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Mediterr. J. Math. 7 (2010), 471–482DOI 10.1007/s00009-010-0036-11660-5446/10/040471-12, published online March 23, 2010© 2010 Birkhäuser / Springer Basel AG
Mediterranean Journalof Mathematics
Approximation by ComplexBernstein-Durrmeyer Polynomials inCompact Disks
George A. Anastassiou∗ and S.G. Gal
Abstract. In this paper, the order of simultaneous approximation andVoronovskaja kind results with quantitative estimate for complex Bern-stein-Durrmeyer polynomials attached to analytic functions on compactdisks are obtained. In this way, we put in evidence the overconvergencephenomenon for Bernstein-Durrmeyer polynomials, namely the exten-sions of approximation properties (with quantitative estimates) fromreal intervals to compact disks in the complex plane.
Mathematics Subject Classification (2010). Primary 30E10 ; Secondary41A25.
Keywords. Complex Bernstein-Durrmeyer polynomials, simultaneous a-pproximation, Voronovskaja-type result.
1. Introduction
Concerning the convergence of Bernstein polynomials in the complex plane,Bernstein proved (see e.g. [12, p. 88]) that if f : G → C is analytic in the openset G ⊂ C, with D1 ⊂ G (where D1 = {z ∈ C : |z| < 1}), then the complexBernstein polynomials Bn(f)(z) =
∑nk=0
(nk
)zk(1 − z)n−kf(k/n), uniformly
converge to f in D1.Exact estimates of order O(1/n) of this uniform convergence and, in
addition, of the simultaneous approximation, were proved in [6] and [7]. In [8]a Voronovskaja-type result with quantitative estimate for complex Bernsteinpolynomials in compact disks was obtained.
This paper was written during the 2009 Spring Semester when the second author was a Vis-iting Professor at the Department of Mathematical Sciences, The University of Memphis,TN, U.S.A.∗Corresponding author.
472 G.A. Anastassiou and S.G. Gal Mediterr. J. Math.
In [9]-[11] similar results for Bernstein-Stancu and Kantorovich-Stancupolynomials were obtained while in [2] similar results for Bernstein-Schurerpolynomials were proved.
The goal of this paper is to obtain approximation results for the complexBernstein-Durrmeyer polynomials (introduced and studied in the case of realvariable in [3-5]) defined by
Dn(f)(z) = (n + 1)n∑
k=0
(n
k
)zk(1 − z)n−k
∫ 1
0
(n
k
)tk(1 − t)n−kf(t)dt, z ∈ C.
Note that all these results put in evidence the overconvergence phenomenonfor Bernstein-Durrmeyer polynomials, that is the extensions of approximationproperties (with quantitative estimates) from real intervals to compact disksin the complex plane.
2. Approximation by Complex Bernstein-DurrmeyerPolynomials
For our reasonings will be very useful the following well-known formula (seee.g. [1, p. 133])
Dn(ep)(z) =(n + 1)!
(n + 1 + p)!
min{n,p}∑k=0
(p
k
)p!k!
· n!(n − k)!
zk
=1(
n+1+pn+1
) ·min{n,p}∑
k=0
(p
k
)(n
k
)zk, (2.1)
for all p, n ∈ N⋃{0} and z ∈ C, where ep = zp.
Also, the following lemma holds.
Lemma 2.1. For all p, n ∈ N⋃{0} the inequality
1(n+1+p
n+1
) ·min{n,p}∑
k=0
(p
k
)(n
k
)=
n + 1n + 1 + p
≤ 1,
holds.
Proof. From the formula of definition we have for all n, p
Dn(ep)(1) = (n + 1)∫ 1
0tn+pdt =
n + 1n + 1 + p
≤ 1,
which combined with (2.1) written for z = 1 immediately implies the inequal-ity in the statement. �
The first main result is expressed by the following upper estimates.
Corollary 2.2. Let r ≥ 1.(i) For all p, n ∈ N
⋃{0} and |z| ≤ r we have |Dn(ep)(z)| ≤ rp.
Vol. 7 (2010) Complex Bernstein-Durrmeyer Polynomials 473
(ii) Let f(z) =∑∞
k=0 ckzk for all |z| < R and take 1 ≤ r < R. For all|z| ≤ r and n ∈ N we have
|Dn(f)(z) − f(z)| ≤ Mr(f)n
,
where Mr(f) = 2∑∞
p=1 |cp|p(p + 1)rp.
