimates and standard errors for both predicted and actual values and assumptions of normalityfor both, hypothesis tests for equality between predicted and actual di↵erences are easily implemented viacalculation of the following test statistic:
z =(k � k)predicted � (k � k)actualq
s.e.(k � k)2predicted + s.e.(k � k)2actual
,
Under the null hypothesis of equality, the distribution of z is standard normal. For {p, q, 1 � p � q} ={0.6, 0.3, 0.1}, z = 10.3, (p < 0.01). For {p, q, 1 � p � q} = {0.4, 0.3, 0.3}, z = 16.1, (p < 0.01). For{p, q, 1 � p� q} = {0.1, 0.3, 0.6}, z = 9.95, (p < 0.01).
22
4.3 Subject-level Analysis
Each subject in our experiment provides us with data on equalizing reductions and certainty
equivalents. Accordingly, we can replicate our analysis at the subject level. For each subject and
each probability vector, we calculate the average k and k for values of X 0 < Y and X > Y +m,
respectively.33 Additionally, we use each subject’s certainty equivalent data to estimate their
CPT risk preference parameters based on (4), and then predict equalizing reductions for each
probability vector based on (2) and (3). The estimates of (4) imply well-defined values of k or
k for 136 of our 143 subjects.34
Figure 4 presents the distributions of predicted and actual values for k � k for each prob-
ability vector, along with their relationship for the subjects considered. For {p, q, 1 � p �
q} = {0.6, 0.3, 0.1}, the median actual value for k � k is $0 and the interquartile range is
[�$0.33, $0.66]. Results for the other probability vectors are similar.35 Thus, the changes in
equalizing reductions for our subjects are concentrated within a small band around zero.
Though the equalizing reductions exhibit almost no rank dependence, substantial di↵erences
between k and k are predicted; see Figure 4, Panel A.36 Panel B shows the relationship between
predicted and actual values of k � k. For every probability vector, the correlation between
predicted and actual behavior is indistinguishable from zero.37
Our subject-level results provide striking evidence against CPT’s assumption of rank-
dependent probability weighting. The majority of subjects exhibit only small changes in equal-
33This calculation is based on the midpoints of the intervals for k or k implied by each subject’s switch point.34Though we obtain estimates of ↵ and � for the remaining seven subjects, the values are extreme. (In five
cases the values of � are extreme, and in two cases the values of both ↵ and � are extreme.) The non-lineartechnique we use to estimate k or k can fail to converge at extreme values.
35For {p, q, 1 � p � q} = {0.4, 0.3, 0.3}, the median actual value for k � k is $0 and the interquartile rangeis [�$0.33, $0.33] while for {p, q, 1 � p � q} = {0.1, 0.3, 0.6}, the median actual value for k � k is $0 and theinterquartile range is [�$0.21, $0.25].
36For {p, q, 1 � p� q} = {0.6, 0.3, 0.1}, the median predicted value for k � k is $-1.12, for {p, q, 1 � p� q} ={0.4, 0.3, 0.3}, it is $-1.24, and for {p, q, 1 � p � q} = {0.1, 0.3, 0.6}, it is $-0.63. Wilcoxon signed rank testsfor equivalent distributions across predicted and actual values of k � k yield the following test statistics: z =7.48, (p < 0.01), z = 8.90, (p < 0.01), and z = 7.45, (p < 0.01) for {p, q, 1�p�q} = {0.6, 0.3, 0.1}, {0.4, 0.3, 0.3},and {0.1, 0.3, 0.6}, respectively.
37 Correlations between predicted and actual values of k� k are ⇢ = �0.05, (p = 0.58), ⇢ = 0.08, (p = 0.37),and ⇢ = 0.05, (p = 0.53) for {p, q, 1 � p� q} = {0.6, 0.3, 0.1}, {0.4, 0.3, 0.3}, and {0.1, 0.3, 0.6}, respectively.
23
Figure 4: Individual Results0
1020
3040
500
1020
3040
500
1020
3040
50
-5 -4 -3 -2 -1 0 1 2 3 4 5
p = 0.60
p = 0.40
p = 0.10
Actual Predicted
Perc
ent
Difference in Equivalent Reductions
Panel A: Predicted and Actual Distributions
-50
5-5
05
-50
5
-3 -2 -1 0 1
p = 0.60
p = 0.40
p = 0.10Ac
tual
Diff
eren
ce
Predicted Difference
Panel B: Predicted and Actual Relationship
Notes : Mean actual value of k � k calculated for each individual in each probability set.Predicted value of k� k calculated for each individual from (2) and (3) for CPT decisionmakerwith parameters estimated from each individual’s certainty equivalent responses. Not includedin graph, but included in statistics, are four observations with actual values for |k � k| > 5.
izing reductions as ranks change from X > Y to X 0 < Y . Further, the individualized CPT
models predict sizable changes for many subjects, and those predictions bear no relation to
the actual magnitudes. Plainly, our main findings are not driven by a few unrepresentative
subjects.
4.4 Robustness: Between-Subject Variation
Our main findings exploit within-subject variation in payo↵ rank. If a subject’s early responses
in the tasks used to elicit equalizing reductions somehow anchor their later responses, that
approach could obscure rank dependence. We note, however, that responses often change
24
considerably at the individual level from one block of tasks to the next. For example, between
the first and second block of tasks, 59% of individual responses di↵er and 37% of responses
di↵er by more than 25 percent.38
To address any residual concerns about anchoring, we replicate our analysis using only
the first task block for each subject. Recall that payo↵ rank is fixed within each block. It
follows that, with this alternative approach, we identify possible rank-dependence entirely from
between-subject variation using responses that are untainted by anchoring. For such between-
subjects analysis, we rely only on the variation in the ordering of tasks across sessions. To
account for selection on observable characteristics, we additionally include measures of gender,
age, and cognitive ability from a post-study questionnaire and each subject’s average certainty
equivalent in their binary lottery tasks to control for the level of risk aversion.39
Table 4 presents between-subjects results based on the first task blocks with and without the
controls noted above.40 We see a hint of rank dependence, particularly for {p, q, 1 � p � q} =
{0.6, 0.3, 0.1}, without controls in Panel A. With controls in Panel B we find essentially no
di↵erences between k and k. In all cases, the degree of observed rank dependence falls far short
of the CPT predictions from Table 3, Panel B.
Can one construe the small di↵erences between k and k without controls as limited evidence
of rank-dependent probability weighting and CPT? In our view, any such inference would be
unwarranted. With 143 subjects in total, the subsamples that first faced X 0 < Y and X > Y
38The 143 subjects make three decisions in each task block yielding 429 potential di↵erences across the firstand second task blocks. Of these, 175 responses (41%) exhibit no change, 100 responses (23%) increase, and 154(36%) decrease. The order of the first two task blocks has no measurable relationship with changes. Forty-foursubjects began with X
0< Y first and then proceeded to X > Y , giving 132 potential di↵erences. Of these,
57 responses (43%) exhibit no change, 34 responses (26%) increase, and 41 (31%) decrease. Forty-one subjectsbegan with X > Y first and then proceeded to X
0< Y , giving 123 potential di↵erences. Of these, 50 responses
(41%) exhibit no change, 33 responses (27%) increase, and 40 (33%) decrease. Under the estimated CPT model,one would expect more frequent decreases for subjects with X
0< Y first and more frequent increases for subjects
with X > Y first. The di↵erences in response across the first two blocks does not seem localized to a limitednumber of subjects with only 28 of 143 subjects (20%) exhibiting no change across any of the three decisions,and 45 (31%) exhibiting a change in all three.
39Cognitive ability is measured with the three question Cognitive Reflection Test introduced and validated inFrederick (2005).
40 See Appendix Table A3, columns (3) and (5) for further detail on these regressions. Of the 143 subjects inthe primary sample, 21 had the X
0 = 19 block first, 23 had the X
0 = 21 block first, 21 had the X
0 = 23 blockfirst, 22 had the X = 30 block first, 19 had the X = 32 block first, and 37 had the X = 34 block first.
25
are of modest size, and consequently, not perfectly matched. Indeed, we find some hints of
selection across these subsamples in observable characteristics such as gender, cognitive ability,
and average risk aversion, all of which correlate highly with equalizing reductions (see Appendix
Table A3, Columns (5) and (6) for detail).41 Absent controls for this potential selection, the
di↵erences in characteristics inflate k relative to k, spuriously producing the appearance of rank
dependence.42
Table 4: Equalizing Reductions Between Subjects
Panel A: First Task Block (without Controls) Panel B: First Task Block (with Controls)
{p, q, 1� p� q} k k k - k % Change k k k- k % Change[95% Conf.] [95% Conf.] [95% Conf.] [95% Conf.]
{0.6, 0.3, 0.1} 9.81 (0.65) 8.71 (0.56) -1.10 (0.85) -11.23 (8.15) 9.77 (0.60) 9.13 (0.56) -0.64 (0.83) -6.56 (8.16)[-2.77,0.57] [-27.21,4.76] [-2.26,0.98] [-22.54,9.43]
{0.4, 0.3, 0.3} 4.78 (0.19) 4.41 (0.19) -0.37 (0.27) -7.82 (5.50) 4.65 (0.22) 4.61 (0.21) -0.04 (0.31) -0.87 (6.72)[-0.91,0.16] [-18.60,2.95] [-0.65,0.57] [-14.03,12.29]
{0.1, 0.3, 0.6} 3.16 (0.16) 2.88 (0.12) -0.28 (0.20) -8.91 (6.00) 3.01 (0.20) 3.07 (0.16) 0.06 (0.26) 2.16 (8.84)[-0.68,0.11] [-20.66,2.84] [-0.45,0.58] [-15.17,19.49]
Notes: Mean values of k and k estimated from interval regression (Stewart, 1983) of experimental responseon indicators for probability vectors interacted with indicator for whether X > Y . Standard errors clusteredat individual level in parentheses. See Appendix Tables A3, columns (3) and (5) and Table A8 for detail.Panel A: No controls; 143 total subjects. Panel B: controls include age, gender, Cognitive Reflection Taskscore, and mean certainty equivalent from seven certainty equivalents tasks; 135 total subjects.
41Subjects who first faced X
0< Y (X > Y ) are 51% (45%) male, with Cognitive Reflection Test scores of 2.28
(2.02), and average certainty equivalents of 11.96 (11.35). Of these comparisons, the di↵erence in risk aversionhas a two-sided t-test p-value of 0.05 and the di↵erence in cognitive ability has a two-sided p-value of 0.15. Anomnibus test of selection from the regression of assignment to X
0< Y first on the controls of Table 4, Panel
B yields F (5, 134) = 1.60, p = 0.17), suggestive of the potential for selection on observables. These di↵erencesare of no consequence for the main portion of our analysis, which relies on within-subject variation, but couldbe influencing the results of Table 4, Panel A.
42 In Appendix Table A6, we also present a specification that includes controls for gender, age and cognitiveability, but omits our risk aversion proxy. The latter specification addresses any concerns that the averagecertainty equivalent in binary lottery tasks might be sensitive to the types of three-outcome lottery tasks(X 0
< Y versus X > Y ) the subject encounters first, a possibility we regard as remote. Results for thatspecification are similar to those reported in Table 4, Panel B.
26
4.4.1 Additional Robustness Exercises
We conduct several additional exercises to ensure the robustness of the current findings. In
Appendix E, we provide additional analyses examining alternative formulations for CPT using
the functional forms of Prelec (1998), exploring behavior in tasks where X = 25 (which implies
that adding m = $5 to Y = $24 changes the ranking), and including potentially confused sub-
jects who switch more than once in a given task. These exercises all yield the same conclusion:
rank dependence in risky choice and the predictions of CPT are soundly rejected.
5 Event Splitting and Violations of Dominance
Our analysis casts doubt on the empirical validity of the rank-dependent probability weighting
assumption that lies at the core of CPT. What type of model should behavioral economists
consider in its place? One possibility is that PT is correct, in which case people should actually
exhibit the implied violations of first-order stochastic dominance that motivated the formulation
of CPT in the first place. After we obtained our main results, we fielded an additional treatment
designed to investigate that hypothesis.
We conducted the follow-up experiment at Stanford University and UC San Diego during the
Spring and Fall of 2015. A total of 214 subjects completed the experiment, and 182 exhibited
no instances of multiple switching.43 We elicited certainty equivalents first for binary lotteries,
such as a 40% chance of receiving $30 and 60% chance or receiving $20. In one task the lower
payo↵ was more likely, and in another it was less likely. Then we elicited certainty equivalents
for related “split-event” lotteries, which we created by splitting the more likely event in each of
the binary lotteries. For the preceding example, a “split-event” lottery would take the following
form: a 40% chance of receiving $30, a 30% chance of receiving $20 + ✏, and a 30% chance of
receiving $20� ✏. Across tasks, ✏ took on the following values: $0.50, $1, $2, and $3. Subjects
43We recruited 126 at UC San Diego and 88 at Stanford. Those who exhibited no instances of multipleswitching include 99 subjects from UC San Diego and 83 from Stanford. Subjects from the two locations madequalitatively similar choices.
27
also completed a series of seven prospect theory elicitation tasks involving binary lotteries, as
before.
Most empirical parameterizations of PT imply that a 60% probability receives significantly
less than twice the weight of a 30% probability. Splitting an event occurring with 60% prob-
ability into two similar events, each occurring with 30% probability, should therefore increase
certainty equivalents dramatically. It follows that PT predicts a sharp downward discontinuity
at ✏ = 0. As noted in Section 1, such discontinuities imply violations of dominance. In con-
trast, CPT and EUT predict responses that vary smoothly with ✏ and thereby avoid dominance
violations.
Figure 5 presents our findings. As shown in Panel A, the prospect theory elicitation tasks
exhibit the hallmark pattern of probability weighting. In Panel B, we use the fitted probability
weighting to predict the e↵ect of event-splitting on certainty equivalents.44 The predicted
certainty equivalents vary smoothly with ✏ under CPT, but feature a sharp increase at zero
under PT.45 In contrast, the means of the actual certainty equivalents decrease sharply when
we split the low-outcome event, and then level o↵. Specifically, moving from ✏ = 0 to ✏ = 0.5
reduces the average certainty equivalent by $0.47 (clusted s.e. = 0.11), (z = 4.16, p < 0.01).46
We observe a qualitatively similar though somewhat muted pattern when we split the high-
outcome event.47
The findings in Panel B of Figure 5 are inconsistent with PT, CPT, and EUT, and therefore
call for an alternative explanation. A viable theory must account simultaneously for all three
patterns discussed in this study: (1) the inverse S-shaped certainty equivalent profile, (2)
44 Using the same estimation strategy as before, we obtain the following parameter values: ↵̂ = 0.975(clustered s.e. = 0.019) and �̂ = 0.671 (0.013).
45Notice that under CPT, splitting the low-outcome event leads to decreasing certainty equivalents whilesplitting the high outcome leads to increasing certainty equivalents.
46Test statistics are derived from interval regressions (Stewart, 1983) of certainty equivalents on indicatorsfor ✏. Standard errors are clustered at the subject level.
47 The apparent distaste for splitting an event, which turns a binary lottery into a trinary one, is not anartifact of di↵erences in presentation. As shown in Figure 5, certainty equivalents are essentially the sameregardless of whether we present a binary lottery as a 60%-40% gamble, or as a 30%-30%-40% gamble withidentical payo↵s for the first two events. Recall that we employed a single presentation of binary lotteries foreach subject, so this finding reflects between-subject comparisons.
28
Figure 5: Certainty Equivalents and Split Probabilities0
510
1520
25C
erta
inty
Equ
ival
ent
0 .2 .4 .6 .8 1Chance of $25
CERisk Neutral95% CICPT Model
Panel A: Certainty Equivalents
2325
27C
erta
inty
Equ
ival
ent
0 1 2 3Splitting Value, epsilon
Split Low, $20 Split High, $3095% CI CPT PredictionPT Prediction Version 60-40Version 30-30-40
Panel B: Split Probabilities
Notes: Panel A: Average certainty equivalent, C, estimated from an interval regression (Stewart, 1983) ofelicited certainty equivalents on the probability of winning $25. Confidence intervals based on standard errorsclustered at the subject level. Dashed line corresponds to CPT predictions with ↵̂ = 0.975 (s.e. = 0.019) and�̂ = 0.671 (0.013); standard errors clustered at individual level. Panel B: Average certainty equivalent, C,estimated from interval regressions of elicited certainty equivalents on the value of ✏. Confidence intervals basedon standard errors clustered at subject level. For ✏ = 0, separate averages reported based on presentation style(either 60%-40% or 30%-30%-40% with identical payo↵s for the first two events). Dashed line corresponds toCPT predictions assuming PT at aggregate parameters. Solid line corresponds to prediction assuming CPT ataggregate parameters.
the absence of rank-dependence in equalizing reductions, and (3) the sharp drop in certainty
equivalents that results from splitting an event. EU is inconsistent with (1) and (3), while CPT
is inconsistent with (2) and (3), and PT is inconsistent with (3). Alternatives to CPT that
likewise incorporate rank-dependent probability weighting are also rejected.
One possibility is to reformulate PT probability weighting in terms of normalized weights
– that is, ⇡(pk)⇡(p1)+...+⇡(pK) rather than simply ⇡(pk). That model accounts for the downward
discontinuity observed when splitting the low-payo↵ event, but implies an upward discontinuity
when splitting the high-payo↵ event, which we do not observe. It also precludes the theory from
accounting for the well-known certainty e↵ect, which Allais famously described as a “preference
29
for security in the neighborhood of certainty” (Allais, 2008), for which there is considerable
evidence (see, e.g., Camerer, 1992; Harless and Camerer, 1994).
A second and more promising possibility is that the observed behavior reflects a combination
of standard PT and a form of complexity aversion: people may prefer lotteries with fewer
outcomes because they are easier to understand. One can think of the certainty e↵ect as a
special case of this more general phenomenon. Under this hypothesis, su�ciently small values
of epsilon lead subjects to see a lottery as binary rather than trinary, which discretely increases
their certainty equivalents. Because the PT probability-weighting e↵ect works in the opposite
direction, the composite e↵ect of reducing ✏ to zero can be positive or negative.
The aforementioned theory can in principle account for the somewhat di↵erent patterns
observed when we split the high-payo↵ and low-payo↵ events. Higher stakes may reduce the
magnitude of the complexity e↵ect by making subjects more willing to ponder their prospects.
Additionally, if subjects think of discrepancies between payo↵s in relative terms, a higher payo↵
will tend to enlarge the “neighborhood” within which they implicitly “merge” events yielding
similar outcomes. Both implications are consistent with the pattern observed in Panel B of
Figure 5, but we acknowledge that this is an ex post rationalization for a somewhat limited
collection of results rather than a bona fide and systematic test of the theory.
It is important to acknowledge that complexity e↵ects, like PT, potentially give rise to
violations of dominance. However, the implied violations are explicable, because they involve
the selection of options that are easier to understand. To illustrate, in our experiment, splitting
a 60% chance of receiving $20 into a 30% chance of receiving $20.50 and a 30% chance of
receiving $19.50 decreases the certainty equivalent by $0.47. Assuming the addition of $0.50
to the $19.50 payo↵ increases the certainty equivalent by less than $0.47, we plainly have a
violation of dominance: the individual attaches more value to the original lottery than to the
revised split-event lottery even though the latter dominates the former.48
48Viewing complexity as a rationale for indirect violations of dominance between binary and trinary lotteriesmay also yield insights concerning other indirect dominance violations between binary and degenerate lotteries,such as those documented by Gneezy, List and Wu (2006); Andreoni and Sprenger (2011).
