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Course Outline Functions/Graphing Solving Equations Applications Definitions of function, graph, domain, range, x- and y- intercepts, vertical line test(1.1- 1.2) Linear functions (1.3-1.5) -Parallel and perpendicular lines Linear Equations Linear Inequalities (1.6) Fahrenheit to Celsius conver- sion, Cost per hour, Average rate of change Piecewise Functions: Absolute value functions (2.1) Absolute Value Equations and Inequalities (3.5) Quadratic Functions: Completing the square, ver- tex, increasing/decreasing, maximum/minimum, graph movements (2.1, 2.5, 3.2-3.3) Quadratic Equations: Complex numbers, Quadratic formula (3.1-3.2) Maximum/minimum problems Polynomial functions: Relative/Absolute Maxi- mum/Minimum (4.1-4.3) Polynomial Equations: Long/Synthetic Division (4.3) Radical Functions: Graphing with movements Radical Equations (3.4) Rational Functions: Horizontal/Vertical asymptotes (4.5) Rational Equations (3.4) Algebra of Functions: Sums and Differences, Products and Quotients, Compositions, Difference Quotients (2.2-2.3) Inverse Functions (5.1) Finding Inverses Exponential Functions (5.2) Exponential Equations (5.5) Interest, Growth/Decay (5.6) Logarithmic Functions (5.3) Logarithmic Equations: Logarithm rules (5.4) Solving more complicated log- arithmic/exponential equations (5.5) 1

Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

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Page 1: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

Course Outline

Functions/Graphing Solving Equations Applications

Definitions of function, graph,domain, range, x- and y-intercepts, vertical line test(1.1-1.2)Linear functions (1.3-1.5)-Parallel and perpendicularlines

Linear EquationsLinear Inequalities (1.6)

Fahrenheit to Celsius conver-sion, Cost per hour, Averagerate of change

Piecewise Functions:Absolute value functions (2.1)

Absolute Value Equations andInequalities (3.5)

Quadratic Functions:Completing the square, ver-tex, increasing/decreasing,maximum/minimum, graphmovements (2.1, 2.5, 3.2-3.3)

Quadratic Equations:Complex numbers, Quadraticformula (3.1-3.2)

Maximum/minimum problems

Polynomial functions:Relative/Absolute Maxi-mum/Minimum (4.1-4.3)

Polynomial Equations:Long/Synthetic Division (4.3)

Radical Functions:Graphing with movements

Radical Equations (3.4)

Rational Functions:Horizontal/Vertical asymptotes(4.5)

Rational Equations (3.4)

Algebra of Functions:Sums and Differences, Productsand Quotients, Compositions,Difference Quotients (2.2-2.3)Inverse Functions (5.1) Finding InversesExponential Functions (5.2) Exponential Equations (5.5) Interest, Growth/Decay (5.6)Logarithmic Functions (5.3) Logarithmic Equations:

Logarithm rules (5.4)Solving more complicated log-arithmic/exponential equations(5.5)

1

Page 2: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

2

Introduction to Functions and Graphing (Sections 1.1-1.2)

Definition. A function is a rule that assigns to each member of the first set (called the domain)exactly one member of a second set (called the range).

x(input)

f(x)(output)f

Example. Determine whether or not each diagram represents a function.

a

b

c

d

1

2

3

a

b

c

d

1

2

3

Page 3: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

3

Notation. Functions are usually given by formulas, such as:

y = f(x) = g(x) =

Example. Let f(x) = 2x + 3 and g(x) = x2 + 2x + 1. Determine the outputs below.

f(−1) f(4)

g(−2) g(3)

Example. Now let’s try some that are a little harder.

f(x) = 5x− 7 and g(x) = −x2 + 3x.

Determine the outputs below.

f(2t + 4) g(t + 1)

Page 4: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

4

Definition. The graph of a function, f(x), is the picture obtained by plotting all ordered pairsof the form (x, f(x)), i.e. (input, output).

Example. Determine if the following graphs correspond to functions.

-9 -8 -7 -6 -5 -4 -3 -2 -1

1 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

-9 -8 -7 -6 -5 -4 -3 -2 -1

1 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

-9 -8 -7 -6 -5 -4 -3 -2 -1

1 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

-9 -8 -7 -6 -5 -4 -3 -2 -1

1 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

Theorem (Vertical Line Test). If it is possible for a vertical line to cross a graph more thanonce, then the graph is . . .

Page 5: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

5

Definition. Given a function y = f(x):

• x-intercept(s) of the function • y-intercept of the function

• domain of the function • range of the function

Interval Notation:

Page 6: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

6

Example. Graph the following functions using a table. Then use the graph to estimate the x-and y-intercepts, as well as the domain and range.

