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RING DESIGN - SACSAnalysis: InplaceJoint No: 1561-1565
86.4cm BRACE
6.5 cm
45.0 cm
182.9 cmCHORD
0.0 cm
3.0 cm 0.0 cm
A) PROPERTIES DATA
Chord Outer Diameter (OD) = 182.9 cm @ 72.01 inchChord Wall Thickness (WT) = 6.5 cm @ 2.56 inchBrace Outer Diameter (OD) = 86.4 cm @ 34.02 inchBrace Wall Thickness (WT) = 2.5 cm @ 0.98 inch
Chord Effective Diameter = 1.1*(D*t)^0.5= 37.93 cm @ 14.932
Ring Stiffener Depth = 45.0 cm @ 17.72 inchRing Stiffener Thickness = 3.0 cm @ 1.18 inch
Flange Thickness= 0.0 @ 0.00 inchFlange Height= 0.0 @ 0.00 inch
No of ring required = 2Yield Strength, Fy = 345 Mpa @ 50.04 ksi
Young's Modulus, E = 200 Gpa @ 29.01 kksiPoisson Ratio = 0.3
B) REACTION FORCES
Axial Force, Fx = -5987.4 kNMoment, Mz = -11.80 kNm Moment, My = -126.90 kNm
Lever arm, L1 = 64.4 cm Ring distance, L2 = 54.6 cmForce from Moment = 9.2 kN Force from Moment = -232.4176 kN
MyBrace
MzBrace
Lever armLever arm Ring
Flange
Ring
Section A-A Section I-I
x
z
Reaction Force
x
y
I
I
A
A
x
z
Since 2 nos of ring required, Fx need to be distributed equally
Thus, Fx = -2993.7 kN
3 cases to be considered for ring design Case 8 , Case 18 and Case 16
Case 18 Point Load, F = -2993.68 kN
Moment = -126.90 kNmForce, Ft = Moment
Ring distance, L2
= -232.42 kNTotal Force, W1 = 3226.10 kN @ 725.23 kips
Case 8 Uniform Load,w =
= 24.21 kN/cm @ 13.82 kips/inch
Alpha, = 46.77 degree
Theta, = 133.23 degree
Case 16
Moment = -11.80 kNmTotal Force,W2 = Moment
Lever arm, L1= 9.16 kN @ 2.06 kips
For case 16,Theta, = 133.23 degreePhi, = -133.23 degree
W1 = 3226.10 kN w = 24.21 kN/cm W2 = 9.16 kN
Initially, the jacket leg has been checked without ring stiffener. The result is as follow;
Allowable Ring Stress = 0.66 x Fy= 228 Mpa
Based on the ring stiffener analysis of the jacket leg by considering the ring stiffener, the result is as follow;
Maximum Outer Fibre Stress = -7.88 ksi @ 54.33 MpaMaximum Inner Fibre Stress = 26 ksi @ 179.26 Mpa
Stress Interaction Ratio = Actual Stress / Allowable Stress= 0.787 < 1, ==>> OK!
W1/(2*R*sin )
+
=
CASE-18
w
2 w R sin
CASE-8
w
W1
+
W2
CASE-16
+
W2 W2
W2
RING DESIGN - SACSAnalysis: InplaceJoint No: 1563-1565
86.4cm BRACE
6.5 cm
45.0 cm
182.9 cmCHORD
0.0 cm
3.0 cm 0.0 cm
A) PROPERTIES DATA
Chord Outer Diameter (OD) = 182.9 cm @ 72.01 inchChord Wall Thickness (WT) = 6.5 cm @ 2.56 inchBrace Outer Diameter (OD) = 86.4 cm @ 34.02 inchBrace Wall Thickness (WT) = 2.5 cm @ 0.98 inch
Chord Effective Diameter = 1.1*(D*t)^0.5= 37.93 cm @ 14.932
Ring Stiffener Depth = 45.0 cm @ 17.72 inchRing Stiffener Thickness = 3.0 cm @ 1.18 inch
Flange Thickness= 0.0 @ 0.00 inchFlange Height= 0.0 @ 0.00 inch
No of ring required = 2Yield Strength, Fy = 345 Mpa @ 50.04 ksi
Young's Modulus, E = 200 Gpa @ 29.01 kksiPoisson Ratio = 0.3
B) REACTION FORCES
Axial Force, Fx = -5683.7 kNMoment, Mz = 2.28 kNm Moment, My = -91.85 kNm
Lever arm, L1 = 64.4 cm Ring distance, L2 = 54.6 cmForce from Moment = 1.8 kN Force from Moment = -168.2234 kN
MyBrace
MzBrace
Lever armLever arm Ring
Flange
Ring
Section A-A Section I-I
x
z
Reaction Force
x
y
I
I
A
A
x
z
Since 2 nos of ring required, Fx need to be distributed equally
Thus, Fx = -2841.9 kN
3 cases to be considered for ring design Case 8 , Case 18 and Case 16
Case 18 Point Load, F = -2841.87 kN
Moment = -91.85 kNmForce, Ft = Moment
Ring distance, L2
= -168.22 kNTotal Force, W1 = 3010.09 kN @ 676.67 kips
Case 8 Uniform Load,w =
= 22.59 kN/cm @ 12.90 kips/inch
Alpha, = 46.77 degree
Theta, = 133.23 degree
Case 16
Moment = 2.28 kNmTotal Force,W2 = Moment
Lever arm, L1= 1.77 kN @ 0.40 kips
For case 16,Theta, = 133.23 degreePhi, = -133.23 degree
W1 = 3010.09 kN w = 22.59 kN/cm W2 = 1.77 kN
Initially, the jacket leg has been checked without ring stiffener. The result is as follow;
Allowable Ring Stress = 0.66 x Fy= 228 Mpa
Based on the ring stiffener analysis of the jacket leg by considering the ring stiffener, the result is as follow;
Maximum Outer Fibre Stress = -7.35 ksi @ 50.68 MpaMaximum Inner Fibre Stress = 24.25 ksi @ 167.20 Mpa
Stress Interaction Ratio = Actual Stress / Allowable Stress= 0.734 < 1, ==>> OK!
W1/(2*R*sin )
+
=
CASE-18
w
2 w R sin
CASE-8
w
W1
+
W2
CASE-16
+
W2 W2
W2
RING DESIGN (1561-1565-F)RING DESIGN (1563-1565-F)