Proof. (i) By (2.1) and Lemma 2.1 we obtain
|Dn(ep)(z)|
≤ 1(n+1+p
n+1
) ·min{n,p}∑
k=0
(p
k
)(n
k
)rk ≤ rp 1(
n+1+pn+1
) ·min{n,p}∑
k=0
(p
k
)(n
k
)≤ rp,
which proves (i).(ii) First we prove that Dn(f)(z) =
∑∞k=0 ckDn(ek)(z), for all |z| ≤ r.
Indeed, denoting fm(z) =∑m
j=0 cjzj, |z| ≤ r, m ∈ N, since from the lin-
earity of Dn we obviously have Dn(fm)(z) =∑m
k=0 ckDn(ek)(z), it suf-fices to prove that for any fixed n ∈ N and |z| ≤ r with r ≥ 1, we havelimm→∞Dn(fm)(z) = Dn(f)(z). But this is immediate from limm→∞ ‖fm −f‖r = 0 (where ‖f‖r = max{|f(z)|; |z| ≤ r} ) and from the inequality
|Dn(fm)(z) − Dn(f)(z)|
≤ (n + 1)n∑
k=0
(n
k
)|zk(1 − z)n−k|
∫ 1
0
(n
k
)|tk(1 − t)n−k| · |fm(t) − f(t)|dt
≤n∑
k=0
(n
k
)|zk(1 − z)n−k| · ‖fm − f‖r ≤ Mr,n‖fm − f‖r,
valid for all |z| ≤ r.Therefore we get
|Dn(f)(z) − f(z)| ≤∞∑
p=0
|cp| · |Dn(ep)(z) − ep(z)|
=∞∑
p=1
|cp| · |Dn(ep)(z) − ep(z)|,
since Dn(e0) = e0.We have two cases : 1) 1 ≤ p ≤ n ; 2) p > n.Case 1). From (2.1) and Lemma 2.1 we obtain
Dn(ep)(z) − ep(z) = zp
( (np
)(n+1+p
n+1
) − 1
)+
1(n+1+p
n+1
) p−1∑j=0
(p
j
)(n
j
)zj,
474 G.A. Anastassiou and S.G. Gal Mediterr. J. Math.
and
|Dn(ep)(z) − ep(z)| ≤ rp
[1 −
(np
)(n+1+p
n+1
)]
+ rp
[n + 1
n + 1 + p−
(np
)(n+1+p
n+1
)]
≤ 2rp
[1 −
(np
)(n+1+p
n+1
)]
.
Here it is easy to see that we can write(np
)(n+1+p
n+1
) =
(np
)(n+1+p
p
) = Πpj=1
n − p + j
n + j + 1.
But applying the inequality (easily proved by mathematical induction)
1 − Πkj=1xj ≤
k∑j=1
(1 − xj), 0 ≤ xj ≤ 1, j = 1, ..., k,
for xj = n−p+jn+j+1 and k = p, we obtain
1 − Πpj=1
n − p + j
n + j + 1≤
p∑j=1
(1 − n − p + j
n + j + 1
)= (p + 1)
p∑j=1
1n + j + 1
≤ p(p + 1)n + 2
.
Therefore it follows
|Dn(ep)(z) − ep(z)| ≤ 2p(p + 1)rp
n + 2≤ 2p(p + 1)rp
n.
Case 2). By (i) and by p > n we obtain
|Dn(ep)(z) − ep(z)| ≤ |Dn(ep)(z)| + |ep(z)| ≤ 2rp <2p
nrp.
In conclusion, from both cases (i) and (ii) we obtain for all p, n ∈ N
|Dn(ep)(z) − ep(z)| ≤ 2p(p + 1)rp
n,
which implies
|Dn(f)(z) − f(z)| ≤ 2n
∞∑p=1
|cp|p(p + 1)rp
and proves the theorem. �
In what follows we look for a Voronovskaja type result with a quan-titative estimate. For this purpose first we need a recurrence formula forDn(ep)(z).
Lemma 2.3. For all p, n ∈ N⋃{0} and z ∈ C we have
Dn(ep+1)(z) =z(1 − z)n + p + 2
D′n(ep)(z) +nz + p + 1n + p + 2
Dn(ep)(z).