• f(x) = x2 + 4x + 5

-9-8-7-6-5-4-3-2-11 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

• h(x) =√x− 1

-9-8-7-6-5-4-3-2-11 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

Page 7: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

7

Example. You can also use a table to draw graphs of equations that are not functions. Afteryou have drawn the graph, estimate the x- and y-intercepts, as well as the domain and range.

• y = 3± x

-9-8-7-6-5-4-3-2-11 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

• x2 + y2 = 4

-9-8-7-6-5-4-3-2-11 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

Page 8: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

8

Example. Graph the following on your graphing calculator. Using the graph, estimate the x-and y-intercepts, as well as the domain and range.

y = −√x− 3 y = x4 − 2x3 − 3

x-intercept(s)

y-intercept

Domain

Range

x-intercept(s)

y-intercept

Domain

Range

y =1

x + 5y = 2

√x− 1− 4

x-intercept(s)

y-intercept

Domain

Range

x-intercept(s)

y-intercept

Domain

Range

Since we can’t always rely on the graph to be able to determine the x-/y-intercepts and thedomain/range exactly, we will have to learn algebraic methods as well.

Page 9: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

9

Linear Functions and Linear Equations (Sections 1.3-1.5)

Definition. A function f is called a linear function if it can be written in the form

where m and b are constants.

Example. Determine whether each of the following is a linear function.

2y − 3x = 5 y2 − 4x + 2 = 0

y − 2x = 01

2(8x− 3y + 4) = 0

Page 10: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

10

Remark. The two constants m and b represent important parts of the graph.

• The constant b is

• The constant m is called the slope of the line and is a measure of the “steepness” of theline

where (x1, y1) and (x2, y2) are two points on the line.

(x1, y1)

(x2, y2)

x2 − x1

(run)

y2 − y1 (rise)

Page 11: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

11

Example. Graph the following linear functions without using a table.

f(x) = 2x− 3 y = 3x + 1

-9 -8 -7 -6 -5 -4 -3 -2 -1

1 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

-9 -8 -7 -6 -5 -4 -3 -2 -1

1 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

2x + y = 4 g(x) = −2

-9 -8 -7 -6 -5 -4 -3 -2 -1

1 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

-9 -8 -7 -6 -5 -4 -3 -2 -1

1 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

Page 12: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

12

Example. Find the slope of the line through the two given points.

(3, 2) and (−1, 5) (6, 8) and (3, 8)

(1,−3) and (5, 1) (2, 0) and (2, 8)

(−1, 4) and (12, 4) (20, 1) and (8, 12)

Page 13: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

13

Remark.

• Horizontal lines: y = b←− Are linear functions• Vertical lines: x = a←− Are NOT linear functions

Example. Graph the following lines.

y = −2 y = 5

-9 -8 -7 -6 -5 -4 -3 -2 -1

1 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

-9 -8 -7 -6 -5 -4 -3 -2 -1

1 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

x = 4 x = −1

-9 -8 -7 -6 -5 -4 -3 -2 -1

1 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

-9 -8 -7 -6 -5 -4 -3 -2 -1

1 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

Note: The slope of a horizontal line is .

The slope of a vertical line is .

Page 14: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

14

Remark. To find the equation of a line, you can use one of the following forms of a line.However, your answer should always be given in slope-intercept form.

Slope-Intercept Form Point-Slope Formy = mx + b y − y1 = m(x− x1)

Example. Find the equation of the line through (2, 5) having slope m =−2

7.

Example. Find the equation of the line given a point on the line and the slope.

(−3, 4) and m = −2 (0, 5) and m =3

7

Page 15: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

15

Example. Find the equation of the line through (3, 2) and (−1, 5).

Example. Find the equation of the line through the given points.

(1, 5) and (0, 4) (2, 5) and (2, 8)

(3, 6) and (−7, 6) (4,−1) and (2, 5)

Page 16: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

16

Remark. To find x- and y-intercepts algebraically:

• Set x = 0 for y-interceptNote: For linear equations in the form y = mx + b, the y-intercept is just (0, b)• Set y = 0 for x-intercept(s)

Example. Find the x- and y-intercepts for the graph of each equation.

y = 2x + 7 y =−2

3x + 1

x-intercept(s)

y-intercept

x-intercept(s)

y-intercept

x = −3 y = 5

x-intercept(s)

y-intercept

x-intercept(s)

y-intercept

Page 17: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

17

Applications of Linear Functions–Average Rate of Change (Section 1.3)

Remark. The average rate of change between any two data points on a graph is the slope ofthe line passing through the two points.

Example. Kevin’s savings account balance changed from $1140 in January to $1450 in April.Find the average rate of change per month.

Example. A plane left Chicago at 8:00am. At 1:00pm, the plane landed in Los Angeles, whichis 1500 miles away. What was the average speed of the plane for the trip?