30
6 Conclusion
The main lessons of this study concern the empirical validity of rank-dependent probability
weighting, an assumption that lies at the core of Cumulative Prospect Theory (CPT). We
propose and implement an experimental test involving the elicitation of ‘equalizing reductions.’
CPT implies that these equalizing reductions should change discontinuously when a shift in
the payo↵ associated with an unrelated realization alters the ranking of payo↵s, but should
otherwise remain constant. Based on standard parameterizations of CPT as well as our own
estimates for our subject pool, these discontinuities should be substantial. And yet we find
no evidence of the predicted pattern at either the aggregate or individual level, based on both
within and between-subjects analysis. Thus we conclude that an empirical foundation for
rank-dependent probability weighting is absent.
Our findings pose serious challenges for future research on choice under uncertainty. If
CPT has taken the PT agenda in the wrong direction by promoting the assumption of rank-
dependent probability weighting (which several other recent theories embrace), how can we
reconcile PT with the presumed absence of implied dominance violations? As we demonstrate
in a supplemental experiment involving the e↵ects of “event splitting,” those violations indeed
do not arise. Instead, we observe a di↵erent type of violation that is at odds not only with
PT, but also with CPT and EUT. An important direction for future research is to explore
tractable explanations for this finding that do not involve rank-dependence. One potential
explanation involves a general form of aversion to complexity. That notion rationalizes the
behavioral patterns discussed in this study, but whether it survives rigorous and systematic
testing remains to be seen.
A potential defense of rank dependence is that it is an assumption of convenience: it renders
PT more tractable for applications, but is rarely required to account for observed behavior,
including anomalies. This argument strikes us as odd. First, rank dependence undeniably plays
a critical role in a number of applications, and is responsible for generating particular results.
We noted several examples in footnote 5. If there is no empirical support for rank dependence,
31
then plainly those applications require reexamination. Second, in other applications, either (1)
it is known that rank dependence is inessential for generating the results of interest, or (2) it
is not known. Case (1) cannot arise unless the researcher has conducted the analysis without
assuming rank dependence and found it tractable, in which case there is no reason to employ
rank dependence as an assumption of convenience. In case (2), the possibility remains that the
result of interest may be an artifact of an assumption that lacks empirical validity.
Additional research is plainly required to test the robustness of our findings. In twenty-
five years since the publication of Tversky and Kahneman (1992), there have been numerous
studies of probability weighting for binary lotteries, but decidedly few systematic studies of
rank dependence. Further work is needed to resolve the relevance of rank dependence in a
variety of experimental and naturally occurring contexts.
32
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35
A Re-examination of Prior Prospect Theory ElicitationData
Experiments designed to elicit prospect theory parameters such as Tversky and Kahneman(1992), Tversky and Fox (1995), and Gonzalez and Wu (1999) generally have subjects providecertainty equivalents for binary lotteries. Such data may potentially shed light on rank depen-dence provided an appropriate range of outcomes are considered. For example, Tversky andKahneman (1992) elicit certainty equivalents for a 10%, 50% and 90% chance of receiving $50with the alternative being zero, and also elicit certainty equivalents for a 10%, 50% and 90%chance of receiving $50 with the alternative being $100. Such data can potentially shed lighton whether a given probability of receiving $50 is weighted di↵erently depending on its rank.Under CPT decisionmaking, when the alternative payment is $0, the relevant weighting of ap-probability of receiving $50 is ⇡(p), while when the alternative is $100 it is 1� ⇡(1� p).
When the alternative is $0, Tversky and Kahneman (1992) report median certainty equiva-lents for p 2 {0.1, 0.5, 0.9} of {$9, $21, $37}. When the alternative is $100, the median certaintyequivalents for the same probabilities are {$59, $71, $83}. These data are ideal for examiningwhether the wighting of a given chance of receiving $50 is rank dependent. Given the twoparameter model and non-linear estimation techniques noted in section 4.1, with three obser-vations we can estimate both probability weighting, � and utility function curvature, ↵, withone degree of freedom in each series. Conducting such an exercise on the reported median datawhen the alternative payment is $0, we find � = 0.64 and ↵ = 0.98. The same exercise whenthe alternative payment is $50 yields � = 0.57 and ↵ = 1.01. These findings suggest substan-tial rank dependence in choice. Consider a 10% chance of receiving $50 when the alternativeis $0. With � = 0.64, ⇡(0.1) = 0.18. Now, consider a 10% chance of receiving $50 when thealternative is $100. With � = 0.57, ⇡(0.9) = 0.67 and 1 � ⇡(0.9) = 0.33. The 10% chance of$50 is either treated like 18% or 33% depending on what the alternative is. This conclusion isbarely altered if one imposes a common ↵ = 0.98 across the two data sets (the estimated � forthe alternative of $100 remains at 0.57).
Figure A1, Panel A provides graphical intuition presenting the weighted expected utilitiesfor lotteries over $50 and $0 and over $50 and $100. Panel A assumes a global shape forutility, ↵ = 0.98, and � = 0.64 when the alternative is $0 and � = 0.57 when the alternativeif $50. The blue vertical line corresponds to the expected value of a 10% chance of receiving$50 when the alternative is $0 and the red vertical line corresponds to the expected value of a10% chance of receiving $50 when the alternative is $100. The median certainty equivalents arepresented as the blue and red dots respectively, with their calculated utilities provided as thetwo horizontal bars. That the horizontal and vertical bars intersect at the weighted expectedutility in each case is evidence of the model fitting the data (i.e., predicting well the mediancertainty equivalent). The slight risk tolerance when considering a 10% chance of $50 withan alternative of zero is consistent with overweighting of the 10% chance. The more apparentrisk aversion when considering a 10% chance of $50 with an alternative of $100 is consistentwith sizable underweighting of the 90% chance of $100. But this substantial underweightingimplies even more dramatic overweighting of the 10% chance of $50 in this setting. The dataand corresponding estimates are suggestive of a rank dependence in probability weighting.
The exercise above assumes a global shape to utility, ↵ = 0.98. Importantly, this assumption
1
Figure A1: Rank Dependence in Binary Lotteries
0 20 40 60 80 100
020
4060
80
Panel A: Rank Dependent Interpretation
Outcome
Util
ity
●
●
●
●
Implied Weighting of Chance for $50
10% $50, 90% $0: π(0.1) = 0.18
10% $50, 90% $100: 1−π(0.9) = 0.33
0 20 40 60 80 100
020
4060
80
Panel B: Non−Rank Dependent Interpretation
OutcomeU
tility
●
●
●
●
Implied Weighting of Chance for $50
10% $50, 90% $0: π(0.1) = 0.18
10% $50, 90% $100: 1−π(0.9) = 0.18
is not innocuous. For example, if instead one assumed linear utility up to a certain pointand then applied substantial curvature thereafter, a qualitatively di↵erent conclusion wouldbe reached. Figure A1, Panel B presents results assuming that until x = 50, u(x) = x.Thereafter, u(x) = 50 + (x � 50)0.3, mimicking sharply diminishing marginal utility after acertain point. Under such a simple formulation for utility, one estimates � = 0.63 when thealternative is $0 and � = 0.76 when the alternative is $100. The corresponding weightedexpected utilities are again presented for each of these cases along with expected values andcertainty equivalents for the 10% chance of receiving $50. Once again, the estimated modelsfit the data quite well. In contrast to the prior results, however, there is virtually no evidenceof rank dependence. Consider a 10% chance of receiving $50 when the alternative is $0. With� = 0.63, ⇡(0.1) = 0.18. Now, consider a 10% chance of receiving $50 when the alternative is$100. With � = 0.76, ⇡(0.9) = 0.82 and 1 � ⇡(0.9) = 0.18. The 10% chance of $50 is treatedexactly the same regardless of the alternative.
This exercise demonstrates that interpreting data from binary lotteries as evidence for (oragainst) rank dependence can be quite sensitive. Depending on what assumes about the shapeof utility can lead to qualitative di↵erences in the extent of apparent rank dependence. Oneclear benefit of our proposed test of rank dependence is that at its core it is free from functionalform assumptions both for the shape of utility and probability weighting.
B Equalizing Reductions Under Di↵erent ReferencePoint Formulations
This section investigates the predictions of CPT decisionmaking under alternative formulationsof the reference point. Under CPT, the decisionmaker is assumed to separate gains and losses
2
and weight the corresponding probabilities separately. Gains are weighted according to thecumulative distribution beginning with the best possible outcome, while losses are weightedaccording to the decumulative distribution beginning with the worst possible outcome. CPTalso allows for di↵erences in the extent of probability weighting for gains and losses, ⇡+(·) and⇡�(·), and the shape of utility for gains and losses, u+(·) and u�(·).
A first observation is that when r lies above all possible outcomes, such that any potentialoutcome is a loss, the above insights are qualitatively unchanged. CPT again predicts potentialdiscontinuities in equalizing reductions as ranks change. This is also true for cases where thereference point lies between two outcomes, for cases when the reduction of k from Z induces achange from a gain to a loss, and for cases where adding m to Y induces a change from a lossto a gain. This last case is critical as adding m to Y changes the treatment of gains and losseswhile changing X to X 0 changes the ranks. Simulations identical to those presented in themain text show that even with both events occurring at the same time, substantial di↵erencesin equalizing reductions are observed. This development indicates that the predictions of CPTwith respect to equalizing reductions do not overly depend on the location of a fixed referencepoint. In the next subsections we analyze additional models of reference dependence that allowthe reference point to change as lotteries changes.
B.1 When All Outcomes Are Losses
When r > X > Y > Z and r > X > Y + m > Z � k, the equalizing reduction is identifiedfrom the indi↵erence condition
⇡�(1� p� q)u�(Z|r)+[⇡�(q + 1� p� q)� ⇡�(1� p� q)]u�(Y |r)
+[1� ⇡�(q + 1� p� q)]u�(X|r) =⇡�(1� p� q)u�(Z � k|r)
+[⇡(q + 1� p� q)� � ⇡�(1� p� q)]u�(Y +m|r)+[1� ⇡(q + 1� p� q)�]u�(X|r),
yielding
k = Z � u�1�
✓u�(Z|r)�
⇡�(q + 1� p� q)� ⇡�(1� p� q)
⇡�(1� p� q)
�[u�(Y +m|r)� u�(Y |r)]
◆.
When r > Y > X 0 > Z and r > Y +m > X 0 > Z � k, the equalizing reduction is identifiedfrom the indi↵erence condition
⇡�(1� p� q)u�(Z|r)+[⇡�(p+ 1� p� q)� ⇡�(1� p� q)]u�(X
0|r)+[1� ⇡�(p+ 1� p� q)]u�(Y |r) =
⇡�(1� p� q)u�(Z � k|r)+[⇡�(p+ 1� p� q)� ⇡�(1� p� q)]u�(X
0|r)+[1� ⇡(q + 1� p� q)�]u�(Y |r),
3
yielding
k = Z � u�1�
✓u�(Z|r)�
1� ⇡�(p+ 1� p� q)
⇡�(1� p� q)
�[u�(Y +m|r)� u�(Y |r)]
◆.
Again, k and k will not generally be equal unless ⇡(·) is linear, yielding similar potential fordiscontinuities as observed in our prior development.
B.2 When the Reference Point Lies Between Two Outcomes
When X > Y > r > Z and X > Y + m > r > Z � k, the equalizing reduction is identifiedfrom the indi↵erence condition
⇡+(p)u+(X|r) + [⇡+(p+ q)� ⇡+(p)]u+(Y |r) + ⇡�(1� p� q)u�(Z|r) =⇡+(p)u+(X|r) + [⇡+(p+ q)� ⇡+(p)]u+(Y +m|r) + ⇡�(1� p� q)u�(Z � k|r)
yielding
k = Z � u�1�
✓u�(Z|r)�
⇡+(p+ q)� ⇡+(p)
⇡�(1� p� q)
�[u+(Y +m|r)� u+(Y |r)]
◆.
When Y > X 0 > r > Z and Y +m > X 0 > r > Z � k, the equalizing reduction is identifiedfrom the indi↵erence condition
⇡+(q)u+(Y |r) + [⇡+(p+ q)� ⇡+(q)]u+(X0|r) + ⇡�(1� p� q)u�(Z|r) =
⇡+(q)u+(Y +m|r) + [⇡+(p+ q)� ⇡+(q)]u+(X0|r) + ⇡�(1� p� q)u�(Z � k|r)
yielding
k = Z � u�1�
✓u�(Z|r)�
⇡+(q)
⇡�(1� p� q)
�[u+(Y +m|r)� u+(Y |r)]
◆.
B.3 When Subtracting k from Z Induces a Loss
When X > Y > Z > r and X > Y + m > r > Z � k, the equalizing reduction is identifiedfrom the indi↵erence condition
⇡+(p)u+(X|r) + [⇡+(p+ q)� ⇡+(p)]u+(Y |r) + [1� ⇡+(p+ q)]u+(Z|r) =⇡+(p)u+(X|r) + [⇡+(p+ q)� ⇡+(p)]u+(Y +m|r) + ⇡�(1� p� q)u�(Z � k|r),
yielding
k = Z � u�1�
✓1� ⇡+(p+ q)
⇡�(1� p� q)
�u+(Z|r)�
⇡+(p+ q)� ⇡+(p)
⇡�(1� p� q)
�[u+(Y +m|r)� u+(Y |r)]
◆.
4
When Y > X 0 > Z > r and Y +m > X 0 > r > Z � k, the equalizing reduction is identifiedfrom the indi↵erence condition
⇡+(q)u+(Y |r) + [⇡+(p+ q)� ⇡+(q)]u+(X0|r) + [1� ⇡+(p+ q)]u+(Z|r) =
⇡+(q)u+(Y +m|r) + [⇡+(p+ q)� ⇡+(q)]u+(X0|r) + ⇡�(1� p� q)u�(Z � k|r),
yielding
k = Z � u�1�
✓1� ⇡+(p+ q)
⇡�(1� p� q)
�u+(Z|r)�
⇡+(q)
⇡�(1� p� q)
�[u+(Y +m|r)� u+(Y |r)]
◆.
B.4 When Adding m to Y Induces a Gain
When X > r > Y > Z and X > Y + m > r > Z � k, the equalizing reduction is identifiedfrom the indi↵erence condition
⇡+(p)u+(X|r) + ⇡�(1� p� q)u�(Z|r) + [⇡�(q + 1� p� q)� ⇡�(1� p� q)]u�(Y |r) =⇡+(p)u+(X|r) + ⇡�(1� p� q)u�(Z � k|r) + [⇡+(p+ q)� ⇡+(p)]u+(Y +m|r),
yielding
k = Z � u�1� ((u�(Z|r)�
⇡+(p+ q)� ⇡+(p)
⇡�(1� p� q)
�u+(Y +m|r)
�⇡�(q + 1� p� q)� ⇡�(1� p� q)
⇡�(1� p� q)
�u�(Y |r)).
When r > Y > X 0 > Z and Y + m > r > x01 > Z � k, the equalizing reduction is identified
from the indi↵erence condition
⇡�(1� p� q)u�(Z|r) + [⇡�(p+ 1� p� q)� ⇡�(1� p� q)]u�(X0|r)
+[1� ⇡�(p+ 1� p� q)]u�(Y |r) =⇡�(1� p� q)u�(Z � k|r) + [⇡�(p+ 1� p� q)� ⇡�(1� p� q)]u�(X
0|r) + ⇡+(q)u+(Y +m|r),
yielding
k = Z � u�1�
✓u�(Z|r)�
⇡+(q)
⇡�(1� p� q)
�u+(Y +m|r)�
1� ⇡�(p+ 1� p� q)
⇡�(1� p� q)
�u�(Y |r)
◆.
Note that when adding m to Y induces a gain, two things occur as X is reduced below Y :X switches from gain to loss, while Y switches from loss to gain. In principle, it is possible forthese two forces to o↵set yielding limited discontinuities in practice. In Table A1, we conductanalysis similar to Table 1 assuming a reference point of r = $25. Following the empiricalfindings of Tversky and Kahneman (1992), we assume that gain and loss probability weightingare equivalent, ⇡�(p) = ⇡+(p) = p�/(p� + (1 � p)�)1/�. We also assume a piecewise linearformulation for loss averse utility such that u�(�x) = ��u+(x) with u+(x) = x. Acrosscolumns, we vary the value of � to demonstrate the force of loss aversion for the obtained
5
values. Across values of loss aversion, substantial discontinuities in equalizing reductions areobserved.
Table A1: Simulated Equalizing Reductions When Adding m to Y Induces a Gain
� = 3 � = 2 � = 1.5 � = 1.05
{p, q, 1� p� q} k k k - k k k k- k k k k - k k k k - k(% Change) (% Change) (% Change) (% Change)
{0.6, 0.3, 0.1} 4.78 2.69 -2.09 5.92 3.54 -2.38 7.06 4.39 -2.67 9.01 5.85 -3.16(-44%) (-40%) (-38%) (-35%)
{0.4, 0.3, 0.3} 2.80 1.17 -1.62 3.46 1.52 -1.95 4.13 1.86 -2.27 5.27 2.45 -2.83(-58%) (-56%) (-55%) (-54%)
{0.1, 0.3, 0.6} 1.88 1.02 -0.86 2..33 1.28 -1.05 2.78 1.54 -1.24 3.54 1.98 -1.56(-46%) (-45%) (-45%) (44%)
Notes: Dollar values for equalizing reductions in Z for increase in Y to Y +m. k calculated with {X,Y, Z} ={$30, $24, $18}, m = $5. k calculated with {X 0
, Y, Z} = {$23, $24, $18}, m = $5, r = $25 throughout. CPTcalculations with ⇡(p) = p
�/(p� + (1 � p)�)1/� with � = 0.61; u�(�x) = ��u+(x) with u+(x) = x with �
varying by column
6
C Additional Models
C.1 KR Preferences
Koszegi and Rabin (2006, 2007) (KR) build upon standard reference-dependent preferences inone important way: the referent is expectations-based, taken to be the entire distribution ofexpected outcomes.49
Let r represent a possible reference point drawn according to measure G. Let x be anoutcome drawn according to measure F . Then the KR utility formulation is the double integral
U(F |G) =
ZZu(x|r)dG(r)dF (x)
withu(x|r) = m(x) + µ(m(x)�m(r)).
Every possible outcome of F is compared to every possible reference point of G and gains andlosses are evaluated. The function m(·) represents standard utility and µ(·) represents gain-lossutility relative to the reference point, r. Several simplifying assumptions are made. First, weassume m(x) = x to demonstrate the forces of changing reference points alone for equalizingreductions. Second, following Koszegi and Rabin (2006, 2007), we assume a piecewise-lineargain-loss utility function,
µ(y) =
⇢⌘ · y if y � 0⌘ · � · y if y < 0
�,
where the parameter ⌘ captures sensitivity to gains and losses and � represents the degree ofloss aversion.
