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Chapter 9 Stoichiometry Review

Chapter 9 Stoichiometry Review. Vocabulary composition stoichiometry reaction stoichiometry mole ratio limiting reactant excess reactant percent yield

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Page 1: Chapter 9 Stoichiometry Review. Vocabulary composition stoichiometry reaction stoichiometry mole ratio limiting reactant excess reactant percent yield

Chapter 9 Stoichiometry

Review

Page 2: Chapter 9 Stoichiometry Review. Vocabulary composition stoichiometry reaction stoichiometry mole ratio limiting reactant excess reactant percent yield

Vocabulary

• composition stoichiometry • reaction stoichiometry • mole ratio• limiting reactant • excess reactant • percent yield • actual yield • theoretical yield

Page 3: Chapter 9 Stoichiometry Review. Vocabulary composition stoichiometry reaction stoichiometry mole ratio limiting reactant excess reactant percent yield

Section 9-1• Reaction stoichiometry involves the mass relationships between reactants and

products in a chemical reaction. • A mole ratio is the conversion factor that relates the amount in moles of any two

substances in a chemical reaction. The mole ratio is derived from the balanced equation.

• Amount of a substance is expressed in moles, and mass of a substance is

expressed using mass units such as grams, kilograms, and milligrams. • Mass and amount of substance are quantities, whereas moles and grams are

units. • A balanced chemical equation is necessary to solve any stoichiometric problem.

Page 4: Chapter 9 Stoichiometry Review. Vocabulary composition stoichiometry reaction stoichiometry mole ratio limiting reactant excess reactant percent yield

Section 9-2

• In an ideal stoichiometric calculation, the mass or the amount of any reactant or product can be calculated if the balanced chemical equation and the mass or amount of any other reactant or product are known.

• Types of Stoichiometry problems: Mole – Mole,

Mass – Mole, Mole – Mass, Mass – Mass.

Page 5: Chapter 9 Stoichiometry Review. Vocabulary composition stoichiometry reaction stoichiometry mole ratio limiting reactant excess reactant percent yield

Section 9-3• In actual reactions, the reactants are usually combined in proportions

different from the precise proportions required for complete reaction. • The limiting reactant controls the maximum possible amount of product

formed. • Given certain quantities of reactants, the quantity of the product is

always less than the maximum possible. Percent yield shows the relationship between the theoretical yield and actual yield for the product of a reaction.

percent = actual yield x 100 yield theoretical yield

Page 6: Chapter 9 Stoichiometry Review. Vocabulary composition stoichiometry reaction stoichiometry mole ratio limiting reactant excess reactant percent yield

Answer the following questions

1. Given the following equation:

C3H4(g) + x O2(g) 3CO2(g) + 2H2O(g)

a. What is the value of the coefficient x in this equation?b. What is the molar mass of C3H4?

c. What is the mole ratio of O2 to H2O in the above equation?

d. How many moles are in an 8.0 g sample of C3H4?

e. If z mols of C3H4 react, how many moles of CO2 are produced, in terms of z?

Page 7: Chapter 9 Stoichiometry Review. Vocabulary composition stoichiometry reaction stoichiometry mole ratio limiting reactant excess reactant percent yield

Review Answers

#1.a. 4 b. 40.0 g/mol c. 2 mol O2:1 mol H2O

d. 0.20 mole. 3z

Page 8: Chapter 9 Stoichiometry Review. Vocabulary composition stoichiometry reaction stoichiometry mole ratio limiting reactant excess reactant percent yield

Review Questions

2. a. What is meant by ideal conditions relative

to stoichiometric calculations?b. What function do ideal stoichiometric calculations serve?c. Are actual yields typically larger or smaller

than theoretical yields?

Page 9: Chapter 9 Stoichiometry Review. Vocabulary composition stoichiometry reaction stoichiometry mole ratio limiting reactant excess reactant percent yield

Review Answers

#2. a. The limiting reactant is completely converted

to product with no losses, as dictated by the ratio of coefficients.

b. They determine the theoretical yield of the products of the reaction.

c. smaller

Page 10: Chapter 9 Stoichiometry Review. Vocabulary composition stoichiometry reaction stoichiometry mole ratio limiting reactant excess reactant percent yield

Review Questions

3. Assume the reaction represented by the following equation goes all the way to completion:

N2 + 3H2 2NH3

a. If 6 mol of H2 are consumed, how many moles of NH3 are produced?

b. How many grams are in a sample of NH3 that contains 3.0 x1023 molecules?

c. If 0.1 mol of N2 combine with H2, what must be true about the quantity of H2 for N2 to be the

limiting reactant?

Page 11: Chapter 9 Stoichiometry Review. Vocabulary composition stoichiometry reaction stoichiometry mole ratio limiting reactant excess reactant percent yield

Review Answers

#3. a. 4 mol

b. 8.5 g

c. At least 0.3 mol of H2 must be provided.

Page 12: Chapter 9 Stoichiometry Review. Vocabulary composition stoichiometry reaction stoichiometry mole ratio limiting reactant excess reactant percent yield

Review Questions

4.

If a reaction’s theoretical yield is 8.0 g and the actual yield is 6.0 g, what is the percentage

yield?