Example. Find the average rate of change for each function on the given interval.f(x) = x3 + 2x2 − x on [−1, 2] f(x) = 7x− 3 on [4, 7]

Page 18: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

18

Applications of Linear Functions–Modeling (Section 1.4-1.5)

Example. Given the following information, determine a formula to convert degrees Celsius todegrees Fahrenheit.

• Water freezes at 0◦ Celsius and 32◦ Fahrenheit.• Water boils at 100◦ Celsius and 212◦ Fahrenheit.

Example. A taxi service charges a $3.25 pickup fee and an additional $1.75 per mile. If thecab fare was $17.60, how many miles was the cab ride?

Page 19: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

19

Parallel and Perpendicular Lines (Section 1.4)

Definition. Two distinct lines are called parallel iff

(1) they are both vertical lines, or(2) they have the same slope

Example. Determine if the two lines are parallel.

6x− 2y = 2 4y − 7 = 8x4y − 8 = 12x 2y + 4x = 1

Example. Find the equation of the line through the given point and parallel to the given line.

(0, 3), y = −x + 11 (9, 1), y = −4

Page 20: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

20

(2, 5), y =1

2x + 3 (5, 4), x = 2

Definition. Two distinct lines are called perpendicular iff

(1) one is vertical and one is horizontal, or(2) their two slopes, m1 and m2, satisfy m1 ·m2 = −1

Example. Determine if the two lines are perpendicular.

y = −2x + 4 −5y = x4y + 2x + 1 = 0 5x− y = −4

Page 21: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

21

Example. Find the equation of the line through the given point and perpendicular to the givenline.

(0, 3), y = −x + 11 (9, 1), y = −4

(2, 5), y =1

2x + 3 (5, 4), x = 2

Page 22: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

22

Intersection Points and Zeros (Section 1.5)

Definition. An intersection point of two functions is a point (x, y) where the graphs of eachfunction cross (i.e. it is a point that is in common to both graphs).

Example. Find the intersection point (if any) between the two given lines.y = 3x + 2 and y = 5x− 6 y = 2x− 5 and y = 2x + 8

y =−3

4x + 2 and y =

4

3x− 5 y = 5 and x = −2

Example. A private plane leaves Midway Airport and flies due east at a speed of 180 km/h.Two hours later, a jet leaves Midway and flies due east at a speed of 900 km/h. After how manyhours will the jet overtake the private plane?

Page 23: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

23

Definition. Zeros of a function are the values of x that make the function equal 0 (also thex-coordinate of the x-intercept).

Example. Find the zero(s) of each function (if any).

f(x) = 8x + 4 g(x) = −5

g(x) =1

2x− 3 f(x) = 4x + 3

Example. A plane is descending from a height of 28,000 feet at a constant rate of 300 feet perminute. After how long will the plane have landed on the ground?

Page 24: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

24

Linear Inequalities (Section 1.6)

Rules: The sign stays the same unless you mutliply/divide by a negative, then the sign flips.

Example. Solve each inequality. Then graph the solution set, and then write the solution setin interval notation.

2x + 5 ≤ 3− 6x 16 + 3x > 4x + 8

2 ≤ 5x + 3 < 10 −4 < −2x + 7 ≤ 4

Example. Macho Movers charges $200 plus $45 per hour to move a household across town.Brute Force Movers charges a flat fee of $65 per hour for the same move. For what lengths oftime does it cost less to hire Brute Force Movers?

Page 25: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

25

Piecewise Defined Functions (Section 2.1)

These are just functions whose rules are defined in different parts/pieces.

-9 -8 -7 -6 -5 -4 -3 -2 -1

1 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

Example. Determine the function values.

(a) f(x) =

{2x + 1 , x > 1x2 − 2 , x ≤ 1

• f(3)

• f(1)

• f(−4)

(b) g(x) =

−3x + 5 , x ≤ 0√x + 1 , 0 < x ≤ 5

7 , x > 5

• g(−2)

• g(0)

• g(3)

• g(8)

Page 26: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

26

Absolute Value Function (Sections 2.1 and 3.5)

Definition. h(x) =

{−x , x < 0x , x ≥ 0

is the absolute value function, denoted by h(x) = |x|.

Remark. To solve absolute value equations:

No solution if a < 0| −− | = a

Equivalent to −− = a or −− = −a if a ≥ 0

Example. Solve each of the following.

|x− 3| = 2 |x + 2| = −5

|2x− 3|+ 1 = 6 12− |x + 6| = 5

Page 27: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

27

Remark. To solve absolute value inequalities when a > 0:

| −− | < a means −a < −− < a (Also true for ≤)

| −− | > a means −− > a or −− < −a (Also true for ≥)

Example. Solve each of the following. Write your answer in interval notation.

|2x| < 4 |x− 0.5| ≤ 0.2

|3x| ≥ 18 |6− 4x| > 8

Page 28: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

28

Quadratic Functions (Sections 2.1 and 3.2)

Definition. Quadratic functions are functions that can be written in the form

f(x) = ax2 + bx + c , a 6= 0

where a, b, and c are real numbers.