Under these preferences, one can construct the utility of lottery L, which yields X > Y > Zwith probabilities p, q, (1� p� q),
UKR(L|L) = p (p[X] + q[Y + ⌘�(Y �X)] + (1� p� q)[Z + ⌘�(Z �X)]) +
q (p[X + ⌘(X � Y )] + q[Y ] + (1� p� q)[Z + ⌘�(Z � Y )]) +
(1� p� q) (p[X + ⌘(X � Z)] + q[Y + ⌘(Y � Z)] + (1� p� q)[Z]) ,
49An additional innovation of Koszegi and Rabin (2006, 2007) is a rational expectations equilibrium concept,the Unacclimating Personal Equilibrium (UPE). The objective of the UPE concept is to represent the notionthat rational individuals will only expect as the referent outcomes that they will definitely consume given theexpectation of said outcomes. Hence, consumption outcomes and referents coincide in UPE. To select among thepotential multiplicity of such equilibria, the KR model features a refinement, the Preferred Personal Equilibrium(PPE). The PPE concept maintains that the UPE with the highest ex-ante expected utility is selected. Anotherequilibrium concept in Koszegi and Rabin (2006, 2007) is the Choice-acclimating Personal Equilibrium (CPE)which applies to decisions made far in advance of the resolution of uncertainty. The operational distinctionbetween the two concepts is that a CPE need not be UPE, but a PPE must be UPE. In the present contextCPE and PPE have similar implications, as both are based on the coincidence of referent and consumptionoutcomes. We implicitly apply CPE/PPE in constructing the predictions of KR. That is, we assume theequalizing reduction corresponds to the point where the the decisionmaker switches from choosing L to Le inCPE/PPE. Sprenger (Forthcoming) demonstrates that such equilibrium behavior may have limited support inrisky choice experiments.
7
or
UKR(L|L) = (p+ pq⌘(1� �) + p(1� p� q)⌘(1� �))X +
(q + pq⌘(�� 1) + q(1� p� q)⌘(1� �))Y +
((1� p� q) + p(1� p� q)⌘(�� 1) + q(1� p� q)⌘(�� 1))Z.
Increasing Y to Y +m < X does not alter any of these gain loss comparisons.50 Hence, theequalizing reduction for increasing Y to Y +m is
k =(q + pq⌘(�� 1) + q(1� p� q)⌘(1� �))
((1� p� q) + p(1� p� q)⌘(�� 1) + q(1� p� q)⌘(�� 1))m.
Similarly, one can evaluate the lottery L0 with which yields Y > X 0 > Z with identical proba-bilities to construct
U(L0|L0) = (p+ pq⌘(�� 1) + p(1� p� q)⌘(1� �))X 0 +
(q + pq⌘(1� �) + q(1� p� q)⌘(1� �))Y +
((1� p� q) + p(1� p� q)⌘(�� 1) + q(1� p� q)⌘(�� 1))Z.
Critically, because Y now lies above X 0, the gain loss comparisons are changed relative to theprior formulation. Increasing Y further induces no further changes to these comparisons.51
Hence, the equalizing reduction, k is identified as
k =(q + pq⌘(1� �) + q(1� p� q)⌘(1� �))
((1� p� q) + p(1� p� q)⌘(�� 1) + q(1� p� q)⌘(�� 1))m.
Note that as X passes below Y , a discontinuity is generated such that k and k will di↵er. Thus,even though KR does not assume rank-dependent probability weighting, its implications arequalitatively similar to those of CPT, and we can test it in the same way.
50 If we consider X > Y + m > Z � k, the ranks remain unchanged and the indi↵erence condition,
(p + pq⌘(1 � �) + p(1 � p� q)⌘(1 � �))X + (q + pq⌘(�� 1) + q(1 � p� q)⌘(1 � �))Y +
((1 � p� q) + p(1 � p� q)⌘(�� 1) + q(1 � p� q)⌘(�� 1))Z =
(p + pq⌘(1 � �) + p(1 � p� q)⌘(1 � �))X + (q + pq⌘(�� 1) + q(1 � p� q)⌘(1 � �))(Y + m) +
((1 � p� q) + p(1 � p� q)⌘(�� 1) + q(1 � p� q)⌘(�� 1))(Z � k),
identifies the equalizing reduction, k.51 If we consider Y + m > X
0> Z � k, the ranks remain unchanged and the indi↵erence condition,
(p + pq⌘(�� 1) + p(1 � p� q)⌘(1 � �))X 0 + (q + pq⌘(1 � �) + q(1 � p� q)⌘(1 � �))Y +
((1 � p� q) + p(1 � p� q)⌘(�� 1) + q(1 � p� q)⌘(�� 1))Z =
(p + pq⌘(�� 1) + p(1 � p� q)⌘(1 � �))X 0 + (q + pq⌘(1 � �) + q(1 � p� q)⌘(1 � �))(Y + m) +
((1 � p� q) + p(1 � p� q)⌘(�� 1) + q(1 � p� q)⌘(�� 1))(Z � k)
identifies the equalizing reduction, k.
8
C.2 DA Preferences
Disappointment Aversion (Bell, 1985; Loomes and Sugden, 1986) (DA) provides an alternativeformulation of expectations-based reference dependence. Instead of the entire distribution ofexpected outcomes, a lottery’s reference point is its expected utility certainty equivalent, c.When constructing the DA utility for the lottery, L, X, Y and Z are all compared to c. AsX > Y > Z, X will be considered a gain and Z will be considered a loss.52 When reducing Xto X 0 < Y , c is reduced to c0. If X 0 remains a gain relative to the induced certainty equivalent,c0, no gain-loss comparisons are altered. This implies that no discontinuity should be presentas ranks change, k = k. Importantly, however, if X is further reduced to X 00, such that X 00 is aloss relative to the induced certainty equivalent, c00, the equalizing reduction will change. Thatis, disappointment aversion has the potential to deliver a discontinuity, but the discontinuityoccurs at a di↵erent location than with CPT and KR. Discontinuities in equalizing reductionswill occur when X passes below the induced lottery’s certainty equivalent, not when X passesbelow Y .
We demonstrate this possibility for a standard formulation of DA decisionmaking. Considerthe lottery, L, which yields X > Y > Z with corresponding probabilities p, q, 1 � p � q. Thedisappointment averse representation of (L) is
UDA(L) = pu(X|c) + qu(Y |c) + (1� p� q)u(Z|c),
wherec = v�1 (pv(X) + qv(Y ) + (1� p� q)v(Z)) ,
with v(·) representing a standard expected utility function. As before, we will assume thatv(x) = x, to demonstrate the forces of changing reference points alone for equalizing reductions,and consider the piece-wise linear formulation for u(x|r). Note that X > c is a gain relative toc, and Z < c is a loss. For simplicity, we first consider the case where Y is also a gain, so thatthe disappointment averse utility is
UDA(L) = p[X + ⌘(X � pX � qY � (1� p� q)Z)] +
q[Y + ⌘(Y � pX � qY � (1� p� q)Z)] +
(1� p� q)[Z + ⌘�(Z � pX � qY � (1� p� q)Z)]
or
UDA(L) = (p+ ⌘p� ⌘p2 � ⌘pq � ⌘�p(1� p� q))X +
(q + ⌘q � ⌘pq � ⌘q2 � ⌘�q(1� p� q))Y +
((1� p� q) + ⌘�(1� p� q)� ⌘p(1� p� q)� ⌘q(1� p� q)� ⌘�(1� p� q)2)Z.
As Y is assumed to be treated as a gain relative to c, increasing Y by m and decreasing Z
52Whether Y is a loss or a gain depends on the exact values, probabilities, and shape of the utility function.In Appendix C, we analyze the case when Y is a gain.
9
by k does not alter the treatment of gains and losses.53 Hence, the equalizing reduction forincreasing Y to Y +m < X is
k =
q + ⌘q � ⌘pq � ⌘q2 � ⌘�q(1� p� q)
(1� p� q) + ⌘�(1� p� q)� ⌘p(1� p� q)� ⌘q(1� p� q)� ⌘�(1� p� q)2
�m.
Now consider the lottery L0, which yields Y > X 0 > Z. If X 0 is a gain, X 0 > c0 = pX 0 + qY +(1� p� q)Z, then the disappointment averse utility is
UDA(L0) = p[X 0 + ⌘(X � pX 0 � qY � (1� p� q)Z)] +
q[Y + ⌘(Y � pX 0 � qY � (1� p� q)Z)] +
(1� p� q)[Z + ⌘�(Z � pX 0 � qY � (1� p� q)Z)].
For additions of m to Y that do not alter the treatment of X 0 as a gain, the equalizing reductionis again
k =
q + ⌘q � ⌘pq � ⌘q2 � ⌘�q(1� p� q)
(1� p� q) + ⌘�(1� p� q)� ⌘p(1� p� q)� ⌘q(1� p� q)� ⌘�(1� p� q)2
�m,
with the implication that no discontinuity should be present as the ranks change, k = k.Importantly, however, if X 0 is reduced further to X 00 < c00 = pX 00 + qY +(1� p� q)Z, then X 00
will be treated as a loss. As such the disappointment averse utility will be
UDA(L00) = p[X 00 + ⌘�(X � pX 00 � qY � (1� p� q)Z)] +
q[Y + ⌘(Y � pX 00 � qY � (1� p� q)Z)] +
(1� p� q)[Z + ⌘�(Z � pX 00 � qY � (1� p� q)Z)].
Provided the addition of m and reduction of k does not further alter the treatment of X 00, theequalizing reduction will be
k =
q + ⌘q � ⌘�pq � ⌘q2 � ⌘�q(1� p� q)
(1� p� q) + ⌘�(1� p� q)� ⌘�p(1� p� q)� ⌘q(1� p� q)� ⌘�(1� p� q)2
�m,
di↵erent from k and k.
53The equalizing reduction, k is identified from the indi↵erence condition
(p + ⌘p� ⌘p
2 � ⌘pq � ⌘�p(1 � p� q))X +
(q + ⌘q � ⌘pq � ⌘q
2 � ⌘�q(1 � p� q))Y +
((1 � p� q) + ⌘�(1 � p� q) � ⌘p(1 � p� q) � ⌘q(1 � p� q) � ⌘�(1 � p� q)2)Z =
(p + ⌘p� ⌘p
2 � ⌘pq � ⌘�p(1 � p� q))X +
(q + ⌘q � ⌘pq � ⌘q
2 � ⌘�q(1 � p� q))(Y + m)
((1 � p� q) + ⌘�(1 � p� q) � ⌘p(1 � p� q) � ⌘q(1 � p� q) � ⌘�(1 � p� q)2)(Z � k)
.
10
D Additional Tables and Figures
The following tables are referenced in the main text and Appendix E
Table A2: Certainty Equivalents
Certainty Equivalents Risk Premia(1) (2)
p = 0.05 2.88 1.63***(0.19) (0.19)
p = 0.10 3.83 1.33***(0.19) (0.19)
p = 0.25 6.45 0.20(0.17) (0.17)
p = 0.50 10.72 -1.78***(0.23) (0.23)
p = 0.75 15.44 -3.31***(0.31) (0.31)
p = 0.90 19.83 -2.67***(0.29) (0.29)
p = 0.95 21.63 -2.12***(0.24) (0.24)
Notes: Coe�cients for certainty equivalents and risk pre-
mia calculated from interval regression of certainty equiva-
lent on indicators for probability. Standard errors clustered
on individual level in parentheses. Result of �2(1) test for
the null hypothesis of risk neutrality (risk premium equal
to zero) presented in column (2). Levels of significance: *
0.10, ** 0.05, *** 0.01.
11
Table A3: Equalizing Reductions Within and Between Subjects
(1) (2) (3) (4) (5) (6)
{p, q, 1� p� q} = {0.4, 3, 0.3} -4.72*** -4.72*** -5.03*** -5.13*** -5.13*** -5.13***(0.31) (0.17) (0.60) (0.60) (0.60) (0.60)
{p, q, 1� p� q} = {0.1, 3, 0.6} -6.40*** -6.40*** -6.65*** -6.77*** -6.77*** -6.77***(0.37) (0.18) (0.68) (0.68) (0.68) (0.68)
(X > Y ) 0.26 0.26 -1.10 -0.93 -0.64 -0.74(0.17) (0.22) (0.85) (0.87) (0.83) (0.83)
(X > Y ) ⇥ {0.4, 3, 0.3} -0.22 -0.22 0.73 0.60 0.60 0.60(0.16) (0.24) (0.75) (0.76) (0.76) (0.76)
(X > Y ) ⇥ {0.1, 3, 0.6} -0.33 -0.33 0.82 0.71 0.71 0.71(0.18) (0.26) (0.88) (0.89) (0.89) (0.89)
19 < Age < 22 -0.10 -0.24(0.41) (0.43)
Age � 22 -0.33 -0.46(0.45) (0.46)
Male 0.89** 0.98**(0.39) (0.39)
Cognitve Reflect Test 0.41** 0.40**(0.17) (0.17)
Avg. Certainty Equivalent 0.19**(0.08)
Constant 9.02 7.44 9.81 9.92 6.37 8.73(0.39) (0.59) (0.65) (0.65) (1.17) (0.77)
Predicted {0.6, 3, 0.1} 9.02 9.02 9.81 9.92 9.77 9.82(0.39) (0.16) (0.65) (0.65) (0.60) (0.60)
H0: No Rank Dependence �2(3) = 4.50 �2(3) = 1.82 �2(3) = 3.76 �2(3) = 2.50 �2(3) = 0.64 �2(3) = 0.86(p = 0.21) (p = 0.61) (p = 0.29) (p = 0.47) (p = 0.89) (p = 0.84)
Fixed E↵ects No Yes No No No NoFirst Block of Tasks Only No No Yes Yes Yes YesDemographic Controls No No No No Yes Yes# Observations 2574 2574 429 405 405 405# Subjects 143 143 143 135 135 135Log-Likelihood -8891.80 -8191.34 -1481.49 -1393.60 -1379.56 -1382.05
Notes: Coe�cients from interval regression of equalizing reduction on indicators for probability series {p, q, 1 � p � q} and order of outcome
X > Y . Standard errors clustered on individual level in columns (1), (3), (4), (5), (6). Robust standard errors in parentheses in column (2).
Column (4) restricts Column (3) sample to 135 Individuals with full control information. Constant, omitted category, is {p, q, 1 � p � q} =
{0.6, 3, 0.1} with X
0< Y . Predicted average for {p, q, 1 � p� q} = {0.6, 3, 0.1} in (2), (5), (6) calculated as average of of fixed e↵ects or at the
average level of controls. Tested null hypothesis of no rank dependence corresponds to test that coe�cients (X > Y ), (X > Y ) ⇥ {0.4, 3, 0.3},(X > Y ) ⇥ {0.1, 3, 0.6} all equal zero. Levels of significance: * 0.10, ** 0.05, *** 0.01.
12
Table A4: Equalizing Reductions for All Conditions
k k(1) (2) (3) (4) (5) (6) (7) (8)
{p, q, 1� p� q} X 0 = 19 X 0 = 21 X 0 = 23 X 0 < 24 X = 30 X = 32 X = 34 X > 24
{0.6, 0.3, 0.1} 9.03 9.03 9.02 9.02 9.24 9.44 9.17 9.28(0.41) (0.40) (0.42) (0.39) (0.41) (0.42) (0.40) (0.38)
{0.4, 0.3, 0.3} 4.33 4.22 4.37 4.31 4.30 4.34 4.38 4.34(0.14) (0.13) (0.14) (0.12) (0.14) (0.15) (0.13) (0.12)
{0.1, 0.3, 0.6} 2.65 2.60 2.64 2.63 2.58 2.52 2.57 2.56(0.09) (0.11) (0.11) (0.08) (0.08) (0.08) (0.09) (0.07)
Notes: Coe�cients calculated from interval regression of equalizing reduction on indicators for probability set, value
of X/X
0 and all interactions. Standard errors clustered on individual level in parentheses. Columns (4) and (8)
provide estimated averages for k and k for columns (1)-(3) and (5)-(7), respectively.
Table A5: Equalizing Reductions with Fixed E↵ects
Panel A: Mean Behavior Panel B: CPT Predicted Values
{p, q, 1� p� q} k k k - k % Change k k k- k % Change[95% Conf.] [95% Conf.] [95% Conf.] [95% Conf.]
{0.6, 0.3, 0.1} 9.02 (0.16) 9.28 (0.16) 0.26 (0.22) 2.87 (2.52) 7.58 (0.22) 6.06 (0.21) -1.52 (0.01) -20.04 (0.53)[-0.18,0.70] [-2.07,7.82] [-1.55,-1.49] [-21.07,-19.01]
{0.4, 0.3, 0.3} 4.31 (0.07) 4.34 (0.07) 0.04 (0.10) 0.86 (2.25) 4.01 (0.06) 2.52 (0.08) -1.49 (0.03) -37.17 (1.09)[-0.15,0.23] [-3.55,5.27] [-1.54,-1.44] [-39.31,-35.03]
{0.1, 0.3, 0.6} 2.63 (0.09) 2.56 (0.09) -0.07 (0.13) -2.74 (4.71) 2.65 (0.01) 1.87 (0.03) -0.78 (0.03) -29.34 (1.12)[-0.32,0.17] [-11.99,6.50] [-0.83,-0.72] [-31.53,-27.14]
Notes: Panel A: Mean behavior for k and k estimated from interval regression (Stewart, 1983) of experimentalresponse on indicators for probability vector interacted with indicator for whether X > Y with individual fixede↵ects. Constant taken as mean of fixed e↵ects. Robust standard errors parentheses. Panel B: Predicted behaviorcalculated from (2) and (3) for CPT decision maker with aggregate parameters ↵̂ = 0.941 (s.e. = 0.012) and�̂ = 0.715 (0.010). Robust standard errors calculated using the delta method, in parentheses.
13
Table A6: Equalizing Reductions Between Subjects Alternate Controls
Panel A: First Task Block (without Controls) Panel B: First Task Block (with Alternate Controls)
{p, q, 1� p� q} k k k - k % Change k k k- k % Change[95% Conf.] [95% Conf.] [95% Conf.] [95% Conf.]
{0.6, 0.3, 0.1} 9.81 (0.65) 8.71 (0.56) -1.10 (0.85 ) -11.23 (8.15) 9.82 (0.60) 9.09 (0.56) -0.74 (0.83) -7.52 (8.10)[-2.77,0.57] [-27.21,4.76] [-2.36 ,0.88] [-23.40,8.35]
{0.4, 0.3, 0.3} 4.78 (0.19) 4.41 (0.19) -0.37 (0.27) -7.82 (5.50) 4.70 (0.22) 4.56 (0.20) -0.14 (0.30) -2.96 (6.33)[-0.91,0.16] [-18.60,2.95] [-0.73,0.45] [-15.37,9.46]
{0.1, 0.3, 0.6} 3.16 (0.16) 2.88 (0.12) -0.28 (0.20) -8.91 (6.00) 3.06 (0.19) 3.03 (0.15) -0.03 (0.25) -1.09 (8.08)[-0.68,0.11] [-20.66,2.84] [-0.52 ,0.45] [-16.94,14.75]
Notes: Mean values of k and k estimated from interval regression (Stewart, 1983) of experimental response onindicators for probability vectors interacted with indicator for whether X > Y . Standard errors clustered atindividual level in parentheses. See Appendix Table A3, columns (3) and (5) for detail. Panel A: No controls;143 total subjects. Panel B: controls include age, gender, Cognitive Reflection Task score; 135 total subjects.
