Embed Size (px)
Citation preview
Co
pyrig
ht © G
lencoe/M
cGraw
-Hill, a d
ivision o
f The M
cGraw
-Hill C
om
panies, Inc.
Chapter 2 A2 Glencoe Algebra 1
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Stud
y G
uide
and
Inte
rven
tion
(co
nti
nu
ed)
Wri
tin
g E
qu
ati
on
s
2-1
Cha
pte
r 2
6 G
lenc
oe A
lgeb
ra 1
Wri
te V
erb
al S
ente
nce
s Yo
u c
an t
ran
slat
e eq
uat
ion
s in
to v
erba
l se
nte
nce
s.
T
ran
slat
e ea
ch e
qu
atio
n i
nto
a s
ente
nce
.
a. 4
n -
8 =
12.
4n
-
8
=
1
2F
our
tim
es n
min
us
eigh
t eq
ual
s tw
elve
.
b.
a2
+ b
2 =
c2
a
2 +
b2
=
c2
Th
e su
m o
f th
e sq
uar
es o
f a
and
b is
equ
al t
o th
e sq
uar
e of
c.
Exer
cise
sT
ran
slat
e ea
ch e
qu
atio
n i
nto
a s
ente
nce
.
1. 4
a -
5 =
23
2. 1
0 +
k =
4k
3. 6
xy =
24
4. x
2 +
y2
= 8
5. p
+ 3
= 2
p 6.
b =
1 −
3 (
h -
1)
7. 1
00 -
2x
= 8
0 8.
3(g
+ h
) =
12
9. p
2 -
2p
= 9
10
. C =
5
−
9 (
F -
32)
11. V
= 1
−
3
Bh
12
. A
= 1
−
2
hb
Exam
ple
4
tim
es a
min
us
5 is
eq
ual
to
23.
T
he
sum
of
10 a
nd
k is
eq
ual
to
4
tim
es k
.
6
tim
es t
he
pro
du
ct o
f x a
nd
y is
Th
e su
m o
f th
e sq
uar
es o
f x a
nd
eq
ual
to
24.
y is
eq
ual
to
8.
T
he
sum
of
p a
nd
3 is
eq
ual
to
b
is 1 −
3 o
f th
e d
iffer
ence
of
h a
nd
1.
2 ti
mes
p.
1
00
min
us
2 ti
mes
x is
eq
ual
3
tim
es t
he
sum
of
g a
nd
h is
12.
to
80.
T
he
squ
are
of
p m
inu
s 2
tim
es
C is
eq
ual
to
5 −
9 o
f th
e d
iffer
ence
of
p
is e
qu
al t
o 9
.
F a
nd
32.
V
is e
qu
al t
o 1 −
3 o
f th
e p
rod
uct
of
A
is e
qu
al t
o 1 −
2 o
f th
e p
rod
uct
of
B
an
d h
. h
an
d b
.
001_
012_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
612
/22/
10
12:1
8 P
M
Lesson 2-1
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Skill
s Pr
acti
ceW
riti
ng
Eq
uati
on
s
2-1
Cha
pte
r 2
7 G
lenc
oe A
lgeb
ra 1
Tra
nsl
ate
each
sen
ten
ce i
nto
an
eq
uat
ion
.
1. T
wo
adde
d to
th
ree
tim
es a
nu
mbe
r m
is
the
sam
e as
18.
2. T
wic
e a
incr
ease
d by
th
e cu
be o
f a
equ
als
b.
3. S
even
les
s th
an t
he
sum
of
p an
d t
is a
s m
uch
as
6.
4. T
he
sum
of
x an
d it
s sq
uar
e is
equ
al t
o y
tim
es z
.
5. F
our
tim
es t
he
sum
of
f an
d g
is i
den
tica
l to
six
tim
es g
.
Tra
nsl
ate
each
sen
ten
ce i
nto
a f
orm
ula
.
6. T
he
peri
met
er P
of
a sq
uar
e eq
ual
s fo
ur
tim
es t
he
len
gth
of
a si
de �
.
7. T
he
area
A o
f a
squ
are
is t
he
len
gth
of
a si
de �
squ
ared
.
8. T
he
peri
met
er P
of
a tr
ian
gle
is e
qual
to
the
sum
of
the
len
gth
s of
sid
es a
, b, a
nd
c.
9. T
he
area
A o
f a
circ
le i
s pi
tim
es t
he
radi
us
r sq
uar
ed.
10. T
he
volu
me
V o
f a
rect
angu
lar
pris
m e
qual
s th
e pr
odu
ct o
f th
e le
ngt
h �
, th
e w
idth
w,
and
the
hei
ght
h.
Tra
nsl
ate
each
eq
uat
ion
in
to a
sen
ten
ce.
11. g
+ 1
0 =
3g
12. 2
p +
4t
= 2
0
13. 4
(a +
b)
= 9
a 14
. 8 -
6x
= 4
+ 2
x
15.
1 −
2 (f
+ y
) =
f -
5
16. k
2 -
n2
= 2
b
Wri
te a
pro
ble
m b
ased
on
th
e gi
ven
in
form
atio
n.
17. c
= c
ost
per
pou
nd
of p
lain
cof
fee
bean
s
18.
p =
cos
t of
din
ner
c
+ 3
= c
ost
per
pou
nd
of f
lavo
red
coff
ee b
ean
s
0.15
p =
cos
t of
a 1
5% t
ip
2c
+ (
c +
3)
= 2
1
p +
0.1
5p =
23
3m +
2 =
18
2a +
a3
= b
(p +
t)
- 7
= 6
x +
x2
= y
z
4(f
+ g
) =
6g
P =
4�
A =
�2
P =
a +
b +
c
A =
πr
2
V =
�w
h
g
plu
s 10
is t
he
sam
e as
Tw
ice
p p
lus
4 ti
mes
t is
20.
3
tim
es g
.
4
tim
es t
he
sum
of
a a
nd
b
8 m
inu
s 6
tim
es x
is 4
plu
s
is 9
tim
es a
.
2 ti
mes
x.
H
alf
of
the
sum
of
f an
d y
is
k s
qu
ared
min
us
n s
qu
ared
is
f m
inu
s 5.
twic
e b
.
S
amp
le a
nsw
er: T
he
cost
of
two
po
un
ds
S
amp
le a
nsw
er: T
he
cost
of
of
pla
in c
off
ee b
ean
s p
lus
on
e p
ou
nd
of
din
ner
plu
s a
15%
tip
was
fl
avo
red
bea
ns
is $
21. H
ow
mu
ch d
oes
$2
3. H
ow
mu
ch w
as t
he
1 p
ou
nd
of
pla
in b
ean
s co
st?
d
inn
er?
001_
012_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
712
/22/
10
12:1
8 P
M
Answers (Lesson 2-1)
A01_A14_ALG1_A_CRM_C02_AN_661315.indd A2 12/22/10 1:07 PM
An
swer
s
Co
pyr
ight
© G
lenc
oe/
McG
raw
-Hill
, a d
ivis
ion
of
The
McG
raw
-Hill
Co
mp
anie
s, In
c.
Chapter 2 A3 Glencoe Algebra 1
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Prac
tice
W
riti
ng
Eq
uati
on
s
2-1
Cha
pte
r 2
8
Gle
ncoe
Alg
ebra
1
Tra
nsl
ate
each
sen
ten
ce i
nto
an
eq
uat
ion
.
1. F
ifty
-th
ree
plu
s fo
ur
tim
es b
is
as m
uch
as
21.
2. T
he
sum
of
five
tim
es h
an
d tw
ice
g is
equ
al t
o 23
.
3. O
ne
fou
rth
th
e su
m o
f r
and
ten
is
iden
tica
l to
r m
inu
s 4.
4. T
hre
e pl
us
the
sum
of
the
squ
ares
of
w a
nd
x is
32.
Tra
nsl
ate
each
sen
ten
ce i
nto
a f
orm
ula
.
5. D
egre
es K
elvi
n K
equ
als
273
plu
s de
gree
s C
elsi
us
C.
6. T
he
tota
l co
st C
of
gas
is t
he
pric
e p
per
gall
on t
imes
th
e n
um
ber
of g
allo
ns
g.
7. T
he
sum
S o
f th
e m
easu
res
of t
he
angl
es o
f a
poly
gon
is
equ
al t
o 18
0 ti
mes
th
e di
ffer
ence
of
th
e n
um
ber
of s
ides
n a
nd
2.
Tra
nsl
ate
each
eq
uat
ion
in
to a
sen
ten
ce.
8. r
- (
4 +
p)
= 1 −
3 r
9.
3 −
5 t
+ 2
= t
10. 9
(y2
+ x
) =
18
11.
2(m
- n
) =
x +
7
Wri
te a
pro
ble
m b
ased
on
th
e gi
ven
in
form
atio
n.
12. a
= c
ost
of o
ne
adu
lt’s
tic
ket
to z
oo
13. c
= r
egu
lar
cost
of
one
airl
ine
tick
eta
- 4
= c
ost
of o
ne
chil
dren
’s t
icke
t to
zoo
0
.20c
= a
mou
nt o
f 20%
pro
mot
iona
l dis
coun
t
2a
+ 4
(a -
4)
= 3
8
3(c
- 0
.20c
) =
330
14. G
EOG
RA
PHY
Abo
ut
15%
of
all
fede
rall
y-ow
ned
lan
d in
th
e 48
con
tigu
ous
stat
es o
f th
e U
nit
ed S
tate
s is
in
Nev
ada.
If
F r
epre
sen
ts t
he
area
of
fede
rall
y-ow
ned
lan
d in
th
ese
stat
es, a
nd
N r
epre
sen
ts t
he
port
ion
in
Nev
ada,
wri
te a
n e
quat
ion
for
th
is s
itu
atio
n.
15. F
ITN
ESS
Dea
nn
a an
d P
ietr
a ea
ch g
o fo
r w
alks
aro
un
d a
lake
a f
ew t
imes
per
wee
k. L
ast
wee
k, D
ean
na
wal
ked
7 m
iles
mor
e th
an P
ietr
a.
a.
If
p re
pres
ents
th
e n
um
ber
of m
iles
Pie
tra
wal
ked,
wri
te a
n e
quat
ion
th
at r
epre
sen
ts
the
tota
l n
um
ber
of m
iles
T t
he
two
girl
s w
alke
d.
b
. If
Pie
tra
wal
ked
9 m
iles
du
rin
g th
e w
eek,
how
man
y m
iles
did
Dea
nn
a w
alk?
c.
If
Pie
tra
wal
ked
11 m
iles
du
rin
g th
e w
eek,
how
man
y m
iles
did
th
e tw
o gi
rls
wal
k to
geth
er?
53 +
4b
= 2
1
5h
+ 2
g =
23
3 +
(w
2 +
x2)
= 3
2
K =
273 +
C
C =
pg
S =
180(n
- 2
)
r m
inu
s t
he s
um
o
f 4 a
nd
p e
qu
als
1
−
3 t
imes r
. Tw
o m
ore
th
an
3
−
5 o
f t
eq
uals
t.
9 t
imes t
he s
um
Tw
ice t
he q
uan
tity
o
f y s
qu
are
d a
nd
x i
s 1
8.
m m
inu
s n
is x
plu
s 7
.
S
am
ple
an
sw
er:
Th
e c
ost
of
two
S
am
ple
an
sw
er:
Th
e c
ost
of
thre
e
ad
ult
’s t
ickets
an
d 4
ch
ild
ren
’s
air
lin
e t
ickets
th
at
are
dis
co
un
ted
ti
ckets
to
th
e z
oo
is $
38. H
ow
20%
is $
330. W
hat
is t
he r
eg
ula
r m
uch
is a
n a
du
lt’s
tic
ket?
co
st
of
a t
icket?
0.1
5F =
N
T =
p +
(p
+ 7
)
16 m
i
29 m
i
1
−
4 (r
+ 1
0)
= r
- 4
001_
012_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
812
/22/
10
12:1
8 P
M
Lesson 2-1
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Wor
d Pr
oble
m P
ract
ice
Wri
tin
g E
qu
ati
on
s
2-1
Cha
pte
r 2
9
Gle
ncoe
Alg
ebra
1
1.H
OU
SES
Th
e ar
ea o
f th
e H
arts
tein
’s
kitc
hen
is
182
squ
are
feet
. Th
is i
s 20
% o
f th
e ar
ea o
f th
e fi
rst
floo
r of
th
eir
hou
se.
Let
F r
epre
sen
t th
e ar
ea o
f th
e fi
rst
floo
r. W
rite
an
equ
atio
n t
o re
pres
ent
the
situ
atio
n.
2. F
AM
ILY
Kat
ie i
s tw
ice
as o
ld a
s h
er
sist
er M
ara.
Th
e su
m o
f th
eir
ages
is
24.
Wri
te a
on
e-va
riab
le e
quat
ion
to
repr
esen
t th
e si
tuat
ion
.
3. G
EOM
ETRY
Th
e fo
rmu
la F
+ V
=
E +
2 s
how
s th
e re
lati
onsh
ip b
etw
een
th
e n
um
ber
of f
aces
F, e
dges
E, a
nd
vert
ices
V o
f a
poly
hed
ron
, su
ch a
s a
pyra
mid
. Wri
te t
he
form
ula
in
wor
ds.
Face
Verte
xEd
ge
4. W
IREL
ESS
PHO
NE
Spi
nfr
og w
irel
ess
phon
e co
mpa
ny
bill
s on
a m
onth
ly b
asis
. E
ach
bil
l in
clu
des
a $2
9.95
ser
vice
fee
for
10
00 m
inu
tes
plu
s a
$2.9
5 fe
dera
l co
mm
un
icat
ion
tax
. Add
itio
nal
ly, t
her
e is
a
char
ge o
f $0
.05
for
each
min
ute
use
d ov
er 1
000.
Let
m r
epre
sen
t th
e n
um
ber
of m
inu
tes
over
100
0 u
sed
duri
ng
the
mon
th. W
rite
an
equ
atio
n t
o de
scri
be t
he
cost
p o
f th
e w
irel
ess
phon
e se
rvic
e pe
r m
onth
.
5. T
EMPE
RA
TUR
E T
he
tabl
e be
low
sh
ows
the
tem
pera
ture
in
Fah
ren
hei
t fo
r so
me
corr
espo
ndi
ng
tem
pera
ture
s in
Cel
siu
s.
Ce
lsiu
sF
ah
ren
he
it
-2
0°
-4
°
-10
°14
°
0°
32
°
10
°5
0°
20
°6
8°
30
°8
6°
a. W
rite
a f
orm
ula
for
con
vert
ing
Cel
siu
s te
mpe
ratu
res
to F
ahre
nh
eit
tem
pera
ture
s.
b
. F
ind
the
Fah
ren
hei
t eq
uiv
alen
ts f
or
25ºC
an
d 35
ºC.
182 =
0.2
F
m
+ 2
m =
24 o
r 3
m =
24
T
he s
um
of
the n
um
ber
of
faces
an
d n
um
ber
of
vert
ices i
s e
qu
al
to
the s
um
of
two
an
d t
he n
um
ber
of
ed
ges.
p
= 3
2.9
0 +
0.0
5m
F =
1.8
C +
32 7
7ºF
an
d
95ºF
001_
012_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
912
/22/
10
12:1
8 P
M
Answers (Lesson 2-1)
A01_A14_ALG1_A_CRM_C02_AN_661315.indd A3 12/22/10 1:07 PM
An
swer
s
Co
pyr
ight
© G
lenc
oe/
McG
raw
-Hill
, a d
ivis
ion
of
The
McG
raw
-Hill
Co
mp
anie
s, In
c.
Chapter 2 A5 Glencoe Algebra 1
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Stud
y G
uide
and
Inte
rven
tion
(co
nti
nu
ed)
So
lvin
g O
ne-S
tep
Eq
uati
on
s
2-2
Cha
pte
r 2
12
Gle
ncoe
Alg
ebra
1
Solv
e Eq
uat
ion
s U
sin
g M
ult
iplic
atio
n a
nd
Div
isio
n I
f ea
ch s
ide
of a
n e
quat
ion
is
mu
ltip
lied
by
the
sam
e n
um
ber,
the
resu
ltin
g eq
uat
ion
is
equ
ival
ent
to t
he
give
n o
ne.
You
ca
n u
se t
he
prop
erty
to
solv
e eq
uat
ion
s in
volv
ing
mu
ltip
lica
tion
an
d di
visi
on. T
o so
lve
equ
atio
ns
wit
h m
ult
ipli
cati
on a
nd
divi
sion
, you
can
als
o u
se t
he
Div
isio
n P
rope
rty
of
Equ
alit
y. I
f ea
ch s
ide
of a
n e
quat
ion
is
divi
ded
by t
he
sam
e n
um
ber,
the
resu
ltin
g eq
uat
ion
is
tru
e.
Mu
ltip
licat
ion
Pro
per
ty o
f E
qu
alit
yF
or a
ny n
umbe
rs a
, b
, an
d c,
if a
= b
, th
en a
c =
bc.
Div
isio
n P
rop
erty
of
Eq
ual
ity
For
any
num
bers
a,
b,
and
c, w
ith c
≠ 0
, if
a =
b,
then
a −
c =
b
−
c .
S
olve
3 1 −
2 p
= 1
1 −
2 .
3
1 −
2 p
= 1
1 −
2
Orig
inal
equ
atio
n
7 −
2 p
= 3 −
2
2 −
7 ( 7
−
2 p) =
2 −
7 ( 3
−
2 ) M
ultip
ly e
ach
side
by
2 −
7 .
p
= 3 −
7
Sim
plify
.
Th
e so
luti
on i
s 3 −
7 .
S
olve
-5n
= 6
0.
-
5n =
60
Orig
inal
equ
atio
n
-5n
−
-5
= 6
0 −
-
5 D
ivid
e ea
ch s
ide
by -
5.
n
= -
12
Sim
plify
.
Th
e so
luti
on i
s -
12.
Exer
cise
sS
olve
eac
h e
qu
atio
n. C
hec
k y
our
solu
tion
.
1.
h
−
3 = -
2
2. 1 −
8 m
= 6
3.
1 −
5 p
= 3 −
5
4. 5
=
y −
12
5.
- 1 −
4 k
= -
2.5
6.
- m
−
8 =
5 −
8
7. -
1 1 −
2 h
= 4
8.
