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ESE319 Introduction to Microelectronics 1 2008 by Kenneth R. Laker (based on P.V. Lopresti 2006) update 09Sep08 KRL) BJT Intro and Large Signal Model

BJT Intro and Large Signal Model - Penn Engineeringese319/Lecture_Notes/Lec_3_BJTLgSig_08.pdf · BJT Intro and Large Signal Model. ESE319 Introduction to Microelectronics 2008 by

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Page 1: BJT Intro and Large Signal Model - Penn Engineeringese319/Lecture_Notes/Lec_3_BJTLgSig_08.pdf · BJT Intro and Large Signal Model. ESE319 Introduction to Microelectronics 2008 by

ESE319 Introduction to Microelectronics

12008 by Kenneth R. Laker (based on P.V. Lopresti 2006) update 09Sep08 KRL)

BJT Intro and Large Signal Model

Page 2: BJT Intro and Large Signal Model - Penn Engineeringese319/Lecture_Notes/Lec_3_BJTLgSig_08.pdf · BJT Intro and Large Signal Model. ESE319 Introduction to Microelectronics 2008 by

ESE319 Introduction to Microelectronics

22008 by Kenneth R. Laker (based on P.V. Lopresti 2006) update 09Sep08 KRL)

Why BJT?What's the competition to BJT and bipolar technologies?

What advantages does the competition have over BJT?

What advantages does BJT and bipolar have over their com-petition?

What circuit applications benefit from BJT and bipolar tech-nologies?

Page 3: BJT Intro and Large Signal Model - Penn Engineeringese319/Lecture_Notes/Lec_3_BJTLgSig_08.pdf · BJT Intro and Large Signal Model. ESE319 Introduction to Microelectronics 2008 by

ESE319 Introduction to Microelectronics

32008 by Kenneth R. Laker (based on P.V. Lopresti 2006) update 09Sep08 KRL)

Why BJTWhat's the competition to BJT and bipolar technologies?

MOSFET, in particular CMOS is the leading competitor

What advantages does the competition have over BJT?Small size (die area), low cost and low power dissipation

What advantages does BJT and bipolar have over their competi-tion?

High frequency operation, high current drive, high reliability in severe environmental conditions.

What circuit applications benefit from BJT and bipolar technolo-gies?

RF analog and digital circuits,power electronics and power am-plifiers, automobile electronics, radiation hardened electronics

Page 4: BJT Intro and Large Signal Model - Penn Engineeringese319/Lecture_Notes/Lec_3_BJTLgSig_08.pdf · BJT Intro and Large Signal Model. ESE319 Introduction to Microelectronics 2008 by

ESE319 Introduction to Microelectronics

42008 by Kenneth R. Laker (based on P.V. Lopresti 2006) update 09Sep08 KRL)

BJT Physical Configuration

Each transistor looks like two back-to-back diodes, but each behaves much dif-ferently!

NPN PNP

Closer to actual layout

Page 5: BJT Intro and Large Signal Model - Penn Engineeringese319/Lecture_Notes/Lec_3_BJTLgSig_08.pdf · BJT Intro and Large Signal Model. ESE319 Introduction to Microelectronics 2008 by

ESE319 Introduction to Microelectronics

52008 by Kenneth R. Laker (based on P.V. Lopresti 2006) update 09Sep08 KRL)

BJT Symbols and ConventionsNPN PNP

Note reversal in current directions and voltage signs for PNP vs. NPN!

Page 6: BJT Intro and Large Signal Model - Penn Engineeringese319/Lecture_Notes/Lec_3_BJTLgSig_08.pdf · BJT Intro and Large Signal Model. ESE319 Introduction to Microelectronics 2008 by

ESE319 Introduction to Microelectronics

62008 by Kenneth R. Laker (based on P.V. Lopresti 2006) update 09Sep08 KRL)

NPN BJT Modes of Operation

ModeForward-ActiveReverse-ActiveCutoffSaturation

VBE

VBC

> 0 < 0< 0 > 0< 0 < 0> 0 > 0

Forward-Active ModeEBJ forward bias (V

BE > 0)

CBJ reverse bias (VBC

< 0)

Not Useful!