Table A7: Equalizing Reductions with Multiple Switchers
k k(1) (2) (3) (4) (5) (6) (7) (8)
{p, q, 1� p� q} X 0 = 19 X 0 = 21 X 0 = 23 X 0 < 24 X = 30 X = 32 X = 34 X > 24
{0.6, 0.3, 0.1} 8.72 8.78 8.69 8.73 8.92 9.09 8.76 8.93(0.41) (0.38) (0.41) (0.38) (0.40) (0.42) (0.40) (0.38)
{0.4, 0.3, 0.3} 4.31 4.17 4.29 4.26 4.24 4.32 4.28 4.28(0.14) (0.12) (0.14) (0.12) (0.14) (0.15) (0.14) (0.12)
{0.1, 0.3, 0.6} 2.62 2.56 2.58 2.59 2.59 2.55 2.59 2.58(0.09) (0.11) (0.11) (0.08) (0.09) (0.08) (0.09) (0.07)
Notes: Coe�cients calculated from interval regression of equalizing reduction on indicators for probability set, value
of X/X
0 and all interactions. Standard errors clustered on individual level in parentheses. Columns (4) and (8)
provide estimated averages for k and k for columns (1)-(3) and (5)-(7), respectively.
14
Table A8: Equalizing Reductions First/Last Task Block
k k(1) (2) (3) (4) (5) (6) (7) (8)
{p, q, 1� p� q} X 0 = 19 X 0 = 21 X 0 = 23 X 0 < 24 X = 30 X = 32 X = 34 X > 24
Panel A: First Task Block
{0.6, 0.3, 0.1} 11.10 8.01 10.49 9.81 7.87 9.39 8.85 8.71(1.14) (0.99) (1.13) (0.65) (1.12) (1.21) (0.72) (0.56)
{0.4, 0.3, 0.3} 4.89 4.24 5.27 4.78 4.02 4.61 4.54 4.41(0.32) (0.34) (0.30) (0.19) (0.48) (0.29) (0.24) (0.19)
{0.1, 0.3, 0.6} 3.17 3.08 3.24 3.16 2.62 2.89 3.03 2.88(0.25) (0.25) (0.35) (0.16) (0.20) (0.11) (0.20) (0.12)
Panel B: Last Task Block
{0.6, 0.3, 0.1} 9.46 11.37 6.85 9.12 8.09 8.53 9.72 8.75(0.77) (0.93) (0.95) (0.54) (0.93) (1.11) (1.24) (0.64)
{0.4, 0.3, 0.3} 4.27 4.59 3.84 4.22 4.07 4.15 4.16 4.13(0.25) (0.31) (0.31) (0.17) (0.24) (0.51) (0.42) (0.23)
{0.1, 0.3, 0.6} 2.63 2.37 2.60 2.55 2.51 2.56 2.37 2.48(0.19) (0.23) (0.28) (0.13) (0.14) (0.34) (0.17) (0.14)
Notes: Coe�cients calculated from interval regression of equalizing reduction on indicators for probability set, value
of X/X
0 and all interactions. Standard errors clustered on individual level in parentheses. Columns (4) and (8)
provide estimated averages for k and k for columns (1)-(3) and (5)-(7), respectively.
15
E Additional Robustness Exercises
E.1 Alternative CPT Formulations
Up to this point, we have focused exclusively on the Tversky and Kahneman (1992) parame-terization of CPT. Others have proposed alternative functional forms. One leading alternativeis due to Prelec (1998), who posits a probability weighting function of the form
⇡(p) = exp(�(�ln(p))�).
To explore whether our conclusions are sensitive to functional form, we repeat our analysis forPrelec’s specification. Using our data on certainty equivalents for binary lotteries, we arriveat the following estimates: weighting parameter �̂ = 0.665 (clustered s.e. = 0.021) and utilityparameter ↵̂ = 0.928 (0.019). We then use the parameterized model to predict k and k asbefore. Results appear in Table A9, Panel A. For convenience, we reproduce our results forTversky and Kahneman’s specification in Panel B. Note that the predicted discontinuities areeven larger, and hence less consistent with actual behavior, with the Prelec specification.
Table A9: Equalizing Reduction Predictions for Alternative Functional Forms
Panel A: Prelec Weighting Panel B: Tversky Kahneman Weighting
{p, q, 1� p� q} k k k - k % Change k k k- k % Change[95% Conf.] [95% Conf.] [95% Conf.] [95% Conf.]
{0.6, 0.3, 0.1} 8.77 (0.27) 6.50 (0.38) -2.26 (0.13) -25.80 (2.14) 7.58 (0.36) 6.06 (0.35) -1.52 (0.03) -20.04 (0.83)[-2.51,-2.01] [-30.02,-21.57] [-1.57,-1.47] [-21.68,-18.40]
{0.4, 0.3, 0.3} 4.81 (0.05) 2.63 (0.12) -2.18 (0.11) -45.34 (2.37) 4.01 (0.10) 2.52 (0.13) -1.49 (0.04) -37.17 (1.74)[-2.40,-1.96] [-50.02,-40.65] [-1.57,-1.41] [-40.61,-33.72]
{0.1, 0.3, 0.6} 2.95 (0.04) 1.70 (0.05) -1.26 (0.09) -42.49 (2.42) 2.65 (0.03) 1.87 (0.06) -0.78 (0.04) -29.34 (1.79)[-1.43,-1.09] [-47.27,-37.71] [-0.86,-0.69] [-32.88,-25.80]
Notes: Panel A: Predicted behavior calculated from (2) and (3) for Prelec CPT decision maker with parameters↵̂ = 0.928 (s.e. = 0.019) and �̂ = 0.665 (0.021). Standard errors clustered at individual level and calculatedusing the delta method, in parentheses. Panel B: Predicted behavior calculated from (2) and (3) for Kahnemanand Tversky CPT decision maker with parameters ↵̂ = 0.965 (s.e. = 0.021) and �̂ = 0.703 (0.015). Standarderrors clustered at individual level and calculated using the delta method, in parentheses.
E.2 Using Explicit Rank Changes
The last task block in each session featured X = $25 and Y = $24, so that adding m = $5to Y changes its rank. Using the estimated aggregate CPT parameter values, one predictsequalizing reductions of 7.28, 3.71, and 2.49 for {p, q, 1� p� q} = {0.6, 0.3, 0.1}, {0.4, 0.3, 0.3}and {0.1, 0.3, 0.6}, respectively. Note that these values are close to the CPT predictions of kreported in Table 3, Panel B and are substantially higher than those of k.
16
For {p, q, 1 � p � q} = {0.6, 0.3, 0.1}, the mean equalizing reduction is 8.94 (clustered s.e.= 0.41). This value is statistically indistinguishable from the actual value of k for X 0 < Yreported in Table 3, Panel A, �2(1) = 0.27, (p = 0.61), and is significantly lower than the valueof k for X > Y , �2(1) = 3.44, (p = 0.06). For {p, q, 1 � p � q} = {0.4, 0.3, 0.3}, the meanequalizing reduction is 4.12 (0.13), significantly lower than the values of both k and k reportedin Table 3, Panel A, �2(1) = 4.19, (p = 0.04) and �2(1) = 5.36, (p = 0.02), respectively. For{p, q, 1�p�q} = {0.1, 0.3, 0.6}, the mean equalizing reduction is 2.34 (0.08), significantly lowerthan the values of both k and k reported in Table 3, Panel A, �2(1) = 18.82, (p < 0.01) and�2(1) = 11.55, (p < 0.01), respectively.
The pattern described in the previous paragraph is, on its face, somewhat puzzling. Ifthe equalizing reduction does not depend on the ranking of the payo↵ Y , it is di�cult to seewhy it should be systematically lower in the transitional region. Certainly, that implication isinconsistent not only with CPT, but also with PT and EUT. A possible explanation is thatthe X = 25 task block always comes last, and equalizing reductions decline as the experimentprogresses from the first task block to the last (see Table A8, Panel B). Consistent with thishypothesis, the equalizing reductions in the X = $25 tasks are quite close to the values reportedfor the those for last task block (see Table A8, Panel B).
E.3 Multiple Switching
Our main results are derived from the choices of 143 subjects who did not exhibit multipleswitching in any task. For Table A10, we include the remaining subjects, each of whom exhib-ited multiple switching at least once. The results are qualitatively unchanged. As in Table 3,we predict substantial di↵erences between k and k but observe none.54 Thus our conclusionsare robust with respect to the inclusion or exclusion of potentially confused subjects.
54Appendix Table A7 provides estimates of equalizing reductions for each value of X and X
0, and demonstratesthe stability of equalizing reductions across these values.
17
Table A10: Equalizing Reductions with Multiple Switchers
Panel A: Mean Behavior Panel B: CPT Predicted Values
{p, q, 1� p� q} k k k - k % Change k k k- k % Change[95% Conf.] [95% Conf.] [95% Conf.] [95% Conf.]
{0.6, 0.3, 0.1} 8.73 (0.38) 8.93 (0.38) 0.20 (0.16) 2.25 (1.88) 7.43 (0.36) 5.88 (0.34) -1.54 (0.03) -20.77 (0.88)[-0.12, 0.51] [-1.42, 5.94] [-1.60, -1.48] [-22.32, -19.22]
{0.4, 0.3, 0.3} 4.26 (0.12) 4.28 (0.12) 0.02 (0.08) 0.52 (1.95) 3.99 (0.10) 2.45 (0.12) -1.54 (0.04) -38.55 (1.67)[-0.14, 0.18] [-3.30, 4.33] [-1.61, -1.46] [-41.85, -35.25]
{0.1, 0.3, 0.6} 2.59 (0.08) 2.58 (0.07) - 0.01 (0.06) - 0.32 (2.34) 2.66 (0.03) 1.85 (0.06) -0.82 (0.04) -30.75 (1.76)[-0.13, 0.11] [-4.91, 4.27] [-0.90, -0.73] [-34.22, -27.27]
Notes: Panel A: Mean behavior for k and k estimated from interval regression (Stewart, 1983) of experimentalresponse on indicators for probability vector interacted with indicator for whether X > Y . Standard errorsclustered at individual level in parentheses. See Appendix Table A4 for detail. Panel B: Predicted behaviorcalculated from (2) and (3) for CPT decision maker with aggregate parameters ↵̂ = 0.941 (s.e. = 0.019) and�̂ = 0.715 (0.015). Standard errors clustered at individual level and calculated using the delta method, inparentheses.
18
F Experimental Instructions
19
Hello and Welcome.
ELIGIBILITY FOR THIS STUDY: To be in this study, you must be a
Stanford student. There are no other requirements. The study will be completely
anonymous. We will not collect your name, student ID or any other identifying
information. You have been assigned a participant number and it is on the note
card in front of you. This number will be used throughout the study. Please inform
us if you do not know or cannot read your participant number.
Participant Number:
EARNING MONEY: Whatever you earn from the study today will be paid in cash at the end of the
study today. In addition to your earnings from the study, you will receive a $5 participation payment. This $5
participation payment will also be paid to you at the end of the study today.
In this study you will complete 28 tasks, each of which asks you to make a series of decisions between two options.
The first option will always be called OPTION A. The second option will always be called OPTION B. Each decision
you make is a choice. For each decision, all you have to do is decide whether you prefer OPTION A or OPTION B.
Once all of the decision tasks have been completed, we will randomly select one decision as the decision-that-
counts. This will done in two steps. First, we will randomly select one of the 28 tasks, and, second, we will randomly
select a decision from that task to be the decision-that-counts. Each decision has an equal chance of being the
decision-that-counts. So, it is in your interest to treat each decision as if it could be the one that determines your
payments.
If you prefer OPTION A in the decision-that-counts, then OPTION A will be implemented. If you prefer
OPTION B, then OPTION B will be implemented.
Throughout the tasks, either OPTION A, OPTION B or both will involve chance. You will be fully informed
of the chance involved for every decision. Once we know which is the decision-that-counts, and whether you prefer
OPTION A or OPTION B, we will then determine the value of your payments.
For example, OPTION A could be a 10 in 100 chance of receiving $20, a 30 in 100 chance of receiving $14 and
60 in 100 chance of receiving $8. This might be compared to OPTION B of a 10 in 100 chance of receiving $20, a
30 in 100 chance of receiving $19 and 60 in 100 chance of receiving $8. Imagine for a moment which one you would
prefer. You have been provided with a calculator should you like to use it in making your decisions.
If this was chosen as the decision-that-counts, and you preferred OPTION A, we would then randomly choose
a number from 1 to 100. This would be done by throwing two ten-sided die: one for the tens digit and one for the
ones digit (0-0 will be 100). If the chosen number was between 1 and 10 (inclusive) you would receive $20. If the
number was between 11 and 40 (inclusive) you would receive $14 . If the number was between 41 and 100 (inclusive)
you would receive $8.
If, instead, you preferred OPTION B, we would randomly choose another number from 1 to 100. This random
number would be completely independent of the random number previously described. If the chosen number was
between 1 and 10 (inclusive) you would receive $20. If the number was between 11 and 40 (inclusive) you would
receive $19. If the number was between 41 and 100 (inclusive) you would receive $8 .
In this example, if you preferred OPTION B and the die read 6-8, how much would you receive (don’t forget
your participation payment!):
In this example, if you preferred OPTION A and the die read 0-9, how much would you receive (don’t forget
your participation payment!):
The tasks are presented in eight separate blocks. In a moment we will begin the first block of tasks.
TASK BLOCK 1
Participant Number:
TASKS 1-3
On the following pages you will complete 3 tasks. In each task you are asked to make a series of
decisions between two uncertain options: Option A and Option B. You may complete the tasks in
any order you wish.
In each task, Option A will be fixed, while Option B will vary. For example, in Task 1 Option
A will be a 10 in 100 chance of receiving $34, a 30 in 100 chance of receiving $24 and 60 in 100
chance of receiving $18. This will remain the same for all decisions in the task. Option B will vary
across decisions. Initially Option B will be a 10 in 100 chance of receiving $34, a 30 in 100 chance
of receiving $29 and 60 in 100 chance of receiving $18. As you proceed, Option B will change. The
amount you receive with 60 in 100 chance will decrease.
For each row, all you have to do is decide whether you prefer Option A or Option B. Indicate
your preference by checking the corresponding box. The first question from Task 1 is reproduced
as an example.
EXAMPLE
Option A or Option B
10 in 100 30 in 100 60 in 100 10 in 100 30 in 100 60 in 100Chance Chance Chance Chance Chance Chance
1) $34 $24 $18 2 or $34 $29 $18.00 2If your prefer Option A, check the green box...
1) $34 $24 $18 2� or $34 $29 $18.00 2If your prefer Option B, check the blue box...
1) $34 $29 $18 2 or $34 $29 $18.00 2�
The other tasks in this block will involve the same payment amounts, but the
chance of receiving the payments will change. Please take a look at all the tasks
and raise your hand if you have any questions.
Remember, each decision could be the decision-that-counts. So, it is in your
interest to treat each decision as if it could be the one that determines your pay-
ments.