Vol. 7 (2010) Complex Bernstein-Durrmeyer Polynomials 475
Proof. By simple calculation we obtain
D′n(ep)(z) = (n + 1)n∑
k=0
(n
k
)kzk−1(1 − z)n−k
∫ 1
0
(n
k
)tk(1 − t)n−ktpdt
− (n + 1)n∑
k=0
(n
k
)(n − k)zk(1 − z)n−k−1
∫ 1
0
(n
k
)tk(1 − t)n−ktpdt
=1z
[(n + 1)
n∑k=0
(n
k
)zk(1 − z)n−k
∫ 1
0
(n
k
)ktk(1 − t)n−ktpdt
]
− n
1 − z· Dn(ep)(z) (2.2)
+1
1 − z(n + 1)
n∑k=0
(n
k
)zk(1 − z)n−k
∫ 1
0
(n
k
)ktk(1 − t)n−ktpdt
=1
z(1 − z)
[(n + 1)
n∑k=0
(n
k
)zk(1 − z)n−k
∫ 1
0
(n
k
)ktp+k(1 − t)n−kdt
]
− n
1 − zDn(ep)(z). (2.3)
Denoting the Euler’s Beta function B(p, q) =∫ 10 tp−1(1 − t)q−1dt it is
known that we have the formula (see e.g. [1, p. 132]) B(p, q) = (p−1)!(q−1)!(p+q−1)! .
This allows to immediately prove the relationship
(n+p+2)(
n
k
)B(p+k+2, n−k+1) = (p+1+k)
(n
k
)B(p+k+1, n−k+1),
which is equivalent to
(n+p+2)∫ 1
0
(n
k
)tp+1+k(1− t)n−kdt = (p+1+k)
∫ 1
0
(n
k
)tp+k(1− t)n−kdt,
and to∫ 1
0
(n
k
)ktp+k(1 − t)n−kdt = (n + p + 2)
∫ 1
0
(n
k
)tp+1+k(1 − t)n−kdt
− (p + 1)∫ 1
0
(n
k
)tp+k(1 − t)n−kdt.
Using this last formula in (2.2) we obtain
D′n(ep)(z)
=1
z(1 − z)(n + p + 2)Dn(ep+1)(z) − p + 1
z(1 − z)Dn(ep)(z) − n
1 − zDn(ep)(z),
which implies the recurrence in the statement. �
In the real case, the following Voronovskaja’s theorem is well-known
limn→∞
[Dn(f)(x) − f(x) − [x(1 − x)f ′(x)]′
n
]= 0
476 G.A. Anastassiou and S.G. Gal Mediterr. J. Math.
for all x ∈ [0, 1].In what follows we will prove the Voronovskaja theorem with a quanti-
tative estimate for the complex version of Bernstein-Durrmeyer polynomials,as follows.
Theorem 2.4. Let R > 1 and suppose that f : DR → C is analytic in DR ={z ∈ C; |z| < R}, that is we can write f(z) =
∑∞k=0 ckzk, for all z ∈ DR.
For any fixed r ∈ [1, R) and for all n ∈ N, |z| ≤ r, the following Voro-novskaja-type result holds∣∣∣∣Dn(f)(z) − f(z) − [z(1 − z)f ′(z)]′
n
∣∣∣∣ ≤ Mr(f)n2 ,
where Mr(f) =∑∞
k=1 |ck|kBk,rrk−1 < ∞ and
Bk,r = 2(k − 1)3 + r(4k3 + 6k2 + 6k + 2) + 2r2k(k2 + 1) + 4k(k − 1)2(1 + r).
Proof. Denoting ek(z) = zk, k = 0, 1, ..., and πk,n(z) = Dn(ek)(z), by theproof of Corollary 2.2, (ii) we can write Dn(f)(z) =
∑∞k=0 ckπk,n(z). Also,
since
[z(1 − z)f ′(z)]′
n=
(z(1 − z)
n
∞∑k=1
kckzk−1
)′=
( ∞∑k=1
kck
nzk(1 − z)
)′
=∞∑
k=1
kck
n[kzk−1(1 − z) − zk] =
∞∑k=1
ckkzk−1
n[k − (k + 1)z],
this immediately implies∣∣∣∣Dn(f)(z) − f(z) − [z(1 − z)f ′(z)]′
n
∣∣∣∣≤
∞∑k=1
|ck| ·∣∣∣∣πk,n(z) − ek(z) − kzk−1[k − (k + 1)z]
n
∣∣∣∣ ,for all z ∈ D1, n ∈ N.