-12
= -
3 −
2 k
9.
j −
3 = 2 −
5
10. -
3 1 −
3 b
= 5
11
. 7 −
10
m =
10
12
. p −
5 =
- 1 −
4
13. 3
h =
-42
14
. 8m
= 1
6
15. -
3t =
51
16. -
3r =
-24
17
. 8k
= -
64
18. -
2m =
16
19. 1
2h =
4
20. -
2.4p
= 7
.2
21. 0
.5j
= 5
22. -
25 =
5m
23
. 6m
= 1
5
24. -
1.5p
= -
75
Exam
ple
2Ex
amp
le 1
Rew
rite
each
mix
ed n
umbe
r as
an
impr
oper
fra
ctio
n.
-6
483
6010
-
5
-8
−
3 8
1 1 −
5
-1
1 −
2
14 2 −
7
-1
1 −
4
-14 8
1 −
3 -
5
2 -8
-17 -8
-3
10
502
1 −
2
001_
012_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
1212
/22/
10
12:1
8 P
M
Lesson 2-2
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
2-2
Skill
s Pr
acti
ceS
olv
ing
On
e-S
tep
Eq
uati
on
s
Cha
pte
r 2
13
Gle
ncoe
Alg
ebra
1
Sol
ve e
ach
eq
uat
ion
. Ch
eck
you
r so
luti
on.
1. y
- 7
= 8
2.
w +
14
= -
8
3. p
- 4
= 6
4.
-13
= 5
+ x
5. 9
8 =
b +
34
6.
y -
32
= -
1
7. n
+ (
-28
) =
0
8. y
+ (
-10
) =
6
9. -
1 =
t +
(-
19)
10
. j -
(-
17)
= 3
6
11. 1
4 =
d +
(-
10)
12
. u +
(-
5) =
-15
13. 1
1 =
-16
+ y
14
. c -
(-
3) =
100
15. 4
7 =
w -
(-
8)
16. x
- (
-74
) =
-22
17. 4
- (
-h
) =
68
18
. -56
= 2
0 -
(-
j)
19. 1
2z =
108
20
. -7t
= 4
9
21. 1
8f =
-21
6
22. -
22 =
11v
23. -
6d =
-42
24
. 96
= -
24a
25.
c −
4 =
16
26
. a −
16
= 9
27. -
84 =
d
−
3 28
. - d
−
7 =
-13
29.
t −
4 = -
13
30. 3
1 =
- 1 −
6 n
31. -
6 =
2 −
3 z
32
. 2 −
7 q
= -
4
33.
5 −
9 p
= -
10
34.
a −
10 =
2 −
5
15 10
64
28
18 24
27 39 64
9 -12
-22
-18
31 16 19 -10
97
-96 -76
-7 -
2
7-
4
6414
4
-25
291
-52
-18
6
-9
-14
-18
4
013_
022_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
1312
/22/
10
12:1
8 P
M
Answers (Lesson 2-2)
A01_A14_ALG1_A_CRM_C02_AN_661315.indd A5 12/22/10 1:07 PM
Co
pyrig
ht © G
lencoe/M
cGraw
-Hill, a d
ivision o
f The M
cGraw
-Hill C
om
panies, Inc.
Chapter 2 A6 Glencoe Algebra 1
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Prac
tice
So
lvin
g O
ne-S
tep
Eq
uati
on
s
2-2
Cha
pte
r 2
14
Gle
ncoe
Alg
ebra
1
Sol
ve e
ach
eq
uat
ion
. Ch
eck
you
r so
luti
on.
1. d
- 8
= 1
7
2. v
+ 1
2 =
-5
3.
b -
2 =
-11
4. -
16 =
m +
71
5.
29
= a
- 7
6
6. -
14 +
y =
-2
7. 8
- (
-n
) =
1
8. 7
8 +
r =
-15
9.
f +
(-
3) =
-9
10. 8
j =
96
11
. -13
z =
-39
12
. -18
0 =
15m
13. 2
43 =
27r
14
. y −
9 =
-8
15
. - j −
12
= -
8
16.
a −
15 =
4 −
5
17.
g −
27
= 2 −
9
18.
q −
24
= 1 −
6
Wri
te a
n e
qu
atio
n f
or e
ach
sen
ten
ce. T
hen
sol
ve t
he
equ
atio
n.
19. N
egat
ive
nin
e ti
mes
a n
um
ber
equ
als
-11
7.
20. N
egat
ive
one
eigh
th o
f a
nu
mbe
r is
- 3 −
4 .
21. F
ive
sixt
hs
of a
nu
mbe
r is
- 5 −
9 .
22. 2
.7 t
imes
a n
um
ber
equ
als
8.37
.
23. H
UR
RIC
AN
ES T
he
day
afte
r a
hu
rric
ane,
th
e ba
rom
etri
c pr
essu
re i
n a
coa
stal
tow
n h
as
rise
n t
o 29
.7 i
nch
es o
f m
ercu
ry, w
hic
h i
s 2.
9 in
ches
of
mer
cury
hig
her
th
an t
he
pres
sure
w
hen
th
e ey
e of
th
e h
urr
ican
e pa
ssed
ove
r.
a.
Wri
te a
n a
ddit
ion
equ
atio
n t
o re
pres
ent
the
situ
atio
n.
b
. Wh
at w
as t
he
baro
met
ric
pres
sure
wh
en t
he
eye
pass
ed o
ver?
24. R
OLL
ER C
OA
STER
S K
ingd
a K
a in
New
Jer
sey
is t
he
tall
est
and
fast
est
roll
er c
oast
er i
n
the
wor
ld. R
ider
s tr
avel
at
an a
vera
ge s
peed
of
61 f
eet
per
seco
nd
for
3118
fee
t. T
hey
re
ach
a m
axim
um
spe
ed o
f 18
7 fe
et p
er s
econ
d.
a.
If
x re
pres
ents
th
e to
tal
tim
e th
at t
he
roll
er c
oast
er i
s in
mot
ion
for
eac
h r
ide,
w
rite
an
exp
ress
ion
to
repr
esen
t th
e si
tati
on.
(Hin
t: U
se t
he
dist
ance
fo
rmu
la d
= r
t.)
b
. How
lon
g is
th
e ro
ller
coa
ster
in
mot
ion
?
25-
17-
9
-87
105
12
-7
-93
-6
123
-12
9-
7296
-9n
= -
117;
13
- 1 −
8 n
= -
3 −
4 ;
6 b +
2.9
= 2
9.7
26.8
in. o
f m
ercu
ry
126
4
61x =
311
8
51.1
sec
on
ds
5 −
6 n
= -
5 −
9 ;
- 2 −
3
2.7
n =
8.3
7; 3
.1
013_
022_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
1412
/22/
10
12:1
8 P
M
Lesson 2-2
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Wor
d Pr
oble
m P
ract
ice
So
lvin
g O
ne-S
tep
Eq
uati
on
s
2-2
Cha
pte
r 2
15
Gle
ncoe
Alg
ebra
1
1. S
UPR
EME
CO
UR
T C
hief
Jus
tice
W
illi
am R
ehnq
uist
ser
ved
on t
he
Sup
rem
e C
ourt
for
33
year
s un
til h
is
deat
h in
200
5. W
rite
and
sol
ve a
n
equa
tion
to
dete
rmin
e th
e ye
ar h
e w
as
conf
irm
ed a
s a
just
ice
on t
he S
upre
me
Cou
rt.
2. S
ALA
RY I
n a
rec
ent
year
, th
e an
nu
al
sala
ry o
f th
e G
over
nor
of
New
Yor
k w
as
$179
,000
. Du
rin
g th
e sa
me
year
, th
e an
nu
al s
alar
y of
th
e G
over
nor
of
Ten
nes
see
was
$94
,000
les
s. W
rite
an
d so
lve
an e
quat
ion
it
to f
ind
the
ann
ual
sa
lary
of
the
Gov
ern
or o
f Ten
nes
see
in
that
yea
r.
3. W
EATH
ER O
n a
col
d Ja
nu
ary
day,
M
avis
not
iced
th
at t
he
tem
pera
ture
dr
oppe
d 21
deg
rees
ove
r th
e co
urs
e of
th
e da
y to
–9º
C. W
rite
an
d so
lve
an e
quat
ion
to
det
erm
ine
wh
at t
he
tem
pera
ture
was
at
th
e be
gin
nin
g of
th
e da
y.
4. F
AR
MIN
G M
r. H
ill’s
far
m i
s 12
6 ac
res.
M
r. H
ill’s
far
m i
s 1 − 4 t
he
size
of
Mr.
Mil
ler’
s fa
rm. H
ow m
any
acre
s is
M
r. M
ille
r’s
farm
?
5. N
AU
TIC
AL
On
th
e se
a, d
ista
nce
s ar
e m
easu
red
in n
auti
cal
mil
es r
ath
er t
han
m
iles
.
a.
If
a bo
at t
rave
ls 1
6 kn
ots
in 1
hou
r, h
ow f
ar w
ill
it h
ave
trav
eled
in
fee
t?
Wri
te a
nd
solv
e an
equ
atio
n.
b
. A
bou
t h
ow f
ast
was
th
e bo
at t
rave
lin
g in
mil
es p
er h
our?
Rou
nd
you
r an
swer
to
th
e n
eare
st h
un
dred
th.
1 na
utic
al m
ile =
608
0 fe
et
1 kn
ot =
1
naut
ical
mile
−
ho
ur
2
005
- x
= 3
3; x
= 1
972
1
79,0
00
- 9
4,0
00
= s
or
179,
00
0 -
s =
94,
00
0;
s =
$85
,00
0
x
- 2
1 =
-9;
x =
12º
C
504
acre
s
6080
× 1
6 =
x;
x =
97,
280
ft
97,2
80 ÷
528
0 =
18.
42 m
ph
013_
022_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
1512
/22/
10
12:1
8 P
M
Answers (Lesson 2-2)
A01_A14_ALG1_A_CRM_C02_AN_661315.indd A6 12/22/10 1:07 PM
Co
pyrig
ht © G
lencoe/M
cGraw
-Hill, a d
ivision o
f The M
cGraw
-Hill C
om
panies, Inc.
Chapter 2 A8 Glencoe Algebra 1
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Stud
y G
uide
and
Inte
rven
tion
(co
nti
nu
ed)
So
lvin
g M
ult
i-S
tep
Eq
uati
on
s
2-3
Cha
pte
r 2
18
Gle
ncoe
Alg
ebra
1
Solv
e M
ult
i-St
ep E
qu
atio
ns
To
solv
e eq
uat
ion
s w
ith
mor
e th
an o
ne
oper
atio
n, o
ften
ca
lled
mu
lti-
step
eq
uat
ion
s, u
ndo
ope
rati
ons
by w
orki
ng
back
war
d. R
ever
se t
he
usu
al
orde
r of
ope
rati
ons
as y
ou w
ork.
S
olve
5x
+ 3
= 2
3.
5x
+ 3
= 2
3 O
rigin
al e
quat
ion
5x +
3 -
3 =
23
- 3
S
ubtr
act
3 fr
om e
ach
side
.
5x
= 2
0 S
impl
ify.
5x
−
5
= 20
−
5
Div
ide
each
sid
e by
5.
x
= 4
S
impl
ify.
Exer
cise
sS
olve
eac
h e
qu
atio
n. C
hec
k y
our
solu
tion
.
1. 5
x +
2 =
27
2.
6x
+ 9
= 2
7
3. 5
x +
16
= 5
1
4. 1
4n -
8 =
34
5.
0.6
x -
1.5
= 1
.8
6. 7 −
8 p
- 4
= 1
0
7. 1
6 =
d -
12
−
14
8.
8 +
3n
−
12 =
13
9.
g
−
-5 +
3 =
-13
10.
4b +
8
−
-2
= 1
0
11. 0
.2x
- 8
= -
2
12. 3
.2y
- 1
.8 =
3
13. -
4 =
7x
- (
-1)
−
-8
14
. 8 =
-12
+
k −
-4
15. 0
= 1
0y -
40
Wri
te a
n e
qu
atio
n a
nd
sol
ve e
ach
pro
ble
m.
16. F
ind
thre
e co
nse
cuti
ve i
nte
gers
wh
ose
sum
is
96.
17. F
ind
two
con
secu
tive
odd
in
tege
rs w
hos
e su
m i
s 17
6.
18. F
ind
thre
e co
nse
cuti
ve i
nte
gers
wh
ose
sum
is
-93
.
Exam
ple
53
7
35.
516
236
2080
-7
301.
5
4 3 −
7
-80
4
n
+ (
n +
1)
+ (
n +
2)
= 9
6; 3
1, 3
2, 3
3
n
+ (
n +
2)
= 1
76;
87, 8
9
n
+ (
n +
1)
+ (
n +
2)
= -
93;
-32
, -31
, -30
013_
022_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
1812
/22/
10
12:1
8 P
M
Lesson 2-3
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Skill
s Pr
acti
ceS
olv
ing
Mu
lti-
Ste
p E
qu
ati
on
s
2-3
Cha
pte
r 2
19
Gle
ncoe
Alg
ebra
1
Sol
ve e
ach
pro
ble
m b
y w
ork
ing
bac
kw
ard
.
1. A
nu
mbe
r is
div
ided
by
2, a
nd
then
th
e qu
otie
nt
is a
dded
to
8. T
he
resu
lt i
s 33
.F
ind
the
nu
mbe
r.
2. T
wo
is s
ubt
ract
ed f
rom
a n
um
ber,
and
then
th
e di
ffer
ence
is
divi
ded
by 3
.T
he
resu
lt i
s 30
. Fin
d th
e n
um
ber.
3. A
nu
mbe
r is
mu
ltip
lied
by
2, a
nd
then
th
e pr
odu
ct i
s ad
ded
to 9
. Th
e re
sult
is
49.
Wh
at i
s th
e n
um
ber?
4. A
LLO
WA
NC
E A
fter
Ric
ardo
rec
eive
d h
is a
llow
ance
for
th
e w
eek,
he
wen
t to
th
e m
all
wit
h s
ome
frie
nds
. He
spen
t h
alf
of h
is a
llow
ance
on
a n
ew p
aper
back
boo
k. T
hen
he
bou
ght
him
self
a s
nac
k fo
r $1
.25.
Wh
en h
e ar
rive
d h
ome,
he
had
$5.
00 l
eft.
How
mu
ch
was
his
all
owan
ce?
Sol
ve e
ach
eq
uat
ion
. Ch
eck
you
r so
luti
on.
5. 5
x +
3 =
23
6.
4 =
3a
- 1
4
7. 2
y +
5 =
19
8. 6
+ 5
c =
-29
9.
8 -
5w
= -
37
10. 1
8 -
4v
= 4
2
11.
n
−
3 - 8
= -
2
12. 5
+ x −
4 =
1
13. -
h
−
3 - 4
= 1
3
14. -
d
−
6 + 1
2 =
-7
15
. a −
5 -
2 =
9
16.
w
−
7 + 3
= -
1
17.
3 −
4 q
- 7
= 8
18
. 2 −
3 g
+ 6
= -
12
19.
5 −
2 z
- 8
= -
3
20.
4 −
5 m
+ 2
= 6
21
. c
- 5
−
4 =
3
22.
b +
1
−
3 =
2
Wri
te a
n e
qu
atio
n a
nd
sol
ve e
ach
pro
ble
m.
23. T
wic
e a
nu
mbe
r pl
us
fou
r eq
ual
s 6.
Wh
at i
s th
e n
um
ber?
24. S
ixte
en i
s se
ven
plu
s th
ree
tim
es a
nu
mbe
r. F
ind
the
nu
mbe
r.
25. F
ind
two
con
secu
tive
in
tege
rs w
hos
e su
m i
s 35
.
26. F
ind
thre
e co
nse
cuti
ve i
nte
gers
wh
ose
sum
is
36.
50
92
20
$12.
50
46
7
-7
9-
6
18-
16-
51
114
55-
28
20-
272
517
5
2n +
4 =
6;
1
16 =
7 +
3n
; 3
n +
(n
+ 1
) =
35;
17,
18
n +
(n
+ 1
) +
(n
+ 2
) =
36;
11
, 12,
13
013_
022_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
1912
/22/
10
12:1
8 P
M
Answers (Lesson 2-3)
A01_A14_ALG1_A_CRM_C02_AN_661315.indd A8 12/22/10 1:08 PM
An
swer
s
Co
pyr
ight
© G
lenc
oe/
McG
raw
-Hill
, a d
ivis
ion
of
The
McG
raw
-Hill
Co
mp
anie
s, In
c.
Chapter 2 A9 Glencoe Algebra 1
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Prac
tice
So
lvin
g M
ult
i-S
tep
Eq
uati
on
s
2-3
Cha
pte
r 2
20
Gle
ncoe
Alg
ebra
1
Sol
ve e
ach
pro
ble
m b
y w
ork
ing
bac
kw
ard
.
1. T
hre
e is
add
ed t
o a
nu
mbe
r, an
d th
en t
he
sum
is
mu
ltip
lied
by
4. T
he
resu
lt i
s 16
. Fin
d th
e n
um
ber.
2. A
nu
mbe
r is
div
ided
by
4, a
nd
the
quot
ien
t is
add
ed t
o 3.
Th
e re
sult
is
24. W
hat
is
the
nu
mbe
r?
3. T
wo
is s
ubt
ract
ed f
rom
a n
um
ber,
and
then
th
e di
ffer
ence
is
mu
ltip
lied
by
5. T
he
resu
lt
is 3
0. F
ind
the
nu
mbe
r.
4. B
IRD
WA
TCH
ING
Wh
ile
Mic
hel
le s
at o
bser
vin
g bi
rds
at a
bir
d fe
eder
, on
e fo
urt
h o
f th
e bi
rds
flew
aw
ay w
hen
th
ey w
ere
star
tled
by
a n
oise
. Tw
o bi
rds
left
th
e fe
eder
to
go t
o an
oth
er s
tati
oned
a f
ew f
eet
away
. Th
ree
mor
e bi
rds
flew
in
to t
he
bran
ches
of
a n
earb
y tr
ee. F
our
bird
s re
mai
ned
at
the
feed
er. H
ow m
any
bird
s w
ere
at t
he
feed
er i
nit
iall
y?
Sol
ve e
ach
eq
uat
ion
. Ch
eck
you
r so
luti
on.
5. -
12n
- 1
9 =
77
6.
17
+ 3
f =
14
7.
15t
+ 4
= 4
9
8.
u
−
5 + 6
= 2
9.
d
−
-4 +
3 =
15
10
. b −
3 -
6 =
-2
11.