Example. Use a table to sketch the graph of f(x) = x2.

-9 -8 -7 -6 -5 -4 -3 -2 -1

1 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

Now use your graphing calculator to graph each of the following and describe how it is differentfrom the graph of f(x) = x2:

y = (x− 2)2 y = x2 − 2 y = 2x2

y = (x + 2)2 y = x2 + 2 y =1

2x2

y = (x− 5)2 y = x2 − 5 y = 5x2

y = (x + 5)2 y = x2 + 5 y =1

5x2

For c > 0:

y = (x− c)2 y = x2 − c y = cx2

y = (x + c)2 y = x2 + c y = cx2

Also:

y = −x2

Page 29: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

29

Example. Describe how the graph of g(x) could be obtained from the graph of f(x) = x2.

g(x) = (x− 4)2 − 3

g(x) = (x + 6)2 − 1

g(x) = (x + 3)2 + 9

g(x) = 3(x + 1)2

g(x) = −(x− 5)2 + 6

g(x) = −15(x− 2)2 + 4

Remark. Every quadratic function (i.e. function of the form f(x) = ax2 + bx+ c where a 6= 0),can be written in the form:

f(x) = a(x− h)2 + k.

This is called the for a quadratic function and (h, k) is

the .

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30

Definition.

(1) A function f is called increasing on an open interval I, if for all a, b ∈ I, a < b impliesf(a) < f(b). (Rises as you go to the right)

(2) A function f is called decreasing on an open interval I, if for all a, b ∈ I, a < b impliesf(a) > f(b). (Falls as you go to the right)

(3) A function f is called constant on I, if f(a) = f(b) for all a, b ∈ I.

Example. For each of the functions below, determine the intervals of increase and decrease.

f(x) = (x + 2)2 − 3 Increasing: g(x) = −(x− 6)2 Increasing:

Decreasing: Decreasing:

-9-8-7-6-5-4-3-2-11 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

-9-8-7-6-5-4-3-2-11 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

Page 31: Course Outline Functions/Graphing Solving …...Course Outline Functions/Graphing Solving Equations Applications De nitions of function, graph, domain, range, x- and y-intercepts,

31

f(x) =1

2x2 + 4 Increasing: f(x) = −3(x + 4)2 + 2 Increasing:

Decreasing: Decreasing:

-9 -8 -7 -6 -5 -4 -3 -2 -1

1 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

-9 -8 -7 -6 -5 -4 -3 -2 -1

1 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

Completing the Square

If every quadratic function f(x) = ax2 + bx + c where a 6= 0 can be written in the formf(x) = a(x− h)2 + k, how do you get it in that form?

f(x) = x2 + 4x− 3 Method

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32

Example. Complete the square to write each quadratic function in the form f(x) = (x −h)2 + k. Determine the vertex of the parabola, the axis of symmetry, and the intervals ofincrease/decrease.

f(x) = x2 − 6x + 10 f(x) = x2 + 10x + 18

Remark. Notice that the coordinates of the vertex for

f(x) = x2 + bx + c

are .

Example. Write the following quadratic functions in the form f(x) = (x− h)2 + k.

f(x) = x2 + 7x− 1 f(x) = x2 + 8x + 4

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33

What happens if a 6= 0 in f(x) = ax2 + bx + c? How do you complete the square to write it inthe form f(x) = a(x− h)2 + k?

f(x) = 2x2 + 8x− 1 Method

Example. Complete the square to write each quadratic function in the form f(x) = (x −h)2 + k. Determine the vertex of the parabola, the axis of symmetry, and the intervals ofincrease/decrease.

f(x) = −4x2 + 8x− 3 f(x) = 3x2 − 9x + 2

Remark. Notice that the coordinates of the vertex for

f(x) = ax2 + bx + c

are .

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34

Example. Write the following quadratic functions in the form f(x) = a(x− h)2 + k.

f(x) = −2x2 − 12x− 1 f(x) = 3x2 + 5x + 4

Definition. Let f(x) be a function. Then f(c) is . . .

. . . called a relative (local) maximum if thereexists an open interval I containing c such thatf(c) > f(x), for all x in I where x 6= c.

. . . called a relative (local) minimum if thereexists an open interval I containing c such thatf(c) < f(x), for all x in I where x 6= c.