In what follows, we will use the recurrence obtained in Lemma 2.3
πk+1,n(z) =z(1 − z)n + k + 2
π′k,n(z) +nz + k + 1n + k + 2
πk,n(z),
for all n ∈ N, z ∈ C and k = 0, 1, ....If we denote
Ek,n(z) = πk,n(z) − ek(z) − kzk−1[k − (k + 1)z]n
,
then it is clear that Ek,n(z) is a polynomial of degree ≤ k and by a sim-ple calculation and the use of the above recurrence we obtain the followingrelationship
Ek,n(z) =z(1 − z)n + k + 1
E′k−1,n(z) +nz + k
n + k + 1Ek−1,n(z) + Xk,n(z),
Vol. 7 (2010) Complex Bernstein-Durrmeyer Polynomials 477
where
Xk,n(z) =zk−2
n(n + k + 1){2(k− 1)3 + z[−4k3 +6k2− 6k+2]+ z2[2k(k2 +1)]},
for all k ≥ 1, n ∈ N and |z| ≤ r.We will use the estimate obtained in the proof of Corollary 2.2,
|πk,n(z) − ek(z)| ≤ 2k(k + 1)rk
n,
for all k, n ∈ N, |z| ≤ r, with 1 ≤ r.For all k, n ∈ N, k ≥ 1 and |z| ≤ r, it implies
|Ek,n(z)| ≤ r(1 + r)n + k + 1
|E′k−1,n(z)| + nr + k
n + k + 1|Ek−1,n(z)| + |Xk,n(z)|
Since r(1+r)n+k+1 ≤ r(1+r)
n and nr+kn+k+1 ≤ r it follows
|Ek,n(z)| ≤ r(1 + r)n
|E′k−1,n(z)| + r|Ek−1,n(z)| + |Xk,n(z)|.Now we will estimate |E′k−1,n(z)|, for k ≥ 1. Taking into account thatEk−1,n(z) is a polynomial of degree ≤ (k − 1), we obtain
|E′k−1,n(z)| ≤ k − 1r
‖Ek−1,n(z)‖r
≤ k − 1r
[‖πk−1,n − ek−1‖r +
∥∥∥∥ (k − 1)ek−2[k − 1 − ke1]n
∥∥∥∥r
]
≤ k − 1r
[2(k − 1)krk−1
n+
rk−2(r + 1)(k − 1)kn
]
≤ k(k − 1)2
n
[2rk−2 +
r + 1r
rk−2]≤ k(k − 1)2
n
[2rk−2 + 2rk−2]
=4k(k − 1)2rk−2
n.
This implies
r(1 + r)n
|E′k−1,n(z)| ≤ 4k(k − 1)2(1 + r)rk−1
n2 ,
and
|Ek,n(z)| ≤ r|Ek−1,n(z)| + 4k(k − 1)2(1 + r)rk−1
n2 + |Xk,n(z)|,where
|Xk,n(z)| ≤ rk−2
n2 {2(k − 1)3 + r(4k3 + 6k2 + 6k + 2) + 2r2k(k2 + 1)}
≤ rk−1
n2 Ak,r,
for all |z| ≤ r, k ≥ 1, n ∈ N, where
Ak,r = 2(k − 1)3 + r(4k3 + 6k2 + 6k + 2) + 2r2k(k2 + 1).
478 G.A. Anastassiou and S.G. Gal Mediterr. J. Math.
Denoting now
Bk,r = Ak,r + 4k(k − 1)2(1 + r),
we obtain
|Ek,n(z)| ≤ r|Ek−1,n(z)| + rk−1
n2 Bk,r,
for all |z| ≤ r, k ≥ 1, n ∈ N, where Bk,r is a polynomial of degree 3 in k.But E0,n(z) = 0, for any z ∈ C and therefore by writing the last in-
equality for k = 1, 2, ..., we easily obtain, step by step the following
|Ek,n(z)| ≤ rk−1
n2
⎡⎣ k∑
j=1
Bj,r
⎤⎦ ≤ krk−1
n2 Bk,r.
As a conclusion, we obtain∣∣∣∣Dn(f)(z) − f(z)− [z(1 − z)f ′(z)]′
n
∣∣∣∣ ≤∞∑
k=1
|ck| · |Ek,n(z)|
≤ 1n2
∞∑k=1
|ck|kBk,rrk−1.
Note that since f (4)(z) =∑∞
k=4 ckk(k − 1)(k − 2)(k − 3)zk−4, and theseries is absolutely convergent in |z| ≤ r, it easily follows that
∑∞k=4 |ck|k(k−
1)(k − 2)(k − 3)rk−4 < ∞, which implies that∑∞
k=1 |ck|kBk,rrk−1 < ∞ and
proves the theorem. �
Finally we will obtain the exact order in approximation by complexBernstein-Durrmeyer polynomials and their derivatives. In this sense wepresent the following results.