1 −
2 y
- 1 −
8 =
7 −
8
12. -
32 -
3 −
5 f
= -
17
13. 8
- 3 −
8 k
= -
4
14.
r +
13
−
12
=
1
15.
15 -
a
−
3
= -
9
16.
3k -
7
−
5
= 1
6
17.
x −
7 -
0.5
= 2
.5
18. 2
.5g
+ 0
.45
= 0
.95
19
. 0.4
m -
0.7
= 0
.22
Wri
te a
n e
qu
atio
n a
nd
sol
ve e
ach
pro
ble
m.
20. S
even
les
s th
an f
our
tim
es a
nu
mbe
r eq
ual
s 13
. Wh
at i
s th
e n
um
ber?
21. F
ind
two
con
secu
tive
odd
in
tege
rs w
hos
e su
m i
s 11
6.
22. F
ind
two
con
secu
tive
eve
n i
nte
gers
wh
ose
sum
is
126.
23. F
ind
thre
e co
nse
cuti
ve o
dd i
nte
gers
wh
ose
sum
is
117.
24. C
OIN
CO
LLEC
TIN
G J
un
g h
as a
tot
al o
f 92
coi
ns
in h
is c
oin
col
lect
ion
. Th
is i
s 8
mor
e th
an t
hre
e ti
mes
th
e n
um
ber
of q
uar
ters
in
th
e co
llec
tion
. How
man
y qu
arte
rs d
oes
Jun
g h
ave
in h
is c
olle
ctio
n?
1
84
8
12
-8
-1
3
-20
-48
12
2-
2532
-1
4229
210.
22.
3
4n -
7 =
13;
5
n +
(n
+ 2
) =
116
; 57
, 59
n +
(n
+ 2
) =
126
; 62
, 64
n +
(n
+ 2
) +
(n
+ 4
) =
117
; 37
, 39,
41
28
013_
022_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
2012
/22/
10
12:1
8 P
M
Lesson 2-3
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Wor
d Pr
oble
m P
ract
ice
So
lvin
g M
ult
i-S
tep
Eq
uati
on
s
2-3
Cha
pte
r 2
21
Gle
ncoe
Alg
ebra
1
1. T
EMPE
RA
TUR
E T
he
form
ula
for
co
nve
rtin
g a
Fah
ren
hei
t te
mpe
ratu
re t
o
a
Cel
siu
s te
mpe
ratu
re i
s C
=
F -
32º
−1.
8 .
F
ind
the
equ
ival
ent
Cel
siu
s te
mpe
ratu
re
fo
r 68
ºF.
2. H
UM
AN
HEI
GH
T It
is
a co
mm
only
use
d gu
idel
ine
that
for
th
e av
erag
e A
mer
ican
ch
ild,
th
eir
max
imu
m a
dult
hei
ght
wil
l be
abo
ut
twic
e th
eir
hei
ght
at a
ge 2
. S
upp
ose
that
Mic
ah’s
adu
lt h
eigh
t fi
ts
the
foll
owin
g eq
uat
ion
a =
2c
– 1,
wh
ere
a re
pres
ents
his
adu
lt h
eigh
t an
d c
repr
esen
ts h
is h
eigh
t at
age
2. A
t ag
e 2
Mic
ah w
as 3
5 in
ches
tal
l. W
hat
is
Mic
ah’s
adu
lt h
eigh
t? W
rite
an
d so
lve
an
equ
atio
n.
3. C
HEM
ISTR
Y T
he
hal
f-li
fe o
f a
radi
oact
ive
subs
tan
ce i
s th
e ti
me
requ
ired
for
hal
f of
a s
ampl
e to
un
derg
o ra
dioa
ctiv
e de
cay,
or
for
the
quan
tity
to
fall
to
hal
f it
s or
igin
al a
mou
nt.
Car
bon
14
has
a h
alf-
life
of
5730
yea
rs. S
upp
ose
gi
ven
sam
ples
of
carb
on 1
4 w
eigh
5 −
8 o
f
a po
un
d an
d 7 −
8 o
f a
pou
nd.
Wh
at w
as t
he
to
tal
wei
ght
of t
he
sam
ples
11,
460
year
s
ago?
4. N
UM
BER
TH
EORY
Wri
te a
nd
solv
e an
eq
uat
ion
to
fin
d th
ree
con
secu
tive
odd
in
tege
rs w
hos
e su
m i
s 3.
5. G
EOM
ETRY
A r
ecta
ngu
lar
swim
min
g po
ol i
s su
rrou
nde
d by
a c
oncr
ete
side
wal
k th
at i
s 3
feet
wid
e. T
he
dim
ensi
ons
of t
he
rect
angl
e cr
eate
d by
th
e si
dew
alk
are
21 f
eet
by 3
1 fe
et.
a.F
ind
the
len
gth
an
d w
idth
of
the
pool
.
b
. Fin
d th
e ar
ea o
f th
e po
ol.
c.
Wri
te a
nd
solv
e an
equ
atio
n t
o fi
nd
the
area
of
the
side
wal
k in
squ
are
feet
.
3 ft
31 ft
21 ft
pool
2
0ºC
a
= 2
c -
1;
c =
69
inch
es
w
= ( 5
−
8 + 7 −
8 ) ×
2 ×
2
w
= 6
po
un
ds
n
+ (n
+ 2
) + (n
+ 4
) =
3
3n
+ 6
= 3
3n =
-3
n =
-1
n +
2 =
1
n
+ 4
= 3
ℓ
= 2
1 -
3 -
3
w =
31
- 3
- 3
ℓ
= 1
5 fe
et
w =
25
feet
A
= ℓ
. w
A
= 1
5 . 2
5
A =
375
sq
uar
e fe
et
A
= ℓ
. w
- 3
75
A
= (
21 .
31)
- 3
75
A
= 6
51 -
375
A =
276
sq
uar
e fe
et
013_
022_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
2112
/22/
10
12:1
8 P
M
Answers (Lesson 2-3)
A01_A14_ALG1_A_CRM_C02_AN_661315.indd A9 12/22/10 1:08 PM
An
swer
s
Co
pyr
ight
© G
lenc
oe/
McG
raw
-Hill
, a d
ivis
ion
of
The
McG
raw
-Hill
Co
mp
anie
s, In
c.
Chapter 2 A11 Glencoe Algebra 1
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Stud
y G
uide
and
Inte
rven
tion
(co
nti
nu
ed)
So
lvin
g E
qu
ati
on
s w
ith
th
e V
ari
ab
le o
n E
ach
Sid
e
2-4
Cha
pte
r 2
24
Gle
ncoe
Alg
ebra
1
Gro
up
ing
Sym
bo
ls W
hen
sol
vin
g eq
uat
ion
s th
at c
onta
in g
rou
pin
g sy
mbo
ls, f
irst
use
th
e D
istr
ibu
tive
Pro
pert
y to
eli
min
ate
grou
pin
g sy
mbo
ls. T
hen
sol
ve.
S
olve
4(2
a -
1)
= -
10(a
- 5
).
4(2
a -
1)
= -
10(a
- 5
) O
rigin
al e
quat
ion
8a
- 4
= -
10a
+ 5
0 D
istr
ibut
ive
Pro
pert
y
8a -
4 +
10a
= -
10a
+ 5
0 +
10a
A
dd 1
0a to
eac
h si
de.
18
a -
4 =
50
Sim
plify
.
18
a -
4 +
4 =
50
+ 4
A
dd 4
to e
ach
side
.
18
a =
54
Sim
plify
.
18a
−
18
= 54
−
18
D
ivid
e ea
ch s
ide
by 1
8.
a
= 3
S
impl
ify.
Th
e so
luti
on i
s 3.
Exer
cise
s S
olve
eac
h e
qu
atio
n. C
hec
k y
our
solu
tion
.
1. -
3(x
+ 5
) =
3(x
- 1
) 2.
2(7
+ 3
t) =
-t
3. 3
(a +
1)
- 5
= 3
a -
2
4. 7
5 -
9g
= 5
(-4
+ 2
g)
5. 5
(f +
2)
= 2
(3 -
f)
6. 4
(p +
3)
= 3
6
7. 1
8 =
3(2
t +
2)
8. 3
(d -
8)
= 3
d
9. 5
(p +
3)
+ 9
= 3
( p -
2)
+ 6
10. 4
(b -
2)
= 2
(5 -
b)
11. 1
.2(x
- 2
) =
2 -
x
12.
3 +
y
−
4 =
-y
−
8
13.
a -
8
−
12
= 2a
+ 5
−
3
14. 2
(4 +
2k)
+ 1
0 =
k
15. 2
(w -
1)
+ 4
= 4
(w +
1)
16. 6
(n -
1)
= 2
(2n
+ 4
) 17
. 2[2
+ 3
(y -
1)]
= 2
2 18
. -4(
r +
2)
= 4
(2 -
4r)
19. -
3(x
- 8
) =
24
20. 4
(4 -
4k)
= -
10 -
16k
21. 6
(2 -
2y)
= 5
(2y
- 2
)
Exam
ple
-
2 -
2 a
ll n
um
ber
s
5
-
4 −
7
6
2
n
o s
olu
tio
n
-12
3
2
-
2
-
4 -
6 -
1
7
4
1
1 −
3
0
n
o s
olu
tio
n
1
023_
041_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
2412
/22/
10
12:1
8 P
M
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Lesson 2-4
Skill
s Pr
acti
ceS
olv
ing
Eq
uati
on
s w
ith
th
e V
ari
ab
le o
n E
ach
Sid
e
2-4
Cha
pte
r 2
25
Gle
ncoe
Alg
ebra
1
Ju
stif
y ea
ch s
tep
.
1.
4k -
3 =
2k
+ 5
4
k -
3 -
2k
= 2
k +
5 -
2k
a.
2k -
3 =
5
b.
2k -
3 +
3 =
5 +
3
c.
2k =
8
d.
2k
−
2 =
8 −
2
e.
k =
4
f.
2.
2(8u
+ 2
) =
3(2
u -
7)
16u
+ 4
= 6
u -
21
a.
16u
+ 4
- 6
u =
6u
- 2
1 -
6u
b
.
10u
+ 4
= -
21
c.
10u
+ 4
- 4
= -
21 -
4
d.
10u
= -
25
e.
10u
−
10
= -
25
−
10
f.
u =
-2.
5 g.
Sol
ve e
ach
eq
uat
ion
. Ch
eck
you
r so
luti
on.
3. 2
m +
12
= 3
m -
31
4.
2h
- 8
= h
+ 1
7
5. 7
a -
3 =
3 -
2a
6.
4n
- 1
2 =
12
- 4
n
7. 4
x -
9 =
7x
+ 1
2
8. -
6y -
3 =
3 -
6y
9. 5
+ 3
r =
5r
- 1
9
10. -
9 +
8k
= 7
+ 4
k
11. 8
q +
12
= 4
(3 +
2q)
12
. 3(5
j + 2
) = 2
(3j -
6)
13. 6
(-3v
+ 1
) = 5
(-2v
- 2
)
14. -
7(2b
- 4
) = 5
(-2b
+ 6
)
15. 3
(8 -
3t)
= 5
(2 +
t)
16
. 2(3
u +
7) =
-4(
3 -
2u)
17. 8
(2f -
2) =
7(3
f + 2
)
18. 5
(-6
- 3
d) =
3(8
+ 7
d)
19. 6
(w -
1) =
3(3
w +
5)
20
. 7(-
3y +
2) =
8(3
y -
2)
21.
2 −
3 v
- 6
= 6
- 2 −
3 v
22
. 1 −
2 -
5 −
8 x
= 7 −
8 x
+ 7 −
2
Su
btr
act
2k f
rom
eac
h s
ide.
Sim
plif
y.A
dd
3 t
o e
ach
sid
e.S
imp
lify.
Div
ide
each
sid
e by
2.
Sim
plif
y.
Dis
trib
uti
ve P
rop
erty
Su
btr
act
6u f
rom
eac
h s
ide.
Sim
plif
y.
Su
btr
act
4 fr
om
eac
h s
ide.
Sim
plif
y.
Div
ide
each
sid
e by
10.
Sim
plif
y.
4325
2 −
3
3
-7
no
so
luti
on
124
all n
um
ber
s-
2
2-
0.5
or
- 1 −
2
113
-6
-1.
5 o
r -
1 1 −
2
-7
2 −
3
9-
2
023_
041_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
2512
/22/
10
12:1
8 P
M
Answers (Lesson 2-4)
A01_A14_ALG1_A_CRM_C02_AN_661315.indd A11 12/22/10 1:08 PM
Co
pyrig
ht © G
lencoe/M
cGraw
-Hill, a d
ivision o
f The M
cGraw
-Hill C
om
panies, Inc.
Chapter 2 A12 Glencoe Algebra 1
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Prac
tice
So
lvin
g E
qu
ati
on
s w
ith
th
e V
ari
ab
le o
n E
ach
Sid
e
2-4
Cha
pte
r 2
26
Gle
ncoe
Alg
ebra
1
Sol
ve e
ach
eq
uat
ion
. Ch
eck
you
r so
luti
on.
1. 5
x -
3 =
13
- 3
x
2. -
4r -
11
= 4
r +
21
3. 1
- m
= 6
- 6
m
4. 1
4 +
5n
= -
4n +
17
5.
1 −
2 k
- 3
= 2
- 3 −
4 k
6.
1 −
2 (
6 -
y) =
y
7. 3
(-2
- 3
x) =
-9x
- 4
8.
4(4
- w
) = 3
(2w
+ 2
)
9. 9
(4b
- 1
) = 2
(9b
+ 3
)
10. 3
(6 +
5y)
= 2
(-5
+ 4
y)
11. -
5x -
10
= 2
- (x
+ 4
)
12. 6
+ 2
(3j -
2) =
4(1
+ j)
13.
5 −
2 t
- t
= 3
+ 3 −
2 t
14
. 1.4
f + 1
.1 =
8.3
- f
15.
2 −
3 x
- 1 −
6 =
1 −
2 x
+ 5 −
6
16. 2
- 3 −
4 k
= 1 −
8 k
+ 9
17.
1 −
2 (3
g -
2) =
g −
2
18.
1 −
3 (n
+ 1
) = 1 −
6 (3
n -
5)
19.
1 −
2 (5
- 2
h) =
h −
2
20.
1 −
9 (
2m -
16)
= 1 −
3 (2
m +
4)
21. 3
(d -
8)
- 5
= 9
(d +
2)
+ 1
22
. 2(a
- 8
) + 7
= 5
(a +
2) -
3a
- 1
9
23. N
UM
BER
S T
wo
thir
ds o
f a n
umbe
r re
duce
d by
11
is e
qual
to
4 m
ore
than
the
num
ber.
Fin
d th
e nu
mbe
r.
24. N
UM
BER
S F
ive
tim
es t
he
sum
of
a n
um
ber
and
3 is
th
e sa
me
as 3
mu
ltip
lied
by
1 le
ss
than
tw
ice
the
nu
mbe
r. W
hat
is
the
nu
mbe
r?
25. N
UM
BER
TH
EORY
Tri
plin
g th
e gr
eate
r of
tw
o co
nse
cuti
ve e
ven
in
tege
rs g
ives
th
e sa
me
resu
lt a
s su
btra
ctin
g 10
fro
m t
he
less
er e
ven
in
tege
r. W
hat
are
th
e in
tege
rs?
26. G
EOM
ETRY
Th
e fo
rmu
la f
or t
he
peri
met
er o
f a
rect
angl
e is
P =
2�,
+ 2
w, w
her
e �
is
the
len
gth
an
d w
is
the
wid
th. A
rec
tan
gle
has
a p
erim
eter
of
24 i
nch
es. F
ind
its
dim
ensi
ons
if i
ts l
engt
h i
s 3
inch
es g
reat
er t
han
its
wid
th.
all n
um
ber
s
2-
4
1 1 −
3
42
no
so
luti
on
1
5 −
6
-4
-2
1
no
so
luti
on
3
6-
8
17
1 2 −
3
-7
-8
-45
18
-8,
-6
4.5
in. b
y 7.
5 in
.
023_
041_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
2612
/22/
10
12:1
8 P
M
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Lesson 2-4
Wor
d Pr
oble
m P
ract
ice
So
lvin
g E
qu
ati
on
s w
ith
th
e V
ari
ab
le o
n E
ach
Sid
e
2-4
Cha
pte
r 2
27
Gle
ncoe
Alg
ebra
1
1.O
LYM
PIC
S In
th
e 20
10 W
inte
r O
lym
pic
Gam
es i
n V
anco
uve
r, C
anad
a, t
he
Un
ited
S
tate
s at
hle
tes
won
1 m
ore
than
4 t
imes
th
e n
um
ber
of g
old
met
als
won
by
the
Fre
nch
ath
lete
s. T
he
Un
ited
Sta
tes
won
7
mor
e go
ld m
etal
s th
an t
he
Fre
nch
. S
olve
th
e eq
uat
ion
7 +
F=
4F
+ 1
to
fin
d th
e n
um
ber
of g
old
met
als
won
by
the
Fre
nch
ath
lete
s.
2. A
GE
Die
go’s
mot
her
is
twic
e as
old
as
he
is. S
he
is a
lso
as o
ld a
s th
e su
m o
f th
e ag
es o
f D
iego
an
d bo
th o
f h
is y
oun
ger
twin
bro
ther
s. T
he
twin
s ar
e 11
yea
rs
old.
Sol
ve t
he
equ
atio
n 2
d =
d +
11
+ 1
1 to
fin
d th
e ag
e of
Die
go.
3. G
EOM
ETRY
Su
pple
men
tary
an
gles
ar
e an
gles
wh
ose
mea
sure
s h
ave
a su
m
of 1
80º.
Com
plem
enta
ry a
ngl
es a
re
angl
es w
hos
e m
easu
res
hav
e a
sum
of
90º
. Fin
d th
e m
easu
re o
f an
an
gle
wh
ose
supp
lem
ent
is 1
0º m
ore
than
tw
ice
its
com
plem
ent.
Let
90
– x
equ
al t
he
degr
ee m
easu
re o
f it
s co
mpl
emen
t an
d 18
0 –
x eq
ual
th
e de
gree
mea
sure
of
its
supp
lem
ent.
Wri
te a
nd
solv
e an
equ
atio
n.
4. N
ATU
RE
Th
e ta
ble
show
s th
e cu
rren
t h
eigh
ts a
nd
aver
age
grow
th r
ates
of
two
diff
eren
t sp
ecie
s of
tre
es. H
ow l
ong
wil
l it
tak
e fo
r th
e tw
o tr
ees
to b
e th
e sa
me
hei
ght?