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Remark. A function can have several relative maximums and several relative minimums. Hereare some examples:

Maximum and Minimum Applications (Section 3.3)

Example. A model rocket is launched into the air with an initial velocity of 90 ft/sec from thetop of a building that is 40 feet high. The rocket’s height, in feet, t seconds after it has beenlaunched is given by the function:

s(t) = −16t2 + 90t + 40.

Determine the maximum height that the rocket will reach along with the time when the rocketwill reach that maximum height.

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Example. A manufacturer of dog houses has determined that when x hundred wooden dog-houses are built, the average cost (in hundreds of dollars) per doghouse is given by

C(x) = 0.1x2 − 0.7x + 1.625.

How many doghouses should be built in order to minimize the average cost per doghouse?

Example. In business:

P (x) = R(x) − C(x)↑ ↑ ↑

Profit Revenue Cost(in $) (in $) (in $)

where x is the number of units sold. Find the maximum profit, along with how many units mustbe sold when:

R(x) = 50− 0.5x2

C(x) = 10x + 3

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Example. When Mentos are added to Diet Coke, the Diet Coke is propelled upward fromground level at a rate of 32 feet per second. The height of the Diet Coke (in feet) after t secondsis given by the function

s(t) = −16t2 + 32t.

Determine the maximum height of the Diet Coke.

Example. A landscaper has enough stone to enclose a rectangular koi pond next to an existinggarden wall of a house with 24 feet of stone wall. If the garden wall forms one side of therectangle, what is the maximum area that the landscaper can enclose? What dimensions shouldthe koi pond be?

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Quadratic Equations (Section 3.2)

Definition. A quadratic equation is an equation that can be written in the form

ax2 + bx + c = 0

where a 6= 0.

Example. Determine if the following equations are linear, quadratic, or neither.

4x = 8− 9x 3√x + 4 = x 2x2 − 8 = 3− 4x

3x + x3 = 4x2 5x = 83

x= 5− x

How do you solve quadratic equations?

Step #1 : Move everything to one side of the equation.

Step #2 : Try to factor.

Step #3 : If you can’t seem to factor the equation, use the quadratic formula.

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The solutions of ax2 + bx + c = 0 where a 6= 0 are given by:

x =−b±

√b2 − 4ac

2a.

Where does the quadratic formula come from?

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Example. Solve the following equations.

2x2 − 3x− 2 = 0 x2 = 8x− 9

4x2 − 12 = 0 y2 + 8y = −15

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Example. (Continued from previous page) Solve the following equations.

w2 + 9 = 6w x2 − 4x + 5 = 0

How many solutions does ax2 + bx + c = 0 have where a 6= 0?

Real Solutions and the Discriminant Overall Solutions

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Applications with Quadratic Equations (Section 3.2)

Example. The number of U.S. forces in Afghanistan decreased to approximately 34,000 in 2014from a high of about 100,000 in 2010. The amount of U.S. funding for Afghan security forcesalso decreased during this period. The function

f(x) = −1.321x2 + 5.156x + 5.517

can be used to estimate the amount of U.S. funding for Afghan security forces, in billions of dol-lars, x years after 2009. In what year was the amount of U.S. funding for Arghan security forcesabout $10.5 billion? (Source: U.S. Department of Defense; Brookings Institution; InternationalSecurity Assistance Force; ESRI ).

Example. A stone is thrown directly upward from a height of 30 feet with an initial velocity of60 feet per second. The height of the stone, in feet, t seconds after it has been thrown is givenby the function

s(t) = −16t2 + 60t + 30.

Determine the total number of seconds the stone was in the air.

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Quadratic Type Equations (Section 3.3)

Sometimes an equation is not a quadratic equation, but using a substitution of variables we canmake it “look like” a quadratic equation. Consider:

x4 − 5x2 + 4 = 0

Example. Solve the following quadratic type equations.x4 − 3x2 + 2 = 0 x4 − 8x2 = 9

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Polynomial Functions and Graphs (Section 4.1-4.2)

Definition. A polynomial function is a function of the form

where the coefficients an, an−1, . . . a1, a0 are real numbers and the exponents are whole numbers.The degree of the polynomial P (x) is n, and the leading coefficient of P (x) is an.

Example. Determine the degree, leading coefficient, domain, and range of each polynomialfunction.

Function Degree Leading Domain Range TinyCoefficient Sketch

f(x) = 5

f(x) = 3x + 2

f(x) = 3x2 − 6x + 5

f(x) = −x2 + 4x− 1

f(x) = x3 + 2x2 − 12

f(x) = −x4 + 2x3

f(x) = x5 + 4x3 + x2

Can you describe any aspects of the shape of the graph of f(x) based on its degree?

