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Lecture on Prospect TheoryNational University of Singapore
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Prospect Theory
EC4394 L2 1
Outline
• Review of expected utility
• Prospect theory
– Value function
• Experimental Evidence
• Expected utility vs Prospect theory
– Probability weighting function
• Experimental Evidence
• Expected utility vs Prospect theory
EC4394 L2 2
St. Petersburg Paradox and Expected Utility
• How to define the utility/value of a lottery – mean?
• St. Petersburg paradox: You are faced with a sequence of tosses of a fair coin. The game will end for the first time the coin comes up Head. If this happens on the 𝑛 th trial, you get 2𝑛 dollars. – What is your willingness to pay to participate in
this game?
EC4394 L2 3
St. Petersburg Paradox and Expected Utility
• Mean: U=1
2× 2 +
1
4× 4 +
1
8× 8 +⋯ =
1 + 1 + 1 +⋯ = +∞ – But you will not pay a large amount for the game
– Mean is not a good measure of utility
• Expected utility: 𝑢(𝑥) = 𝑙𝑛𝑥, U= 1
2× ln2 +
1
4× ln4 +
1
8× ln8 + …… =
[ (𝑛
2𝑛+∞𝑛=1 )] 𝑙𝑛2 = 2𝑙𝑛2
– The utility is finite with a concave 𝑢 𝑥
EC4394 L2 4
Expected Utility
• A lottery specifies the probability for each prize. 𝑙 = (𝑥, 𝑝; 𝑦, 1 − 𝑝), 𝑥 occurs with probability 𝑝 and 𝑦 occurs with probability 1 − 𝑝.
• The expected utility that represents the decision maker - DM’s preference would be U 𝑙 =𝑝𝑢 𝑥 + 1 − 𝑝 𝑢 𝑦 , where 𝑢(𝑥) and 𝑢(𝑦) is utility for 𝑥 and 𝑦.
• Note that 𝐔 is the utility function over lottery, while 𝐮 is the utility over outcome/money. Thus, the preference over lottery solely depends on 𝑢 function
EC4394 L2 5
Risk Aversion
• DM is risk averse if she prefers the mean of the gamble over the gamble.
• DM is risk averse if u is concave. – 𝑢(𝑎𝑥 + (1 − 𝑎)𝑦) ≥ 𝑎𝑢(𝑥) + (1 − 𝑎)𝑢(𝑦) for
any 𝑥, 𝑦, and 𝑎є[0,1]; OR 𝑢 ′′(x)≤0
• DM is risk neutral if she is indifferent between the mean of the gamble and the gamble.
• DM is risk seeking if she prefers the gamble over the mean of the gamble.
EC4394 L2 6
An Example
• 𝑙 = ($100, 0.5; 0, 0.5)
– The mean of the lottery is $50
• If u(𝑥) = 𝑥0.5,
– The expected utility of the lottery is U(𝑙) =0.5(1000.5)+0.5(00.5)=5
– The expected utility of $50 is 𝑈 50 = 𝑢 50 = 500.5
– 𝑈 50 > U 𝑙 , so DM prefers $50 over the lottery
EC4394 L2 7
Axioms of Expected Utility
• Completeness and transitivity
• Continuity
• Independence: For every lottery 𝑃, 𝑄, 𝑅, and every α ∈ 0,1 ,
𝑃 ≽ 𝑄 iff α𝑃 + (1 − α)𝑅 ≽ α𝑄 + (1 − α)𝑅
EC4394 L2 8
An Example
• If 50 ≽ 100, 0.5; 0, 0.5 , independence implies 50, 0.02; 0, 0.98 ≽ 100, 0.01; 0, 0.99 .
• Why? 𝑃 = 50, 𝑄 = 100, 0.5; 0, 0.5 , R = 0, and α = 0.02 – α𝑃 + (1 − α)𝑅 = 50, 0.02; 0, 0.98
– α𝑄 + 1 − α 𝑅 = 100, 0.01; 0, 0.99 .
• Is your choice consistent with independence?
EC4394 L2 9
Three Tenets of Expected Utility
• Asset Integration: (𝑥1, 𝑝1;⋯ ; 𝑥𝑛, 𝑝𝑛) is acceptable at asset w iff
𝑈(𝑤 + 𝑥1, 𝑝1;⋯ ;𝑤 + 𝑥𝑛, 𝑝𝑛) ≥ 𝑢(𝑤)
• Risk Aversion: 𝑢 is concave
• Expectation: 𝑈(𝑥1, 𝑝1;⋯ ; 𝑥𝑛, 𝑝𝑛) = 𝑝1𝑢(𝑥1) + ⋯+ 𝑝𝑛𝑢(𝑥𝑛)
EC4394 L2 10
Asset Integration
• In addition to whatever you own, you have been given 1,000. You are now asked to choose between A1: (1,000, 0.5), and B1: (500)
– Most people would choose: 𝐵1 ≻ 𝐴1
• In addition to whatever you own, you have been given 2,000. You are now asked to choose between A2: (-1,000, 0.5), and B2: (-500)
– Most people would choose: 𝐴2 ≻ 𝐵2
EC4394 L2 11
Asset Integration
• 𝑈(𝐴1) = 0.5𝑢(𝑤 + 1000 + 1000) + 0.5𝑢(𝑤 + 1000) = 0.5𝑢 𝑤 + 2000 + 0.5𝑢 𝑤 + 1000
• 𝑈 𝐵1 = 𝑢 𝑤 + 1000 + 500 = 𝑢 𝑤 + 1500
• 𝑈(𝐴2) = 0.5𝑢(𝑤 + 2000 − 1000) + 0.5𝑢(𝑤 + 2000) = 0.5𝑢 𝑤 + 1000 + 0.5𝑢 𝑤 + 2000
• 𝑈(𝐵2) = 𝑢(𝑤 + 2000 − 500) = 𝑢(𝑤 + 1500)
• Expected utility with asset integration could not account for the observation.
