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Chapter 30 Serway & Beichner

Chapter 30

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Chapter 30. Serway & Beichner. Force between two current carrying wires. Electric current The A mpere - PowerPoint PPT Presentation

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Page 1: Chapter 30

Chapter 30

Serway & Beichner

Page 2: Chapter 30
Page 3: Chapter 30

Force between two current carrying wires

Page 4: Chapter 30

Electric current The Ampere

The ampere is that constant current which, if maintained in two straight parallel conductors of infinite length, of negligible circular cross-section, and placed 1 m apart in vacuum, would produce a force between them equal to 2 × 10-7 Newton per meter of length.

Page 5: Chapter 30

Fig 30-8, p.932

Page 6: Chapter 30

Fig 30-9c, p.933

Page 7: Chapter 30

Fig 30-1, p.927

Page 8: Chapter 30

Fig 30-3, p.929

120

0

coscos4

sin4

2

1

aI

daIB

See Ex. 30.1

Page 9: Chapter 30

Fig 30-7, p.931

See Ex. 30.3

2/322

20

axis2 Rz

IRB

R

I2

0 @ z = 0

3

20

2zIR

z >> R

Page 10: Chapter 30

Ch. 30 10

Page 11: Chapter 30

Fig 30-17, p.938

Page 12: Chapter 30

Fig 30-12, p.935

rIB

2

0

rRIB 2

0

2

for r > R

for r < R

Application of Ampère’s Law

Page 13: Chapter 30

Fig 30-19, p.939

nI

IlNB

0

0

Field inside Solenoid

Page 14: Chapter 30
Page 15: Chapter 30

start

9/13/04

Page 16: Chapter 30

Fig P30-20, p.940

Magnetic Flux

B = B•dA = BAcos

Page 17: Chapter 30

Ampère’s Law One More Time

Ampere’s law states that the line integral of B . ds around any closed loop equals oI where I is the total steady current passing through any surface bounded by the closed loop.

Surface

oIldB

Page 18: Chapter 30

Now introduce a capacitor to interrupt the the circuit. If our power supply is strong enough to keep I constant, the gray surface will give B = 0!

What’s wrong?

Assume that I is constant.

Apply Ampère’s Law to either the,white or gray surfaces, both of which are bounded by the red loop.This leads to:

rIB

2

0

Page 19: Chapter 30

If the power supply can keepthe current constant, the cap.will be charged: +Q/-Q onleft/right plate. This establishesan E-field between the two plates.

E = E•dA = Q/o

Electric flux will change in time corresponding to an effective current called the Displacement Current

dtdQ

dtd

o

Page 20: Chapter 30

Consider to different surfaces

Slide 39 Fig 30-26, p.943

Page 21: Chapter 30

Fig 30-27, p.945

Orbital Motion of the Electron in an Atom

Page 22: Chapter 30

Fig 30-28, p.946

Magnetic Moments due to Spin of electron, neutron and proton

Page 23: Chapter 30

Table 30-1, p.946

Electron Proton neutron

-928 1.41 -0.966

Magnetic Moments 10-26 J/T

Page 24: Chapter 30

Polarization

Generated Field points in the opposite direction

Page 25: Chapter 30
Page 26: Chapter 30

Table 30-2, p.948

Page 27: Chapter 30

Paramagnetism

0M

Generated field adds to applied field

Atomic currents

Page 28: Chapter 30

Diamagnetism0M Generated field opposes applied field

Page 29: Chapter 30

Magnetic Domains

Page 30: Chapter 30

The Earth as a big magnet