Theorem 2.5. Let R > 1, DR = {z ∈ C; |z| < R} and let us suppose thatf : DR → C is analytic in DR, that is we can write f(z) =
∑∞k=0 ckzk, for all
z ∈ DR. If f is not a polynomial of degree 0, then for any r ∈ [1, R) we have
‖Dn(f) − f‖r ≥ Cr(f)n
, n ∈ N,
where the constant Cr(f) depends only on f and r.
Proof. For all z ∈ DR and n ∈ N we have
Dn(f)(z) − f(z)
=1n
{[z(1 − z)f ′(z)]′ +
1n
[n2
(Dn(f)(z) − f(z) − [z(1 − z)f ′(z)]′
n
)]}.
In what follows we will apply to this identity the following obvious property:
‖F + G‖r ≥ | ‖F‖r − ‖G‖r | ≥ ‖F‖r − ‖G‖r.
Vol. 7 (2010) Complex Bernstein-Durrmeyer Polynomials 479
It follows
‖Dn(f) − f‖r
≥ 1n
{‖[e1(1 − e1)f ′]′‖r −
1n
[n2
∥∥∥∥Dn(f) − f − [e1(1 − e1)f ′]′
n
∥∥∥∥r
]}.
Taking into account that by hypothesis f is not a polynomial of degree 0 inDR, we get ‖[e1(1 − e1)f ′]′‖r > 0. Indeed, supposing the contrary it followsthat [z(1 − z)f ′(z)]′ = 0 for all z ∈ Dr, which implies z(1 − z)f ′(z) = C forall |z| ≤ r, that is f ′(z) = C
z(1−z) for all |z| ≤ r. But since f is analytic inDr we necessarily have C = 0, which implies f ′(z) = 0 and f(z) = c for allz ∈ Dr, a contradiction. But by Theorem 2.4 we have
n2∥∥∥∥Dn(f) − f − [e1(1 − e1)f ′]′
n
∥∥∥∥r
≤ Mr(f).
Therefore, there exists an index n0 depending only on f and r, such that forall n ≥ n0 we have
‖[e1(1 − e1)f ′]′‖r −1n
[n2
∥∥∥∥Dn(f) − f − [e1(1 − e1)f ′]′
n
∥∥∥∥r
]
≥ 12‖[e1(1 − e1)f ′]′‖r ,
which immediately implies
‖Dn(f) − f‖r ≥ 1n· 12‖[e1(1 − e1)f ′]′‖r , ∀n ≥ n0.
For n ∈ {1, ..., n0 − 1} we obviously have ‖Dn(f) − f‖r ≥ Mr,n(f)n with
Mr,n(f) = n · ‖Dn(f)− f‖r > 0. Indeed, if we would have ‖Dn(f)− f‖r = 0would follow Dn(f)(z) = f(z) for all |z| ≤ r, which is valid only for f aconstant function, contradicting the hypothesis on f .
Therefore, finally we get ‖Dn(f)−f‖r ≥ Cr(f)n for all n, where Cr(f) =
min{Mr,1(f), ..., Mr,n0−1(f), 12 ‖[e1(1 − e1)f ′]′‖r}, which ends the proof. �
Combining now Corollary 2.5 with Corollary 2.2 (ii) we immediately getthe following.
Corollary 2.6. Let R > 1, DR = {z ∈ C; |z| < R} and let us suppose thatf : DR → C is analytic in DR. If f is not a polynomial of degree 0, then forany r ∈ [1, R) we have
‖Dn(f) − f‖r ∼ 1n
, n ∈ N,
where the constants in the equivalence depend only on f and r.
For the derivatives of complex Bernstein-Durrmeyer polynomials we canstate the following result.
Theorem 2.7. Let DR = {z ∈ C; |z| < R} be with R > 1 and let us supposethat f : DR → C is analytic in DR, i.e. f(z) =
∑∞k=0 ckzk, for all z ∈ DR.
480 G.A. Anastassiou and S.G. Gal Mediterr. J. Math.
Also, let 1 ≤ r < r1 < R and p ∈ N be fixed. If f is not a polynomial ofdegree ≤ p − 1, then we have
‖D(p)n (f) − f (p)‖r ∼ 1
n,
where the constants in the equivalence depend only on f , r, r1 and p.