EC4394 L2 12
Reference Dependence
1/22/2015 EC4394 L2 13
Reference Dependence
• Consider the following example
– Ice water in left hand bowl; hot water in right hand bowl; room temperature in the middle bowl.
– Immerse left hand in left bowl, and right hand in right bowl.
– And then dip both hand in the middle.
EC4394 L2 14
Reference Dependence
• DM separates gain and loss relative to a reference point without asset integration
– 𝑈 𝐴1 = 0.5𝑢 1000 + 0.5𝑢 0 , and 𝑈(𝐵1) =𝑢(500)
– 𝑈 𝐴2 = 0.5𝑢 0 + 0.5𝑢 −1000 , and 𝑈 𝐵2 = 𝑢 −500
– We could have both 𝐵1 ≻ 𝐴1 and 𝐴2 ≻ 𝐵2 given some 𝑢 function.
1/22/2015 EC4394 L2 15
Risk Aversion
• You are asked to choose between A1: (3,000) and B1:(4,000,0.8). – Most people choose A1 ≻ B1, risk averse in the
gain domain
• You are asked to choose between A2: (-3,000) and B2: (-4,000,0.8). – Most people choose B2 ≻ A2, risk seeking in the
loss domain
– This is not consistent with the usual assumption of risk aversion
EC4394 L2 16
Diminishing Sensitivity
• Principle of diminishing sensitivity applies to sensory dimensions (Weber-Fechner law).
– Turning on a weak light in a dark room versus turning on a weak light in a bright room
• Diminishing sensitivity in gain, u’’(x)<0 for x>0; diminishing sensitivity in loss, u’’(x)>0 for x<0.
– The difference between getting 900 and 1000 is smaller than the difference between getting 100 and 200.
EC4394 L2 17
Loss Aversion
• You are asked to choose between A1: 0 and B1: −100, 0.5; 100, 0.5
– Most people choose A1 ≻ B1, risk averse across gain and loss domain
– 0.5𝑢(100) + 0.5𝑢(−100) < 𝑢(0) = 0 => 𝑢(100) < −𝑢(−100)
EC4394 L2 18
Loss Aversion
• 0.5𝑢 𝑥 + 0.5𝑢 −𝑥 < 𝑢 0 => 𝑢(𝑥) < −𝑢(−𝑥)
• Loss looms larger than gain.
EC4394 L2 19
Valuation Function
• Gain/loss relative to reference dependence
• Diminishing sensitivity towards gain and loss
• Loss aversion (Loss looms larger than gain)
EC4394 L2 20
Reference
point
Sensitivity to probability
• Russian roulette: a potentially lethal game of chance in which a player places n bullets in a revolver (full with 6 bullets), spins the cylinder, places the muzzle against his or her head, and pulls the trigger. What is your willingness to pay for each of the reduction of bullets as follows.
– 6 to 5 (From sure to 5/6 chance)
– 3 to 2
– 1 to 0 (From 1/6 chance to impossible)
• People like to pay more for 6 to 5, and for 1 to 0.
EC4394 L2 21
Allais Paradox: Common Ratio
• It is commonly observed that
– (3000, 0.90) ≻ (6000, 0.45)
– (6000, 0.001) ≻ (3000, 0.002)
• The expected utility of the choice:
– 0.9u(3000)> 0.45u(6000)
– 0.001u(6000)>0.002u(3000)
– Contradiction!
EC4394 L2 22
Allais Paradox: Common Ratio
• Here we show that it violates the independence
• 𝑃 :(3000, 0.90) , 𝑄 :(6000, 0.45), R=0, α=2/900
• α𝑃 + 1 − α 𝑅 =(3000, 0.002).
• α𝑄 + 1 − α 𝑅 =(6000, 0.001).
• Hence (3000, 0.90) ≻ (6000, 0.45) and (6000, 0.001) ≻ (3000, 0.002) violates independence.
EC4394 L2 23
Allais Paradox: Common Ratio
• When expected utility, U 𝑙 = 𝑝𝑢 𝑥 +1 − 𝑝 𝑢 𝑦 , could not account for the choice
behavior, we need to extend the theory further.