Even Degree Odd Degree

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Remark (The Leading-Term Test). For the polynomial

P (x) = anxn + an−1x

n−1 + · · ·+ a1x + a0

the behavior of the graph as x → ∞ (as the graph goes to the far right) and as x → −∞ (asthe graph goes to the far left):

n an > 0 an < 0

Example. Determine the end behavior of each polynomial.

f(x) = 4x3 − 5x + 3 f(x) = −3x7 + 4x6 − 3x5 + x2 f(x) = x10 − x9 + 6x4 + 3x2 − 9

f(x) = −2x5 + x4 + x3 − 3x2 f(x) = −4x8 − 4x6 + x5 + 8 f(x) = x100 − 3x2 + 8x− 50

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Solving Polynomial Equations (Sections 4.1-4.3)

Example. Solve the following equations.x3 − 2x2 − 8x = 0 x4 + 4x2 − 45 = 0

But what if we couldn’t see how to factor easily? If we can guess/find one root (i.e. solution)to the equation, we can use that to help us factor using the following relationship:

x = c is a solution to f(x) = 0 ⇐⇒ (x− c) is a factor of f(x)

To use this relationship, we need to know how to do polynomial long division.

Example. x = 2 is a zero of f(x) = x3 − 2x2 − 9x + 18. So (x− 2) is a factor:

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Example. Use polynomial long division to factor f(x), given a zero of f(x).

f(x) = x3 + 2x2 − 5x− 6, x = −1 f(x) = x4 − 6x3 + x2 + 24x− 20, x = 2

Polynomial long division takes up a lot of space . . . and since we are only dividing by (x− c)we can use a process called synthetic division that works in these cases.

Example. Let’s consider the problem f(x) = x4−6x3 +x2 + 24x−20 with the zero x = 2 fromthe previous example.

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Example. Use synthetic division to factor the following functions, given a zero of the function.

f(x) = x3 − 3x2 − 6x + 8, x = 1 f(x) = x4 − 7x3 + 9x2 + 27x− 54, x = 3

How can we use this to sketch a graph of a polynomial? Consider f(x) = x3 − 3x2 − 6x + 8(from the previous example).

• Step #1: Find a zero by guess & check.

• Step #2: Use synthetic division to factor.

• Step #3: Completely factor f(x).

• Step #4: Plot all x-intercepts.

• Step #5: Use a sign chart to sketch the graph.

-9 -8 -7 -6 -5 -4 -3 -2 -1

1 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

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Example. Sketch the graph of each function.f(x) = x3 − 7x + 6

-9 -8 -7 -6 -5 -4 -3 -2 -1

1 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

f(x) = −x4 + 2x3 + 3x2 − 4x− 4

-9 -8 -7 -6 -5 -4 -3 -2 -1

1 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

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Polynomial Inequalities (Section 4.6)

Example. Solve the following inequalities.x2 − 4x− 5 > 0 x2 + 3x− 5 ≤ x + 3

x3 < x x3 − 9x + 27 ≥ 3x2

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Radical Functions (Section 3.4)

Definition. Radical functions are functions that involve

n√

Example. Use a table to sketch the graph of f(x) =√x.

-9 -8 -7 -6 -5 -4 -3 -2 -1

1 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

Now use your graphing calculator to graph each of the following and describe how it is differentfrom the graph of f(x) =

√x:

y =√x− 2 y =

√x− 2 y = 2

√x

y =√x + 2 y =

√x + 2 y =

1

2

√x

y = −√x y =

√−x

Remark. So just like we saw for f(x) = x2 . . .

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Example. Describe how the graph of g(x) could be obtained from the graph of f(x) = x2.

g(x) =√x− 4 + 2

g(x) = −3√x + 1

g(x) =1

8

√x− 5

g(x) =√

4− x

g(x) = −√x− 3 + 6

g(x) = 0.9√−1− x− 7

Example. Given the graph of y = f(x), sketch the graph of each.

y = 2f(x− 1) y = −f(x) + 4 y = f(−x)− 3

-9-8-7-6-5-4-3-2-11 2 3 4 5 6 7 8 9123456789

-1-2-3-4-5-6-7-8-9

-9-8-7-6-5-4-3-2-11 2 3 4 5 6 7 8 9123456789

-1-2-3-4-5-6-7-8-9

-9-8-7-6-5-4-3-2-11 2 3 4 5 6 7 8 9123456789

-1-2-3-4-5-6-7-8-9

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Example. Determine the domain and range for each of the following functions below.

Recall: The domain and range of f(x) =√x are

f(x) =√x + 3− 4 f(x) =

√x− 1 + 9

f(x) = 2√x + 3− 4 f(x) = −3

√x + 4

f(x) =√

1− x f(x) = −√

2− x + 1

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Solving Radical Equations (Section 3.4)

Example. Simplify the following.

√64 3

√27 3

√−8

4√

81 5√−32 4

√1

How do you use your calculator to help with things like 4√

15?

Example. Use your calculator to round the following to three decimal places.

