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Chemical shift scale
Interpretation of 1H NMR spectrum
11/20/2012Organic Spectroscopy 1
Lecture 820th November 2012
Chemical shift is the frequency of signal on
an NMR spectrum where the peak occurs.
Atoms in different chemical environment will
resonate at different frequency and will
appear at different chemical shifts.
The chemical shift scale is calibrated such
that the frequency point is tetramethyl saline
(TMS).
11/20/2012Organic Spectroscopy 2
Since silicon is less electronegative than
carbon, TMS protons are highly shielded and
its signal defined as zero.
Organic protons absorb downfield (to the left)
of the TMS signal
It’s is inert to most organic samples
11/20/2012Organic Spectroscopy 3
Si
CH3
H3C CH3
CH3
11/20/2012Organic Spectroscopy 4
TMS
Chemical shift can be expressed in terms of Hz by
setting the TMS peak at 0 Hz. The magnetic field
decreases toward left.
When chemical shifts are given in Hz the applied
magnetic frequency must be specified
i.e 60, 90, MHz because the chemical shift in Hz is directly proportional to
the strength of the applied field, Bo and therefore to the applied frequency.
The value of chemical shift, n in Hz is;
n (in Hz)= nsample - nreference
11/20/2012Organic Spectroscopy 5
The number of Hz shift from TMS for a given
proton (or nuclei) will depend on the strength
of the applied magnetic field.
Thus, the resonance proton in an applied
field of 14,100 G is at approx. 60 MHz where
100 MHz is at field strength of 23,500 G.
11/20/2012Organic Spectroscopy 6
The ratio of the resonance frequency is the
same as the ratio of the two field strength.
Note:
In 100 MHz the shift in Hz from TMS is 5/3 larger than at 60MHz.
The SI unit Telsa (T) is the unit of measurement for B,
replacing the term Gauss (G). i.e 1T = 104 G.
11/20/2012Organic Spectroscopy 7
100 MHz
60 MHz
23,500
14,100
5
3= =
Usually chemical shifts are expressed in d
unit, a form that is independent of the field
strength (instrument used i.e 60, 90, 300,
MHz).
It is a proportionality and thus dimensionless.
11/20/2012Organic Spectroscopy 8
The factor 106 is included in the equation to
avoid fractional values, since d (which is
dimensionless) is expressed in part per
million (ppm).
11/20/2012Organic Spectroscopy 9
Observed shift from TMS in Hz Spectrometer frequency in Hz
x 106Chemical shift, dor ppm) =
On a delta scale in ppm, the frequency of aresonating proton is recorded such that thevalue of chemical shift increases from right toleft.
Different protons have different resonancebecause protons surrounded by differentelectronic environments
11/20/2012Organic Spectroscopy 10
Increasing chemical shift from 0 to 12 ppm theproton is said to be Downfield or Deshielded.
Decreasing chemical shift from 10 to 0 ppm,proton is said to be Upfield or Shielded
Protons with high electron density are said to beshielded whereas those with low electron densityare said to be deshielded.
11/20/2012Organic Spectroscopy 11
11/20/2012Organic Spectroscopy 12
A peak of proton X at 60 Hz (n 60) from TMS
at an applied frequency 60 MHz would be at
d1.00 or 1.00 ppm.
The same peak of the same proton at 100
MHz would be at 100 Hz but would still be at
d1.00 or 1.00 ppm.
11/20/2012Organic Spectroscopy 13
d (or ppm)60
60
106= = 1.00 d (or ppm)
100
100
106= = 1.00106 106
Solution:
The chemical shift in d unit express the amount bywhich a proton resonance is shifted from TMS inppm of the spectrometer basic operatingfrequency. It is independent of the field strength
Hence the value of d for a given proton will alwaysbe the same irrespective of whether themeasurement was made at 60 MHz or at 90 MHz.
So the peak of that proton will be observed at 3.4ppm.
11/20/2012Organic Spectroscopy 14
What would be the chemical shift of a peak
that occur 655.2 Hz downfield of TMS on a
spectrum recorded using a 90 MHz
spectrometer?
Solution:
d (or ppm) = [655.2 Hz/90x106 Hz]×106
= 7.28 ppm
11/20/2012Organic Spectroscopy 15
1) At what frequency would the chemical shift
of CHCl3, δ = 7.28 ppm occur relative to
TMS on a spectrum recorded on a 300 MHz?
2) Why we measure the resonance of nuclei in
ppm and not in Hz?
Solution:
ν= 7.28 ppm x 300 MHz = 2184 Hz
11/20/2012Organic Spectroscopy 16
1. How many type of H’s?
This indicated by how many groups of signals are there in a spectrum
2. What type of H’s?
Indicated by the chemical shift of each group e.g shielded or deshielded, CH,
CH2, CH3 with respect to chemical environment.