Page 13: Chapter 9 Stoichiometry Review. Vocabulary composition stoichiometry reaction stoichiometry mole ratio limiting reactant excess reactant percent yield

Review Answers

# 4.

75%

Page 14: Chapter 9 Stoichiometry Review. Vocabulary composition stoichiometry reaction stoichiometry mole ratio limiting reactant excess reactant percent yield

Review Questions5. Joseph Priestley generated oxygen gas by strongly heating

mercury(II) oxide according to the following equation:

2HgO(s) 2Hg(l) + O2(g)

a. If 15.0 g HgO decompose, how many moles of HgO does this represent?b. How many moles of O2 are theoretically produced?

c. How many grams of O2 is this?

d. If the percentage yield is 95.0%, how many grams of O2 are actually collected?

Page 15: Chapter 9 Stoichiometry Review. Vocabulary composition stoichiometry reaction stoichiometry mole ratio limiting reactant excess reactant percent yield

Review Answers

#5. a. 0.0693 molb. 0.0346 molc. 1.11 g d. 1.05 g

Page 16: Chapter 9 Stoichiometry Review. Vocabulary composition stoichiometry reaction stoichiometry mole ratio limiting reactant excess reactant percent yield

Review Questions

6. Copper reacts with silver nitrate through single replacement.

a. If 2.25 g of silver are produced from the reaction, how many moles of copper(II) nitrate are produced?

b. How many moles of each reactant are required to complete this same reaction?

Page 17: Chapter 9 Stoichiometry Review. Vocabulary composition stoichiometry reaction stoichiometry mole ratio limiting reactant excess reactant percent yield

Review Answers

#6 Cu + 2 AgNO3 2 Ag + Cu(NO3)2

a. 0.0104 mol Cu(NO3)2

b. 0.0104 mol Cu, 0.0209 mol AgNO3

Page 18: Chapter 9 Stoichiometry Review. Vocabulary composition stoichiometry reaction stoichiometry mole ratio limiting reactant excess reactant percent yield

Review Questions

7. Sulfuric acid reacts with aluminum hydroxide by double replacement.

a. If 30.0 g of sulfuric acid react with 25.0 g of aluminum hydroxide, identify the limiting reactant.b. Determine the mass of excess reactant remaining.c. Determine the mass of each product formed. Assume 90% yield.

Page 19: Chapter 9 Stoichiometry Review. Vocabulary composition stoichiometry reaction stoichiometry mole ratio limiting reactant excess reactant percent yield

Review Answers

#7 3H2SO4 + 2Al(OH)3 Al2(SO4)3 + 6HOH

a. H2SO4 is the limiting reactant.

b. 9.05 g excess Al(OH)3

c. 34.9 g Al2(SO4)3 11.0 g H2O

Page 20: Chapter 9 Stoichiometry Review. Vocabulary composition stoichiometry reaction stoichiometry mole ratio limiting reactant excess reactant percent yield

Review Questions

8. Coal gasification is a process that converts coal into methane gas.

2C(s) + 2H2O(l) .→ CH4(g) + CO2(g)

a. If this reaction has a percentage yield of 85.0%, what mass of methane can be obtained from 1250 g of carbon?b. If the percentage yield for the coal gasification process is increased to 95%, what mass of methane

can be obtained from 2750 g of carbon?

Page 21: Chapter 9 Stoichiometry Review. Vocabulary composition stoichiometry reaction stoichiometry mole ratio limiting reactant excess reactant percent yield

Review Answers

#8

a. 710. g CH4

b. 1750 g CH4

Page 22: Chapter 9 Stoichiometry Review. Vocabulary composition stoichiometry reaction stoichiometry mole ratio limiting reactant excess reactant percent yield

Review Questions

9. Magnesium is obtained from sea water. Ca(OH)2 is added to sea water to precipitate Mg(OH)2. The precipitate is filtered and reacted with HCl to produce MgCl2. The MgCl2 is electrolyzed to produce Mg and Cl2. If 185.0 g of magnesium are recovered from decomposition of 1000 g MgCl2, what is the percentage yield for this reaction?

(READ THE PROBLEM CAREFULLY!)

Page 23: Chapter 9 Stoichiometry Review. Vocabulary composition stoichiometry reaction stoichiometry mole ratio limiting reactant excess reactant percent yield

Review Answers

#9

72.46%

Page 24: Chapter 9 Stoichiometry Review. Vocabulary composition stoichiometry reaction stoichiometry mole ratio limiting reactant excess reactant percent yield

Review Questions

10. In a blast furnace, iron(lll) oxide is used to produce iron by the following (unbalanced) reaction:

Fe2O3(s) + CO(g) → Fe(s) + CO2(g)

a. If 4.00 kg Fe2O3 are available to react, how many moles of CO are needed?b. How many moles of each product are formed?

Page 25: Chapter 9 Stoichiometry Review. Vocabulary composition stoichiometry reaction stoichiometry mole ratio limiting reactant excess reactant percent yield

Review Answers

#10

a. 75.1 mol CO

b. 50.1 mol Fe, 75.1 mol CO2