5. N
UM
BER
TH
EORY
Mrs
. Sim
ms
told
h
er c
lass
to
fin
d tw
o co
nse
cuti
ve e
ven
in
tege
rs s
uch
th
at t
wic
e th
e le
sser
of
two
in
tege
rs i
s 4
less
th
an t
wo
tim
es t
he
grea
ter
inte
ger.
a.
Wri
te a
nd
solv
e an
equ
atio
n t
o fi
nd
the
inte
gers
.
b
. Doe
s th
e eq
uat
ion
hav
e on
e so
luti
on,
no
solu
tion
s, o
r is
it
an i
den
tity
? E
xpla
in.
Tree
Sp
ecie
sC
urr
ent
Hei
gh
tA
nn
ual
gro
wth
A38
inch
es4
inch
es
B
45.5
inch
es
2.5
inch
es
2
2
2 ye
ars
old
1
80 -
x =
10
+ 2
(90
- x
); 1
0
3
8 +
4x =
45.
5 +
2.5
x
1.5
x =
7.5
x =
5 y
ears
L
et in
teg
ers
be
n a
nd
(n
+ 2
)
2n =
2(n
+ 2
) -
4
2n
= 2
n +
4 -
4
2n =
2n
1 =
1, n
≠ 0
I
t is
an
iden
tity
bec
ause
it
is t
rue
for
ever
y p
air
of
con
secu
tive
eve
n in
teg
ers.
023_
041_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
2712
/22/
10
12:1
8 P
M
Answers (Lesson 2-4)
A01_A14_ALG1_A_CRM_C02_AN_661315.indd A12 12/22/10 1:08 PM
An
swer
s
Co
pyr
ight
© G
lenc
oe/
McG
raw
-Hill
, a d
ivis
ion
of
The
McG
raw
-Hill
Co
mp
anie
s, In
c.
Chapter 2 A15 Glencoe Algebra 1
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Skill
s Pr
acti
ceS
olv
ing
Eq
uati
on
s I
nvo
lvin
g A
bso
lute
Valu
e
2-5
Cha
pte
r 2
32
G
lenc
oe A
lgeb
ra 1
Eva
luat
e ea
ch e
xpre
ssio
n i
f a
= 2
, b =
-3,
an
d c
= -
4.
1.
⎪ a -
5⎪
- 1
2
2. ⎪
b +
1⎪
+ 8
10
3. 5
- ⎪
c +
1⎪
2
4. ⎪
a +
b⎪
- c
5
Sol
ve e
ach
eq
uat
ion
. Th
en g
rap
h t
he
solu
tion
set
.
5. ⎪
w +
1⎪
= 5
{-
6, 4}
6. ⎪
c -
3⎪
= 1
{2, 4}
7. ⎪
n +
2⎪
= 1
{-
3, -
1}
8. ⎪
t +
6⎪
= 4
{-
10, -
2}
9. ⎪
w -
2⎪
= 2
{0, 4}
10. ⎪
k -
5⎪
= 4
{1, 9}
Wri
te a
n e
qu
atio
n i
nvo
lvin
g ab
solu
te v
alu
e fo
r ea
ch g
rap
h.
11.
-5
-4
-3
-2
-1
01
23
45
12
.
⎪x ⎪ =
1
⎪ x
+ 3
⎪ = 2
13.
14.
⎪ x
- 4
⎪ = 1
⎪x ⎪ =
4
-2
-1
-4
-5
-6
-3
01
23
4-
8-
7-
10-
9-
6-
5-
4-
3-
2-
10
01
23
45
67
89
10
-2
-3
-4
-5
-6
-7
-1
01
23
-2
-3
-4
-5
-1
01
23
45
-2
-3
-4
-5
-1
01
23
45
-3
-4
-5
-6
-2
-1
01
23
4-
3-
10
12
34
56
-2
7
-3
-4
-2
-1
01
23
45
6
023_
041_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
3212
/23/
10
2:20
PM
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Lesson 2-5
Prac
tice
So
lvin
g E
qu
ati
on
s I
nvo
lvin
g A
bso
lute
Valu
e
2-5
Cha
pte
r 2
33
G
lenc
oe A
lgeb
ra 1
Eva
luat
e ea
ch e
xpre
ssio
n i
f x
= -
1, y
= 3
, an
d z
= -
4.
1. 1
6 -
⎪2z
+ 1
⎪ 9
2.
⎪x
- y
⎪ +
4 8
3. ⎪
-3y
+ z
⎪ -
x 1
4
4. 3
⎪ z -
x⎪ +
⎪2
- y
⎪ 10
Sol
ve e
ach
eq
uat
ion
. Th
en g
rap
h t
he
solu
tion
set
.
5. |
2z -
9|
= 1
{4, 5}
6. |
3 -
2r|
= 7
{-
2, 5}
-
5-
4-
3-
2-
10
12
34
5
-
5-
4-
3-
2-
10
12
34
5
7. |
3t +
6|
= 9
{-
5, 1}
8. |
2 g -
5|
= 9
{-
2, 7}
-5
-4
-3
-2
-1
01
23
45
-2
-1
01
23
45
67
8
Wri
te a
n e
qu
atio
n i
nvo
lvin
g ab
solu
te v
alu
e fo
r ea
ch g
rap
h.
9.
12
34
56
78
910
11
10.
-2
-3
-4
-5
-6
-7
-8
-1
01
2
⎪ x
- 6
⎪ =
5
⎪ x
+ 4
⎪ =
2
11.
-2
-3
-4
-5
-6
-7
-8
-1
01
2
12.
-2
-3
-1
01
23
45
67
⎪ x
+ 3
⎪ =
4
⎪ x
- 2
⎪ =
4
13. F
ITN
ESS
Tai
sha
use
s th
e el
lipt
ical
cro
ss-t
rain
er a
t th
e gy
m. H
er g
ener
al g
oal
is t
o bu
rn
280
Cal
orie
s pe
r w
orko
ut,
bu
t sh
e va
ries
by
as m
uch
as
25 C
alor
ies
from
th
is a
mou
nt
on
any
give
n d
ay. W
rite
an
d so
lve
an e
quat
ion
to
fin
d th
e m
axim
um
an
d m
inim
um
nu
mbe
r of
Cal
orie
s T
aish
a bu
rns
on t
he
cros
s-tr
ain
er.
{
⎪ c -
280
⎪ =
25;
min
= 2
55;
max =
305
}
14. T
EMPE
RA
TUR
E A
th
erm
omet
er i
s gu
aran
teed
to
give
a t
empe
ratu
re n
o m
ore
than
1.
2°F
fro
m t
he
actu
al t
empe
ratu
re. I
f th
e th
erm
omet
er r
eads
28°
F, w
rite
an
d so
lve
an
equ
atio
n t
o fi
nd
the
max
imu
m a
nd
min
imu
m t
empe
ratu
res
it c
ould
be.
{ ⎪
t -
28
⎪ =
1.2
; m
in =
26.8
°F;
max =
29.2
°F}
023_
041_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
3312
/22/
10
12:1
8 P
M
Answers (Lesson 2-5)
A15_A29_ALG1_A_CRM_C02_AN_661315.indd A15 12/23/10 2:24 PM
An
swer
s
Co
pyr
ight
© G
lenc
oe/
McG
raw
-Hill
, a d
ivis
ion
of
The
McG
raw
-Hill
Co
mp
anie
s, In
c.
Chapter 2 A21 Glencoe Algebra 1
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Skill
s Pr
acti
ceP
erc
en
t o
f C
han
ge
2-7
Cha
pte
r 2
44
Gle
ncoe
Alg
ebra
1
Sta
te w
het
her
eac
h p
erce
nt
of c
han
ge i
s a
per
cen
t of
in
crea
se o
r a
per
cen
t of
d
ecre
ase
. Th
en f
ind
eac
h p
erce
nt
of c
han
ge. R
oun
d t
o th
e n
eare
st w
hol
e p
erce
nt.
1. o
rigi
nal
: 25
2. o
rigi
nal
: 50
new
: 10
new
: 75
3. o
rigi
nal
: 55
4. o
rigi
nal
: 25
new
: 50
new
: 28
5. o
rigi
nal
: 50
6. o
rigi
nal
: 90
new
: 30
new
: 95
7. o
rigi
nal
: 48
8. o
rigi
nal
: 60
new
: 60
new
: 45
Fin
d t
he
tota
l p
rice
of
each
ite
m.
9. d
ress
: $69
.00
10. b
inde
r: $
14.5
0ta
x: 5
%
tax
: 7%
11. h
ardc
over
boo
k: $
28.9
5 12
. gro
ceri
es: $
47.5
2ta
x: 6
%
tax
: 3%
13. f
ille
r pa
per:
$6.
00
14. s
hoe
s: $
65.0
0ta
x: 6
.5%
t
ax: 4
%
15. b
aske
tbal
l: $1
7.00
16
. con
cert
tic
kets
: $48
.00
tax:
6%
t
ax: 7
.5%
Fin
d t
he
dis
cou
nte
d p
rice
of
each
ite
m.
17. b
ackp
ack:
$56
.25
18. m
onit
or: $
150.
00di
scou
nt:
20%
d
isco
un
t: 5
0%
19. C
D: $
15.9
9 20
. sh
irt:
$25
.50
disc
oun
t: 2
0%
dis
cou
nt:
40%
21. s
leep
ing
bag:
$12
5 22
. cof
fee
mak
er: $
102.
00di
scou
nt:
25%
d
isco
un
t: 4
5%
d
ecre
ase;
60%
incr
ease
; 50
%
d
ecre
ase;
9%
incr
ease
; 12
%
d
ecre
ase;
40%
incr
ease
; 6%
i
ncr
ease
; 25
%
d
ecre
ase;
25%
$
72.4
5
$15.
52
$
30.6
9
$48.
95
$
6.39
$67.
60
$
18.0
2
$51.
60
$
45.0
0
$75.
00
$
12.7
9
$15.
30
$
93.7
5
$56.
10
042_
060_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
4412
/22/
10
12:1
8 P
M
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Lesson 2-7
2-7
Prac
tice
Perc
en
t o
f C
han
ge
Cha
pte
r 2
45
Gle
ncoe
Alg
ebra
1
Sta
te w
het
her
eac
h p
erce
nt
of c
han
ge i
s a
per
cen
t of
in
crea
se o
r a
per
cen
t of
d
ecre
ase
. Th
en f
ind
eac
h p
erce
nt
of c
han
ge. R
oun
d t
o th
e n
eare
st w
hol
e p
erce
nt.
1. o
rigi
nal
: 18
2. o
rigi
nal
: 140
3.
ori
gin
al: 2
00n
ew: 1
0 n
ew: 1
60
new
: 320
4. o
rigi
nal
: 10
5. o
rigi
nal
: 76
6. o
rigi
nal
: 128
new
: 25
new
: 60
new
: 120
7. o
rigi
nal
: 15
8. o
rigi
nal
: 98.
6 9.
ori
gin
al: 5
8.8
new
: 35.
5 n
ew: 6
4 n
ew: 6
5.7
Fin
d t
he
tota
l p
rice
of
each
ite
m.
10. c
oncr
ete
bloc
ks: $
95.0
0 11
. cri
b: $
240.
00
12. j
acke
t: $
125.
00ta
x: 6
%
tax
: 6.5
%
tax
: 5.5
%
13. c
lass
rin
g: $
325.
00
14. b
lan
ket:
$24
.99
15. k
ite:
$18
.90
tax:
6%
t
ax: 7
%
tax
: 5%
Fin
d t
he
dis
cou
nte
d p
rice
of
each
ite
m.
16. d
ry c
lean
ing:
$25
.00
17. c
ompu
ter
gam
e: $
49.9
9 18
. lu
ggag
e: $
185.
00di
scou
nt:
15%
d
isco
un
t: 2
5%
dis
cou
nt:
30%
19. s
tati
oner
y: $
12.9
5 20
. pre
scri
ptio
n g
lass
es: $
149
21. p
air
of s
hor
ts: $
24.9
9 di
scou
nt:
10%
d
isco
un
t: 2
0%
d
isco
un
t: 4
5%
Fin
d t
he
fin
al p
rice
of
each
ite
m.
22. t
elev
isio
n: $
375.
00
23. D
VD
pla
yer:
$26
9.00
24
. pri
nte
r: $
255.
00di
scou
nt:
25%
d
isco
un
t: 2
0%
dis
cou
nt:
30%
tax:
6%
t
ax: 7
%
tax
: 5.5
%
25. I
NV
ESTM
ENTS
Th
e pr
ice
per
shar
e of
a s
tock
dec
reas
ed f
rom
$90
per
sh
are
to $
36 p
er
shar
e. B
y w
hat
per
cen
t di
d th
e pr
ice
of t
he
stoc
k de
crea
se?
26. H
EATI
NG
CO
STS
Cu
stom
ers
of a
uti
lity
com
pan
y re
ceiv
ed n
otic
es i
n t
hei
r m
onth
ly
bill
s th
at h
eati
ng
cost
s fo
r th
e av
erag
e cu
stom
er h
ad i
ncr
ease
d 12
5% o
ver
last
yea
r be
cau
se o
f an
un
usu
ally
sev
ere
win
ter.
In J
anu
ary
of l
ast
year
, th
e G
arci
a’s
paid
$12
0 fo
r h
eati
ng.
Wh
at s
hou
ld t
hey
exp
ect
to p
ay t
his
Jan
uar
y if
th
eir
bill
in
crea
sed
by 1
25%
?
d
ecre
ase;
44%
i
ncr
ease
; 14
%
in
crea
se;
60%
i
ncr
ease
; 15
0%
dec
reas
e; 2
1%
dec
reas
e; 6
%
i
ncr
ease
; 13
7%
dec
reas
e; 3
5%
in
crea
se;
12%
$
100.
70
$25
5.60
$
131.
88
$
344.
50
$26
.74
$19
.85
$
21.2
5 $
37.4
9 $
129.
50
$
11.6
6 $
119.
20
$13
.74
$
298.
13
$23
0.26
$
188.
32
60%
$270
042_
060_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
4512
/22/
10
12:1
8 P
M
Answers (Lesson 2-7)
A15_A29_ALG1_A_CRM_C02_AN_661315.indd A21 12/22/10 1:07 PM
Co
pyrig
ht © G
lencoe/M
cGraw
-Hill, a d
ivision o
f The M
cGraw
-Hill C
om
panies, Inc.
Chapter 2 A22 Glencoe Algebra 1
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Wor
d Pr
oble
m P
ract
ice
Perc
en
t o
f C
han
ge
2-7
Cha
pte
r 2
46
Gle
ncoe
Alg
ebra
1
1. S
POR
TS A
reg
ula
tion
gir
ls’ f
ast
pitc
h
soft
ball
dia
mon
d h
as b
ases
th
at a
re
60 f
eet
apar
t. A
reg
ula
tion
pro
fess
ion
al
base
ball
dia
mon
d h
as b
ases
th
at a
re 5
0%
fart
her
apa
rt. L
abel
th
e di
stan
ce
betw
een
th
e ba
ses
on t
he
regu
lati
on
base
ball
dia
mon
d di
agra
m.
2. S
ALE
S TA
X O
livi
a pu
rch
ases
a D
VD
m
ovie
pri
ced
at $
21.9
9. T
he
sale
s ta
x is
6.
5%. W
hat
is
the
tota
l pr
ice
of t
he
mov
ie, i
ncl
udi
ng
tax?
3. E
DU
CA
TIO
N T
he
AC
T i
s a
coll
ege
entr
ance
exa
m t
aken
by
hig
h s
choo
l st
ude
nts
. Th
e m
axim
um
sco
re t
hat
can
be
ear
ned
is
36. T
he
aver
age
scor
e in
th
e U
nit
ed S
tate
s w
as 2
1.2
duri
ng
a re
cen
t ye
ar. T
he
aver
age
scor
e fo
r V
erm
ont
stu
den
ts t
hat
yea
r w
as 7
.5%
hig
her
th
an
the
nat
ion
al a
vera
ge. W
hat
was
th
e av
erag
e A
CT
sco
re f
or V
erm
ont
stu
den
ts?
Rou
nd
you
r an
swer
to
the
nea
rest
ten
th.
4. C
AR
S M
r. T
hom
pson
pla
ns
to p
urc
has
e a
use
d ca
r pr
iced
at
$840
0. H
e w
ill
rece
ive
a 15
% e
mpl
oyee
dis
cou
nt
and
then
wil
l h
ave
to p
ay a
5.5
% s
ales
tax
. W
hat
wil
l be
th
e fi
nal
pri
ce o
f th
e ca
r?
5.M
USI
C T
he t
able
bel
ow s
how
s th
e to
tal
num
ber
of C
Ds,
dow
nloa
ded
sing
les,
and
m
usic
vid
eos
sold
in 2
004,
200
6, a
nd 2
008.
So
urce
: Rec
ordi
ng In
dustr
y As
socia
tion
of A
mer
ica
a. F
ind
the
perc
ent
of c
han
ge i
n t
he
nu
mbe
r of
un
its
sold
bet
wee
n 2
004
and
2006
an
d be
twee
n 2
006
and
2008
fo
r ea
ch f
orm
at. R
oun
d yo
ur
answ
ers
to t
he
nea
rest
ten
th.
b.
Tel
l w
het
her
eac
h p
erce
nt
of c
han
ge
in p
art
a is
a p
erce
nt
of i
ncr
ease
or
a pe
rcen
t of
dec
reas
e.
c. D
id t
hes
e tr
ends
ch
ange
fro
m 2
004
to
2008
? E
xpla
in.
90 ft
90 ft
90 ft
90 ft
Sal
es o
f R
eco
rded
Mu
sic
and
Mu
sic
Vid
eos
(mill
ion
s o
f u
nit
s)
Form
at20
0420
0620
08
CD
767.
061
4.9
368.
4
Dow
nloa
ded
139.
458
6.4
1042
.7
Vid
eo32
.823
.120
.8
$
23.4
2
2
2.8
CD
19
.8%
; 40
.1%
Do
wn
load
ed
320.
6%;
77.8
% V
ideo
29
.6%
; 10
.0%
C
D
dec
reas
e; d
ecre
ase
D
ow
nlo
aded
in
crea
se;
incr
ease
D
VD
vid
eo
incr
ease
; in
crea
se
Th
e C
D s
ales
an
d v
ideo
sal
es
dec
reas
ed in
bo
th t
ime
per
iod
s
and
do
wn
load
ed s
ales
in
crea
sed
bo
th t
ime
per
iod
s.