3√−83 4

√76 5

√19

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How do we solve an equation like 3√

2− x = 4?

Example. Solve each of the following equations.√4x + 1 = 3

√y − 1 + 4 = 0

5√

3x + 4 = 2 3√

6x− 9 + 8 = 5

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How do we solve an equation like√x + 1 + 1 = x?

Example. Solve each of the following equations.√7x + 4 = x + 2

√x− 3 + 5 = x

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Graphs of Rational Functions (Section 4.5)

Definition. A rational function if a function of the form:

where p(x) and q(x) are polynomials and q(x) 6= 0.

Example. Graph the following functions on your graphing calculator and determine the domain.

f(x) =3

x + 5f(x) =

x + 1

x2 − x− 6

Remark. The domain for a rational function f(x) =p(x)

q(x)is:

Example. Determine the domain for each of the following functions.

f(x) =2x− 11

x2 + 2x− 8f(x) =

x2 − 4x

x3 − x

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Graph f(x) =x2 − 4x

x3 − xon your graphing calculator:

-9 -8 -7 -6 -5 -4 -3 -2 -1

1 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

Remark. To find vertical asymptotes for a rational function f(x) =p(x)

q(x):

(1) Reduce f(x) by canceling out any common factors between p(x) and q(x).(2) Set the new denominator equal to zero.(3) The vertical asymptotes correspond to the answers found above.

Example. Determine the vertical asymptotes for each of the following rational functions.

f(x) =x2 − 2x

x2 + 2x− 8f(x) =

2x + 6

x2 + 7x− 8

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Solving Rational Equations (Section 3.4)

How do we solve an equation likex− 8

3+

x− 3

2= 0?

. . . or how would you solve an equation like2x

x + 7=

5

x− 3?

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60

Example. Solve the following equations.

x +6

x= 5

1

2+

2

x=

1

3+

3

x

2

x− 1=

3

x + 2

3y + 5

y2 + 5y+

y + 4

y + 5=

y + 1

y

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61

More About Graphs of Rational Functions (Section 4.5)

Previously, we learned how to find the domain, vertical asymptotes, and horizontal asymptotesfor a rational function. This information told us some keys as to what the graph of the functionwould look like. Now, we review how to find x- and y-intercepts. To graph a rational functionaccurately, you would need to do all of these things and then to create a table to find additionalpoints.

Example. Find the x- and y-intercepts for following functions.

f(x) =x2 + 3x− 10

x2 − 2xg(x) =

x2 − 4x

x3 − x

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62

Compositions of Functions (Section 2.3)

In the beginning of the semester, we did problems like this one:

For f(x) = 3x− 1 and g(x) = x2 + 4x− 1 find the following:

f(4 + h) g(1 + h)

This leads into the composition of functions. For the two functions f(x) and g(x), the compo-sition functions f ◦ g and g ◦ f are defined as:

Example. Consider the functions f(x) = 3x + 1 and g(x) = x2 + 4. Find:(f ◦ g)(x) (g ◦ f)(x)

Remark. Notice that:

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63

Example. Let f(x) = 1− 2x, g(x) =√x + 1, and h(x) = x2 + 8. Find:

(g ◦ f)(x) (f ◦ f)(x)

(f ◦ h)(x) (h ◦ g)(x)

It is very important in Calculus that you can do compositions of functions, because the derivativeis defined using compositions of functions via the difference quotient. For a function f(x), thedifference quotient of f(x) is:

f(x + h)− f(x)

hLet’s find the difference quotient for f(x) = 4x− 1.

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64

Example. Find the difference quotient for each function.f(x) = x2 + 3 g(x) = 2x2 − x

Example. Consider f(x) = 3x− 2 and g(x) =x + 2

3. Find (f ◦ g)(x) and (g ◦ f)(x)

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65

Inverses Functions (Section 5.1)

In the previous example, f(x) = 3x− 2 and g(x) =x + 2

3are inverses:

Definition. Two functions f and g are called inverses if

Example. Determine if the given two functions are inverses of each other.

f(x) = 3√x + 1 and g(x) = x3 + 1 f(x) =

1− x

xand g(x) =

1

x + 1

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66

So when does a function have an inverse? And then how do we find the inverse?

Example. Determine the inverse of f(x) (if it exists).

f(x) = x2 − 4x + 1 f(x) =x + 5

7

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Example. Determine the inverse of the given function (if it exists).

f(x) =3

x− 1g(x) = 5

√x + 2

We know want to look at two different types of functions, called logarithmic functions andexponential functions. It will turn out that these two types of functions are inverses of eachother, i.e. the inverse of a logarithmic function will be an exponential function and the inverseof an exponential function will be a logarithmic function.

Exponential Functions (Section 5.2)

Definition. The function

x is a real number, a > 0, and a 6= 1, is called the exponential function with base a.