3. How many H’s of each type are there?
Indicated by integration (relative area of signal for each group)
4. What is the connectivity?
Look at the coupling patterns. This tells you what is next to each group
11/20/2012Organic Spectroscopy 17
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Both phenyl acetone and
benzyl acetate have δ = 7.3
ppm.
Methyl groups attached
directly to a carbonyl have
resonance at δ = 2.1 ppm.
Aromatic protons characteris-
tically have resonance near 7-
8 ppm
Acetyl groups (methyl group of
this type) resonance ~2 ppm.
11/20/2012Organic Spectroscopy 19
01234567PPM
CO
OCH2
CH3H
H
H H
H (a)
(b)
(c)
(a)
012345678PPM
CH2
CH3
O
HH
H
H H
Resonance of the benzyl (-
CH2-) protons comes at higher
value of δ = 5.1 ppm in benzyl
acetate than phenyl acetone δ
= 3.6 ppm. Reason?
Being attached to an
electronegative element
(oxygen atom) these electrons
are more deshielding than
those in phenyl acetone
11/20/2012Organic Spectroscopy 20
01234567PPM
CO
OCH2
CH3H
H
H H
H (a)
(b)
(c)
(a)
012345678PPM
CH2
CH3
O
HH
H
H H
The higher the electron density the higher the
shielding hence the slow the resonance.
The higher the shielding the more the
external energy is required.
11/20/2012Organic Spectroscopy 21
The intensity of an 1H-NMR signal is proportional to the
number of proton of each type in the molecule.
The integral measures the area of the peak and gives the
relative ratio of the number of H’s for each peak.
An FT-NMR instrument (to be discussed later) digitally
integrates each signal area and provides ratios of number of
hydrogen for each signal.
11/20/2012Organic Spectroscopy 22
1. For a known molecular formula
Proton per unit is determined by taking total number of proton divide by total units.
11/20/2012Organic Spectroscopy 23
# of Hs in signal =total heights of all integrals
total # of Hsheight of integral
x
2. For unknown molecular formulaIntegrate by determine the ratio between thesignals and round off to a nearest wholenumber or multiply by a factor to produce awhole number
11/20/2012Organic Spectroscopy 24
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Given formula C5H10OSolution
Signal units (units ÷ total units)× Total Hs # of Hs
(1) 2 (2 /10) x 10 = 2H
(2) 3 (3 /10) x 10 = 3H
(3) 2 (2 /10) x 10 = 2H
(4) 3 (3 /10) x 10 = 3H
Total 10 10 H
Calculating DBE = [(2C+2+N)-(H + h)]/2 =1; May be 1 double bond or a ring.
H3C
H2C
CH2
O
CH3(2)
(1)(4)
(3)
Possible structure pentan-2-one
11/20/2012Organic Spectroscopy 26
Qn 1. Dispersion is a term used to express thenotion of how well resonances in an NMR spectrumare separated from one another (in Hz) - it is aqualitative term expressing the ease with whichsignals can be distinguished. Two signals occur at2.1 and 2.3 ppm in the proton spectrum in aspectrometer operating at 200 MHz for 1H.
i) What is the frequency difference between theresonances in Hz?
ii) What is their frequency difference (in Hz) in aspectrometer operating at 600 MHz for 1Hobservation?
11/20/2012Organic Spectroscopy 27
Qn2. In order to acquire a good spectrumappropriate filling of the sample tube withrespect to coil is the main concern. Thefollowing figures are spectrum A though Dacquired from the same sample but withsample tube filled differently (sample tube 1to 4).
Giving reasons, assign each spectrum withsample responsible for.
11/20/2012Organic Spectroscopy 28
11/20/2012Organic Spectroscopy 29
1. Stronger magnetic fields Bo cause the instrument to operateat higher frequency (v)
2. NMR field strength vs 1H operating frequency
1.41T => 60 MHz; 2.36T => 100MHz; 7.06T => 300 MHz
3. The d unit has been criticized because d values increased inthe downfield direction. These are really negative numbers.Other scales are expressed in t values; t = 10.00 - d.
4. d unit is treated as positive number. Shifts at higher fieldsthan TMS are rare, that is, if d = -1.00. Then, t = 10.00- (-1.00) = 11.00.
5. Each ppm unit represents either a 1 ppm change in Bo
(magnetic field strength, Tesla) or a 1 ppm change in theprocessional frequency in (MHz)
11/20/2012Organic Spectroscopy 30
6. The shift observed for a given proton inHz also depends on the frequency of theinstrument used. Higher frequencieslarger shifts in Hz
i.e 60, 100 and 300 MHz( Operating frequency) is 60,100 and 300 Hz (equivalent to 1 ppm), respectively.
n MHz x 10-6 = n Hz
11/20/2012Organic Spectroscopy 31
Larmor frequency is dependent upon MF strength, and
the use of Hz position of the peaks are also dependent uponMF strength
11/20/2012Organic Spectroscopy 32