$
7532
.70
042_
060_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
4612
/22/
10
12:1
8 P
M
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Lesson 2-7
Enri
chm
ent
2-7
Cha
pte
r 2
47
Gle
ncoe
Alg
ebra
1
Usin
g P
erc
en
t
Use
wh
at y
ou h
ave
lear
ned
ab
out
per
cen
t to
sol
ve e
ach
pro
ble
m.
A T
V m
ovie
had
a “
rati
ng”
of
15 a
nd
a 25
“sh
are.
” T
he
rati
ng
is t
he
perc
enta
ge o
f th
e n
atio
n’s
tot
al T
V h
ouse
hol
ds t
hat
wer
e tu
ned
in
to
this
sh
ow. T
he
shar
e is
th
e pe
rcen
tage
of
hom
es w
ith
TV
s tu
rned
on
th
at w
ere
tun
ed t
o th
e m
ovie
. How
man
y T
V h
ouse
hol
ds h
ad
thei
r T
Vs
turn
ed o
ff a
t th
is t
ime?
To
fin
d ou
t, l
et T
= t
he
nu
mbe
r of
TV
hou
seh
olds
an
d x
= t
he
nu
mbe
r of
TV
hou
seh
olds
wit
h t
he
TV
off
.
Th
en T
- x
= t
he
nu
mbe
r of
TV
hou
seh
olds
wit
h t
he
TV
on
.S
ince
0.1
5T a
nd
0.25
(T -
x)
both
rep
rese
nt
the
nu
mbe
r of
hou
seh
olds
tu
ned
to
th
e m
ovie
,
0.15
T =
0.2
5(T
- x
)
0.15
T =
0.2
5T -
0.2
5x.
Sol
ve f
or x
. 0.
25x
= 0
.10T
x
= 0.
10T
−
0.25
or
0.4
0T
For
ty p
erce
nt
of t
he
TV
hou
seh
olds
had
th
eir
TV
s of
f w
hen
th
e m
ovie
was
air
ed.
An
swer
eac
h q
ues
tion
.
1. D
urin
g th
at s
ame
wee
k, a
spo
rts
broa
dcas
t ha
d a
rati
ng o
f 22
.1 a
nd a
43
shar
e. S
how
tha
t th
e pe
rcen
t of
TV
hou
seho
lds
wit
h th
eir
TV
s of
f w
as a
bout
48.
6%.
2. F
ind
the
perc
ent
of T
V h
ouse
hol
ds w
ith
th
eir
TV
s tu
rned
off
du
rin
g a
show
w
ith
a r
atin
g of
18.
9 an
d a
29 s
har
e.
3. S
how
th
at i
f T
is
the
nu
mbe
r of
TV
hou
seh
olds
, r i
s th
e ra
tin
g, a
nd
s is
th
e
sh
are,
th
en t
he
nu
mbe
r of
TV
hou
seh
olds
wit
h t
he
TV
off
is
(s -
r)T
−
s .
4. I
f th
e fr
acti
on o
f TV
hou
seh
olds
wit
h n
o T
V o
n i
s s
- r
−
s t
hen
sh
ow t
hat
th
e
frac
tion
of T
V h
ouse
hol
ds w
ith
TV
s on
is
r −
s .
5. F
ind
the
perc
ent
of T
V h
ouse
hol
ds w
ith
TV
s on
du
rin
g th
e m
ost
wat
ched
se
rial
pro
gram
in
his
tory
: th
e la
st e
piso
de o
f M
*A*S
*H, w
hic
h h
ad a
60.
3 ra
tin
g an
d a
77 s
har
e.
6. A
loc
al s
tati
on n
ow h
as a
2 s
har
e. E
ach
sh
are
is w
orth
$50
,000
in
adv
erti
sin
g re
ven
ue
per
mon
th. T
he
stat
ion
is
thin
kin
g of
goi
ng
com
mer
cial
fre
e fo
r th
e th
ree
mon
ths
of s
um
mer
to
gain
mor
e li
sten
ers.
Wh
at w
ould
its
new
sh
are
hav
e to
be
for
the
last
4 m
onth
s of
th
e ye
ar t
o m
ake
mor
e m
oney
for
th
e ye
ar
than
it
wou
ld h
ave
mad
e h
ad i
t n
ot g
one
com
mer
cial
fre
e?
0
.221
T =
0.4
3T -
0.4
3x
x =
0.
221T
- 0
.43T
−
-
0.43
= 0
.486
T
34.8
%
So
lve
rT =
s(T
- x
) fo
r x.
60.3
−
77
= 7
8.3%
gre
ater
th
an 3
.5
1 -
s -
r
−
s
= r −
s
042_
060_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
4712
/22/
10
12:1
8 P
M
Answers (Lesson 2-7)
A15_A29_ALG1_A_CRM_C02_AN_661315.indd A22 12/22/10 1:07 PM
An
swer
s
Co
pyr
ight
© G
lenc
oe/
McG
raw
-Hill
, a d
ivis
ion
of
The
McG
raw
-Hill
Co
mp
anie
s, In
c.
Chapter 2 A23 Glencoe Algebra 1
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Spre
adsh
eet
Act
ivit
yD
isco
un
ts
2-7
Cha
pte
r 2
48
Gle
ncoe
Alg
ebra
1
Exer
cise
s 1
. For
th
e se
con
d w
eek
of t
he
sale
, th
e E
lect
ron
ics
War
ehou
se m
anag
er i
s ch
angi
ng
the
disc
oun
ts t
o 20
%, 3
0%, 4
5%, a
nd
75%
off
. Use
a s
prea
dsh
eet
to c
reat
e a
new
dis
coun
t pr
ice
list
for
the
sof
twar
e.
2. H
ow s
hou
ld t
he
spre
adsh
eet
be a
lter
ed i
f th
e m
anag
er w
ish
ed t
o sh
ow t
he
fin
al p
rice
s of
th
e so
ftw
are
incl
udi
ng
the
6% s
ales
tax
for
th
eir
area
?
Ele
ctro
nic
s W
areh
ouse
is
hav
ing
a so
ftw
are
clea
ran
ce s
ale.
Th
e m
anag
er i
s m
akin
g a
dis
cou
nte
d p
rice
lis
t to
dis
trib
ute
to
cust
omer
s as
th
ey s
hop
. Dif
fere
nt
tab
les
wil
l h
ave
soft
war
e th
at i
s d
isco
un
ted
by
a d
iffe
ren
t p
erce
nt.
Use
a s
pre
adsh
eet
to s
how
th
e d
isco
un
ted
pri
ce o
f so
ftw
are
that
is
orig
inal
ly p
rice
d $
5.99
, $7.
99, $
9.99
, $15
.99,
$1
9.99
, $23
.99,
$27
.99,
$29
.99,
$33
.99,
an
d $
35.9
9. C
omp
ute
dis
cou
nte
d p
rice
s fo
r so
ftw
are
that
is
10%
, 15%
, 25%
, an
d 5
0% o
ff.
If a
n i
tem
is
on s
ale
for
10%
off
, th
at m
ean
s th
at d
isco
un
ted
pric
e is
(1
- 0
.1)
or 0
.9 t
imes
th
e or
igin
al p
rice
. Use
th
is p
atte
rn t
o co
mpl
ete
the
spre
adsh
eet.
Ste
p 1
U
se C
olu
mn
A o
f th
e sp
read
shee
t fo
r th
e or
igin
al p
rice
s.
Ste
p 2
C
olu
mn
s B
th
rou
gh E
con
tain
th
e fo
rmu
las
for
the
disc
oun
ted
pric
es.
Ste
p 3
B
ecau
se t
hes
e ar
e pr
ices
, th
e n
um
bers
mu
st b
e ro
un
ded
to 2
dig
its.
You
can
pr
ogra
m t
he
spre
adsh
eet
to l
ist
the
info
rmat
ion
as
doll
ars
and
cen
ts b
y ch
oosi
ng
curr
ency
fro
m t
he
nu
mbe
r m
enu
wh
en y
ou f
orm
at t
he
cell
s.
Dis
cou
nts
.xls
A1 3 4 5 6 7 8 9 10 112
BC
DE
12S
hee
t 1
Sh
eet
2S
hee
t 3
The
form
ula
ince
ll C
11 is
0.8
5*A1
1
The
form
ula
ince
ll E6
is 0
.5*A
6
Orig
inal
pric
e10
% o
ff15
% o
ff25
% o
ff50
% o
ff
$5.9
9$7
.99
$9.9
9$1
5.99
$19.
99$2
3.99
$27.
99$2
9.99
$33.
99$3
5.99
$5.3
9$7
.19
$8.9
9$1
4.39
$17.
99$2
1.59
$25.
19$2
6.99
$30.
59$3
2.39
$5.0
9$8
.79
$8.4
9$1
3.59
$16.
99$2
0.39
$23.
79$2
5.49
$28.
89$3
0.59
$3.0
0$4
.00
$5.0
0$8
.00
$10.
00$1
2.00
$14.
00$1
5.00
$17.
00$1
8.00
$4.4
9$5
.99
$7.4
9$1
1.99
$14.
99$1
7.99
$20.
99$2
2.49
$25.
49$2
6.99
See
stu
den
ts’ w
ork
.
Mu
ltip
ly e
ach
dis
cou
nte
d p
rice
by
1.06
.
042_
060_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
4812
/22/
10
12:1
8 P
M
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Lesson 2-8
2-8
Stud
y G
uide
and
Inte
rven
tion
Lit
era
l E
qu
ati
on
s a
nd
Dim
en
sio
nal A
naly
sis
Cha
pte
r 2
49
Gle
ncoe
Alg
ebra
1
Solv
e fo
r V
aria
ble
s S
omet
imes
you
may
wan
t to
sol
ve a
n e
quat
ion
su
ch a
s V
= �
wh
for
on
e of
its
var
iabl
es. F
or e
xam
ple,
if
you
kn
ow t
he
valu
es o
f V
, w, a
nd
h, t
hen
th
e eq
uat
ion
� =
V
−
wh i
s m
ore
use
ful
for
fin
din
g th
e va
lue
of �
. If
an e
quat
ion
th
at c
onta
ins
mor
e th
an o
ne
vari
able
is
to b
e so
lved
for
a s
peci
fic
vari
able
, use
th
e pr
oper
ties
of
equ
alit
y to
iso
late
th
e sp
ecif
ied
vari
able
on
on
e si
de o
f th
e eq
uat
ion
.
S
olve
2x
- 4
y =
8, f
or y
.
2x
- 4
y =
8 2x
- 4
y -
2x
= 8
- 2
x
-4y
= 8
- 2
x
-
4y
−
-4 =
8 -
2x
−
-4
y
= 8
- 2
x −
-
4
or
2x -
8
−
4
Th
e va
lue
of y
is
2x -
8
−
4 .
S
olve
3m
- n
= k
m -
8, f
or m
.
3m
- n
= k
m -
8
3m -
n -
km
= k
m -
8 -
km
3m
- n
- k
m =
- 8
3m -
n -
km
+ n
= -
8 +
n
3m -
km
= -
8 +
n
m(3
- k
) =
-8
+ n
m
(3 -
k)
−
3 -
k =
-8
+ n
−
3 -
k
m
= -
8 +
n
−
3 -
k
or
n -
8
−
3 -
k
The
val
ue o
f m
is n
- 8
−
3 -
k .
Sin
ce d
ivis
ion
by 0
is
un
defi
ned
, 3 -
k ≠
0, o
r k
≠ 3
.
Exer
cise
s S
olve
eac
h e
qu
atio
n o
r fo
rmu
la f
or t
he
vari
able
in
dic
ated
.
1. a
x -
b =
c, f
or x
2.
15x
+ 1
= y
, for
x
3. (
x +
f)
+ 2
= j
, for
x
4. x
y +
w =
9, f
or y
5.
x(4
- k
) =
p, f
or k
6.
7x
+ 3
y =
m, f
or y
7. 4
(r +
3)
= t
, for
r
8. 2
x +
b =
w, f
or x
9.
x(1
+ y
) =
z, f
or x
10. 1
6w +
4x
= y
, for
x
11. d
= r
t, f
or r
12
. A =
h(a
+ b
) −
2
, fo
r h
13. C
= 5 −
9 (F
- 3
2), f
or F
14
. P =
2�
+ 2
w, f
or w
15
. A =
�w
, for
�
Exam
ple
2Ex
amp
le 1
x
= c
+ b
−
a
, a ≠
0
x =
y -
1
−
15
x
= j
- 2
- f
y
= 9
- w
−
x
, x ≠
0
k =
4 -
p
−
x ,
x ≠
0
y =
m -
7x
−
3
r
= t −
4 -
3
x =
w -
b
−
2
x =
z
−
1 +
y ,
y ≠
-1
x
= y
- 1
6w
−
4
r =
d
−
t , t
≠ 0
h
= 2
A
−
a +
b ,
a ≠
-b
F
= 9
−
5 C +
32
W =
p -
2�
−
2
� =
A
−
w
, w
≠ 0
042_
060_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
4912
/22/
10
12:1
8 P
M
Answers (Lesson 2-7 and Lesson 2-8)
A15_A29_ALG1_A_CRM_C02_AN_661315.indd A23 12/22/10 1:07 PM
Co
pyrig
ht © G
lencoe/M
cGraw
-Hill, a d
ivision o
f The M
cGraw
-Hill C
om
panies, Inc.
Chapter 2 A24 Glencoe Algebra 1
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Stud
y G
uide
and
Inte
rven
tion
(co
nti
nu
ed)
Lit
era
l E
qu
ati
on
s a
nd
Dim
en
sio
nal A
naly
sis
2-8
Cha
pte
r 2
50
Gle
ncoe
Alg
ebra
1
Use
Fo
rmu
las
Man
y re
al-w
orld
pro
blem
s re
quir
e th
e u
se o
f fo
rmu
las.
Som
etim
es s
olvi
ng
a fo
rmu
la f
or a
spe
cifi
ed v
aria
ble
wil
l h
elp
solv
e th
e pr
oble
m.
T
he
form
ula
C =
πd
rep
rese
nts
th
e ci
rcu
mfe
ren
ce o
f a
circ
le, o
r th
e d
ista
nce
aro
un
d t
he
circ
le, w
her
e d
is
the
dia
met
er. I
f an
air
pla
ne
cou
ld f
ly a
rou
nd
E
arth
at
the
equ
ator
wit
hou
t st
opp
ing,
it
wou
ld h
ave
trav
eled
ab
out
24,9
00 m
iles
. F
ind
th
e d
iam
eter
of
Ear
th.
C =
πd
G
iven
form
ula
d =
C
−
π
Sol
ve fo
r d
.
d =
24,9
00
−
3.14
Use
π =
3.1
4.
d ≈
793
0 S
impl
ify.
Th
e di
amet
er o
f E
arth
is
abou
t 79
30 m
iles
.
Exer
cise
s 1
. GEO
MET
RY T
he
volu
me
of a
cyl
inde
r V
is
give
n b
y th
e fo
rmu
la V
= π
r2 h, w
her
e r
is
the
radi
us
and
h i
s th
e h
eigh
t.
a. S
olve
th
e fo
rmu
la f
or h
.
b.
Fin
d th
e h
eigh
t of
a c
ylin
der
wit
h v
olu
me
2500
π c
ubi
c fe
et a
nd
radi
us
10 f
eet.
2. W
ATE
R P
RES
SUR
E T
he
wat
er p
ress
ure
on
a s
ubm
erge
d ob
ject
is
give
n b
y P
= 6
4d,
wh
ere
P i
s th
e pr
essu
re i
n p
oun
ds p
er s
quar
e fo
ot, a
nd
d i
s th
e de
pth
of
the
obje
ct
in f
eet.
a. S
olve
th
e fo
rmu
la f
or d
.
b.
Fin
d th
e de
pth
of a
sub
mer
ged
obje
ct if
the
pre
ssur
e is
672
pou
nds
per
squa
re f
oot.
3. G
RA
PHS
Th
e eq
uat
ion
of
a li
ne
con
tain
ing
the
poin
ts (
a, 0
) an
d (0
, b)
is g
iven
by
the
fo
rmu
la x −
a
+ y −
b =
1.
a. S
olve
th
e eq
uat
ion
for
y.
b.
Su
ppos
e th
e li
ne
con
tain
s th
e po
ints
(4,
0),
and
(0, -
2). I
f x
= 3
, fin
d y.
4. G
EOM
ETRY
Th
e su
rfac
e ar
ea o
f a
rect
angu
lar
soli
d is
giv
en b
y th
e fo
rmu
la
x =
2�w
+ 2
�h +
2w
h, w
her
e �
= l
engt
h, w
= w
idth
, an
d h
= h
eigh
t.
a. S
olve
th
e fo
rmu
la f
or h
.
b.
Th
e su
rfac
e ar
ea o
f a
rect
angu
lar
soli
d w
ith
len
gth
6 c
enti
met
ers
and
wid
th
3 ce
nti
met
ers
is 7
2 sq
uar
e ce
nti
met
ers.
Fin
d th
e h
eigh
t.
Exam
ple
25 f
t
10.5
ft
2 cm
h =
V
−
πr2
d =
p
−
64
y =
b (1
- x
−
a )
- 1 −
2
h =
x
- 2
�w
−
2� +
2w
042_
060_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
5012
/22/
10
12:1
8 P
M
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Lesson 2-8
Skill
s Pr
acti
ceLit
era
l E
qu
ati
on
s a
nd
Dim
en
sio
nal A
naly
sis
2-8
Cha
pte
r 2
51
Gle
ncoe
Alg
ebra
1
Sol
ve e
ach
eq
uat
ion
or
form
ula
for
th
e va
riab
le i
nd
icat
ed.
1. 7
t =
x, f
or t
2.
r =
wp,
for
p
3. q
- r
= r
, for
r
4. 4
m -
t =
m, f
or m
5. 7
a -
b =
15a
, for
a
6. -
5c +
d =
2c,
for
c
7. x
- 2
y =
1, f
or y
8.
d +
3n
= 1
, for
n
9. 7
f +
g =
5, f
or f
10
. ax
- c
= b
, for
x
11. r
t -
2n
= y
, for
t
12. b
c +
3g
= 2
k, f
or c
13. k
n +
4f
= 9
v, f
or n
14
. 8c
+ 6
j =
5p,
for
c
15.
x -
c
−
2 =
d, f
or x
16
. x
- c
−
2 =
d, f
or c
17.
p +
9
−
5 =
r, f
or p
18
. b
- 4
z −
7
= a
, for
b
19. T
he
volu
me
of a
box
V i
s gi
ven
by
the
form
ula
V =
ℓw
h, w
her
e ℓ
is t
he
len
gth
, w
is
the
wid
th, a
nd
h i
s th
e h
eigh
t.
a. S
olve
th
e fo
rmu
la f
or h
.
b.
