Difracción de Bragg

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  • 7/23/2019 Difraccin de Bragg

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    K K

    1.5344 0.0074 K 1.3836 0.0058 K

    1

    n

    n i = s

    2dsen() = n

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    d

    n= nat.pormolecula 1

    mNaCl,

    n= 2 2.16 gcm3 19.71 1023,

    n= 4.45 1022 1

    cm3.

    cm3 N = 4.45 1022 d

    1

    d

    1

    d3 cm3

    d=

    4.45 1022

    1

    3 cm= 2.82.

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    K K K

    2

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    (Cu,K) = 0.154 109

    m

    (Cu,K) = 0.138 109

    m

    K K

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    (Cu,K) (Cu,K)

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    K K

    n 21(K) 21(K) 2

    2(K) 22(K) 2

    3(K) 23(K) 2(K) 2(K)

    Ka K

    Ka K

    (Cu,K) (Cu,K)

    1.5344 0.0074 K 1.3836 0.0058 K

    (Cu,K) (Cu,K)

    1.5344 0.0074 K 1.3836 0.0058 K