Example. Consider the exponential functions

f(x) = 2x and g(x) =

(1

2

)x

and h(x) = ex.

Find the following output values.

f(−2) = g(−2) = h(−2) =

f(0) = g(0) = h(0) =

f(2) = g(2) = h(2) =

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Let’s draw the graphs of f(x) = 2x and f(x) =

(1

2

)x

:

-9-8-7-6-5-4-3-2-11 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

-9-8-7-6-5-4-3-2-11 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

Now, let’s draw the graphs of f(x) = 3x and f(x) =

(1

3

)x

:

-9-8-7-6-5-4-3-2-11 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

-9-8-7-6-5-4-3-2-11 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

So graphs of exponential functions look like:

-11

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69

Logarithms (Section 5.3)

What does loga x mean????

Example. Calculate the following.log2 8 log5 1 log1 00.001

log3 81 log2

(1

8

)log4 16

Definition. The function

is the logarithmic function having base a, where a > 0 is a real number.

Two bases that occur often have special notations:

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70

Example. Compute the following. Round your answers to two decimal places.log 7 ln 2 log 30 ln 20

Your calculator has buttons for ln x and log x, but how do you calculate other base logarithms?

Example. Compute the following. Round your answers to two decimal places.log3 15 log2 6 log6 30

You can convert between logarithmic and exponential equations using the following:

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71

Example. Convert the following logarithmic equations to exponential equations.log5 5 = 1 log 7 = 0.845 ln 40 = x

Example. Convert the following exponential equations to logarithmic equations.

e3 = t 5−3 =1

125103 = 1000

Graphs of Inverse Functions (Section 5.1)

Let’s compare the graphs of two inverse functions. Graph f(x) = 2x − 3 and f−1(x) =x + 3

2on the same coordinate axes:

-9 -8 -7 -6 -5 -4 -3 -2 -1

1 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

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Let’s try another pair of inverse functions. Graph f(x) = x3 + 2 and f−1(x) = 3√x− 2 on the

same coordinate axes:

-9 -8 -7 -6 -5 -4 -3 -2 -1

1 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

Since f(x) = ax and f−1(x) = loga(x), we can use the graph of f(x) = ax to graph f−1(x) =loga(x).

Example. Sketch the graph of each logarithmic equation.y = log2 x y = log 1

2x

-9 -8 -7 -6 -5 -4 -3 -2 -1

1 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

-9 -8 -7 -6 -5 -4 -3 -2 -1

1 2 3 4 5 6 7 8 9

123456789

-1-2-3-4-5-6-7-8-9

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73

Application to Compound Interest (Section 5.2)

If P dollars are invested at an interest rate r (written as a decimal), compounded n times peryear, then the amount A of money in the account after t years is given by:

A = P(

1 +r

n

)ntExample. If $500 is invested at a rate of 1.25%, compounded monthly, how much money willbe in the account after 5 years?

Example. If $1200 is invested at a rate of 2.5%, compounded semiannually, how much moneywill be in the account after 2 years?

As the number of times you compound interest per year increases, the amount in the accountafter t years also increases. Consider investing $100 at a rate of 2% for a time period of 5 years.So

A = 100

(1 +

.02

n

)5n

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74

If interest is compounded continuously, then the amount A in the account after t years is:

A = Pert

Example. If $500 is invested at a rate of 1.25%, compounded continuously, how much moneywill be in the account after 5 years?

Example. If $1200 is invested at a rate of 2.5%, compoundedcontinuously, how much moneywill be in the account after 2 years?

Solving Exponential and Logarithmic Equations (Section 5.5)

Logarithm and exponential functions are inverses, so:

loga (ax) = x and aloga(x) = x

Example. Solve the following equations:2x+3 = 5 log5(3x− 1) = 12

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Example. Solve the following equations:

54x−7 = 125 log5(8− 7x) = 3

2x = 40 ln x = −2

Properties of logarithms:

• loga M + logaN = loga MN

• loga M − loga N = loga

M

N

• p loga M = logaMp

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So, how do we solve logarithmic equations like

log8(x + 1)− log8 x = 2

Example. Solve the following equations:log2(x + 1) + log2(x− 1) = 3 log x + log(x + 4) = log 12

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One more example . . . solve

ln(x + 8) + ln(x− 1) = 2 lnx

Let’s take a look back at solving exponential equations.

Example. Solve the following equations:

1000e0.09t = 5000 250− (1.87)x = 0

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Example. Suppose that $1,500 is invested at an interest rate of 1.75%, compounded quarterly.How long would it take for the amount of money in the account to become $2,000?

Example. Suppose that $5,000 is invested at an interest rate of 5.4%, compounded continuously.How long would it take for the amount of money to double?