Wh
at i
s th
e h
eigh
t of
a b
ox w
ith
a v
olu
me
of 5
0 cu
bic
met
ers,
len
gth
of
10 m
eter
s,
and
wid
th o
f 2
met
ers?
20. T
ren
t pu
rch
ases
44
euro
s w
orth
of
sou
ven
irs
wh
ile
on v
acat
ion
in
Fra
nce
. If
$1
U.S
. = 0
.678
eu
ros,
fin
d th
e co
st o
f th
e so
uve
nir
s in
Un
ited
Sta
tes
doll
ars.
R
oun
d to
th
e n
eare
st c
ent.
t =
x
−
7 p
=
r −
w
r =
q
−
2 m
= t −
3
a =
- b
−
8
c =
d
−
7
y =
x -
1
−
2 n
= 1
- d
−
3
f =
5 -
g
−
7
x =
b +
c
−
a
; a ≠
0
t =
2n +
y
−
r ;
r ≠
0
n =
9v -
4f
−
k
; k ≠
0
c =
2k -
3g
−
b
; b
≠ 0
c =
5p -
6j
−
8
x =
c +
2d
p =
5r
- 9
c =
x -
2d
b =
7a +
4z
h =
V
−
ℓw
2.5
m
$64.
90
042_
060_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
5112
/23/
10
12:0
8 P
M
Answers (Lesson 2-8)
A15_A29_ALG1_A_CRM_C02_AN_661315.indd A24 12/23/10 12:22 PM
An
swer
s
Co
pyr
ight
© G
lenc
oe/
McG
raw
-Hill
, a d
ivis
ion
of
The
McG
raw
-Hill
Co
mp
anie
s, In
c.
Chapter 2 A25 Glencoe Algebra 1
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Prac
tice
Lit
era
l E
qu
ati
on
s a
nd
Dim
en
sio
nal A
naly
sis
2-8
Cha
pte
r 2
52
Gle
ncoe
Alg
ebra
1
Sol
ve e
ach
eq
uat
ion
or
form
ula
for
th
e va
riab
le i
nd
icat
ed.
1. d
= r
t, fo
r r
2.
6w
- y
= 2
z, f
or w
3. m
x +
4y
= 3
t, fo
r x
4.
9s
- 5
g =
-4u
, for
s
5. a
b +
3c
= 2
x, f
or b
6.
2p
= k
x -
t, f
or x
7.
2 −
3 m
+ a
= a
+ r
, for
m
8. 2 −
5 h
+ g
= d
, for
h
9.
2 −
3 y
+ v
= x
, for
y
10.
3 −
4 a
- q
= k
, for
a
11.
rx +
9
−
5 =
h, f
or x
12
. 3b
- 4
−
2 =
c, f
or b
13. 2
w -
y =
7w
- 2
, for
w
14. 3
� +
y =
5 +
5�,
for
�
15. E
LEC
TRIC
ITY
Th
e fo
rmu
la f
or O
hm
’s L
aw i
s E
= I
R, w
her
e E
rep
rese
nts
vol
tage
m
easu
red
in v
olts
, I r
epre
sen
ts c
urr
ent
mea
sure
d in
am
pere
s, a
nd
R r
epre
sen
ts
resi
stan
ce m
easu
red
in o
hm
s.
a. S
olve
th
e fo
rmu
la f
or R
.
b.
Su
ppos
e a
curr
ent
of 0
.25
ampe
re f
low
s th
rou
gh a
res
isto
r co
nn
ecte
d to
a 1
2-vo
lt
batt
ery.
Wh
at i
s th
e re
sist
ance
in
th
e ci
rcu
it?
16. M
OTI
ON
In
un
ifor
m c
ircu
lar
mot
ion
, th
e sp
eed
v of
a p
oin
t on
th
e ed
ge o
f a
spin
nin
g di
sk i
s v
= 2π
−
t
r, w
her
e r
is t
he
radi
us
of t
he
disk
an
d t
is t
he
tim
e it
tak
es t
he
poin
t to
tr
avel
on
ce a
rou
nd
the
circ
le.
a. S
olve
th
e fo
rmu
la f
or r
.
b.
Su
ppos
e a
mer
ry-g
o-ro
un
d is
spi
nn
ing
once
eve
ry 3
sec
onds
. If
a po
int
on t
he
outs
ide
edge
has
a s
peed
of
12.5
6 fe
et p
er s
econ
d, w
hat
is
the
radi
us
of t
he
mer
ry-g
o-ro
un
d?
(Use
3.1
4 fo
r π
.)
17. H
IGH
WA
YS
Inte
rsta
te 9
0 is
th
e lo
nge
st i
nte
rsta
te h
igh
way
in
th
e U
nit
ed S
tate
s,
con
nec
tin
g th
e ci
ties
of
Sea
ttle
, Was
hin
gton
an
d B
osto
n, M
assa
chu
sett
s. T
he
inte
rsta
te
is 4
,987
,000
met
ers
in l
engt
h. I
f 1
mil
e =
1.6
09 k
ilom
eter
s, h
ow m
any
mil
es l
ong
is
Inte
rsta
te 9
0?
48 o
hm
s
6 ft
r =
d
−
t w
= 2z
+ y
−
6
x =
3t
- 4
y
−
m
; m
≠ 0
s =
-
4u +
5g
−
9
b =
2x
- 3
c
−
a
; a ≠
0x =
2p +
t
−
k
; k ≠
0
m =
3 −
2 r
h =
5 −
2 (
d -
g)
y =
3 −
2 (
x -
v)
a =
4 −
3 (
k +
q)
x =
5h
- 9
−
r ;
r ≠
0b
=
2c +
4
−
3
w =
2
- y
−
5
ℓ =
y -
5
−
2
R =
E
−
I
r =
tv
−
2π
3099
mi
042_
060_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
5212
/23/
10
12:1
3 P
M
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Lesson 2-8
Wor
d Pr
oble
m P
ract
ice
Lit
era
l E
qu
ati
on
s a
nd
Dim
en
sio
nal A
naly
sis
2-8
Cha
pte
r 2
53
Gle
ncoe
Alg
ebra
1
1. IN
TER
EST
Sim
ple
inte
rest
th
at y
ou m
ay
earn
on
mon
ey i
n a
sav
ings
ac
cou
nt
can
be
calc
ula
ted
wit
h t
he
form
ula
I=
prt.
I is
th
e am
oun
t of
in
tere
st e
arn
ed, p
is
the
prin
cipa
l or
in
itia
l am
oun
t in
vest
ed, r
is
the
inte
rest
ra
te, a
nd
t is
th
e am
oun
t of
tim
e th
e m
oney
is
inve
sted
for
. Sol
ve t
he
form
ula
fo
r p.
2. D
ISTA
NC
E T
he
dist
ance
d a
car
can
tr
avel
is
fou
nd
by m
ult
iply
ing
its
rate
of
spee
d r
by t
he
amou
nt
of t
ime
t th
at i
t to
ok t
o tr
avel
th
e di
stan
ce. I
f a
car
has
al
read
y tr
avel
ed 5
mil
es, t
he
tota
l di
stan
ce d
is
fou
nd
by t
he
form
ula
d
= r
t + 5
. S
olve
th
e fo
rmu
la f
or r
.
3. E
NV
IRO
NM
ENT
Th
e U
nit
ed S
tate
s re
leas
ed 5
.877
bil
lion
met
ric
ton
s of
ca
rbon
dio
xide
in
to t
he
envi
ron
men
t th
rou
gh t
he
burn
ing
of f
ossi
l fu
els
in a
re
cen
t ye
ar. I
f 1
tril
lion
pou
nds
= 0
.453
6 bi
llio
n m
etri
c to
ns,
how
man
y tr
illi
ons
of
pou
nds
of
carb
on d
ioxi
de d
id t
he
Un
ited
S
tate
s re
leas
e in
th
at y
ear?
4. P
HY
SIC
S T
he
pres
sure
exe
rted
on
an
obj
ect
is c
alcu
late
d by
th
e fo
rmu
la
P =
F − A, w
her
e P
is
the
pres
sure
, F i
s th
e fo
rce,
an
d A
is
the
surf
ace
area
of
the
obje
ct. W
ater
sh
ooti
ng
from
a h
ose
has
a
pres
sure
of
75 p
oun
ds p
er s
quar
e in
ch
(psi
). S
upp
ose
the
surf
ace
area
cov
ered
by
th
e di
rect
hos
e sp
ray
is 0
.442
squ
are
inch
. Sol
ve t
he
equ
atio
n f
or F
an
d fi
nd
the
forc
e of
th
e sp
ray.
5. G
EOM
ETRY
Th
e re
gula
r oc
tago
n i
s di
vide
d in
to 8
con
gru
ent
tria
ngl
es. E
ach
tr
ian
gle
has
an
are
a of
21.
7 sq
uar
e ce
nti
met
ers.
Th
e pe
rim
eter
of
the
octa
gon
is
48 c
enti
met
ers.
a. W
hat
is
the
len
gth
of
each
sid
e of
th
e oc
tago
n?
b. S
olve
the
are
a of
a t
rian
gle
form
ula
for
h.
c. W
hat
is
the
hei
ght
of e
ach
tri
angl
e?
Rou
nd
to t
he
nea
rest
ten
th.
h
≈
12.9
6
3
3.15
po
un
ds
6 ce
nti
met
ers
7.2
cen
tim
eter
s
p =
I −
rt
r =
d -
5
−
t
h =
2A
−
b
042_
060_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
5312
/22/
10
12:1
8 P
M
Answers (Lesson 2-8)
A15_A29_ALG1_A_CRM_C02_AN_661315.indd A25 12/23/10 12:22 PM
Co
pyrig
ht © G
lencoe/M
cGraw
-Hill, a d
ivision o
f The M
cGraw
-Hill C
om
panies, Inc.
Chapter 2 A26 Glencoe Algebra 1
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Enri
chm
ent
2-8
Cha
pte
r 2
54
Gle
ncoe
Alg
ebra
1
Co
mp
ou
nd
Inte
rest
In m
ost
ban
ks, i
nte
rest
on
sav
ings
acc
oun
ts i
s co
mpo
un
ded
at s
et t
ime
peri
ods
such
as
thre
e or
six
mon
ths.
At
the
end
of e
ach
per
iod,
th
e ba
nk
adds
th
e in
tere
st e
arn
ed t
o th
e ac
cou
nt.
Du
rin
g th
e n
ext
peri
od,
the
ban
k pa
ys i
nte
rest
on
all
th
e m
oney
in
th
e ba
nk,
in
clu
din
g in
tere
st.
In t
his
way
, th
e ac
cou
nt
earn
s in
tere
st o
n i
nte
rest
.S
upp
ose
Ms.
Tan
ner
has
$10
00 i
n a
n a
ccou
nt
that
is
com
pou
nde
d qu
arte
rly
at 5
%. F
ind
the
bala
nce
aft
er t
he
firs
t tw
o qu
arte
rs.
Use
I =
prt
to
fin
d th
e in
tere
st e
arn
ed i
n t
he
firs
t qu
arte
r if
p =
100
0
and
r =
5%
. Wh
y is
t e
qual
to
1 −
4 ?
Fir
st q
uar
ter:
I
= 1
000
× 0
.05
× 1 −
4
I =
12.
50
Th
e in
tere
st, $
12.5
0, e
arn
ed i
n t
he
firs
t qu
arte
r is
add
ed t
o $1
000.
T
he
prin
cipa
l be
com
es $
1012
.50.
Sec
ond
quar
ter:
I =
101
2.50
× 0
.05
× 1 −
4
I
= 1
2.65
625
Th
e in
tere
st i
n t
he
seco
nd
quar
ter
is $
12.6
6.
Th
e ba
lan
ce a
fter
tw
o qu
arte
rs i
s $1
012.
50 +
12.
66 o
r $1
025.
16.
An
swer
eac
h o
f th
e fo
llow
ing
qu
esti
ons.
1. H
ow m
uch
in
tere
st i
s ea
rned
in
th
e th
ird
quar
ter
of M
s. T
ann
er’s
ac
cou
nt?
2. W
hat
is
the
bala
nce
in
her
acc
oun
t af
ter
thre
e qu
arte
rs?
3. H
ow m
uch
in
tere
st i
s ea
rned
in
th
e fo
urt
h q
uar
ter?
4. W
hat
is
the
bala
nce
in
her
acc
oun
t af
ter
one
year
?
5. S
upp
ose
Ms.
Tan
ner
’s a
ccou
nt
is c
ompo
un
ded
sem
ian
nu
ally
. Wh
at
is t
he
bala
nce
at
the
end
of s
ix m
onth
s?
6. W
hat
is
the
bala
nce
aft
er o
ne
year
if
her
acc
oun
t is
com
pou
nde
d se
mia
nn
ual
ly?
I = $
12.8
1
$103
7.97
I = $
12.9
7
$105
0.94
$102
5.0
0
$105
0.63
042_
060_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
5412
/22/
10
12:1
8 P
M
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Lesson 2-9
Stud
y G
uide
and
Inte
rven
tion
Weig
hte
d A
vera
ges
2-9
Cha
pte
r 2
55
Gle
ncoe
Alg
ebra
1
Mix
ture
Pro
ble
ms
Mix
ture
Pro
ble
ms
are
prob
lem
s w
her
e tw
o or
mor
e pa
rts
are
com
bin
ed i
nto
a w
hol
e. T
hey
in
volv
e w
eigh
ted
aver
ages
. In
a m
ixtu
re p
robl
em, t
he
wei
ght
is
usu
ally
a p
rice
or
a pe
rcen
t of
som
eth
ing.
Wei
gh
ted
Ave
rag
eT
he w
eigh
ted
aver
age
M o
f a
set
of d
ata
is t
he s
um o
f th
e pr
oduc
t of
eac
h nu
mbe
r in
the
set
an
d its
wei
ght
divi
ded
by t
he s
um o
f al
l the
wei
ghts
.
C
OO
KIE
S D
elec
tab
le C
ook
ie C
omp
any
sell
s ch
ocol
ate
chip
coo
kie
s fo
r $6
.95
per
pou
nd
an
d w
hit
e ch
ocol
ate
cook
ies
for
$5.9
5 p
er p
oun
d. H
ow m
any
pou
nd
s of
ch
ocol
ate
chip
coo
kie
s sh
ould
be
mix
ed w
ith
4 p
oun
ds
of w
hit
e ch
ocol
ate
cook
ies
to o
bta
in a
mix
ture
th
at s
ells
for
$6.
75 p
er p
oun
d.
Let
w =
th
e n
um
ber
of p
oun
ds o
f ch
ocol
ate
chip
coo
kies
Nu
mb
er o
f P
ou
nd
sP
rice
per
Po
un
dTo
tal P
rice
Ch
oco
late
Ch
ipw
6.95
6.95
wW
hit
e C
ho
cola
te4
5.95
4(5.
95)
Mix
ture
w +
46.
756.
75(w
+ 4
)
Equ
atio
n: 6
.95w
+ 4
(5.9
5) =
6.7
5(w
+ 4
)S
olve
th
e eq
uat
ion
.
6.95
w +
4(5
.95)
= 6
.75(
w +
4)
Orig
inal
equ
atio
n
6.
95w
+ 2
3.80
= 6
.75w
+ 2
7 S
impl
ify.
6.95
w +
23.
80 -
6.7
5w =
6.7
5w +
27
- 6
.75w
S
ubtr
act
6.75
w f
rom
eac
h si
de.
0.
2w +
23.
80 =
27
Sim
plify
.
0.
2w +
23.
80 -
23.
80 =
27
- 2
3.80
S
ubtr
act
23.8
0 fr
om e
ach
side
.
0.
2w =
3.2
S
impl
ify.
w
= 1
6 S
impl
ify.
16 p
ound
s of
cho
cola
te c
hip
cook
ies
shou
ld b
e m
ixed
wit
h 4
poun
ds o
f w
hite
cho
cola
te c
ooki
es.
Exer
cise
s 1
. SO
LUTI
ON
S H
ow m
any
gram
s of
su
gar
mu
st b
e ad
ded
to 6
0 gr
ams
of a
sol
uti
on t
hat
is
32%
su
gar
to o
btai
n a
sol
uti
on t
hat
is
50%
su
gar?
2. N
UTS
Th
e Q
uik
Mar
t h
as t
wo
kin
ds o
f n
uts
. Pec
ans
sell
for
$1.
55 p
er p
oun
d an
d w
aln
uts
sel
l fo
r $1
.95
per
pou
nd.
How
man
y po
un
ds o
f w
aln
uts
mu
st b
e ad
ded
to 1
5 po
un
ds o
f pe
can
s to
mak
e a
mix
ture
th
at s
ells
for
$1.
75 p
er p
oun
d?
3. I
NV
ESTM
ENTS
Ali
ce G
leas
on i
nve
sted
a p
orti
on o
f $3
2,00
0 at
9%
in
tere
st a
nd
the
bala
nce
at
11%
in
tere
st. H
ow m
uch
did
sh
e in
vest
at
each
rat
e if
her
tot
al i
nco
me
from
bo
th i
nve
stm
ents
was
$32
00.
4. M
ILK
Wh
ole
mil
k is
4%
bu
tter
fat.
How
mu
ch s
kim
mil
k w
ith
0%
bu
tter
fat
shou
ld b
e ad
ded
to 3
2 ou
nce
s of
wh
ole
mil
k to
obt
ain
a m
ixtu
re t
hat
is
2.5%
bu
tter
fat?
Exam
ple
21.6
g
15 lb
$16,
00
0 at
9%
an
d $
16,0
00
at 1
1%
19.2
oz
042_
060_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
5512
/22/
10
12:1
8 P
M
Answers (Lesson 2-8 and Lesson 2-9)
A15_A29_ALG1_A_CRM_C02_AN_661315.indd A26 12/22/10 1:07 PM
An
swer
s
Co
pyr
ight
© G
lenc
oe/
McG
raw
-Hill
, a d
ivis
ion
of
The
McG
raw
-Hill
Co
mp
anie
s, In
c.