VBC

= -VCB

vCE

= vCB

+ vBE

iE = i

C + i

B

Page 7: BJT Intro and Large Signal Model - Penn Engineeringese319/Lecture_Notes/Lec_3_BJTLgSig_08.pdf · BJT Intro and Large Signal Model. ESE319 Introduction to Microelectronics 2008 by

ESE319 Introduction to Microelectronics

72008 by Kenneth R. Laker (based on P.V. Lopresti 2006) update 09Sep08 KRL)

NPN BJT Forward-Active Mode Basic ModelCollector-base diode is reverse biasedV CB0

Base-emitter diode is forward biased

V BE≈0.7

iC≈ I S evBEV T

iB=iC

iE=iBiC=1iB

V T=kTq≈25mV @ 25oCI s=

AEq Dnni2

N AWArea of base-emitter junctionWidth of base regionDoping concentration in baseElectron diffusion constant Intrinsic carrier concentration = f(T) =common−emitter current gain

( or VBC

< 0)

saturation current

AEWN A

niDn

Page 8: BJT Intro and Large Signal Model - Penn Engineeringese319/Lecture_Notes/Lec_3_BJTLgSig_08.pdf · BJT Intro and Large Signal Model. ESE319 Introduction to Microelectronics 2008 by

ESE319 Introduction to Microelectronics

82008 by Kenneth R. Laker (based on P.V. Lopresti 2006) update 09Sep08 KRL)

Note that the iC equation looks like that of a forward-biased

diode.

Is it?

Page 9: BJT Intro and Large Signal Model - Penn Engineeringese319/Lecture_Notes/Lec_3_BJTLgSig_08.pdf · BJT Intro and Large Signal Model. ESE319 Introduction to Microelectronics 2008 by

ESE319 Introduction to Microelectronics

92008 by Kenneth R. Laker (based on P.V. Lopresti 2006) update 09Sep08 KRL)

Note that the iC equation looks like that of a forward-biased

diode. Is it?

iC=I S ev BEV T−1

By using the other two equations the question can be answered

iE=iBiC=11 iC=

1iC

and write:

iE=1I S e

v BEV T−1= 1

I S e

vBEV T−1

AhHa! This iE equation describes a forward-biased emitter-base

“diode”.

=common−emitter current gain=common−base current gain

Page 10: BJT Intro and Large Signal Model - Penn Engineeringese319/Lecture_Notes/Lec_3_BJTLgSig_08.pdf · BJT Intro and Large Signal Model. ESE319 Introduction to Microelectronics 2008 by

ESE319 Introduction to Microelectronics

102008 by Kenneth R. Laker (based on P.V. Lopresti 2006) update 09Sep08 KRL)

So the new set ofequations is:

iC=I S ev BEV T−1= iE

iE=I Se

vBEV T−1

iB=iC

=

1

Where:

50200

10−18 I S10−12 A.

Typically:

Is is strongly temperature-

dependent, doubling for a 5 degree Celsius increase in ambient temperature!

50200

I s=AE q Dnni

2

N AW

Page 11: BJT Intro and Large Signal Model - Penn Engineeringese319/Lecture_Notes/Lec_3_BJTLgSig_08.pdf · BJT Intro and Large Signal Model. ESE319 Introduction to Microelectronics 2008 by

ESE319 Introduction to Microelectronics

112008 by Kenneth R. Laker (based on P.V. Lopresti 2006) update 09Sep08 KRL)

Two equivalent large signal circuit models for the forward-active mode NPN BJT:

Nonlinear VCCSNonlinear CCCS

iC≈ I S evBEV T=F iE

iE≈I SFeV BE

V T

Key Eqs.=F

Page 12: BJT Intro and Large Signal Model - Penn Engineeringese319/Lecture_Notes/Lec_3_BJTLgSig_08.pdf · BJT Intro and Large Signal Model. ESE319 Introduction to Microelectronics 2008 by

ESE319 Introduction to Microelectronics

122008 by Kenneth R. Laker (based on P.V. Lopresti 2006) update 09Sep08 KRL)

Yet another NPN BJT large signal model

iC= iB≈ I S evBEV T ⇒ iB≈

I SevBEV T

This “looks like” a diode between base and emitter and the equivalent circuit becomes:

Note that in this model, the diode current is represented in terms of the base current. In the previous ones, it was rep-resented in terms of the emitter current.