TASK 1On this page you will make a series of decisions between two uncertain options. Option A will be a 10
in 100 chance of receiving $34, a 30 in 100 chance of receiving $24 and 60 in 100 chance of receiving $18.Initially Option B will be a 10 in 100 chance of receiving $34, a 30 in 100 chance of receiving $29 and 60 in100 chance of receiving $18. As you proceed, Option B will change. The lowest amount you receive with60 in 100 chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B10 in 100 30 in 100 60 in 100 10 in 100 30 in 100 60 in 100Chance Chance Chance Chance Chance Chance
1) $34 $24 $18 2 or $34 $29 $18.00 22) $34 $24 $18 2 or $34 $29 $17.75 23) $34 $24 $18 2 or $34 $29 $17.50 24) $34 $24 $18 2 or $34 $29 $17.00 25) $34 $24 $18 2 or $34 $29 $16.75 26) $34 $24 $18 2 or $34 $29 $16.50 27) $34 $24 $18 2 or $34 $29 $16.25 28) $34 $24 $18 2 or $34 $29 $16.00 29) $34 $24 $18 2 or $34 $29 $15.75 210) $34 $24 $18 2 or $34 $29 $15.50 211) $34 $24 $18 2 or $34 $29 $15.25 212) $34 $24 $18 2 or $34 $29 $15.00 213) $34 $24 $18 2 or $34 $29 $14.50 214) $34 $24 $18 2 or $34 $29 $14.00 215) $34 $24 $18 2 or $34 $29 $13.50 216) $34 $24 $18 2 or $34 $29 $13.00 217) $34 $24 $18 2 or $34 $29 $12.50 218) $34 $24 $18 2 or $34 $29 $12.00 219) $34 $24 $18 2 or $34 $29 $11.50 220) $34 $24 $18 2 or $34 $29 $11.00 221) $34 $24 $18 2 or $34 $29 $10.50 222) $34 $24 $18 2 or $34 $29 $10.00 223) $34 $24 $18 2 or $34 $29 $9.50 224) $34 $24 $18 2 or $34 $29 $9.00 225) $34 $24 $18 2 or $34 $29 $8.50 226) $34 $24 $18 2 or $34 $29 $8.00 227) $34 $24 $18 2 or $34 $29 $7.50 228) $34 $24 $18 2 or $34 $29 $7.00 229) $34 $24 $18 2 or $34 $29 $6.50 230) $34 $24 $18 2 or $34 $29 $6.00 231) $34 $24 $18 2 or $34 $29 $5.50 232) $34 $24 $18 2 or $34 $29 $5.00 233) $34 $24 $18 2 or $34 $29 $4.50 234) $34 $24 $18 2 or $34 $29 $4.00 235) $34 $24 $18 2 or $34 $29 $3.50 236) $34 $24 $18 2 or $34 $29 $3.00 237) $34 $24 $18 2 or $34 $29 $2.50 238) $34 $24 $18 2 or $34 $29 $2.00 2
TASK 2On this page you will make a series of decisions between two uncertain options. Option A will be a 40
in 100 chance of receiving $34, a 30 in 100 chance of receiving $24 and 30 in 100 chance of receiving $18.Initially Option B will be a 40 in 100 chance of receiving $34, a 30 in 100 chance of receiving $29 and 30 in100 chance of receiving $18. As you proceed, Option B will change. The lowest amount you receive with30 in 100 chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B40 in 100 30 in 100 30 in 100 40 in 100 30 in 100 30 in 100Chance Chance Chance Chance Chance Chance
1) $34 $24 $18 2 or $34 $29 $18.00 22) $34 $24 $18 2 or $34 $29 $17.75 23) $34 $24 $18 2 or $34 $29 $17.50 24) $34 $24 $18 2 or $34 $29 $17.00 25) $34 $24 $18 2 or $34 $29 $16.75 26) $34 $24 $18 2 or $34 $29 $16.50 27) $34 $24 $18 2 or $34 $29 $16.25 28) $34 $24 $18 2 or $34 $29 $16.00 29) $34 $24 $18 2 or $34 $29 $15.75 210) $34 $24 $18 2 or $34 $29 $15.50 211) $34 $24 $18 2 or $34 $29 $15.25 212) $34 $24 $18 2 or $34 $29 $15.00 213) $34 $24 $18 2 or $34 $29 $14.50 214) $34 $24 $18 2 or $34 $29 $14.00 215) $34 $24 $18 2 or $34 $29 $13.50 216) $34 $24 $18 2 or $34 $29 $13.00 217) $34 $24 $18 2 or $34 $29 $12.50 218) $34 $24 $18 2 or $34 $29 $12.00 219) $34 $24 $18 2 or $34 $29 $11.50 220) $34 $24 $18 2 or $34 $29 $11.00 221) $34 $24 $18 2 or $34 $29 $10.50 222) $34 $24 $18 2 or $34 $29 $10.00 223) $34 $24 $18 2 or $34 $29 $9.50 224) $34 $24 $18 2 or $34 $29 $9.00 225) $34 $24 $18 2 or $34 $29 $8.50 226) $34 $24 $18 2 or $34 $29 $8.00 227) $34 $24 $18 2 or $34 $29 $7.50 228) $34 $24 $18 2 or $34 $29 $7.00 229) $34 $24 $18 2 or $34 $29 $6.50 230) $34 $24 $18 2 or $34 $29 $6.00 231) $34 $24 $18 2 or $34 $29 $5.50 232) $34 $24 $18 2 or $34 $29 $5.00 233) $34 $24 $18 2 or $34 $29 $4.50 234) $34 $24 $18 2 or $34 $29 $4.00 235) $34 $24 $18 2 or $34 $29 $3.50 236) $34 $24 $18 2 or $34 $29 $3.00 237) $34 $24 $18 2 or $34 $29 $2.50 238) $34 $24 $18 2 or $34 $29 $2.00 2
TASK 3On this page you will make a series of decisions between two uncertain options. Option A will be a 60
in 100 chance of receiving $34, a 30 in 100 chance of receiving $24 and 10 in 100 chance of receiving $18.Initially Option B will be a 60 in 100 chance of receiving $34, a 30 in 100 chance of receiving $29 and 10 in100 chance of receiving $18. As you proceed, Option B will change. The lowest amount you receive with10 in 100 chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B60 in 100 30 in 100 10 in 100 60 in 100 30 in 100 10 in 100Chance Chance Chance Chance Chance Chance
1) $34 $24 $18 2 or $34 $29 $18.00 22) $34 $24 $18 2 or $34 $29 $17.75 23) $34 $24 $18 2 or $34 $29 $17.50 24) $34 $24 $18 2 or $34 $29 $17.00 25) $34 $24 $18 2 or $34 $29 $16.75 26) $34 $24 $18 2 or $34 $29 $16.50 27) $34 $24 $18 2 or $34 $29 $16.25 28) $34 $24 $18 2 or $34 $29 $16.00 29) $34 $24 $18 2 or $34 $29 $15.75 210) $34 $24 $18 2 or $34 $29 $15.50 211) $34 $24 $18 2 or $34 $29 $15.25 212) $34 $24 $18 2 or $34 $29 $15.00 213) $34 $24 $18 2 or $34 $29 $14.50 214) $34 $24 $18 2 or $34 $29 $14.00 215) $34 $24 $18 2 or $34 $29 $13.50 216) $34 $24 $18 2 or $34 $29 $13.00 217) $34 $24 $18 2 or $34 $29 $12.50 218) $34 $24 $18 2 or $34 $29 $12.00 219) $34 $24 $18 2 or $34 $29 $11.50 220) $34 $24 $18 2 or $34 $29 $11.00 221) $34 $24 $18 2 or $34 $29 $10.50 222) $34 $24 $18 2 or $34 $29 $10.00 223) $34 $24 $18 2 or $34 $29 $9.50 224) $34 $24 $18 2 or $34 $29 $9.00 225) $34 $24 $18 2 or $34 $29 $8.50 226) $34 $24 $18 2 or $34 $29 $8.00 227) $34 $24 $18 2 or $34 $29 $7.50 228) $34 $24 $18 2 or $34 $29 $7.00 229) $34 $24 $18 2 or $34 $29 $6.50 230) $34 $24 $18 2 or $34 $29 $6.00 231) $34 $24 $18 2 or $34 $29 $5.50 232) $34 $24 $18 2 or $34 $29 $5.00 233) $34 $24 $18 2 or $34 $29 $4.50 234) $34 $24 $18 2 or $34 $29 $4.00 235) $34 $24 $18 2 or $34 $29 $3.50 236) $34 $24 $18 2 or $34 $29 $3.00 237) $34 $24 $18 2 or $34 $29 $2.50 238) $34 $24 $18 2 or $34 $29 $2.00 2
TASK BLOCK 2
Participant Number:
TASKS 4-6
On the following pages you will complete 3 tasks. In each task you are asked to make a series of
decisions between two uncertain options: Option A and Option B. You may complete the tasks in
any order you wish.
In each task, Option A will be fixed, while Option B will vary. For example, in Task 4 Option
A will be a 10 in 100 chance of receiving $32, a 30 in 100 chance of receiving $24 and 60 in 100
chance of receiving $18. This will remain the same for all decisions in the task. Option B will vary
across decisions. Initially Option B will be a 10 in 100 chance of receiving $32, a 30 in 100 chance
of receiving $29 and 60 in 100 chance of receiving $18. As you proceed, Option B will change. The
amount you receive with 60 in 100 chance will decrease.
For each row, all you have to do is decide whether you prefer Option A or Option B. Indicate
your preference by checking the corresponding box. The first question from Task 4 is reproduced
as an example.
EXAMPLEOption A or Option B
10 in 100 30 in 100 60 in 100 10 in 100 30 in 100 60 in 100Chance Chance Chance Chance Chance Chance
1) $32 $24 $18 2 or $32 $29 $18.00 2If your prefer Option A, check the green box...
1) $32 $24 $18 2� or $32 $29 $18.00 2If your prefer Option B, check the blue box...
1) $32 $29 $18 2 or $32 $29 $18.00 2�
The other tasks in this block will involve the same payment amounts, but the
chance of receiving the payments will change. Please take a look at all the tasks
and raise your hand if you have any questions.
Remember, each decision could be the decision-that-counts. So, it is in your
interest to treat each decision as if it could be the one that determines your pay-
ments.
TASK 4On this page you will make a series of decisions between two uncertain options. Option A will be a 10
in 100 chance of receiving $32, a 30 in 100 chance of receiving $24 and 60 in 100 chance of receiving $18.Initially Option B will be a 10 in 100 chance of receiving $32, a 30 in 100 chance of receiving $29 and 60 in100 chance of receiving $18. As you proceed, Option B will change. The lowest amount you receive with60 in 100 chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B10 in 100 30 in 100 60 in 100 10 in 100 30 in 100 60 in 100Chance Chance Chance Chance Chance Chance
1) $32 $24 $18 2 or $32 $29 $18.00 22) $32 $24 $18 2 or $32 $29 $17.75 23) $32 $24 $18 2 or $32 $29 $17.50 24) $32 $24 $18 2 or $32 $29 $17.00 25) $32 $24 $18 2 or $32 $29 $16.75 26) $32 $24 $18 2 or $32 $29 $16.50 27) $32 $24 $18 2 or $32 $29 $16.25 28) $32 $24 $18 2 or $32 $29 $16.00 29) $32 $24 $18 2 or $32 $29 $15.75 210) $32 $24 $18 2 or $32 $29 $15.50 211) $32 $24 $18 2 or $32 $29 $15.25 212) $32 $24 $18 2 or $32 $29 $15.00 213) $32 $24 $18 2 or $32 $29 $14.50 214) $32 $24 $18 2 or $32 $29 $14.00 215) $32 $24 $18 2 or $32 $29 $13.50 216) $32 $24 $18 2 or $32 $29 $13.00 217) $32 $24 $18 2 or $32 $29 $12.50 218) $32 $24 $18 2 or $32 $29 $12.00 219) $32 $24 $18 2 or $32 $29 $11.50 220) $32 $24 $18 2 or $32 $29 $11.00 221) $32 $24 $18 2 or $32 $29 $10.50 222) $32 $24 $18 2 or $32 $29 $10.00 223) $32 $24 $18 2 or $32 $29 $9.50 224) $32 $24 $18 2 or $32 $29 $9.00 225) $32 $24 $18 2 or $32 $29 $8.50 226) $32 $24 $18 2 or $32 $29 $8.00 227) $32 $24 $18 2 or $32 $29 $7.50 228) $32 $24 $18 2 or $32 $29 $7.00 229) $32 $24 $18 2 or $32 $29 $6.50 230) $32 $24 $18 2 or $32 $29 $6.00 231) $32 $24 $18 2 or $32 $29 $5.50 232) $32 $24 $18 2 or $32 $29 $5.00 233) $32 $24 $18 2 or $32 $29 $4.50 234) $32 $24 $18 2 or $32 $29 $4.00 235) $32 $24 $18 2 or $32 $29 $3.50 236) $32 $24 $18 2 or $32 $29 $3.00 237) $32 $24 $18 2 or $32 $29 $2.50 238) $32 $24 $18 2 or $32 $29 $2.00 2
TASK 5On this page you will make a series of decisions between two uncertain options. Option A will be a 40
in 100 chance of receiving $32, a 30 in 100 chance of receiving $24 and 30 in 100 chance of receiving $18.Initially Option B will be a 40 in 100 chance of receiving $32, a 30 in 100 chance of receiving $29 and 30 in100 chance of receiving $18. As you proceed, Option B will change. The lowest amount you receive with30 in 100 chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B40 in 100 30 in 100 30 in 100 40 in 100 30 in 100 30 in 100Chance Chance Chance Chance Chance Chance
1) $32 $24 $18 2 or $32 $29 $18.00 22) $32 $24 $18 2 or $32 $29 $17.75 23) $32 $24 $18 2 or $32 $29 $17.50 24) $32 $24 $18 2 or $32 $29 $17.00 25) $32 $24 $18 2 or $32 $29 $16.75 26) $32 $24 $18 2 or $32 $29 $16.50 27) $32 $24 $18 2 or $32 $29 $16.25 28) $32 $24 $18 2 or $32 $29 $16.00 29) $32 $24 $18 2 or $32 $29 $15.75 210) $32 $24 $18 2 or $32 $29 $15.50 211) $32 $24 $18 2 or $32 $29 $15.25 212) $32 $24 $18 2 or $32 $29 $15.00 213) $32 $24 $18 2 or $32 $29 $14.50 214) $32 $24 $18 2 or $32 $29 $14.00 215) $32 $24 $18 2 or $32 $29 $13.50 216) $32 $24 $18 2 or $32 $29 $13.00 217) $32 $24 $18 2 or $32 $29 $12.50 218) $32 $24 $18 2 or $32 $29 $12.00 219) $32 $24 $18 2 or $32 $29 $11.50 220) $32 $24 $18 2 or $32 $29 $11.00 221) $32 $24 $18 2 or $32 $29 $10.50 222) $32 $24 $18 2 or $32 $29 $10.00 223) $32 $24 $18 2 or $32 $29 $9.50 224) $32 $24 $18 2 or $32 $29 $9.00 225) $32 $24 $18 2 or $32 $29 $8.50 226) $32 $24 $18 2 or $32 $29 $8.00 227) $32 $24 $18 2 or $32 $29 $7.50 228) $32 $24 $18 2 or $32 $29 $7.00 229) $32 $24 $18 2 or $32 $29 $6.50 230) $32 $24 $18 2 or $32 $29 $6.00 231) $32 $24 $18 2 or $32 $29 $5.50 232) $32 $24 $18 2 or $32 $29 $5.00 233) $32 $24 $18 2 or $32 $29 $4.50 234) $32 $24 $18 2 or $32 $29 $4.00 235) $32 $24 $18 2 or $32 $29 $3.50 236) $32 $24 $18 2 or $32 $29 $3.00 237) $32 $24 $18 2 or $32 $29 $2.50 238) $32 $24 $18 2 or $32 $29 $2.00 2
TASK 6On this page you will make a series of decisions between two uncertain options. Option A will be a 60
in 100 chance of receiving $32, a 30 in 100 chance of receiving $24 and 10 in 100 chance of receiving $18.Initially Option B will be a 60 in 100 chance of receiving $32, a 30 in 100 chance of receiving $29 and 10 in100 chance of receiving $18. As you proceed, Option B will change. The lowest amount you receive with10 in 100 chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B60 in 100 30 in 100 10 in 100 60 in 100 30 in 100 10 in 100Chance Chance Chance Chance Chance Chance
1) $32 $24 $18 2 or $32 $29 $18.00 22) $32 $24 $18 2 or $32 $29 $17.75 23) $32 $24 $18 2 or $32 $29 $17.50 24) $32 $24 $18 2 or $32 $29 $17.00 25) $32 $24 $18 2 or $32 $29 $16.75 26) $32 $24 $18 2 or $32 $29 $16.50 27) $32 $24 $18 2 or $32 $29 $16.25 28) $32 $24 $18 2 or $32 $29 $16.00 29) $32 $24 $18 2 or $32 $29 $15.75 210) $32 $24 $18 2 or $32 $29 $15.50 211) $32 $24 $18 2 or $32 $29 $15.25 212) $32 $24 $18 2 or $32 $29 $15.00 213) $32 $24 $18 2 or $32 $29 $14.50 214) $32 $24 $18 2 or $32 $29 $14.00 215) $32 $24 $18 2 or $32 $29 $13.50 216) $32 $24 $18 2 or $32 $29 $13.00 217) $32 $24 $18 2 or $32 $29 $12.50 218) $32 $24 $18 2 or $32 $29 $12.00 219) $32 $24 $18 2 or $32 $29 $11.50 220) $32 $24 $18 2 or $32 $29 $11.00 221) $32 $24 $18 2 or $32 $29 $10.50 222) $32 $24 $18 2 or $32 $29 $10.00 223) $32 $24 $18 2 or $32 $29 $9.50 224) $32 $24 $18 2 or $32 $29 $9.00 225) $32 $24 $18 2 or $32 $29 $8.50 226) $32 $24 $18 2 or $32 $29 $8.00 227) $32 $24 $18 2 or $32 $29 $7.50 228) $32 $24 $18 2 or $32 $29 $7.00 229) $32 $24 $18 2 or $32 $29 $6.50 230) $32 $24 $18 2 or $32 $29 $6.00 231) $32 $24 $18 2 or $32 $29 $5.50 232) $32 $24 $18 2 or $32 $29 $5.00 233) $32 $24 $18 2 or $32 $29 $4.50 234) $32 $24 $18 2 or $32 $29 $4.00 235) $32 $24 $18 2 or $32 $29 $3.50 236) $32 $24 $18 2 or $32 $29 $3.00 237) $32 $24 $18 2 or $32 $29 $2.50 238) $32 $24 $18 2 or $32 $29 $2.00 2
TASK BLOCK 3
Participant Number:
TASKS 7-9
On the following pages you will complete 3 tasks. In each task you are asked to make a series of
decisions between two uncertain options: Option A and Option B. You may complete the tasks in
any order you wish.
In each task, Option A will be fixed, while Option B will vary. For example, in Task 7 Option
A will be a 10 in 100 chance of receiving $30, a 30 in 100 chance of receiving $24 and 60 in 100
chance of receiving $18. This will remain the same for all decisions in the task. Option B will vary
across decisions. Initially Option B will be a 10 in 100 chance of receiving $30, a 30 in 100 chance
of receiving $29 and 60 in 100 chance of receiving $18. As you proceed, Option B will change. The
amount you receive with 60 in 100 chance will decrease.
For each row, all you have to do is decide whether you prefer Option A or Option B. Indicate
your preference by checking the corresponding box. The first question from Task 7 is reproduced
as an example.
EXAMPLEOption A or Option B
10 in 100 30 in 100 60 in 100 10 in 100 30 in 100 60 in 100Chance Chance Chance Chance Chance Chance
1) $30 $24 $18 2 or $30 $29 $18.00 2If your prefer Option A, check the green box...
1) $30 $24 $18 2� or $30 $29 $18.00 2If your prefer Option B, check the blue box...
1) $30 $29 $18 2 or $30 $29 $18.00 2�
The other tasks in this block will involve the same payment amounts, but the
chance of receiving the payments will change. Please take a look at all the tasks
and raise your hand if you have any questions.
Remember, each decision could be the decision-that-counts. So, it is in your
interest to treat each decision as if it could be the one that determines your pay-
ments.