Chapter 2 A27 Glencoe Algebra 1
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
2-9
Stud
y G
uide
and
Inte
rven
tion
(co
nti
nu
ed)
Weig
hte
d A
vera
ges
Cha
pte
r 2
56
Gle
ncoe
Alg
ebra
1
Un
ifo
rm M
oti
on
Pro
ble
ms
Mot
ion
pro
blem
s ar
e an
oth
er a
ppli
cati
on o
f w
eigh
ted
aver
ages
. Un
ifor
m m
otio
n p
rob
lem
s ar
e pr
oble
ms
wh
ere
an o
bjec
t m
oves
at
a ce
rtai
n
spee
d, o
r ra
te. U
se t
he
form
ula
d =
rt
to s
olve
th
ese
prob
lem
s, w
her
e d
is
the
dist
ance
, r i
s th
e ra
te, a
nd
t is
th
e ti
me.
DR
IVIN
G B
ill
Gu
tier
rez
dro
ve a
t a
spee
d o
f 65
mil
es p
er h
our
on a
n
exp
ress
way
for
2 h
ours
. He
then
dro
ve f
or 1
.5 h
ours
at
a sp
eed
of
45 m
iles
per
h
our
on a
sta
te h
igh
way
. Wh
at w
as h
is a
vera
ge s
pee
d?
M =
65 .
2 +
45
. 1.5
−
2
+ 1
.5
D
efi n
ition
of
wei
ghte
d av
erag
e
≈ 5
6.4
Sim
plify
.
Bil
l dr
ove
at a
n a
vera
ge s
peed
of
abou
t 56
.4 m
iles
per
hou
r.
Exer
cise
s 1
. TR
AV
EL M
r. A
nde
rs a
nd
Ms.
Ric
h e
ach
dro
ve h
ome
from
a b
usi
nes
s m
eeti
ng.
M
r. A
nde
rs t
rave
led
east
at
100
kilo
met
ers
per
hou
r an
d M
s. R
ich
tra
vele
d w
est
at 8
0 ki
lom
eter
s pe
r h
ours
. In
how
man
y h
ours
wer
e th
ey 1
00 k
ilom
eter
s ap
art.
2. A
IRPL
AN
ES A
n a
irpl
ane
flie
s 75
0 m
iles
du
e w
est
in 1
1 −
2 h
ours
an
d 75
0 m
iles
du
e so
uth
in
2 h
ours
. Wh
at i
s th
e av
erag
e sp
eed
of t
he
airp
lan
e?
3. T
RA
CK
Spr
inte
r A
ru
ns
100
met
ers
in 1
5 se
con
ds, w
hil
e sp
rin
ter
B s
tart
s 1.
5 se
con
ds
late
r an
d ru
ns
100
met
ers
in 1
4 se
con
ds. I
f ea
ch o
f th
em r
un
s at
a c
onst
ant
rate
, wh
o is
fu
rth
er i
n 1
0 se
con
ds a
fter
th
e st
art
of t
he
race
? E
xpla
in.
4. T
RA
INS
An
exp
ress
tra
in t
rave
ls 9
0 ki
lom
eter
s pe
r h
our
from
Sm
allv
ille
to
Meg
atow
n.
A l
ocal
tra
in t
akes
2.5
hou
rs l
onge
r to
tra
vel
the
sam
e di
stan
ce a
t 50
kil
omet
ers
per
hou
r. H
ow f
ar a
part
are
Sm
allv
ille
an
d M
egat
own
?
5. C
YC
LIN
G T
wo
cycl
ists
beg
in t
rave
lin
g in
th
e sa
me
dire
ctio
n o
n t
he
sam
e bi
ke p
ath
. On
e tr
avel
s at
15
mil
es p
er h
our,
and
the
oth
er t
rave
ls a
t 12
mil
es p
er h
our.
Wh
en w
ill
the
cycl
ists
be
10 m
iles
apa
rt?
6. T
RA
INS
Tw
o tr
ain
s le
ave
Ch
icag
o, o
ne
trav
elin
g ea
st a
t 30
mil
es p
er h
our
and
one
trav
elin
g w
est
at 4
0 m
iles
per
hou
r. W
hen
wil
l th
e tr
ain
s be
210
mil
es a
part
?
Exam
ple
5 −
9 h
abo
ut
429
mp
h
S
pri
nte
r A
; si
nce
sp
rin
ter
A r
un
s 10
0 m
in 1
5 s,
th
is s
pri
nte
r ru
ns
at a
r
ate
of
100
−
15
m/s
. In
10
seco
nd
s, s
pri
nte
r A
will
hav
e ru
n 10
0 −
15
(1
0) =
66.
7 m
.
S
pri
nte
r B
’s r
ate
is 10
0 −
14
. I
n 1
0 se
con
ds,
wit
h t
he
del
ayed
sta
rt, s
pri
nte
r B
h
as r
un
100
−
14
(10
- 1
.5)
= 6
0.7
m.
281.
25 k
m
3 h
3 1 −
3 h
042_
060_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
5612
/22/
10
12:1
8 P
M
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Lesson 2-9
Skill
s Pr
acti
ceW
eig
hte
d A
vera
ges
2-9
Cha
pte
r 2
57
Gle
ncoe
Alg
ebra
1
1.SE
ASO
NIN
G A
hea
lth
foo
d st
ore
sell
s se
ason
ing
blen
ds i
n b
ulk
. On
e bl
end
con
tain
s 20
% b
asil
. Sh
eila
wan
ts t
o ad
d pu
re b
asil
to
som
e 20
% b
len
d to
mak
e 16
ou
nce
s of
her
ow
n 3
0% b
len
d. L
et b
rep
rese
nt
the
amou
nt
of b
asil
Sh
eila
sh
ould
add
to
the
20%
ble
nd.
a.
Com
plet
e th
e ta
ble
repr
esen
tin
g th
e pr
oble
m.
Ou
nce
sA
mo
un
t o
f B
asil
20%
Bas
il B
len
d
100%
Bas
il
30%
Bas
il B
len
d
b
. W
rite
an
equ
atio
n t
o re
pres
ent
the
prob
lem
.
c.
How
man
y ou
nce
s of
bas
il s
hou
ld S
hei
la u
se t
o m
ake
the
30%
ble
nd?
d
. H
ow m
any
oun
ces
of t
he
20%
ble
nd
shou
ld s
he
use
?
2. H
IKIN
G A
t 7:
00 A
.M.,
two
grou
ps o
f h
iker
s be
gin
21
mil
es a
part
an
d h
ead
tow
ard
each
ot
her
. Th
e fi
rst
grou
p, h
ikin
g at
an
ave
rage
rat
e of
1.5
mil
es p
er h
our,
carr
ies
ten
ts,
slee
pin
g ba
gs, a
nd
cook
ing
equ
ipm
ent.
Th
e se
con
d gr
oup,
hik
ing
at a
n a
vera
ge r
ate
of 2
mil
es p
er h
our,
carr
ies
food
an
d w
ater
. Let
t r
epre
sen
t th
e h
ikin
g ti
me.
a.
Cop
y an
d co
mpl
ete
the
tabl
e re
pres
enti
ng
the
prob
lem
.
rt
d =
rt
Firs
t g
rou
p o
f h
iker
s
Sec
on
d g
rou
p o
f h
iker
s
b
. W
rite
an
equ
atio
n u
sin
g t
that
des
crib
es t
he
dist
ance
s tr
avel
ed.
c.
How
lon
g w
ill
it b
e u
nti
l th
e tw
o gr
oups
of
hik
ers
mee
t?
3. S
ALE
S S
ergi
o se
lls
a m
ixtu
re o
f Vir
gin
ia p
ean
uts
an
d S
pan
ish
pea
nu
ts f
or $
3.40
per
po
un
d. T
o m
ake
the
mix
ture
, he
use
s V
irgi
nia
pea
nu
ts t
hat
cos
t $3
.50
per
pou
nd
and
Spa
nis
h p
ean
uts
th
at c
ost
$3.0
0 pe
r po
un
d. H
e m
ixes
10
pou
nds
at
a ti
me.
a.
How
man
y po
un
ds o
f Vir
gin
ia p
ean
uts
doe
s S
ergi
o u
se?
b
. H
ow m
any
pou
nds
of
Spa
nis
h p
ean
uts
doe
s S
ergi
o u
se?
0.20
(16
- b
) +
1.0
0b =
0.3
0(16
)
2 o
z
14 o
z
1.5t
+ 2
t =
21
6 h
8 lb
2 lb
16 -
b0.
20(1
6 -
b)
b1.
00b
160.
30(1
6)
1.5
t1.
5t2
t2t
042_
060_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
5712
/22/
10
12:1
8 P
M
Answers (Lesson 2-9)
A15_A29_ALG1_A_CRM_C02_AN_661315.indd A27 12/22/10 1:07 PM
Co
pyrig
ht © G
lencoe/M
cGraw
-Hill, a d
ivision o
f The M
cGraw
-Hill C
om
panies, Inc.
Chapter 2 A28 Glencoe Algebra 1
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Prac
tice
Weig
hte
d A
vera
ges
2-9
Cha
pte
r 2
58
Gle
ncoe
Alg
ebra
1
1.G
RA
SS S
EED
A n
urs
ery
sell
s K
entu
cky
Blu
e G
rass
see
d fo
r $5
.75
per
pou
nd
and
Tal
l F
escu
e se
ed f
or $
4.50
per
pou
nd.
Th
e n
urs
ery
sell
s a
mix
ture
of
the
two
kin
ds o
f se
ed f
or
$5.2
5 pe
r po
un
d. L
et k
rep
rese
nt
the
amou
nt
of K
entu
cky
Blu
e G
rass
see
d th
e n
urs
ery
use
s in
5 p
oun
ds o
f th
e m
ixtu
re.
a.
Com
plet
e th
e ta
ble
repr
esen
tin
g th
e pr
oble
m.
Nu
mb
er o
f P
ou
nd
sP
rice
per
Po
un
dC
ost
Ken
tuck
y B
lue
Gra
ss
Tall
Fesc
ue
Mix
ture
b
. W
rite
an
equ
atio
n t
o re
pres
ent
the
prob
lem
.
c.
How
mu
ch K
entu
cky
Blu
e G
rass
doe
s th
e n
urs
ery
use
in
5 p
oun
ds o
f th
e m
ixtu
re?
d
. H
ow m
uch
Tal
l F
escu
e do
es t
he
nu
rser
y u
se i
n 5
pou
nds
of
the
mix
ture
?
2. T
RA
VEL
Tw
o co
mm
ute
r tr
ain
s ca
rry
pass
enge
rs b
etw
een
tw
o ci
ties
, on
e tr
avel
ing
east
, an
d th
e ot
her
wes
t, o
n d
iffe
ren
t tr
acks
. Th
eir
resp
ecti
ve s
tati
ons
are
150
mil
es a
part
. B
oth
tra
ins
leav
e at
th
e sa
me
tim
e, o
ne
trav
elin
g at
an
ave
rage
spe
ed o
f 55
mil
es p
er
hou
r an
d th
e ot
her
at
an a
vera
ge s
peed
of
65 m
iles
per
hou
r. L
et t
rep
rese
nt
the
tim
e u
nti
l th
e tr
ain
s pa
ss e
ach
oth
er.
a.
Cop
y an
d co
mpl
ete
the
tabl
e re
pres
enti
ng
the
prob
lem
.
rt
d =
rt
Firs
t Tra
in
Sec
on
d T
rain
b
. W
rite
an
equ
atio
n u
sin
g t
that
des
crib
es t
he
dist
ance
s tr
avel
ed.
c. H
ow l
ong
afte
r de
part
ing
wil
l th
e tr
ain
s pa
ss e
ach
oth
er?
3. T
RA
VEL
Tw
o tr
ain
s le
ave
Ral
eigh
at
the
sam
e ti
me,
on
e tr
avel
ing
nor
th, a
nd
the
oth
er
sou
th. T
he
firs
t tr
ain
tra
vels
at
50 m
iles
per
hou
r an
d th
e se
con
d at
60
mil
es p
er h
our.
In h
ow m
any
hou
rs w
ill
the
trai
ns
be 2
75 m
iles
apa
rt?
4. J
UIC
E A
pin
eapp
le d
rin
k co
nta
ins
15%
pin
eapp
le ju
ice.
How
mu
ch p
ure
pin
eapp
le ju
ice
shou
ld b
e ad
ded
to 8
qu
arts
of
the
pin
eapp
le d
rin
k to
obt
ain
a m
ixtu
re c
onta
inin
g 50
% p
inea
pple
juic
e?
5.75
k +
4.5
0(5
- k
) =
5.2
5(5)
3 lb
2 lb
55t
+ 6
5t =
150
1.25
h
2.5
h
5.6
qt
k$5
.75
5.75
k
5 -
k$4
.50
4.50
(5 -
k)
$5.2
55.
25(5
)5
55t
55t
65t
65t
042_
060_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
5812
/22/
10
12:1
8 P
M
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Lesson 2-9
Wor
d Pr
oble
m P
ract
ice
Weig
hte
d A
vera
ges
2-9
Cha
pte
r 2
59
Gle
ncoe
Alg
ebra
1
1. D
RIV
ING
Th
e dr
ive
from
New
Yor
k C
ity
to B
osto
n i
s ab
out
240
mil
es. I
t to
ok
Sam
ir 5
hou
rs t
o dr
ive
one
way
, bu
t du
e to
sev
ere
wea
ther
it
took
him
6.5
hou
rs
for
the
retu
rn t
rip.
Wh
at w
as h
is a
vera
ge
spee
d ro
un
d tr
ip?
Rou
nd
the
answ
er t
o th
e n
eare
st h
un
dred
th.
2. G
RA
DES
In
mat
h c
lass
es a
t G
orbi
ne
Hig
h S
choo
l, al
l te
sts
are
give
n d
oubl
e th
e w
eigh
t of
a q
uiz
or
hom
ewor
k sc
ore
wh
en c
alcu
lati
ng
grad
es. U
se D
onn
a’s
gr
ade
reco
rd s
hee
t to
det
erm
ine
her
av
erag
e gr
ade
so f
ar t
his
ter
m.
3. M
IXTU
RE
Kei
th w
ants
to
crea
te a
dri
nk
that
is
40%
juic
e. H
ow m
uch
of
a 10
%
juic
e so
luti
on s
hou
ld h
e ad
d to
100
m
illi
lite
rs o
f 10
0% g
rape
juic
e to
obt
ain
th
e 40
% m
ixtu
re?
4. B
USI
NES
S M
rs. W
insh
ip s
ells
ch
ocol
ate
fudg
e fo
r $7
.50
per
pou
nd
and
pean
ut
butt
er f
udg
e fo
r $7
.00
per
pou
nd.
Th
e to
tal
nu
mbe
r of
pou
nds
sol
d on
Sat
urd
ay
was
146
an
d th
e to
tal
amou
nt
of m
oney
co
llec
ted
was
$10
65. H
ow m
any
pou
nds
of
eac
h t
ype
of f
udg
e w
ere
sold
?
5. T
RA
INS
Tw
o tr
ain
s ar
e 50
00 f
eet
apar
t,
hea
din
g to
war
d ea
ch o
ther
, bu
t on
se
para
te p
aral
lel
stra
igh
t tr
acks
, Tra
in A
is
tra
veli
ng
at 4
5 m
iles
per
hou
r an
d T
rain
B i
s tr
avel
ing
at 2
4 m
iles
per
hou
r.
a.
Ch
ange
45
mil
es p
er h
our
and
24
mil
es p
er h
our
into
fee
t pe
r se
con
d.
b
. A
bou
t h
ow f
ar w
ill
each
tra
in t
rave
l be
fore
th
ey m
eet?
Rou
nd
you
r an
swer
s to
th
e n
eare
st h
un
dred
th.
c. In
how
man
y se
con
ds w
ill T
rain
A a
nd
Tra
in B
mee
t?
A
ssig
nm
ent
Gra
de
H
omew
ork
chap
ter
1 95
Q
uiz
chap
ter
1 80
Te
st c
hapt
er 1
92
H
omew
ork
chap
ter
2 93
Q
uiz
chap
ter
2 96
Te
st c
hapt
er 2
81
4
1.74
mile
s p
er h
ou
r
8
8.75
2
00
mL
8
6 p
ou
nd
s o
f ch
oco
late
an
d 6
0 p
ou
nd
s o
f p
ean
ut
butt
er
Trai
n A
: 66
fee
t p
er s
eco
nd
Tr
ain
B:
35.2
fee
t p
er s
eco
nd
Trai
n A
: 32
60.8
7 fe
etTr
ain
B:
1739
.13
feet
49.4
sec
on
ds
042_
060_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
5912
/22/
10
12:1
8 P
M
Answers (Lesson 2-9)
A15_A29_ALG1_A_CRM_C02_AN_661315.indd A28 12/22/10 1:07 PM
An
swer
s
Co
pyr
ight
© G
lenc
oe/
McG
raw
-Hill
, a d
ivis
ion
of
The
McG
raw
-Hill
Co
mp
anie
s, In
c.
Chapter 2 A29 Glencoe Algebra 1
Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc.
NA
ME
DAT
E
P
ER
IOD
Enri
chm
ent
2-9
Cha
pte
r 2
60
Gle
ncoe
Alg
ebra
1
Exp
ecte
d V
alu
eE
xpec
ted
valu
e is
th
e av
erag
e re
turn
of
an e
ven
t ov
er r
epea
ted
tria
l. E
xpec
ted
valu
e is
als
o a
form
of
wei
ghte
d av
erag
e an
d ca
n b
e u
sed
to d
eter
min
e w
het
her
or
not
you
sh
ould
pla
y a
gam
e ba
sed
on w
hat
th
e ex
pect
ed v
alu
e of
you
r w
inn
ings
is.
It
can
als
o be
use
d to
det
erm
ine
the
expe
cted
len
gth
of
a ga
me.
Y
ou a
re r
olli
ng
a d
ie t
o d
eter
min
e th
e n
um
ber
of
can
dy
bar
s yo
u
wil
l w
in a
t a
sch
ool
fair
. If
you
rol
l a
one,
you
get
12
can
dy
bar
s. I
f yo
u r
oll
a tw
o or
a t
hre
e, y
ou g
et 3
can
dy
bar
s. I
f yo
u r
oll
a fo
ur,
fiv
e or
six
, you
get
2
can
dy
bar
s.