Proof. Denoting by Γ the circle of radius r1 and center 0 (where r1 > r ≥ 1),by the Cauchy’s formulas it follows that for all |z| ≤ r and n ∈ N we have
D(p)n (f)(z) − f (p)(z) =
p!2πi
∫Γ
Dn(f)(v) − f(v)(v − z)p+1 dv,
which by Corollary 2.2 (ii) and by the inequality |v − z| ≥ r1 − r valid for all|z| ≤ r and v ∈ Γ, immediately implies
‖D(p)n (f) − f (p)‖r ≤ p!
2π· 2πr1
(r1 − r)p+1 ‖Dn(f) − f‖r1 ≤ Mr1(f)p!r1
n(r1 − r)p+1 .
It remains to prove the lower estimate for ‖D(p)n (f) − f (p)‖r.
For this purpose, as in the proof of Theorem 2.5, for all v ∈ Γ and n ∈ N
we have
Dn(f)(v) − f(v)
=1n
{[v(1 − v)f ′(v)]′ +
1n
[n2
(Dn(f)(v) − f(v) − [v(1 − v)f ′(v)]′
n
)]},
which replaced in the above Cauchy’s formula implies
D(p)n (f)(z) − f (p)(z) =
1n
{[z(1 − z)f ′(z)](p+1)
+1n· p!2πi
∫Γ
n2(Dn(f)(v) − f(v) − [v(1−v)f ′(v)]′
n
)(v − z)p+1 dv
}
=1n
{[z(1 − z)f ′(z)](p+1)
+1n· p!2πi
∫Γ
n2(Dn(f)(v) − f(v) − [v(1−v)f ′(v)]′
n
)(v − z)p+1 dv
}.
Passing now to ‖ · ‖r it follows
‖D(p)n (f) − f (p)‖r ≥ 1
n
{∥∥∥[e1(1 − e1)f ′](p+1)
∥∥∥r
− 1n
∥∥∥∥∥∥p!2π
∫Γ
n2(Dn(f)(v) − f(v) − [v(1−v)f ′(v)]′
n
)(v − z)p+1 dv
∥∥∥∥∥∥r
},
Vol. 7 (2010) Complex Bernstein-Durrmeyer Polynomials 481
where by using Theorem 2.4 we get∥∥∥∥∥∥p!2π
∫Γ
n2(Dn(f)(v) − f(v) − [v(1−v)f ′(v)]′
n
)(v − z)p+1 dv
∥∥∥∥∥∥r
≤ p!2π
· 2πr1n2
(r1 − r)p+1
∥∥∥∥Dn(f) − f − [e1(1 − e1)f ′]′
n
∥∥∥∥r1
≤ Mr1(f)p!r1
(r1 − r)p+1 .
But by hypothesis on f we have∥∥∥[e1(1 − e1)f ′]
(p+1)∥∥∥
r> 0.
Indeed, supposing the contrary it follows that z(1 − z)f ′(z) is a poly-nomial of degree ≤ p. For p = 1 we get z(1 − z)f ′(z) = Az + B, whichimplies f ′(z) = Az+B
z(1−z) . Because f ′(z) is analytic function, it necessarily fol-lows A = B = 0, that is f ′(z) = 0, for all |z| ≤ r and therefore f is apolynomial of degree 0, contradicting the hypothesis. If p ≥ 2, then from theidentity z(1 − z)f ′(z) = Qp(z) for all |z| ≤ r (where Qp(z) is a polynomialof degree ≤ p in z), it easily follows that f ′(z) is a polynomial of degree≤ p − 2, that is f(z) is a polynomial of degree ≤ p − 1, contradicting againthe hypothesis.
In continuation, taking also into account that because f is not a poly-nomial of degree ≤ p− 1 we have ‖[Dn(f)− f ](p)‖r > 0, reasoning exactly asin the proof of Theorem 2.5, we easily get the desired conclusion. �
References
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[9] S. G. Gal, Approximation by complex Bernstein-Kantorovich and Stancu-Kantorovich polynomials and their iterates in compact disks, Rev. Anal. Numer.Theor. Approx. (Cluj), 37(2008), No. 2, 159-168.
482 G.A. Anastassiou and S.G. Gal Mediterr. J. Math.
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Acknowledgment
The authors thank the referee for the useful remarks.
George A. AnastassiouDepartment of Mathematical SciencesThe University of MemphisMemphis, TN 38152, U.S.A.e-mail: [email protected]
Sorin G. GalDepartment of Mathematics and Computer ScienceUniversity of OradeaStr. Armatei Romane 5410087 Oradea, Romaniae-mail: [email protected]
Received: June 5, 2009.Revised: October 26, 2009.Accepted: November 9, 2009.