TASK 7On this page you will make a series of decisions between two uncertain options. Option A will be a 10
in 100 chance of receiving $30, a 30 in 100 chance of receiving $24 and 60 in 100 chance of receiving $18.Initially Option B will be a 10 in 100 chance of receiving $30, a 30 in 100 chance of receiving $29 and 60 in100 chance of receiving $18. As you proceed, Option B will change. The lowest amount you receive with60 in 100 chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B10 in 100 30 in 100 60 in 100 10 in 100 30 in 100 60 in 100Chance Chance Chance Chance Chance Chance
1) $30 $24 $18 2 or $30 $29 $18.00 22) $30 $24 $18 2 or $30 $29 $17.75 23) $30 $24 $18 2 or $30 $29 $17.50 24) $30 $24 $18 2 or $30 $29 $17.00 25) $30 $24 $18 2 or $30 $29 $16.75 26) $30 $24 $18 2 or $30 $29 $16.50 27) $30 $24 $18 2 or $30 $29 $16.25 28) $30 $24 $18 2 or $30 $29 $16.00 29) $30 $24 $18 2 or $30 $29 $15.75 210) $30 $24 $18 2 or $30 $29 $15.50 211) $30 $24 $18 2 or $30 $29 $15.25 212) $30 $24 $18 2 or $30 $29 $15.00 213) $30 $24 $18 2 or $30 $29 $14.50 214) $30 $24 $18 2 or $30 $29 $14.00 215) $30 $24 $18 2 or $30 $29 $13.50 216) $30 $24 $18 2 or $30 $29 $13.00 217) $30 $24 $18 2 or $30 $29 $12.50 218) $30 $24 $18 2 or $30 $29 $12.00 219) $30 $24 $18 2 or $30 $29 $11.50 220) $30 $24 $18 2 or $30 $29 $11.00 221) $30 $24 $18 2 or $30 $29 $10.50 222) $30 $24 $18 2 or $30 $29 $10.00 223) $30 $24 $18 2 or $30 $29 $9.50 224) $30 $24 $18 2 or $30 $29 $9.00 225) $30 $24 $18 2 or $30 $29 $8.50 226) $30 $24 $18 2 or $30 $29 $8.00 227) $30 $24 $18 2 or $30 $29 $7.50 228) $30 $24 $18 2 or $30 $29 $7.00 229) $30 $24 $18 2 or $30 $29 $6.50 230) $30 $24 $18 2 or $30 $29 $6.00 231) $30 $24 $18 2 or $30 $29 $5.50 232) $30 $24 $18 2 or $30 $29 $5.00 233) $30 $24 $18 2 or $30 $29 $4.50 234) $30 $24 $18 2 or $30 $29 $4.00 235) $30 $24 $18 2 or $30 $29 $3.50 236) $30 $24 $18 2 or $30 $29 $3.00 237) $30 $24 $18 2 or $30 $29 $2.50 238) $30 $24 $18 2 or $30 $29 $2.00 2
TASK 8On this page you will make a series of decisions between two uncertain options. Option A will be a 40
in 100 chance of receiving $30, a 30 in 100 chance of receiving $24 and 30 in 100 chance of receiving $18.Initially Option B will be a 40 in 100 chance of receiving $30, a 30 in 100 chance of receiving $29 and 30 in100 chance of receiving $18. As you proceed, Option B will change. The lowest amount you receive with30 in 100 chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B40 in 100 30 in 100 30 in 100 40 in 100 30 in 100 30 in 100Chance Chance Chance Chance Chance Chance
1) $30 $24 $18 2 or $30 $29 $18.00 22) $30 $24 $18 2 or $30 $29 $17.75 23) $30 $24 $18 2 or $30 $29 $17.50 24) $30 $24 $18 2 or $30 $29 $17.00 25) $30 $24 $18 2 or $30 $29 $16.75 26) $30 $24 $18 2 or $30 $29 $16.50 27) $30 $24 $18 2 or $30 $29 $16.25 28) $30 $24 $18 2 or $30 $29 $16.00 29) $30 $24 $18 2 or $30 $29 $15.75 210) $30 $24 $18 2 or $30 $29 $15.50 211) $30 $24 $18 2 or $30 $29 $15.25 212) $30 $24 $18 2 or $30 $29 $15.00 213) $30 $24 $18 2 or $30 $29 $14.50 214) $30 $24 $18 2 or $30 $29 $14.00 215) $30 $24 $18 2 or $30 $29 $13.50 216) $30 $24 $18 2 or $30 $29 $13.00 217) $30 $24 $18 2 or $30 $29 $12.50 218) $30 $24 $18 2 or $30 $29 $12.00 219) $30 $24 $18 2 or $30 $29 $11.50 220) $30 $24 $18 2 or $30 $29 $11.00 221) $30 $24 $18 2 or $30 $29 $10.50 222) $30 $24 $18 2 or $30 $29 $10.00 223) $30 $24 $18 2 or $30 $29 $9.50 224) $30 $24 $18 2 or $30 $29 $9.00 225) $30 $24 $18 2 or $30 $29 $8.50 226) $30 $24 $18 2 or $30 $29 $8.00 227) $30 $24 $18 2 or $30 $29 $7.50 228) $30 $24 $18 2 or $30 $29 $7.00 229) $30 $24 $18 2 or $30 $29 $6.50 230) $30 $24 $18 2 or $30 $29 $6.00 231) $30 $24 $18 2 or $30 $29 $5.50 232) $30 $24 $18 2 or $30 $29 $5.00 233) $30 $24 $18 2 or $30 $29 $4.50 234) $30 $24 $18 2 or $30 $29 $4.00 235) $30 $24 $18 2 or $30 $29 $3.50 236) $30 $24 $18 2 or $30 $29 $3.00 237) $30 $24 $18 2 or $30 $29 $2.50 238) $30 $24 $18 2 or $30 $29 $2.00 2
TASK 9On this page you will make a series of decisions between two uncertain options. Option A will be a 60
in 100 chance of receiving $30, a 30 in 100 chance of receiving $24 and 10 in 100 chance of receiving $18.Initially Option B will be a 60 in 100 chance of receiving $30, a 30 in 100 chance of receiving $29 and 10 in100 chance of receiving $18. As you proceed, Option B will change. The lowest amount you receive with10 in 100 chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B60 in 100 30 in 100 10 in 100 60 in 100 30 in 100 10 in 100Chance Chance Chance Chance Chance Chance
1) $30 $24 $18 2 or $30 $29 $18.00 22) $30 $24 $18 2 or $30 $29 $17.75 23) $30 $24 $18 2 or $30 $29 $17.50 24) $30 $24 $18 2 or $30 $29 $17.00 25) $30 $24 $18 2 or $30 $29 $16.75 26) $30 $24 $18 2 or $30 $29 $16.50 27) $30 $24 $18 2 or $30 $29 $16.25 28) $30 $24 $18 2 or $30 $29 $16.00 29) $30 $24 $18 2 or $30 $29 $15.75 210) $30 $24 $18 2 or $30 $29 $15.50 211) $30 $24 $18 2 or $30 $29 $15.25 212) $30 $24 $18 2 or $30 $29 $15.00 213) $30 $24 $18 2 or $30 $29 $14.50 214) $30 $24 $18 2 or $30 $29 $14.00 215) $30 $24 $18 2 or $30 $29 $13.50 216) $30 $24 $18 2 or $30 $29 $13.00 217) $30 $24 $18 2 or $30 $29 $12.50 218) $30 $24 $18 2 or $30 $29 $12.00 219) $30 $24 $18 2 or $30 $29 $11.50 220) $30 $24 $18 2 or $30 $29 $11.00 221) $30 $24 $18 2 or $30 $29 $10.50 222) $30 $24 $18 2 or $30 $29 $10.00 223) $30 $24 $18 2 or $30 $29 $9.50 224) $30 $24 $18 2 or $30 $29 $9.00 225) $30 $24 $18 2 or $30 $29 $8.50 226) $30 $24 $18 2 or $30 $29 $8.00 227) $30 $24 $18 2 or $30 $29 $7.50 228) $30 $24 $18 2 or $30 $29 $7.00 229) $30 $24 $18 2 or $30 $29 $6.50 230) $30 $24 $18 2 or $30 $29 $6.00 231) $30 $24 $18 2 or $30 $29 $5.50 232) $30 $24 $18 2 or $30 $29 $5.00 233) $30 $24 $18 2 or $30 $29 $4.50 234) $30 $24 $18 2 or $30 $29 $4.00 235) $30 $24 $18 2 or $30 $29 $3.50 236) $30 $24 $18 2 or $30 $29 $3.00 237) $30 $24 $18 2 or $30 $29 $2.50 238) $30 $24 $18 2 or $30 $29 $2.00 2
TASK BLOCK 4
Participant Number:
TASKS 10-12
On the following pages you will complete 3 tasks. In each task you are asked to make a series of
decisions between two uncertain options: Option A and Option B. You may complete the tasks in
any order you wish.
In each task, Option A will be fixed, while Option B will vary. For example, in Task 10 Option
A will be a 10 in 100 chance of receiving $23, a 30 in 100 chance of receiving $24 and 60 in 100
chance of receiving $18. This will remain the same for all decisions in the task. Option B will vary
across decisions. Initially Option B will be a 10 in 100 chance of receiving $23, a 30 in 100 chance
of receiving $29 and 60 in 100 chance of receiving $18. As you proceed, Option B will change. The
amount you receive with 60 in 100 chance will decrease.
For each row, all you have to do is decide whether you prefer Option A or Option B. Indicate
your preference by checking the corresponding box. The first question from Task 10 is reproduced
as an example.
EXAMPLEOption A or Option B
10 in 100 30 in 100 60 in 100 10 in 100 30 in 100 60 in 100Chance Chance Chance Chance Chance Chance
1) $23 $24 $18 2 or $23 $29 $18.00 2If your prefer Option A, check the green box...
1) $23 $24 $18 2� or $23 $29 $18.00 2If your prefer Option B, check the blue box...
1) $23 $29 $18 2 or $23 $29 $18.00 2�
The other tasks in this block will involve the same payment amounts, but the
chance of receiving the payments will change. Please take a look at all the tasks
and raise your hand if you have any questions.
Remember, each decision could be the decision-that-counts. So, it is in your
interest to treat each decision as if it could be the one that determines your pay-
ments.
TASK 10On this page you will make a series of decisions between two uncertain options. Option A will be a 10
in 100 chance of receiving $23, a 30 in 100 chance of receiving $24 and 60 in 100 chance of receiving $18.Initially Option B will be a 10 in 100 chance of receiving $23, a 30 in 100 chance of receiving $29 and 60 in100 chance of receiving $18. As you proceed, Option B will change. The lowest amount you receive with60 in 100 chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B10 in 100 30 in 100 60 in 100 10 in 100 30 in 100 60 in 100Chance Chance Chance Chance Chance Chance
1) $23 $24 $18 2 or $23 $29 $18.00 22) $23 $24 $18 2 or $23 $29 $17.75 23) $23 $24 $18 2 or $23 $29 $17.50 24) $23 $24 $18 2 or $23 $29 $17.00 25) $23 $24 $18 2 or $23 $29 $16.75 26) $23 $24 $18 2 or $23 $29 $16.50 27) $23 $24 $18 2 or $23 $29 $16.25 28) $23 $24 $18 2 or $23 $29 $16.00 29) $23 $24 $18 2 or $23 $29 $15.75 210) $23 $24 $18 2 or $23 $29 $15.50 211) $23 $24 $18 2 or $23 $29 $15.25 212) $23 $24 $18 2 or $23 $29 $15.00 213) $23 $24 $18 2 or $23 $29 $14.50 214) $23 $24 $18 2 or $23 $29 $14.00 215) $23 $24 $18 2 or $23 $29 $13.50 216) $23 $24 $18 2 or $23 $29 $13.00 217) $23 $24 $18 2 or $23 $29 $12.50 218) $23 $24 $18 2 or $23 $29 $12.00 219) $23 $24 $18 2 or $23 $29 $11.50 220) $23 $24 $18 2 or $23 $29 $11.00 221) $23 $24 $18 2 or $23 $29 $10.50 222) $23 $24 $18 2 or $23 $29 $10.00 223) $23 $24 $18 2 or $23 $29 $9.50 224) $23 $24 $18 2 or $23 $29 $9.00 225) $23 $24 $18 2 or $23 $29 $8.50 226) $23 $24 $18 2 or $23 $29 $8.00 227) $23 $24 $18 2 or $23 $29 $7.50 228) $23 $24 $18 2 or $23 $29 $7.00 229) $23 $24 $18 2 or $23 $29 $6.50 230) $23 $24 $18 2 or $23 $29 $6.00 231) $23 $24 $18 2 or $23 $29 $5.50 232) $23 $24 $18 2 or $23 $29 $5.00 233) $23 $24 $18 2 or $23 $29 $4.50 234) $23 $24 $18 2 or $23 $29 $4.00 235) $23 $24 $18 2 or $23 $29 $3.50 236) $23 $24 $18 2 or $23 $29 $3.00 237) $23 $24 $18 2 or $23 $29 $2.50 238) $23 $24 $18 2 or $23 $29 $2.00 2
TASK 11On this page you will make a series of decisions between two uncertain options. Option A will be a 40
in 100 chance of receiving $23, a 30 in 100 chance of receiving $24 and 30 in 100 chance of receiving $18.Initially Option B will be a 40 in 100 chance of receiving $23, a 30 in 100 chance of receiving $29 and 30 in100 chance of receiving $18. As you proceed, Option B will change. The lowest amount you receive with30 in 100 chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B40 in 100 30 in 100 30 in 100 40 in 100 30 in 100 30 in 100Chance Chance Chance Chance Chance Chance
1) $23 $24 $18 2 or $23 $29 $18.00 22) $23 $24 $18 2 or $23 $29 $17.75 23) $23 $24 $18 2 or $23 $29 $17.50 24) $23 $24 $18 2 or $23 $29 $17.00 25) $23 $24 $18 2 or $23 $29 $16.75 26) $23 $24 $18 2 or $23 $29 $16.50 27) $23 $24 $18 2 or $23 $29 $16.25 28) $23 $24 $18 2 or $23 $29 $16.00 29) $23 $24 $18 2 or $23 $29 $15.75 210) $23 $24 $18 2 or $23 $29 $15.50 211) $23 $24 $18 2 or $23 $29 $15.25 212) $23 $24 $18 2 or $23 $29 $15.00 213) $23 $24 $18 2 or $23 $29 $14.50 214) $23 $24 $18 2 or $23 $29 $14.00 215) $23 $24 $18 2 or $23 $29 $13.50 216) $23 $24 $18 2 or $23 $29 $13.00 217) $23 $24 $18 2 or $23 $29 $12.50 218) $23 $24 $18 2 or $23 $29 $12.00 219) $23 $24 $18 2 or $23 $29 $11.50 220) $23 $24 $18 2 or $23 $29 $11.00 221) $23 $24 $18 2 or $23 $29 $10.50 222) $23 $24 $18 2 or $23 $29 $10.00 223) $23 $24 $18 2 or $23 $29 $9.50 224) $23 $24 $18 2 or $23 $29 $9.00 225) $23 $24 $18 2 or $23 $29 $8.50 226) $23 $24 $18 2 or $23 $29 $8.00 227) $23 $24 $18 2 or $23 $29 $7.50 228) $23 $24 $18 2 or $23 $29 $7.00 229) $23 $24 $18 2 or $23 $29 $6.50 230) $23 $24 $18 2 or $23 $29 $6.00 231) $23 $24 $18 2 or $23 $29 $5.50 232) $23 $24 $18 2 or $23 $29 $5.00 233) $23 $24 $18 2 or $23 $29 $4.50 234) $23 $24 $18 2 or $23 $29 $4.00 235) $23 $24 $18 2 or $23 $29 $3.50 236) $23 $24 $18 2 or $23 $29 $3.00 237) $23 $24 $18 2 or $23 $29 $2.50 238) $23 $24 $18 2 or $23 $29 $2.00 2
TASK 12On this page you will make a series of decisions between two uncertain options. Option A will be a 60
in 100 chance of receiving $23, a 30 in 100 chance of receiving $24 and 10 in 100 chance of receiving $18.Initially Option B will be a 60 in 100 chance of receiving $23, a 30 in 100 chance of receiving $29 and 10 in100 chance of receiving $18. As you proceed, Option B will change. The lowest amount you receive with10 in 100 chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B60 in 100 30 in 100 10 in 100 60 in 100 30 in 100 10 in 100Chance Chance Chance Chance Chance Chance
1) $23 $24 $18 2 or $23 $29 $18.00 22) $23 $24 $18 2 or $23 $29 $17.75 23) $23 $24 $18 2 or $23 $29 $17.50 24) $23 $24 $18 2 or $23 $29 $17.00 25) $23 $24 $18 2 or $23 $29 $16.75 26) $23 $24 $18 2 or $23 $29 $16.50 27) $23 $24 $18 2 or $23 $29 $16.25 28) $23 $24 $18 2 or $23 $29 $16.00 29) $23 $24 $18 2 or $23 $29 $15.75 210) $23 $24 $18 2 or $23 $29 $15.50 211) $23 $24 $18 2 or $23 $29 $15.25 212) $23 $24 $18 2 or $23 $29 $15.00 213) $23 $24 $18 2 or $23 $29 $14.50 214) $23 $24 $18 2 or $23 $29 $14.00 215) $23 $24 $18 2 or $23 $29 $13.50 216) $23 $24 $18 2 or $23 $29 $13.00 217) $23 $24 $18 2 or $23 $29 $12.50 218) $23 $24 $18 2 or $23 $29 $12.00 219) $23 $24 $18 2 or $23 $29 $11.50 220) $23 $24 $18 2 or $23 $29 $11.00 221) $23 $24 $18 2 or $23 $29 $10.50 222) $23 $24 $18 2 or $23 $29 $10.00 223) $23 $24 $18 2 or $23 $29 $9.50 224) $23 $24 $18 2 or $23 $29 $9.00 225) $23 $24 $18 2 or $23 $29 $8.50 226) $23 $24 $18 2 or $23 $29 $8.00 227) $23 $24 $18 2 or $23 $29 $7.50 228) $23 $24 $18 2 or $23 $29 $7.00 229) $23 $24 $18 2 or $23 $29 $6.50 230) $23 $24 $18 2 or $23 $29 $6.00 231) $23 $24 $18 2 or $23 $29 $5.50 232) $23 $24 $18 2 or $23 $29 $5.00 233) $23 $24 $18 2 or $23 $29 $4.50 234) $23 $24 $18 2 or $23 $29 $4.00 235) $23 $24 $18 2 or $23 $29 $3.50 236) $23 $24 $18 2 or $23 $29 $3.00 237) $23 $24 $18 2 or $23 $29 $2.50 238) $23 $24 $18 2 or $23 $29 $2.00 2
TASK BLOCK 5
Participant Number:
TASKS 13-15
On the following pages you will complete 3 tasks. In each task you are asked to make a series of
decisions between two uncertain options: Option A and Option B. You may complete the tasks in
any order you wish.
In each task, Option A will be fixed, while Option B will vary. For example, in Task 13 Option
A will be a 10 in 100 chance of receiving $21, a 30 in 100 chance of receiving $24 and 60 in 100
chance of receiving $18. This will remain the same for all decisions in the task. Option B will vary
across decisions. Initially Option B will be a 10 in 100 chance of receiving $21, a 30 in 100 chance
of receiving $29 and 60 in 100 chance of receiving $18. As you proceed, Option B will change. The
amount you receive with 60 in 100 chance will decrease.
For each row, all you have to do is decide whether you prefer Option A or Option B. Indicate
your preference by checking the corresponding box. The first question from Task 13 is reproduced
as an example.
EXAMPLEOption A or Option B
10 in 100 30 in 100 60 in 100 10 in 100 30 in 100 60 in 100Chance Chance Chance Chance Chance Chance
1) $21 $24 $18 2 or $21 $29 $18.00 2If your prefer Option A, check the green box...
1) $21 $24 $18 2� or $21 $29 $18.00 2If your prefer Option B, check the blue box...
1) $21 $29 $18 2 or $21 $29 $18.00 2�
The other tasks in this block will involve the same payment amounts, but the
chance of receiving the payments will change. Please take a look at all the tasks
and raise your hand if you have any questions.
Remember, each decision could be the decision-that-counts. So, it is in your
interest to treat each decision as if it could be the one that determines your pay-
ments.
