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Chapter 26
Sources of Magnetic Field
Biot-Savart Law (P614)
2
Magnetic equivalent to C’s law by Biot & Savart
. P
Idl
r0
3
4
Idl rdB
r
Magnetic field due to an infinitesimal current:
Permeability of free space 70 4 10 /T m A
:r
position vector from to the field point PIdl
B due to full current
3
. P
Idl
r
03
4
Idl rdB
r
1) Magnitude: 02
sin
4
IdldB
r
2) Direction: right-hand rule
B
3) Total magnetic field due to a full current
03
4
Idl rB
r
Notice: directions
A straight current
4
Example1: Magnetic field of a straight current.
Pa
.
I
x
Idxr
o
x
Solution: Infinitesimal current
02
sin
4
IdxdB
r
/ sin r a
2
sin
addx
cot x a 0 sin
4
Id
a
2
1
0 sin4
IB d
a
1
2
01 2cos cos
4
I
a
5
Discussion:
0 2
IB
a
Pa.
I
01 2 cos cos
4
IB
a
1) Infinite straight current
0
2
Ea
2) Magnetic field at point A or B:
. A
. B
03
04
Idl rdB
r
0B dB
No field!
Square loop
6
Solution:
Example2: of a square loop at O, A and P.B
l
I.O
A
l
. P
01 2 cos cos
4
IB
a
o o0 cos 45 cos135 4 / 2O
IB
l
4
o o0 cos 45 cos90 24A
IB
l
BP can also be obtained by the formula .
Force between parallel wires (P605)
7
0 11
2
IB
d
Long parallel straight wires with current I1 and I2
I1 I2
d
Magnetic field due to I1 :
1 2F B I LAmpere force on I2 :
0 1 21 2 2
I IFB I
L d
F per unit length:
Operational definitions of Ampere & Coulomb
Circular current
8
Magnetic field of a circular current on the axis.
02
sin4
IdlB
r
o
R
P xx.
02
4
IdldB
r
r
Idl
dB
02
sin2
4
IR
r
20
32
IR
r
20
2 2 3/22( )
IR
R x
From the symmetry:B
9
Discussion:2I R
oR
P xx.
20
2 2 3/2
2( )
IRB
R x
1) Magnetic dipole moment
02 2 3/2
2 ( )
BR x
3
02
pE
x0
3 ( )
2x R
x
2) B at the center of a circular / arc current:
0 2
IB
R
2
l
R .
R
Io.
R
Io
Combined currents
10
Example3: Magnetic field at point O.
(a)0
2 2
IB
a
0
2( ) 2
I
a b
.a
b
I
o
(b) Uniform conductor ring
.I
R o 1 1 I l
2 2 I l
0 1 0 21 2 2 2 2 2
I Il lB
R R R R
01 1 2 22
( )4
I l I lR
0
1 21 2( )
l lI I
S S
Rotating charged ring
11
Question: A uniformly charged ring rotates about z axis. Determine the magnetic field at the center.
2
20
30
2 22
dr Q
BR
20
2 2 3/ 22( )
IRB
R x
2 202 0
sin8
Qd
R
0
8
Q
R
r
z
.o
R
Q
Magnetic flux
12
1) Uniform field:
ΦB : Magnetic flux through an area
∝ number of field lines passing that area
B B S
2) General case: B B dS
3) Closed surface:
B dS
→ net flux
Unit: Wb (Weber)
Gauss’s law for magnetic field
13
The total magnetic flux through any closed surface
is always zero.
→ Gauss’s law for magnetic field
0B dS
Closed field lines without beginning or end
0B
Ampere’s law (1)
14
0 inB dl I
1) Magnetic field is produced by all currents
Ampere’s law
The linear integral of B around any closed path is
equal to μ0 times the current passing through the
area enclosed by the chosen path.
2) The closed integral only depends on Iin
3) How to count the enclosed current?
15
The sign of enclosed current: right-hand rule
l
I1
I2
I31 2inI I I
l
I
I
2inI I I
1) Circular path around infinite straight current
Ampere’s law (2)
2B dl B r
0I 0
2
IB
r
r
16
0
2
IB
r
2) Any path around the current in same plane
dl
Bdr
0 cos2
IB dl dl
r
0
2
Ird
r
0
2
Id
Ampere’s law (3)
B
dr
dl
B
dl
3) Any path that encloses no current
17
Magnetic field is not a conservative field
Equations for E & B field
0 inB dl I
Maxwell equations for
steady magnetic field &
electrostatic field
0 0
0
/
0
0
E
E
B
B j
0 B j
Applications of Ampere’s law → symmetry
Cylindrical current
18
Example4: The current is uniformly distributed over the cylindrical conductor. Determine (a) magnetic field; (b) magnetic flux.
Solution: (a) Symmetry of system?
R
I
r
2B dl B r
0 inI
0 : 2
Ir R B
r
2 r
20 : 2
r R B j rr
0
2
jr
2( )
Ij
R
19
(b) Magnetic flux through the area:
R
I
2R
l
0 : ;2
Ir R B
r
0 02
: 2 2
jr Irr R B
R
B B dS
20 0
20
2 2
R R
R
Ir Ildr ldr
R r
ln24 2
o oIl Il
B
= BdS
Coaxial cable
20
Question: Coaxial cable: a wire surrounded by a cylindrical tube. They carry equal and opposite currents I distributed uniformly. What is B ?
×
×
×
×
I
·
··
R3
oI R1
R2·
01 2 :
2
IR r R B
r
3 : 0r R B
1 2 3 or ?r R R r R
21
Solenoid: a long coil of wire with many loops
Solenoid
0 in
abcd
B dl I
0 BL NI 0 0 N
B I nIL
→ Uniform
22
Toroid: solenoid bent into the shape of a circle
Toroid
N loops, current I
Outside: B = 0
Inside?
r
0
2
NIB
r
Nonuniform field
r becomes solenoid again
23
*B produced by moving charge
03
4
Idl rdB
r
F qv B
dF Idl B
Equations about Ampere force & Lorentz force:
03
4
qv rB
r
Magnetic field produced by a single moving charge
B created by rotating charge? .
Q
R
v
24
Increase the magnetic field by ferromagnetics
*Ferromagnetic
0 0B nI 0 mB K B nI
Km: relative permeability
μ : magnetic permeability
Hysteresis:
Electromagnet
“Hard / soft”