iB i

C

iE

Page 13: BJT Intro and Large Signal Model - Penn Engineeringese319/Lecture_Notes/Lec_3_BJTLgSig_08.pdf · BJT Intro and Large Signal Model. ESE319 Introduction to Microelectronics 2008 by

ESE319 Introduction to Microelectronics

132008 by Kenneth R. Laker (based on P.V. Lopresti 2006) update 09Sep08 KRL)

NPN BJT Operating in the Reverse-Active Mode

● We also have transistor action if we:● Forward bias the base-collector junction and● Reverse bias the base emitter junction

● The physical construction of the transistor, how-ever, leads to betas on the order of 0.01 to 1 and correspondingly smaller values of alpha, e. g.:

R=R

R1≈0.11.1

≈0.091 for R=0.1

Recall for NPN Reverse-Active Mode VBE

< 0 & VBC

> 0

Page 14: BJT Intro and Large Signal Model - Penn Engineeringese319/Lecture_Notes/Lec_3_BJTLgSig_08.pdf · BJT Intro and Large Signal Model. ESE319 Introduction to Microelectronics 2008 by

ESE319 Introduction to Microelectronics

142008 by Kenneth R. Laker (based on P.V. Lopresti 2006) update 09Sep08 KRL)

The equivalent large signal circuit model for the reverse-active mode NPN BJT:

iC≈−I SRevBCV T

iE≈−I S evBCV T

iB

iC

iE

RVRS Active

FWD Active

Key Eqs.

F I SE=R I SC=I SSat. or Scale Current Eq.

ACAE

BJT is non-symmetricalR≪F R≪F

Page 15: BJT Intro and Large Signal Model - Penn Engineeringese319/Lecture_Notes/Lec_3_BJTLgSig_08.pdf · BJT Intro and Large Signal Model. ESE319 Introduction to Microelectronics 2008 by

ESE319 Introduction to Microelectronics

152008 by Kenneth R. Laker (based on P.V. Lopresti 2006) update 09Sep08 KRL)

The Ebers-Moll Large Signal ModelThe E-M model combines the FWD & RVRS Active equivalent circuits:

Note that the lower left diode and the upper right controlled current source form the forward-active mode model, while the up-per left diode and the lower right source represent the reverse-active mode model.

iC=F iDE−iDCiE=iDE−R iDCib=1−F I DE1−R I DC

iDE=I SE ev BEV T−1

iDC=I SC evBCV T −1

F I SE=R I SC=I S

Page 16: BJT Intro and Large Signal Model - Penn Engineeringese319/Lecture_Notes/Lec_3_BJTLgSig_08.pdf · BJT Intro and Large Signal Model. ESE319 Introduction to Microelectronics 2008 by

ESE319 Introduction to Microelectronics

162008 by Kenneth R. Laker (based on P.V. Lopresti 2006) update 09Sep08 KRL)

Operation in the Saturation Mode

Consider the E-M model for collector current. We will include the “-I

S” term in the ideal diode equation.iC=F iDE−iDC

The first term is the forward mode collector current:

F iDE= I S evBEV T −1

The second is the reverse mode collector current:

iDC=I SR

evBCV T −1

Recall for Saturation Mode VBE

> 0 & VBC

> 0 (or VCB

< 0)

iC= I S evBEV T−1−

I SR

ev BCV T−1

Page 17: BJT Intro and Large Signal Model - Penn Engineeringese319/Lecture_Notes/Lec_3_BJTLgSig_08.pdf · BJT Intro and Large Signal Model. ESE319 Introduction to Microelectronics 2008 by

ESE319 Introduction to Microelectronics

172008 by Kenneth R. Laker (based on P.V. Lopresti 2006) update 09Sep08 KRL)

Combining terms:

iC=[e vBEV T −1− R1R

e−vCBV T −1] I S

Using typical values:

R=0.1

I S=10−14 A.