TASK 13On this page you will make a series of decisions between two uncertain options. Option A will be a 10
in 100 chance of receiving $21, a 30 in 100 chance of receiving $24 and 60 in 100 chance of receiving $18.Initially Option B will be a 10 in 100 chance of receiving $21, a 30 in 100 chance of receiving $29 and 60 in100 chance of receiving $18. As you proceed, Option B will change. The lowest amount you receive with60 in 100 chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B10 in 100 30 in 100 60 in 100 10 in 100 30 in 100 60 in 100Chance Chance Chance Chance Chance Chance
1) $21 $24 $18 2 or $21 $29 $18.00 22) $21 $24 $18 2 or $21 $29 $17.75 23) $21 $24 $18 2 or $21 $29 $17.50 24) $21 $24 $18 2 or $21 $29 $17.00 25) $21 $24 $18 2 or $21 $29 $16.75 26) $21 $24 $18 2 or $21 $29 $16.50 27) $21 $24 $18 2 or $21 $29 $16.25 28) $21 $24 $18 2 or $21 $29 $16.00 29) $21 $24 $18 2 or $21 $29 $15.75 210) $21 $24 $18 2 or $21 $29 $15.50 211) $21 $24 $18 2 or $21 $29 $15.25 212) $21 $24 $18 2 or $21 $29 $15.00 213) $21 $24 $18 2 or $21 $29 $14.50 214) $21 $24 $18 2 or $21 $29 $14.00 215) $21 $24 $18 2 or $21 $29 $13.50 216) $21 $24 $18 2 or $21 $29 $13.00 217) $21 $24 $18 2 or $21 $29 $12.50 218) $21 $24 $18 2 or $21 $29 $12.00 219) $21 $24 $18 2 or $21 $29 $11.50 220) $21 $24 $18 2 or $21 $29 $11.00 221) $21 $24 $18 2 or $21 $29 $10.50 222) $21 $24 $18 2 or $21 $29 $10.00 223) $21 $24 $18 2 or $21 $29 $9.50 224) $21 $24 $18 2 or $21 $29 $9.00 225) $21 $24 $18 2 or $21 $29 $8.50 226) $21 $24 $18 2 or $21 $29 $8.00 227) $21 $24 $18 2 or $21 $29 $7.50 228) $21 $24 $18 2 or $21 $29 $7.00 229) $21 $24 $18 2 or $21 $29 $6.50 230) $21 $24 $18 2 or $21 $29 $6.00 231) $21 $24 $18 2 or $21 $29 $5.50 232) $21 $24 $18 2 or $21 $29 $5.00 233) $21 $24 $18 2 or $21 $29 $4.50 234) $21 $24 $18 2 or $21 $29 $4.00 235) $21 $24 $18 2 or $21 $29 $3.50 236) $21 $24 $18 2 or $21 $29 $3.00 237) $21 $24 $18 2 or $21 $29 $2.50 238) $21 $24 $18 2 or $21 $29 $2.00 2
TASK 14On this page you will make a series of decisions between two uncertain options. Option A will be a 40
in 100 chance of receiving $21, a 30 in 100 chance of receiving $24 and 30 in 100 chance of receiving $18.Initially Option B will be a 40 in 100 chance of receiving $21, a 30 in 100 chance of receiving $29 and 30 in100 chance of receiving $18. As you proceed, Option B will change. The lowest amount you receive with30 in 100 chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B40 in 100 30 in 100 30 in 100 40 in 100 30 in 100 30 in 100Chance Chance Chance Chance Chance Chance
1) $21 $24 $18 2 or $21 $29 $18.00 22) $21 $24 $18 2 or $21 $29 $17.75 23) $21 $24 $18 2 or $21 $29 $17.50 24) $21 $24 $18 2 or $21 $29 $17.00 25) $21 $24 $18 2 or $21 $29 $16.75 26) $21 $24 $18 2 or $21 $29 $16.50 27) $21 $24 $18 2 or $21 $29 $16.25 28) $21 $24 $18 2 or $21 $29 $16.00 29) $21 $24 $18 2 or $21 $29 $15.75 210) $21 $24 $18 2 or $21 $29 $15.50 211) $21 $24 $18 2 or $21 $29 $15.25 212) $21 $24 $18 2 or $21 $29 $15.00 213) $21 $24 $18 2 or $21 $29 $14.50 214) $21 $24 $18 2 or $21 $29 $14.00 215) $21 $24 $18 2 or $21 $29 $13.50 216) $21 $24 $18 2 or $21 $29 $13.00 217) $21 $24 $18 2 or $21 $29 $12.50 218) $21 $24 $18 2 or $21 $29 $12.00 219) $21 $24 $18 2 or $21 $29 $11.50 220) $21 $24 $18 2 or $21 $29 $11.00 221) $21 $24 $18 2 or $21 $29 $10.50 222) $21 $24 $18 2 or $21 $29 $10.00 223) $21 $24 $18 2 or $21 $29 $9.50 224) $21 $24 $18 2 or $21 $29 $9.00 225) $21 $24 $18 2 or $21 $29 $8.50 226) $21 $24 $18 2 or $21 $29 $8.00 227) $21 $24 $18 2 or $21 $29 $7.50 228) $21 $24 $18 2 or $21 $29 $7.00 229) $21 $24 $18 2 or $21 $29 $6.50 230) $21 $24 $18 2 or $21 $29 $6.00 231) $21 $24 $18 2 or $21 $29 $5.50 232) $21 $24 $18 2 or $21 $29 $5.00 233) $21 $24 $18 2 or $21 $29 $4.50 234) $21 $24 $18 2 or $21 $29 $4.00 235) $21 $24 $18 2 or $21 $29 $3.50 236) $21 $24 $18 2 or $21 $29 $3.00 237) $21 $24 $18 2 or $21 $29 $2.50 238) $21 $24 $18 2 or $21 $29 $2.00 2
TASK 15On this page you will make a series of decisions between two uncertain options. Option A will be a 60
in 100 chance of receiving $21, a 30 in 100 chance of receiving $24 and 10 in 100 chance of receiving $18.Initially Option B will be a 60 in 100 chance of receiving $21, a 30 in 100 chance of receiving $29 and 10 in100 chance of receiving $18. As you proceed, Option B will change. The lowest amount you receive with10 in 100 chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B60 in 100 30 in 100 10 in 100 60 in 100 30 in 100 10 in 100Chance Chance Chance Chance Chance Chance
1) $21 $24 $18 2 or $21 $29 $18.00 22) $21 $24 $18 2 or $21 $29 $17.75 23) $21 $24 $18 2 or $21 $29 $17.50 24) $21 $24 $18 2 or $21 $29 $17.00 25) $21 $24 $18 2 or $21 $29 $16.75 26) $21 $24 $18 2 or $21 $29 $16.50 27) $21 $24 $18 2 or $21 $29 $16.25 28) $21 $24 $18 2 or $21 $29 $16.00 29) $21 $24 $18 2 or $21 $29 $15.75 210) $21 $24 $18 2 or $21 $29 $15.50 211) $21 $24 $18 2 or $21 $29 $15.25 212) $21 $24 $18 2 or $21 $29 $15.00 213) $21 $24 $18 2 or $21 $29 $14.50 214) $21 $24 $18 2 or $21 $29 $14.00 215) $21 $24 $18 2 or $21 $29 $13.50 216) $21 $24 $18 2 or $21 $29 $13.00 217) $21 $24 $18 2 or $21 $29 $12.50 218) $21 $24 $18 2 or $21 $29 $12.00 219) $21 $24 $18 2 or $21 $29 $11.50 220) $21 $24 $18 2 or $21 $29 $11.00 221) $21 $24 $18 2 or $21 $29 $10.50 222) $21 $24 $18 2 or $21 $29 $10.00 223) $21 $24 $18 2 or $21 $29 $9.50 224) $21 $24 $18 2 or $21 $29 $9.00 225) $21 $24 $18 2 or $21 $29 $8.50 226) $21 $24 $18 2 or $21 $29 $8.00 227) $21 $24 $18 2 or $21 $29 $7.50 228) $21 $24 $18 2 or $21 $29 $7.00 229) $21 $24 $18 2 or $21 $29 $6.50 230) $21 $24 $18 2 or $21 $29 $6.00 231) $21 $24 $18 2 or $21 $29 $5.50 232) $21 $24 $18 2 or $21 $29 $5.00 233) $21 $24 $18 2 or $21 $29 $4.50 234) $21 $24 $18 2 or $21 $29 $4.00 235) $21 $24 $18 2 or $21 $29 $3.50 236) $21 $24 $18 2 or $21 $29 $3.00 237) $21 $24 $18 2 or $21 $29 $2.50 238) $21 $24 $18 2 or $21 $29 $2.00 2
TASK BLOCK 6
Participant Number:
TASKS 16-18
On the following pages you will complete 3 tasks. In each task you are asked to make a series of
decisions between two uncertain options: Option A and Option B. You may complete the tasks in
any order you wish.
In each task, Option A will be fixed, while Option B will vary. For example, in Task 16 Option
A will be a 10 in 100 chance of receiving $19, a 30 in 100 chance of receiving $24 and 60 in 100
chance of receiving $18. This will remain the same for all decisions in the task. Option B will vary
across decisions. Initially Option B will be a 10 in 100 chance of receiving $19, a 30 in 100 chance
of receiving $29 and 60 in 100 chance of receiving $18. As you proceed, Option B will change. The
amount you receive with 60 in 100 chance will decrease.
For each row, all you have to do is decide whether you prefer Option A or Option B. Indicate
your preference by checking the corresponding box. The first question from Task 16 is reproduced
as an example.
EXAMPLEOption A or Option B
10 in 100 30 in 100 60 in 100 10 in 100 30 in 100 60 in 100Chance Chance Chance Chance Chance Chance
1) $19 $24 $18 2 or $19 $29 $18.00 2If your prefer Option A, check the green box...
1) $19 $24 $18 2� or $19 $29 $18.00 2If your prefer Option B, check the blue box...
1) $19 $29 $18 2 or $19 $29 $18.00 2�
The other tasks in this block will involve the same payment amounts, but the
chance of receiving the payments will change. Please take a look at all the tasks
and raise your hand if you have any questions.
Remember, each decision could be the decision-that-counts. So, it is in your
interest to treat each decision as if it could be the one that determines your pay-
ments.
TASK 16On this page you will make a series of decisions between two uncertain options. Option A will be a 10
in 100 chance of receiving $19, a 30 in 100 chance of receiving $24 and 60 in 100 chance of receiving $18.Initially Option B will be a 10 in 100 chance of receiving $19, a 30 in 100 chance of receiving $29 and 60 in100 chance of receiving $18. As you proceed, Option B will change. The lowest amount you receive with60 in 100 chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B10 in 100 30 in 100 60 in 100 10 in 100 30 in 100 60 in 100Chance Chance Chance Chance Chance Chance
1) $19 $24 $18 2 or $19 $29 $18.00 22) $19 $24 $18 2 or $19 $29 $17.75 23) $19 $24 $18 2 or $19 $29 $17.50 24) $19 $24 $18 2 or $19 $29 $17.00 25) $19 $24 $18 2 or $19 $29 $16.75 26) $19 $24 $18 2 or $19 $29 $16.50 27) $19 $24 $18 2 or $19 $29 $16.25 28) $19 $24 $18 2 or $19 $29 $16.00 29) $19 $24 $18 2 or $19 $29 $15.75 210) $19 $24 $18 2 or $19 $29 $15.50 211) $19 $24 $18 2 or $19 $29 $15.25 212) $19 $24 $18 2 or $19 $29 $15.00 213) $19 $24 $18 2 or $19 $29 $14.50 214) $19 $24 $18 2 or $19 $29 $14.00 215) $19 $24 $18 2 or $19 $29 $13.50 216) $19 $24 $18 2 or $19 $29 $13.00 217) $19 $24 $18 2 or $19 $29 $12.50 218) $19 $24 $18 2 or $19 $29 $12.00 219) $19 $24 $18 2 or $19 $29 $11.50 220) $19 $24 $18 2 or $19 $29 $11.00 221) $19 $24 $18 2 or $19 $29 $10.50 222) $19 $24 $18 2 or $19 $29 $10.00 223) $19 $24 $18 2 or $19 $29 $9.50 224) $19 $24 $18 2 or $19 $29 $9.00 225) $19 $24 $18 2 or $19 $29 $8.50 226) $19 $24 $18 2 or $19 $29 $8.00 227) $19 $24 $18 2 or $19 $29 $7.50 228) $19 $24 $18 2 or $19 $29 $7.00 229) $19 $24 $18 2 or $19 $29 $6.50 230) $19 $24 $18 2 or $19 $29 $6.00 231) $19 $24 $18 2 or $19 $29 $5.50 232) $19 $24 $18 2 or $19 $29 $5.00 233) $19 $24 $18 2 or $19 $29 $4.50 234) $19 $24 $18 2 or $19 $29 $4.00 235) $19 $24 $18 2 or $19 $29 $3.50 236) $19 $24 $18 2 or $19 $29 $3.00 237) $19 $24 $18 2 or $19 $29 $2.50 238) $19 $24 $18 2 or $19 $29 $2.00 2
TASK 17On this page you will make a series of decisions between two uncertain options. Option A will be a 40
in 100 chance of receiving $19, a 30 in 100 chance of receiving $24 and 30 in 100 chance of receiving $18.Initially Option B will be a 40 in 100 chance of receiving $19, a 30 in 100 chance of receiving $29 and 30 in100 chance of receiving $18. As you proceed, Option B will change. The lowest amount you receive with30 in 100 chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B40 in 100 30 in 100 30 in 100 40 in 100 30 in 100 30 in 100Chance Chance Chance Chance Chance Chance
1) $19 $24 $18 2 or $19 $29 $18.00 22) $19 $24 $18 2 or $19 $29 $17.75 23) $19 $24 $18 2 or $19 $29 $17.50 24) $19 $24 $18 2 or $19 $29 $17.00 25) $19 $24 $18 2 or $19 $29 $16.75 26) $19 $24 $18 2 or $19 $29 $16.50 27) $19 $24 $18 2 or $19 $29 $16.25 28) $19 $24 $18 2 or $19 $29 $16.00 29) $19 $24 $18 2 or $19 $29 $15.75 210) $19 $24 $18 2 or $19 $29 $15.50 211) $19 $24 $18 2 or $19 $29 $15.25 212) $19 $24 $18 2 or $19 $29 $15.00 213) $19 $24 $18 2 or $19 $29 $14.50 214) $19 $24 $18 2 or $19 $29 $14.00 215) $19 $24 $18 2 or $19 $29 $13.50 216) $19 $24 $18 2 or $19 $29 $13.00 217) $19 $24 $18 2 or $19 $29 $12.50 218) $19 $24 $18 2 or $19 $29 $12.00 219) $19 $24 $18 2 or $19 $29 $11.50 220) $19 $24 $18 2 or $19 $29 $11.00 221) $19 $24 $18 2 or $19 $29 $10.50 222) $19 $24 $18 2 or $19 $29 $10.00 223) $19 $24 $18 2 or $19 $29 $9.50 224) $19 $24 $18 2 or $19 $29 $9.00 225) $19 $24 $18 2 or $19 $29 $8.50 226) $19 $24 $18 2 or $19 $29 $8.00 227) $19 $24 $18 2 or $19 $29 $7.50 228) $19 $24 $18 2 or $19 $29 $7.00 229) $19 $24 $18 2 or $19 $29 $6.50 230) $19 $24 $18 2 or $19 $29 $6.00 231) $19 $24 $18 2 or $19 $29 $5.50 232) $19 $24 $18 2 or $19 $29 $5.00 233) $19 $24 $18 2 or $19 $29 $4.50 234) $19 $24 $18 2 or $19 $29 $4.00 235) $19 $24 $18 2 or $19 $29 $3.50 236) $19 $24 $18 2 or $19 $29 $3.00 237) $19 $24 $18 2 or $19 $29 $2.50 238) $19 $24 $18 2 or $19 $29 $2.00 2
TASK 18On this page you will make a series of decisions between two uncertain options. Option A will be a 60
in 100 chance of receiving $19, a 30 in 100 chance of receiving $24 and 10 in 100 chance of receiving $18.Initially Option B will be a 60 in 100 chance of receiving $19, a 30 in 100 chance of receiving $29 and 10 in100 chance of receiving $18. As you proceed, Option B will change. The lowest amount you receive with10 in 100 chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B60 in 100 30 in 100 10 in 100 60 in 100 30 in 100 10 in 100Chance Chance Chance Chance Chance Chance
1) $19 $24 $18 2 or $19 $29 $18.00 22) $19 $24 $18 2 or $19 $29 $17.75 23) $19 $24 $18 2 or $19 $29 $17.50 24) $19 $24 $18 2 or $19 $29 $17.00 25) $19 $24 $18 2 or $19 $29 $16.75 26) $19 $24 $18 2 or $19 $29 $16.50 27) $19 $24 $18 2 or $19 $29 $16.25 28) $19 $24 $18 2 or $19 $29 $16.00 29) $19 $24 $18 2 or $19 $29 $15.75 210) $19 $24 $18 2 or $19 $29 $15.50 211) $19 $24 $18 2 or $19 $29 $15.25 212) $19 $24 $18 2 or $19 $29 $15.00 213) $19 $24 $18 2 or $19 $29 $14.50 214) $19 $24 $18 2 or $19 $29 $14.00 215) $19 $24 $18 2 or $19 $29 $13.50 216) $19 $24 $18 2 or $19 $29 $13.00 217) $19 $24 $18 2 or $19 $29 $12.50 218) $19 $24 $18 2 or $19 $29 $12.00 219) $19 $24 $18 2 or $19 $29 $11.50 220) $19 $24 $18 2 or $19 $29 $11.00 221) $19 $24 $18 2 or $19 $29 $10.50 222) $19 $24 $18 2 or $19 $29 $10.00 223) $19 $24 $18 2 or $19 $29 $9.50 224) $19 $24 $18 2 or $19 $29 $9.00 225) $19 $24 $18 2 or $19 $29 $8.50 226) $19 $24 $18 2 or $19 $29 $8.00 227) $19 $24 $18 2 or $19 $29 $7.50 228) $19 $24 $18 2 or $19 $29 $7.00 229) $19 $24 $18 2 or $19 $29 $6.50 230) $19 $24 $18 2 or $19 $29 $6.00 231) $19 $24 $18 2 or $19 $29 $5.50 232) $19 $24 $18 2 or $19 $29 $5.00 233) $19 $24 $18 2 or $19 $29 $4.50 234) $19 $24 $18 2 or $19 $29 $4.00 235) $19 $24 $18 2 or $19 $29 $3.50 236) $19 $24 $18 2 or $19 $29 $3.00 237) $19 $24 $18 2 or $19 $29 $2.50 238) $19 $24 $18 2 or $19 $29 $2.00 2
TASK BLOCK 7
Participant Number:
TASKS 19-25
On the following pages you will complete 7 tasks. In each task you are asked to make a series of
decisions between two options: Option A and Option B. You may complete the tasks in any order
you wish.
In each task, Option A will be fixed, while Option B will vary. For example, in Task 19 Option
A will be a 5 in 100 chance of receiving $25 and a 95 in 100 chance of receiving $0. This will remain
the same for all decisions in the task. Option B will vary across decisions. Initially Option B will
be a 100 in 100 chance of receiving $25. As you proceed, Option B will change. The amount you
receive with 100 in 100 chance will decrease.
For each row, all you have to do is decide whether you prefer Option A or Option B. Indicate
your preference by checking the corresponding box.
The first question from Task 19 is reproduced as an example.
EXAMPLEOption A or Option B
5 in 100 Chance 95 in 100 Chance 100 in 100 Chance
1) $25 $0 2 or $25.00 2If your prefer Option A, check the green box...
1) $25 $0 2� or $25.00 2If your prefer Option B, check the blue box...
1) $25 $0 2 or $25.00 2�
The other tasks in this block will involve the same payment amounts for Option
A, but the chance of receiving the payments will change. Please take a look at all
the tasks and raise your hand if you have any questions.
Remember, each decision could be the decision-that-counts. So, it is in your
interest to treat each decision as if it could be the one that determines your pay-
ments.