• We introduce probability weighting function 𝜋 𝑝 to have U 𝑙 = 𝜋(𝑝)𝑢 𝑥 + 𝜋 1 − 𝑝 𝑢 𝑦
• We examine the properties of 𝜋 𝑝
EC4394 L2 24
Allais Paradox: Common Ratio
• We derive the condition for 𝜋 𝑝 , under which it can exhibit the choice patterns.
• 𝜋 0.90 𝑢(3000) > 𝜋 0.45 𝑢(6000)
𝜋 0.001 𝑢(6000) > 𝜋 0.002 𝑢(3000)
•𝜋 0.45
𝜋 0.90<𝑢 3000
𝑢 6000<𝜋 0.001
𝜋 0.002
Subproportionality: 𝜋 𝑝𝑞
𝜋 𝑝<𝜋 𝑝𝑞𝑟
𝜋 𝑝𝑟
EC4394 L2 25
Allais Paradox: Common Consequence
• It is commonly observed that
– 2400 ≻ (2500, 0.33; 2400, 0.66)
– (2500, 0.33) ≻(2400, 0.34)
• The expected utility of the choice:
– 𝑢 2400 > 0.33𝑢 2500 + 0.66𝑢 2400
– 0.33𝑢 2500 > 0.34𝑢 2400
– Contradiction!
– Check violation of independence axiom!
EC4394 L2 26
Allais Paradox: Common Consequence
EC4394 L2 27
1-33 (0.33) 34 (0.01) 35-100 (0.66)
Gamble A1 2500 0 2400
Gamble B1 2400 2400 2400
Gamble A2 2500 0 0
Gamble B2 2400 2400 0
Suppose there are 100 balls numbered from 1 to 100. You randomly pick a ball, the number drawn determines your earning as follows.
Allais Paradox: Common Consequence
• Similarly, we derive the condition for 𝜋 𝑝
• 𝜋 0.33 𝑢 2500 > 𝜋 0.34 𝑢 2400
• 𝑢 2400 > 𝜋 0.66 𝑢 2400 + 𝜋 0.33 𝑢 2500
• (1 − 𝜋 0.66))𝑢 2400 > 𝜋 0.33 𝑢 2500 > 𝜋(0.34)𝑢(2400
• 𝜋 0.66 + 𝜋 0.34 < 1
Subcertainty: 𝜋 𝑝 + 𝜋 1 − 𝑝 < 1
EC4394 L2 28
Gambling and Insurance
• Gambling: (5000, 0.001) ≻ (5)
• Expected utility: 0.001𝑢 5000 > 𝑢 5 ⇒𝑢 5
𝑢 5000< 0.001
– If 𝑢(𝑥) 𝑖𝑠 𝑐𝑜𝑛𝑐𝑎𝑣𝑒 𝑓𝑜𝑟 𝑥 > 0, 𝑢 5
𝑢 5000> 0.001,
contradiction!
• Insurance: (-5) ≻ (-5000, 0.0001) – Check whether it contradicts the expected utility!
EC4394 L2 29
Gambling and Insurance
• Similarly, we derive the condition for 𝜋 𝑝
• 𝜋 0.001 𝑢 5000 > 𝑢 5
• 𝜋 0.001 >𝑢 5
𝑢 5000> 0.001
• Overweighting small p: 𝜋 𝑝 > 𝑝
• Check for insurance: (-5) ≻ (-5000, 0.0001)!
EC4394 L2 30
Subadditivity for small p
• It is commonly observed that (0.001,6000) ≻ (0.002, 3000)
• Expected utility: 0.001𝑢 6000 >0.002𝑢 3000 ⇒ 𝑢(3000)/𝑢(6000) < 0.5
– If 𝑢(𝑥) 𝑖𝑠 𝑐𝑜𝑛𝑐𝑎𝑣𝑒 𝑓𝑜𝑟 𝑥 > 0, 𝑢 3000
𝑢 6000> 0.5,
contradiction!
EC4394 L2 31
Subadditivity for small p
• Similarly, we derive the condition for 𝜋 𝑝
• 𝜋 0.001 𝑢(6000) > 𝜋 0.002 𝑢(3000)
• 𝜋(0.001)/𝜋(0.002) > 𝑢(3000)/𝑢(6000) >1/2
• Subadditivity: 𝜋(𝑟𝑝) > 𝑟𝜋(𝑝) for small probability
EC4394 L2 32
Probability Weighting Function
• Subproportionality
• Subcertainty
• Overweighting for small p
• Subadditivity for small p
EC4394 L2 33
Theory
• Editing Phase
– Coding
– Combination
– Cancellation
– Simplification
– Detection of Dominance
• Evaluation Phase
– Valuation
– Probability Weighting EC4394 L2 34
Theory
• 2 or 3 outcomes
–N-outcomes
–Violation of dominance
• What is reference point?
EC4394 L2 35
Earlier Works
Markowitz (1952)
Karmarkar (1978)
EC4394 L2 36
Earlier Works
“Columbus is viewed as the discoverer of America, even though every school child knows that the Americas were inhabited when he arrived, and that he was not even the first to have made a round trip, having been preceded by Vikings and perhaps others. What is important about Columbus’ discovery of America is not that it was the first, but that it was the last. After Columbus, America was never lost again.”
– Al Roth
EC4394 L2 37