V T=0.025V.

iC=[e40 vBE−1−11e−40 vCB−1 ]10−14We obtain:

1R

=R1R

iC= I S evBEV T−1−

I SR

ev BCV T−1

Let's plot iC vs. v

BC (or v

CB) with v

BE = 0.7 V

Page 18: BJT Intro and Large Signal Model - Penn Engineeringese319/Lecture_Notes/Lec_3_BJTLgSig_08.pdf · BJT Intro and Large Signal Model. ESE319 Introduction to Microelectronics 2008 by

ESE319 Introduction to Microelectronics

182008 by Kenneth R. Laker (based on P.V. Lopresti 2006) update 09Sep08 KRL)

Scilab Saturation Mode Calculation//Calculate and plot npn BJT collector//current in saturation modevBE=0.7;VsubT=0.025;VTinv=1/VsubT;betaR=0.1;IsubS=1E-14;alphaR=betaR/(betaR+1);alphaInv=1/alphaR;ForwardExp=exp(VTinv*vBE)-1;vCB=-0.7:0.001:-0.1;vBC=-vCB;ReverseExp=alphaInv*(exp(VTinv*vBC)-1);iC=(ForwardExp-ReverseExp)*IsubS;signiC=sign(iC);iCplus=(iC+signiC.*iC)/2; //Zero negative valuesplot(vCB,1000*iCplus); //Current in mA.

Page 19: BJT Intro and Large Signal Model - Penn Engineeringese319/Lecture_Notes/Lec_3_BJTLgSig_08.pdf · BJT Intro and Large Signal Model. ESE319 Introduction to Microelectronics 2008 by

ESE319 Introduction to Microelectronics

192008 by Kenneth R. Laker (based on P.V. Lopresti 2006) update 09Sep08 KRL)

Saturation Mode Plot

Forward-active

Saturation

Recall for Sat. Mode V

BE > 0

& V

BC > 0

(or VCB

< 0)

A

Page 20: BJT Intro and Large Signal Model - Penn Engineeringese319/Lecture_Notes/Lec_3_BJTLgSig_08.pdf · BJT Intro and Large Signal Model. ESE319 Introduction to Microelectronics 2008 by

ESE319 Introduction to Microelectronics

202008 by Kenneth R. Laker (based on P.V. Lopresti 2006) update 09Sep08 KRL)

The PNP Transistor npnpnp

ModeForward-ActiveReverse-ActiveCutoffSaturation

VEB

VCB

> 0 < 0< 0 > 0< 0 < 0

> 0

Not Useful!

VCB

= -VBC

> 0

Page 21: BJT Intro and Large Signal Model - Penn Engineeringese319/Lecture_Notes/Lec_3_BJTLgSig_08.pdf · BJT Intro and Large Signal Model. ESE319 Introduction to Microelectronics 2008 by

ESE319 Introduction to Microelectronics

212008 by Kenneth R. Laker (based on P.V. Lopresti 2006) update 09Sep08 KRL)

PNP BJT Forward-Active Mode Basic Model

Collector-base diode is reverse biased

V BC0

Emitter-base diode is forward biased

V EB≈0.7 iC=I S ev EBV T−1

iB=iC

iE=iBiC=1iB

Note reversal in voltage polarity and in current directions!

Page 22: BJT Intro and Large Signal Model - Penn Engineeringese319/Lecture_Notes/Lec_3_BJTLgSig_08.pdf · BJT Intro and Large Signal Model. ESE319 Introduction to Microelectronics 2008 by

ESE319 Introduction to Microelectronics

222008 by Kenneth R. Laker (based on P.V. Lopresti 2006) update 09Sep08 KRL)

PNP BJT Large Signal Model FWD. Active

Note reversal in current directions!

iC=I S ev EBV T−1

iB=iC

iE=iBiC=1iBSubstituting, as in the npn case, we get:

iE=I Se

vEBV T−1

Page 23: BJT Intro and Large Signal Model - Penn Engineeringese319/Lecture_Notes/Lec_3_BJTLgSig_08.pdf · BJT Intro and Large Signal Model. ESE319 Introduction to Microelectronics 2008 by

ESE319 Introduction to Microelectronics

232008 by Kenneth R. Laker (based on P.V. Lopresti 2006) update 09Sep08 KRL)

Yet another PNP BJT large signal model

This “looks like” a diode between base and emitter and the equivalent circuit becomes:

Again, in this model, the diode carries only base current, not emitter current.