Sin
ce t
her
e ar
e si
x po
ssib
ilit
ies
for
wh
at y
ou c
an r
oll:
•
1 −
6 o
f th
e ti
me,
you
wil
l w
in 1
2 ca
ndy
bar
s.
•
2 −
6 o
r 1 −
3 o
f th
e ti
me,
you
wil
l w
in 3
can
dy b
ars.
•
3 −
6 o
r 1 −
2 o
f th
e ti
me,
you
wil
l w
in 2
can
dy b
ars.
Th
e ex
pect
ed v
alu
e is
1 −
6 (1
2) +
1 −
3 (3
) +
1 −
2 (2
) or
4 c
andy
bar
s.
Th
eref
ore,
if
you
pla
yed
the
gam
e 10
0 ti
mes
, you
cou
ld e
xpec
t to
win
abo
ut
4 ca
ndy
bar
s ea
ch t
ime.
Exer
cise
sF
ind
th
e ex
pec
ted
val
ue
of e
ach
of
the
foll
owin
g ev
ents
.
1. Y
ou a
re f
lipp
ing
a co
in. I
f yo
u f
lip
hea
ds, y
ou w
in $
5.00
. If
you
fli
p ta
ils,
you
win
$1.
00.
2. Y
ou a
re r
olli
ng
a di
e to
det
erm
ine
the
nu
mbe
r of
can
dy b
ars
you
wil
l w
in a
t a
sch
ool
fair
. If
you
rol
l a
1, y
ou g
et 1
8 ca
ndy
bar
s. I
f yo
u r
oll
a 2
or a
3, y
ou g
et 6
can
dy b
ars.
If
you
ro
ll a
4, 5
or
6, y
ou g
et 0
can
dy b
ars.
3. Y
ou a
re r
olli
ng
a di
e to
det
erm
ine
the
amou
nt
of m
oney
you
wil
l w
in a
t a
sch
ool
fair
. If
you
rol
l a
1, y
ou g
et $
12.0
0.
If y
ou r
oll
a 2
or a
3, y
ou g
et $
3.00
. If
you
rol
l a
4, 5
or
6,
you
ow
e $2
.00.
4. Y
ou a
re f
lipp
ing
a co
in. I
f yo
u f
lip
hea
ds, y
ou w
in $
10. I
f yo
u f
lip
tail
s, y
ou w
in $
2.
5. Y
ou a
re r
olli
ng
a di
e to
det
erm
ine
the
nu
mbe
r of
can
dy b
ars
you
wil
l w
in a
t a
sch
ool
fair
. If
you
rol
l a
1, y
ou g
et 2
4 ca
ndy
bar
s.
If y
ou r
oll
a 2
or a
3, y
ou g
et 6
can
dy b
ars.
If
you
ro
ll a
4, 5
or
6, y
ou g
et n
one.
Exam
ple
$3.0
0
5 $2.0
0
$6.0
0
6
042_
060_
ALG
1_A
_CR
M_C
02_C
R_6
6131
5.in
dd
6012
/22/
10
12:1
8 P
M
Answers (Lesson 2-9)
A15_A29_ALG1_A_CRM_C02_AN_661315.indd A29 12/22/10 1:07 PM
Chapter 2 Assessment Answer Key Quiz 1 (Lessons 2-1 through 2-3) Quiz 3 (Lessons 2-6 and 2-7) Mid Chapter TestPage 63 Page 64 Page 65
Quiz 2 (Lessons 2-4 and 2-5)
Page 63 Quiz 4 (Lessons 2-8 and 2-9) Page 64
Part I
Part II
Co
pyrig
ht © G
lencoe/M
cGraw
-Hill, a d
ivision o
f The M
cGraw
-Hill C
om
panies, Inc.
Chapter 2 A30 Glencoe Algebra 1
1.
2.
3.
4.
5.
6.
7.
8.
9.
10.
y 2 - 12 = 5x
Two times b minus 10 equals 4.The sum of y and the product of 3 and the square of x is 5 times x.
14
-49
-9
40
1.
2.
3.
4.
5.
6.
7.
8.
9.
10.
7
84
-5
no solution
0
7
C
D
11
5
-5
{2, 5}
{-6, 7}
1.
2.
3.
4.
5.
6.
7.
8.
9.
10. B
$19.08
increase; 25%
decrease; 28%
99
27
15
no
no
yes
1.
2.
3.
4.
5.
6. G
H
A
J
7.
8.
9.
10.
11.
12. {-2, 5}
Four times n equals x times the difference of fi ve and n.
$116.15
-2
B
0
all numbers
B
-3 -2 -1 0 1 2 3 4 5
1.
2.
3.
4.
5. ℓ =
p - 2w
_ 2 ; 14 m
A
4 g
b = x - ac
x = p + r
_
n
A30_A35_ALG1_A_CRM_C02_AN_661315.indd A30 12/22/10 1:07 PM
Chapter 2 Assessment Answer KeyVocabulary Test Form 1Page 66 Page 67 Page 68
B
Co
pyr
ight
© G
lenc
oe/
McG
raw
-Hill
, a d
ivis
ion
of
The
McG
raw
-Hill
Co
mp
anie
s, In
c.
An
swer
s
Chapter 2 A31 Glencoe Algebra 1
1.
2.
3.
4.
5.
6.
7.
ratio
weighted average
percent of change
rate
multi-step equation
unit rate
identity
1.
2.
3.
4.
5.
6.
7.
8.
9.
10.
F
C
D
J
A
G
B
D
H
G
F
B
J
B
H
C
J
A
H
B 11.
12.
13.
14.
15.
16.
17.
18.
19.
20.
B: 45
8.
9.
Sample answer: A proportion is an equation stating that two ratios are equal.
Sample answer: A formula is an equation that states a rule for the relationship between certain quantities.
A30_A35_ALG1_A_CRM_C02_AN_661315.indd A31 12/22/10 1:07 PM
Chapter 2 Assessment Answer KeyForm 2A Form 2BPage 69 Page 70 Page 71 Page 72
Co
pyrig
ht © G
lencoe/M
cGraw
-Hill, a d
ivision o
f The M
cGraw
-Hill C
om
panies, Inc.
Chapter 2 A32 Glencoe Algebra 1
1.
2.
3.
4.
5.
6.
7.
8.
9.
10. G
G
C
F
D
H
A
J
C
C
11.
12.
13.
14.
15.
16.
17.
18.
19.
20. H
B
F
D
G
C
G
C
F
B
B: 4 L
11.
12.
13.
14.
15.
16.
17.
18.
19.
20. H
A
F
B
J
B
F
C
J
B
B: 21
1.
2.
3.
4.
5.
6.
7.
8.
9.
10. G
B
J
A
J
A
H
C
H
B
A30_A35_ALG1_A_CRM_C02_AN_661315.indd A32 12/22/10 1:07 PM
Chapter 2 Assessment Answer KeyForm 2CPage 73 Page 74
Co
pyr
ight
© G
lenc
oe/
McG
raw
-Hill
, a d
ivis
ion
of
The
McG
raw
-Hill
Co
mp
anie
s, In
c.
An
swer
s
Chapter 2 A33 Glencoe Algebra 1
15.
16.
17.
18.
19.
20.
21.
22.
23.
24.
25.
B: 8
2.5 h
3 L
$12.84
22.5
yes
-1
all numbers
13
x = bc
_ a
decrease; 20%
h = V
_ πr2
; 10.5 in.
1.
2.
3.
4.
5.
6.
7.
8.
9.
10.
11.
12.
13.
14.
$134.40
5n + 12 = -3; -3
n - 3.5 = 12.7; 16.2
Three times the sum of x and y equals two
times y minus x.
36 - x = 3(4 + x)
6
45
14 2 _ 5
5
-5
-9
3
{-1, 7 _ 5 }
{-1, 0}-4 -3 -2 -1 0 1 2 3 4
-4 -3 -2 -1 0 1 2 3 4
A30_A35_ALG1_A_CRM_C02_AN_661315.indd A33 12/22/10 1:07 PM
Chapter 2 Assessment Answer KeyForm 2DPage 75 Page 76
Co
pyrig
ht © G
lencoe/M
cGraw
-Hill, a d
ivision o
f The M
cGraw
-Hill C
om
panies, Inc.
Chapter 2 A34 Glencoe Algebra 1
15.
16.
17.
18.
19.
20.
21.
22.
23.
24.
25.
B: $9.60
4 h
7.5 lb of nuts, 2.5 lb of dried fruit
$13.50
increase; 25%
r = n(4v - t)
11
no solution
3
20
no
h = V
_ πr2
; 18.67 in.
1.
2.
3.
4.
5.
6.
7.
8.
9.
10.
11.
12.
13.
14.
$176.80
n - 8.1 = 4.9; 13
7
50
7 5 _ 7
7
4
Three divided by y minus fi ve equals x times the sum of y and 7.
18 + n = 7(n - 3)
6n + 15 = 9; -1
11
{-3, -1}
{-4, -2}
-4 -3 -2 -1 0 1 2 3 4
-4 -3 -2 -1 0 1 2 3 4
7
A30_A35_ALG1_A_CRM_C02_AN_661315.indd A34 12/22/10 1:07 PM
Chapter 2 Assessment Answer KeyForm 3Page 77 Page 78
Co
pyr
ight
© G
lenc
oe/
McG
raw
-Hill
, a d
ivis
ion
of
The
McG
raw
-Hill
Co
mp
anie
s, In
c.
An
swer
s
Chapter 2 A35 Glencoe Algebra 1
1.
2.
3.
4.
5.
6.
7.
8.
9.
10.
11.
12.
13.
14.
15. 10 ft
yes
10
Five times the sum of two times x and three times y equals the square of y minus two times the cube of x.
(x + 2)10 = 8x + 36; 8
3 _ 5 x = 1; 5 _
3
8
126
-1 2 _ 13
-2 2 _ 3
-13
-27
{-7, -5}
$4000
-8 -7 -6 -4 -3 -2 -1-5 0
x - 45 _ 12
+ 20 = 5(32 + x)
16.
17.
18.
19.
20.
21.
22.
23.
24.
25.
B: 12 mi
1.95 ft/s
510 mph, 540 mph
$7000
$63.60
increase; 12%
x = ry - t
_ 4
x = r + n _
a
2
- 7 _ 9
- 6
A30_A35_ALG1_A_CRM_C02_AN_661315.indd A35 12/22/10 1:07 PM
Chapter 2 Assessment Answer Key
Page 79, Extended-Response Test Scoring Rubric
Score General Description Specifi c Criteria
4 SuperiorA correct solution that is supported by well-developed, accurate explanations
• Shows thorough understanding of the concepts of translating between verbal sentences and equations, solving equations, percents of increase and decrease, uniform motion problems, and proportions.
• Uses appropriate strategies to solve problems. • Computations are correct. • Written explanations are exemplary. • Goes beyond requirements of some or all problems.
3 Satisfactory A generally correct solution, but may contain minor fl aws in reasoning or computation
• Shows an understanding of the concepts of translating between verbal sentences and equations, solving equations, percents of increase and decrease, uniform motion problems, and proportions.
• Uses appropriate strategies to solve problems. • Computations are mostly correct. • Written explanations are effective. • Satisfi es all requirements of problems.
2 Nearly SatisfactoryA partially correct interpretation and/or solution to the problem
• Shows an understanding of most of the concepts of translating between verbal sentences and equations, solving equations, percents of increase and decrease, uniform motion problems, and proportions.
• May not use appropriate strategies to solve problems. • Computations are mostly correct. • Written explanations are satisfactory. • Satisfi es the requirements of most of the problems.
1 Nearly Unsatisfactory A correct solution with no supporting evidence or explanation
• Final computation is correct. • No written explanations or work is shown to substantiate the
fi nal computation. • Satisfi es minimal requirements of some of the problems.
0 UnsatisfactoryAn incorrect solution indicating no mathematical understanding of the concept or task, or no solution is given
• Shows little or no understanding of most of the concepts of translating between verbal sentences and equations, solving equations, percents of increase and decrease, uniform motion problems, and proportions.
• Does not use appropriate strategies to solve problems. • Computations are incorrect. • Written explanations are unsatisfactory. • Does not satisfy requirements of problems. • No answer may be given.
Co
pyrig
ht © G
lencoe/M
cGraw
-Hill, a d
ivision o
f The M
cGraw
-Hill C
om
panies, Inc.
Chapter 2 A36 Glencoe Algebra 1
A36_A46_ALG1_A_CRM_C02_AN_661315.indd A36 12/22/10 1:07 PM
Chapter 2 Assessment Answer Key Page 79, Extended-Response Test Sample Answers
1a. The student should explain that the first phrase is a product of x and y and then the addition of z, while the second phrase is a product of x and the quantity y + z.
1b. Check that the student’s values for x, y, and z satisfy both xy + z and x(y + z). One example is x = 1, y = 2, and z = 3. Another example is x = 2, y = 3, and z = 0.
2a. ry + z
_ m - t = x
(Original equation)
ry + z
_ m - t + t = x + t
(Add t to each side.)
ry + z
_ m = x + t
(Simplify.)
m ( ry + z _ m ) = m(x + t)
(Multiply each side by m.)
ry + z = mx + mt (Simplify.)
ry + z - z = mx + mt - z (Subtract z from each side.)
ry = mx + mt - z (Simplify.)
ry
_ r = mx + mt - z _ r
(Divide each side by r.)
y = mx + mt - z _ r
(Simplify.)
The value of y is mx + mt - z __ r
2b. Division by 0 is undefined, so in the original equation m ≠ 0, and in the final equation r ≠ 0.
3a. The student should conclude that a 10% decrease followed by a 10% increase results in a net decrease of 1%. Thus, the final cost would be 99% of the original price.
3b. Since multiplication is commutative, multiplying by 1.1 and then 0.9 would yield the same result as multiplying by 0.9 and then 1.1. The student should conclude that a 10% increase followed by a 10% decrease yields the same result as a 10% decrease followed by a 10% increase.
4a. Since the two people walked for the same amount of time and time can be calculated as distance divided by rate, the proportion
Tony’s distance __
Tony’s rate =
can be used to solve this problem.
4b. The length of Tony’s walk can be calculated directly from his rate of 3 miles per hour and his distance of 6 miles. Ivia walked 1 mile per hour faster, so her rate is 4 miles per hour. The length of Ivia’s walk can be calculated directly from her rate of 4 miles per hour and distance of 6 miles. Thus, a proportion would not be used to solve this problem.
5a. Sample answer: x + 2 = 10, x - 2 = 6, 2x = 16, x _
2 = 4
5b. Sample answer: 2x + 1 = x + 9
5c. These two equations are equivalent. The solution to both equations is 5. The student should recognize that the solution to all equations in parts a and b is 8. Therefore neither of these two equations could be equivalent to any of the equations created for parts a and b.
In addition to the scoring rubric found on page A40, the following sample answers may be used as guidance in evaluating extended-response assessment items.
Ivia’s distance __ Ivia’s rate
Co
pyr
ight
© G
lenc
oe/
McG
raw
-Hill
, a d
ivis
ion
of
The
McG
raw
-Hill
Co
mp
anie
s, In
c.
An
swer
s
Chapter 2 A37 Glencoe Algebra 1
A36_A46_ALG1_A_CRM_C02_AN_661315.indd A37 12/22/10 1:07 PM
Chapter 2 Assessment Answer KeyStandardized Test Practice
Page 80 Page 81
15.
9
8
7
6
5
4
3
2
1
0
9
8
7
6
5
4
3
2
1
0
9
8
7
6
5
4
3
2
1
0
9
8
7
6
5
4
3
2
1
0
9
8
7
6
5
4
3
2
1
0
1
16.
9
8
7
6
5
4
3
2
1
0
9
8
7
6
5
4
3
2
1
0
9
8
7
6
5
4
3
2
1
0
9
8
7
6
5
4
3
2
1
0
9
8
7
6
5
4
3
2
1
0
42
Co
pyrig
ht © G
lencoe/M
cGraw
-Hill, a d
ivision o
f The M
cGraw
-Hill C
om
panies, Inc.
Chapter 2 A38 Glencoe Algebra 1
1.
2.
3.
4.
5.
6.
7.
8.
9. A B C D
F G H J
A B C D
F G H J
A B C D
F G H J
A B C D
A B C D
F G H J
10.
11.
12.
13.
14. F G H J
A B C D
F G H J
A B C D
F G H J
A36_A46_ALG1_A_CRM_C02_AN_661315.indd A38 12/22/10 1:07 PM
Chapter 2 Assessment Answer KeyStandardized Test PracticePage 82
Co
pyr
ight
© G
lenc
oe/
McG
raw
-Hill
, a d
ivis
ion
of
The
McG
raw
-Hill
Co
mp
anie
s, In
c.
An
swer
s
Chapter 2 A39 Glencoe Algebra 1
17.
18.
19. Sample answer:
20.
21.
22.
23.
24.
25.
26.
27a.
27b.
7 L
m = x(t - p)
3
-3
7
31
85 - 9y = 7(4 + y)
5u + 9x
22
No; since multiplication is commutative, a 10% increase followed by a 10% decrease would have the same result as a 10% decrease followed by a 10% increase.
y
xO
The fi nal price would be 99% of the original price.
A36_A46_ALG1_A_CRM_C02_AN_661315.indd A39 12/22/10 1:07 PM
Chapter 2 Assessment Answer KeyUnit 1 TestPage 83 Page 84
Co
pyrig
ht © G
lencoe/M
cGraw
-Hill, a d
ivision o
f The M
cGraw
-Hill C
om
panies, Inc.
Chapter 2 A40 Glencoe Algebra 1
1.
2.
3.
4.
5.
6.
7.
8.
9.
10.
11.
12.
13.
14.
15.
16.
Sample answer: the difference of m squared
and 4 is equal to the sum of 2 times r plus 1
6x + 12
Time
Tem
per
atu
re (
°F)
False
23a + 6b
7r + 9t
7t2 + 3t
Multiplicative Inverse Property; 1 _
6
{4}
71
5 - n 3
Sample answer: Four math textbooks are stacked on top of two science textbooks. Write an expression for the total height of the stack of books.
yes
no
8
Sample answer: the sum of four times r and 9
17.
18.
19.
20.
21.
22.
23.
24.
25.
26.
27.
28.
29.
30. 8 lb
v = t - kr
$3.91
3 2 _ 7
11
-2
56
42
-12
-18
1
all real numbers
yes-2-3 -1 0 1 2 4 5 6 7 83
{-2, 3}
A36_A46_ALG1_A_CRM_C02_AN_661315.indd A40 12/22/10 1:07 PM