TASK 19On this page you will make a series of decisions between two options. Option A will be a 5 in 100
chance of receiving $25 and a 95 in 100 chance of receiving $0. Initially Option B will be a 100 in 100chance of receiving $25. As you proceed, Option B will change. The amount you receive with 100 in 100chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B5 in 100 Chance 95 in 100 Chance 100 in 100 Chance
1) $25 $0 2 or $25.00 22) $25 $0 2 or $24.00 23) $25 $0 2 or $23.00 24) $25 $0 2 or $22.00 25) $25 $0 2 or $21.00 26) $25 $0 2 or $20.00 27) $25 $0 2 or $19.00 28) $25 $0 2 or $18.00 29) $25 $0 2 or $17.00 210) $25 $0 2 or $16.00 211) $25 $0 2 or $15.00 212) $25 $0 2 or $14.00 213) $25 $0 2 or $13.00 214) $25 $0 2 or $12.00 215) $25 $0 2 or $11.00 216) $25 $0 2 or $10.00 217) $25 $0 2 or $9.00 218) $25 $0 2 or $8.00 219) $25 $0 2 or $7.00 220) $25 $0 2 or $6.00 221) $25 $0 2 or $5.00 222) $25 $0 2 or $4.00 223) $25 $0 2 or $3.00 224) $25 $0 2 or $2.00 225) $25 $0 2 or $1.00 226) $25 $0 2 or $0.00 2
TASK 20On this page you will make a series of decisions between two options. Option A will be a 10 in 100
chance of receiving $25 and a 90 in 100 chance of receiving $0. Initially Option B will be a 100 in 100chance of receiving $25. As you proceed, Option B will change. The amount you receive with 100 in 100chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B10 in 100 Chance 90 in 100 Chance 100 in 100 Chance
1) $25 $0 2 or $25.00 22) $25 $0 2 or $24.00 23) $25 $0 2 or $23.00 24) $25 $0 2 or $22.00 25) $25 $0 2 or $21.00 26) $25 $0 2 or $20.00 27) $25 $0 2 or $19.00 28) $25 $0 2 or $18.00 29) $25 $0 2 or $17.00 210) $25 $0 2 or $16.00 211) $25 $0 2 or $15.00 212) $25 $0 2 or $14.00 213) $25 $0 2 or $13.00 214) $25 $0 2 or $12.00 215) $25 $0 2 or $11.00 216) $25 $0 2 or $10.00 217) $25 $0 2 or $9.00 218) $25 $0 2 or $8.00 219) $25 $0 2 or $7.00 220) $25 $0 2 or $6.00 221) $25 $0 2 or $5.00 222) $25 $0 2 or $4.00 223) $25 $0 2 or $3.00 224) $25 $0 2 or $2.00 225) $25 $0 2 or $1.00 226) $25 $0 2 or $0.00 2
TASK 21On this page you will make a series of decisions between two options. Option A will be a 25 in 100
chance of receiving $25 and a 75 in 100 chance of receiving $0. Initially Option B will be a 100 in 100chance of receiving $25. As you proceed, Option B will change. The amount you receive with 100 in 100chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B25 in 100 Chance 75 in 100 Chance 100 in 100 Chance
1) $25 $0 2 or $25.00 22) $25 $0 2 or $24.00 23) $25 $0 2 or $23.00 24) $25 $0 2 or $22.00 25) $25 $0 2 or $21.00 26) $25 $0 2 or $20.00 27) $25 $0 2 or $19.00 28) $25 $0 2 or $18.00 29) $25 $0 2 or $17.00 210) $25 $0 2 or $16.00 211) $25 $0 2 or $15.00 212) $25 $0 2 or $14.00 213) $25 $0 2 or $13.00 214) $25 $0 2 or $12.00 215) $25 $0 2 or $11.00 216) $25 $0 2 or $10.00 217) $25 $0 2 or $9.00 218) $25 $0 2 or $8.00 219) $25 $0 2 or $7.00 220) $25 $0 2 or $6.00 221) $25 $0 2 or $5.00 222) $25 $0 2 or $4.00 223) $25 $0 2 or $3.00 224) $25 $0 2 or $2.00 225) $25 $0 2 or $1.00 226) $25 $0 2 or $0.00 2
TASK 22On this page you will make a series of decisions between two options. Option A will be a 50 in 100
chance of receiving $25 and a 50 in 100 chance of receiving $0. Initially Option B will be a 100 in 100chance of receiving $25. As you proceed, Option B will change. The amount you receive with 100 in 100chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B50 in 100 Chance 50 in 100 Chance 100 in 100 Chance
1) $25 $0 2 or $25.00 22) $25 $0 2 or $24.00 23) $25 $0 2 or $23.00 24) $25 $0 2 or $22.00 25) $25 $0 2 or $21.00 26) $25 $0 2 or $20.00 27) $25 $0 2 or $19.00 28) $25 $0 2 or $18.00 29) $25 $0 2 or $17.00 210) $25 $0 2 or $16.00 211) $25 $0 2 or $15.00 212) $25 $0 2 or $14.00 213) $25 $0 2 or $13.00 214) $25 $0 2 or $12.00 215) $25 $0 2 or $11.00 216) $25 $0 2 or $10.00 217) $25 $0 2 or $9.00 218) $25 $0 2 or $8.00 219) $25 $0 2 or $7.00 220) $25 $0 2 or $6.00 221) $25 $0 2 or $5.00 222) $25 $0 2 or $4.00 223) $25 $0 2 or $3.00 224) $25 $0 2 or $2.00 225) $25 $0 2 or $1.00 226) $25 $0 2 or $0.00 2
TASK 23On this page you will make a series of decisions between two options. Option A will be a 75 in 100
chance of receiving $25 and a 25 in 100 chance of receiving $0. Initially Option B will be a 100 in 100chance of receiving $25. As you proceed, Option B will change. The amount you receive with 100 in 100chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B75 in 100 Chance 25 in 100 Chance 100 in 100 Chance
1) $25 $0 2 or $25.00 22) $25 $0 2 or $24.00 23) $25 $0 2 or $23.00 24) $25 $0 2 or $22.00 25) $25 $0 2 or $21.00 26) $25 $0 2 or $20.00 27) $25 $0 2 or $19.00 28) $25 $0 2 or $18.00 29) $25 $0 2 or $17.00 210) $25 $0 2 or $16.00 211) $25 $0 2 or $15.00 212) $25 $0 2 or $14.00 213) $25 $0 2 or $13.00 214) $25 $0 2 or $12.00 215) $25 $0 2 or $11.00 216) $25 $0 2 or $10.00 217) $25 $0 2 or $9.00 218) $25 $0 2 or $8.00 219) $25 $0 2 or $7.00 220) $25 $0 2 or $6.00 221) $25 $0 2 or $5.00 222) $25 $0 2 or $4.00 223) $25 $0 2 or $3.00 224) $25 $0 2 or $2.00 225) $25 $0 2 or $1.00 226) $25 $0 2 or $0.00 2
TASK 24On this page you will make a series of decisions between two options. Option A will be a 90 in 100
chance of receiving $25 and a 10 in 100 chance of receiving $0. Initially Option B will be a 100 in 100chance of receiving $25. As you proceed, Option B will change. The amount you receive with 100 in 100chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B90 in 100 Chance 10 in 100 Chance 100 in 100 Chance
1) $25 $0 2 or $25.00 22) $25 $0 2 or $24.00 23) $25 $0 2 or $23.00 24) $25 $0 2 or $22.00 25) $25 $0 2 or $21.00 26) $25 $0 2 or $20.00 27) $25 $0 2 or $19.00 28) $25 $0 2 or $18.00 29) $25 $0 2 or $17.00 210) $25 $0 2 or $16.00 211) $25 $0 2 or $15.00 212) $25 $0 2 or $14.00 213) $25 $0 2 or $13.00 214) $25 $0 2 or $12.00 215) $25 $0 2 or $11.00 216) $25 $0 2 or $10.00 217) $25 $0 2 or $9.00 218) $25 $0 2 or $8.00 219) $25 $0 2 or $7.00 220) $25 $0 2 or $6.00 221) $25 $0 2 or $5.00 222) $25 $0 2 or $4.00 223) $25 $0 2 or $3.00 224) $25 $0 2 or $2.00 225) $25 $0 2 or $1.00 226) $25 $0 2 or $0.00 2
TASK 25On this page you will make a series of decisions between two options. Option A will be a 95 in 100
chance of receiving $25 and a 5 in 100 chance of receiving $0. Initially Option B will be a 100 in 100 chanceof receiving $25. As you proceed, Option B will change. The amount you receive with 100 in 100 chancewill decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B95 in 100 Chance 5 in 100 Chance 100 in 100 Chance
1) $25 $0 2 or $25.00 22) $25 $0 2 or $24.00 23) $25 $0 2 or $23.00 24) $25 $0 2 or $22.00 25) $25 $0 2 or $21.00 26) $25 $0 2 or $20.00 27) $25 $0 2 or $19.00 28) $25 $0 2 or $18.00 29) $25 $0 2 or $17.00 210) $25 $0 2 or $16.00 211) $25 $0 2 or $15.00 212) $25 $0 2 or $14.00 213) $25 $0 2 or $13.00 214) $25 $0 2 or $12.00 215) $25 $0 2 or $11.00 216) $25 $0 2 or $10.00 217) $25 $0 2 or $9.00 218) $25 $0 2 or $8.00 219) $25 $0 2 or $7.00 220) $25 $0 2 or $6.00 221) $25 $0 2 or $5.00 222) $25 $0 2 or $4.00 223) $25 $0 2 or $3.00 224) $25 $0 2 or $2.00 225) $25 $0 2 or $1.00 226) $25 $0 2 or $0.00 2
TASK BLOCK 8
Participant Number:
TASKS 26-28
On the following pages you will complete 3 tasks. In each task you are asked to make a series of
decisions between two uncertain options: Option A and Option B. You may complete the tasks in
any order you wish.
In each task, Option A will be fixed, while Option B will vary. For example, in Task 26 Option
A will be a 10 in 100 chance of receiving $25, a 30 in 100 chance of receiving $24 and 60 in 100
chance of receiving $18. This will remain the same for all decisions in the task. Option B will vary
across decisions. Initially Option B will be a 10 in 100 chance of receiving $25, a 30 in 100 chance
of receiving $29 and 60 in 100 chance of receiving $18. As you proceed, Option B will change. The
amount you receive with 60 in 100 chance will decrease.
For each row, all you have to do is decide whether you prefer Option A or Option B. Indicate
your preference by checking the corresponding box. The first question from Task 26 is reproduced
as an example.
EXAMPLEOption A or Option B
10 in 100 30 in 100 60 in 100 10 in 100 30 in 100 60 in 100Chance Chance Chance Chance Chance Chance
1) $25 $24 $18 2 or $25 $29 $18.00 2If your prefer Option A, check the green box...
1) $25 $24 $18 2� or $25 $29 $18.00 2If your prefer Option B, check the blue box...
1) $25 $29 $18 2 or $25 $29 $18.00 2�
The other tasks in this block will involve the same payment amounts, but the
chance of receiving the payments will change. Please take a look at all the tasks
and raise your hand if you have any questions.
Remember, each decision could be the decision-that-counts. So, it is in your
interest to treat each decision as if it could be the one that determines your pay-
ments.
TASK 26On this page you will make a series of decisions between two uncertain options. Option A will be a 10
in 100 chance of receiving $25, a 30 in 100 chance of receiving $24 and 60 in 100 chance of receiving $18.Initially Option B will be a 10 in 100 chance of receiving $25, a 30 in 100 chance of receiving $29 and 60 in100 chance of receiving $18. As you proceed, Option B will change. The lowest amount you receive with60 in 100 chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B10 in 100 30 in 100 60 in 100 10 in 100 30 in 100 60 in 100Chance Chance Chance Chance Chance Chance
1) $25 $24 $18 2 or $25 $29 $18.00 22) $25 $24 $18 2 or $25 $29 $17.75 23) $25 $24 $18 2 or $25 $29 $17.50 24) $25 $24 $18 2 or $25 $29 $17.00 25) $25 $24 $18 2 or $25 $29 $16.75 26) $25 $24 $18 2 or $25 $29 $16.50 27) $25 $24 $18 2 or $25 $29 $16.25 28) $25 $24 $18 2 or $25 $29 $16.00 29) $25 $24 $18 2 or $25 $29 $15.75 210) $25 $24 $18 2 or $25 $29 $15.50 211) $25 $24 $18 2 or $25 $29 $15.25 212) $25 $24 $18 2 or $25 $29 $15.00 213) $25 $24 $18 2 or $25 $29 $14.50 214) $25 $24 $18 2 or $25 $29 $14.00 215) $25 $24 $18 2 or $25 $29 $13.50 216) $25 $24 $18 2 or $25 $29 $13.00 217) $25 $24 $18 2 or $25 $29 $12.50 218) $25 $24 $18 2 or $25 $29 $12.00 219) $25 $24 $18 2 or $25 $29 $11.50 220) $25 $24 $18 2 or $25 $29 $11.00 221) $25 $24 $18 2 or $25 $29 $10.50 222) $25 $24 $18 2 or $25 $29 $10.00 223) $25 $24 $18 2 or $25 $29 $9.50 224) $25 $24 $18 2 or $25 $29 $9.00 225) $25 $24 $18 2 or $25 $29 $8.50 226) $25 $24 $18 2 or $25 $29 $8.00 227) $25 $24 $18 2 or $25 $29 $7.50 228) $25 $24 $18 2 or $25 $29 $7.00 229) $25 $24 $18 2 or $25 $29 $6.50 230) $25 $24 $18 2 or $25 $29 $6.00 231) $25 $24 $18 2 or $25 $29 $5.50 232) $25 $24 $18 2 or $25 $29 $5.00 233) $25 $24 $18 2 or $25 $29 $4.50 234) $25 $24 $18 2 or $25 $29 $4.00 235) $25 $24 $18 2 or $25 $29 $3.50 236) $25 $24 $18 2 or $25 $29 $3.00 237) $25 $24 $18 2 or $25 $29 $2.50 238) $25 $24 $18 2 or $25 $29 $2.00 2
TASK 27On this page you will make a series of decisions between two uncertain options. Option A will be a 40
in 100 chance of receiving $25, a 30 in 100 chance of receiving $24 and 30 in 100 chance of receiving $18.Initially Option B will be a 40 in 100 chance of receiving $25, a 30 in 100 chance of receiving $29 and 30 in100 chance of receiving $18. As you proceed, Option B will change. The lowest amount you receive with30 in 100 chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B40 in 100 30 in 100 30 in 100 40 in 100 30 in 100 30 in 100Chance Chance Chance Chance Chance Chance
1) $25 $24 $18 2 or $25 $29 $18.00 22) $25 $24 $18 2 or $25 $29 $17.75 23) $25 $24 $18 2 or $25 $29 $17.50 24) $25 $24 $18 2 or $25 $29 $17.00 25) $25 $24 $18 2 or $25 $29 $16.75 26) $25 $24 $18 2 or $25 $29 $16.50 27) $25 $24 $18 2 or $25 $29 $16.25 28) $25 $24 $18 2 or $25 $29 $16.00 29) $25 $24 $18 2 or $25 $29 $15.75 210) $25 $24 $18 2 or $25 $29 $15.50 211) $25 $24 $18 2 or $25 $29 $15.25 212) $25 $24 $18 2 or $25 $29 $15.00 213) $25 $24 $18 2 or $25 $29 $14.50 214) $25 $24 $18 2 or $25 $29 $14.00 215) $25 $24 $18 2 or $25 $29 $13.50 216) $25 $24 $18 2 or $25 $29 $13.00 217) $25 $24 $18 2 or $25 $29 $12.50 218) $25 $24 $18 2 or $25 $29 $12.00 219) $25 $24 $18 2 or $25 $29 $11.50 220) $25 $24 $18 2 or $25 $29 $11.00 221) $25 $24 $18 2 or $25 $29 $10.50 222) $25 $24 $18 2 or $25 $29 $10.00 223) $25 $24 $18 2 or $25 $29 $9.50 224) $25 $24 $18 2 or $25 $29 $9.00 225) $25 $24 $18 2 or $25 $29 $8.50 226) $25 $24 $18 2 or $25 $29 $8.00 227) $25 $24 $18 2 or $25 $29 $7.50 228) $25 $24 $18 2 or $25 $29 $7.00 229) $25 $24 $18 2 or $25 $29 $6.50 230) $25 $24 $18 2 or $25 $29 $6.00 231) $25 $24 $18 2 or $25 $29 $5.50 232) $25 $24 $18 2 or $25 $29 $5.00 233) $25 $24 $18 2 or $25 $29 $4.50 234) $25 $24 $18 2 or $25 $29 $4.00 235) $25 $24 $18 2 or $25 $29 $3.50 236) $25 $24 $18 2 or $25 $29 $3.00 237) $25 $24 $18 2 or $25 $29 $2.50 238) $25 $24 $18 2 or $25 $29 $2.00 2
TASK 28On this page you will make a series of decisions between two uncertain options. Option A will be a 60
in 100 chance of receiving $25, a 30 in 100 chance of receiving $24 and 10 in 100 chance of receiving $18.Initially Option B will be a 60 in 100 chance of receiving $25, a 30 in 100 chance of receiving $29 and 10 in100 chance of receiving $18. As you proceed, Option B will change. The lowest amount you receive with10 in 100 chance will decrease. For each row, decide whether you prefer Option A or Option B.
Option A or Option B60 in 100 30 in 100 10 in 100 60 in 100 30 in 100 10 in 100Chance Chance Chance Chance Chance Chance
1) $25 $24 $18 2 or $25 $29 $18.00 22) $25 $24 $18 2 or $25 $29 $17.75 23) $25 $24 $18 2 or $25 $29 $17.50 24) $25 $24 $18 2 or $25 $29 $17.00 25) $25 $24 $18 2 or $25 $29 $16.75 26) $25 $24 $18 2 or $25 $29 $16.50 27) $25 $24 $18 2 or $25 $29 $16.25 28) $25 $24 $18 2 or $25 $29 $16.00 29) $25 $24 $18 2 or $25 $29 $15.75 210) $25 $24 $18 2 or $25 $29 $15.50 211) $25 $24 $18 2 or $25 $29 $15.25 212) $25 $24 $18 2 or $25 $29 $15.00 213) $25 $24 $18 2 or $25 $29 $14.50 214) $25 $24 $18 2 or $25 $29 $14.00 215) $25 $24 $18 2 or $25 $29 $13.50 216) $25 $24 $18 2 or $25 $29 $13.00 217) $25 $24 $18 2 or $25 $29 $12.50 218) $25 $24 $18 2 or $25 $29 $12.00 219) $25 $24 $18 2 or $25 $29 $11.50 220) $25 $24 $18 2 or $25 $29 $11.00 221) $25 $24 $18 2 or $25 $29 $10.50 222) $25 $24 $18 2 or $25 $29 $10.00 223) $25 $24 $18 2 or $25 $29 $9.50 224) $25 $24 $18 2 or $25 $29 $9.00 225) $25 $24 $18 2 or $25 $29 $8.50 226) $25 $24 $18 2 or $25 $29 $8.00 227) $25 $24 $18 2 or $25 $29 $7.50 228) $25 $24 $18 2 or $25 $29 $7.00 229) $25 $24 $18 2 or $25 $29 $6.50 230) $25 $24 $18 2 or $25 $29 $6.00 231) $25 $24 $18 2 or $25 $29 $5.50 232) $25 $24 $18 2 or $25 $29 $5.00 233) $25 $24 $18 2 or $25 $29 $4.50 234) $25 $24 $18 2 or $25 $29 $4.00 235) $25 $24 $18 2 or $25 $29 $3.50 236) $25 $24 $18 2 or $25 $29 $3.00 237) $25 $24 $18 2 or $25 $29 $2.50 238) $25 $24 $18 2 or $25 $29 $2.00 2