iB

iC

iC= iB= I S evEBV T−1⇒ iB=

I Se

vEBV T−1≈

I Sev EBV T

Page 24: BJT Intro and Large Signal Model - Penn Engineeringese319/Lecture_Notes/Lec_3_BJTLgSig_08.pdf · BJT Intro and Large Signal Model. ESE319 Introduction to Microelectronics 2008 by

ESE319 Introduction to Microelectronics

242008 by Kenneth R. Laker (based on P.V. Lopresti 2006) update 09Sep08 KRL)

Scilab Plot of NPN Characteristic (i

C vs. v

CE and v

BE)

//Calculate and plot npn BJT collector//characteristic using Ebers-Moll modelVsubT=0.025;VTinv=1/VsubT;betaR=0.1;alphaInv=(betaR+1)/betaR;IsubS=1E-14;for vBE=0.6:0.02:0.68 ForwardExp=exp(VTinv*vBE)-1; vCE=-0:0.001:10; vBC=vBE-vCE; ReverseExp=alphaInv*(exp(VTinv*vBC)-1); iC=(ForwardExp-ReverseExp)*IsubS; signiC=sign(iC); iCplus=(iC+signiC.*iC)/2; //Zero negative vals plot(vCE,1000*iCplus); //Current in mA.end

iC=F iDE−iDC

iDC= I SC evBCV T−1

where

iDE=I SE ev BEV T−1

vBC=vBE−vCENo Early effect

Page 25: BJT Intro and Large Signal Model - Penn Engineeringese319/Lecture_Notes/Lec_3_BJTLgSig_08.pdf · BJT Intro and Large Signal Model. ESE319 Introduction to Microelectronics 2008 by

ESE319 Introduction to Microelectronics

252008 by Kenneth R. Laker (based on P.V. Lopresti 2006) update 09Sep08 KRL)

Plot Output

vBE=0.68V

vBE=0.66V

vBE=0.64V

Early effect not included.

forward-active modesaturation mode

Page 26: BJT Intro and Large Signal Model - Penn Engineeringese319/Lecture_Notes/Lec_3_BJTLgSig_08.pdf · BJT Intro and Large Signal Model. ESE319 Introduction to Microelectronics 2008 by

ESE319 Introduction to Microelectronics

262008 by Kenneth R. Laker (based on P.V. Lopresti 2006) update 09Sep08 KRL)

More on NPN Saturation● The base-collector diode has much larger

area than the base-emitter one.● Therefore, with the same applied voltage, it will

conduct a much larger forward current than will the base-emitter diode.

● When the collector-emitter voltage drops below the base-emitter voltage, the base-collector diode is forward biased and conducts heavily.

vCE≈V CE sat vCB=vCE−vBE when

Page 27: BJT Intro and Large Signal Model - Penn Engineeringese319/Lecture_Notes/Lec_3_BJTLgSig_08.pdf · BJT Intro and Large Signal Model. ESE319 Introduction to Microelectronics 2008 by

ESE319 Introduction to Microelectronics

272008 by Kenneth R. Laker (based on P.V. Lopresti 2006) update 09Sep08 KRL)

IC Expansion Around Zero V

CE

Note that the collector current is zero at about VCE

0.06 V., not 0 V.! Also note the large reverse collector-base current below 0.06 V.

IC

(mA)

VCE

(V)

IC

= 0

Page 28: BJT Intro and Large Signal Model - Penn Engineeringese319/Lecture_Notes/Lec_3_BJTLgSig_08.pdf · BJT Intro and Large Signal Model. ESE319 Introduction to Microelectronics 2008 by

ESE319 Introduction to Microelectronics

282008 by Kenneth R. Laker (based on P.V. Lopresti 2006) update 09Sep08 KRL)

Voltage at Zero Collector Current

IC = 0 =>I SR

evBCV T−1= I S e

v BEV T−1

R ev BEV T−1=e

v BCV T −1

R ev BEV T−1=e

vBE−vCE V T −1

R 1−e−vBEV T =e

−vCEV T−e

−vBEV T

V BE

V T≈40∗0.7⇒ e

−vBEV T ≪1

R=e−vCEV T ⇒ vCE=−V T ln R

vCE=−0.025⋅ln 0.10.11

=0.0599V.

iC= I S evBEV T−1−

I SR

ev BCV T−1