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Angles in Polygons

Angles in Polygons. Sums of Interior Angles TriangleQuadrilateralPentagon Heptagon Octagon Hexagon = 2 triangles = 3 triangles = 4 triangles = 5 triangles=

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Page 1: Angles in Polygons. Sums of Interior Angles TriangleQuadrilateralPentagon Heptagon Octagon Hexagon = 2 triangles = 3 triangles = 4 triangles = 5 triangles=

Angles in Polygons

Page 2: Angles in Polygons. Sums of Interior Angles TriangleQuadrilateralPentagon Heptagon Octagon Hexagon = 2 triangles = 3 triangles = 4 triangles = 5 triangles=

Sums of Interior Angles

Triangle Quadrilateral Pentagon

Heptagon OctagonHexagon

= 2 triangles = 3 triangles

= 4 triangles= 5 triangles = 6 triangles

Page 3: Angles in Polygons. Sums of Interior Angles TriangleQuadrilateralPentagon Heptagon Octagon Hexagon = 2 triangles = 3 triangles = 4 triangles = 5 triangles=

Convex Polygon

# of Sides # of Triangles

Sum of Interior Angles

Triangle

Quadrilateral

Pentagon

Hexagon

Heptagon

Octagon

n-gon

3

4

5

6

7

8

n

1

2

3

4

5

6

n – 2

180360

540

720

900

1080

180•(n – 2)

Page 4: Angles in Polygons. Sums of Interior Angles TriangleQuadrilateralPentagon Heptagon Octagon Hexagon = 2 triangles = 3 triangles = 4 triangles = 5 triangles=

Find the measure of the missing angle in the figure below

100135

70x

135 + 100 + 70 + x =

quadrilateral

360305 + x = 360

-305 -305x = 55

Page 5: Angles in Polygons. Sums of Interior Angles TriangleQuadrilateralPentagon Heptagon Octagon Hexagon = 2 triangles = 3 triangles = 4 triangles = 5 triangles=

m1 =1

2

3

110

(5x - 5)

(4x + 15)

(8x - 10)

pentagon5x - 5 + 4x + 15 + 8x - 10 + 110 + 90 = 540

17x + 200= 540 -200 -200

17x = 340

x = 20 17 17

5(20) - 5

= 95

Find m1.

Page 6: Angles in Polygons. Sums of Interior Angles TriangleQuadrilateralPentagon Heptagon Octagon Hexagon = 2 triangles = 3 triangles = 4 triangles = 5 triangles=

12

34

5 6

Exterior Angles

Interior Angles

Page 7: Angles in Polygons. Sums of Interior Angles TriangleQuadrilateralPentagon Heptagon Octagon Hexagon = 2 triangles = 3 triangles = 4 triangles = 5 triangles=

Sum of Interior Angles =

Sum of Interior & Exterior Angles =

180

12

34

5 6

180

180

180

540

Sum of Exterior Angles = 360 540- 180=

Sums of Exterior Angles

180•3 = 540

Page 8: Angles in Polygons. Sums of Interior Angles TriangleQuadrilateralPentagon Heptagon Octagon Hexagon = 2 triangles = 3 triangles = 4 triangles = 5 triangles=

180

180

180

180

Sum of Interior Angles =

Sum of Interior & Exterior Angles =

360 720

Sum of Exterior Angles = 360 720- 360=

Sums of Exterior Angles

180•4 = 720

Page 9: Angles in Polygons. Sums of Interior Angles TriangleQuadrilateralPentagon Heptagon Octagon Hexagon = 2 triangles = 3 triangles = 4 triangles = 5 triangles=

Sum of Exterior Angles

180 180

180

180

180

Sum of Interior Angles =

Sum of Interior & Exterior Angles =

Sum of Exterior Angles = 360 900- 540=

900

540°

180•5 = 900

Page 10: Angles in Polygons. Sums of Interior Angles TriangleQuadrilateralPentagon Heptagon Octagon Hexagon = 2 triangles = 3 triangles = 4 triangles = 5 triangles=

Sum of Exterior Angles

Sum of Interior Angles = Sum of Interior & Exterior Angles =

Sum of Exterior Angles =

180

180180

180

180

180

360 1080- 720=

1080720°

180•6 = 1080

Page 11: Angles in Polygons. Sums of Interior Angles TriangleQuadrilateralPentagon Heptagon Octagon Hexagon = 2 triangles = 3 triangles = 4 triangles = 5 triangles=

Sums of Exterior Angles

Polygon # of Sides

Interior +

Exterior

Interior Angles

Exterior Angles

Triangle 3

Quadrilateral 4

Pentagon 5

Hexagon 6

180

360

540

720

540

720

900

1080

360

360

360

360Sum of Exterior Angles

is always 360!

Page 12: Angles in Polygons. Sums of Interior Angles TriangleQuadrilateralPentagon Heptagon Octagon Hexagon = 2 triangles = 3 triangles = 4 triangles = 5 triangles=

Angles of Regular Polygons

Sum of the Interior Angles

Sum of the Exterior Angles

Each Interior Anglen

Each Exterior Angle n

180(n – 2)

Always 360!

180(n – 2)

360

Page 13: Angles in Polygons. Sums of Interior Angles TriangleQuadrilateralPentagon Heptagon Octagon Hexagon = 2 triangles = 3 triangles = 4 triangles = 5 triangles=

Find the sum of the measures of the interior angles of a regular dodecagon.

180•(n – 2) = 180•(12 – 2)

n = 12

= 180•(10)= 1800 all 12 angles

= 150180012

each angle

What is the measure of each angle?

Page 14: Angles in Polygons. Sums of Interior Angles TriangleQuadrilateralPentagon Heptagon Octagon Hexagon = 2 triangles = 3 triangles = 4 triangles = 5 triangles=

The sum of the interior angles of a convex polygon is 1440.

How many sides does the polygon have?

180•(n – 2) = 1440

180n = 1800+ 360 +360

180 180

n = 10 10 sides

180n – 360 = 1440

Page 15: Angles in Polygons. Sums of Interior Angles TriangleQuadrilateralPentagon Heptagon Octagon Hexagon = 2 triangles = 3 triangles = 4 triangles = 5 triangles=

Exterior Angles

What is the measure of each exterior angle of a regular hexagon?

360

6 sides

6= 60

Page 16: Angles in Polygons. Sums of Interior Angles TriangleQuadrilateralPentagon Heptagon Octagon Hexagon = 2 triangles = 3 triangles = 4 triangles = 5 triangles=

The measure of each exterior angle of a regular polygon is 20. How many

sides does it have?

20360 = 18

The measure of each interior angle of a regular polygon is 120. How many

sides does it have?

60360 = 6

180 - 120 = 60

exterior angle

Page 17: Angles in Polygons. Sums of Interior Angles TriangleQuadrilateralPentagon Heptagon Octagon Hexagon = 2 triangles = 3 triangles = 4 triangles = 5 triangles=

Find the sum of the interior angles of a 100-gon!

Find the sum of the exterior angles of a 100-gon.

Find the measure of each interior angle of a 100-gon.

Find the measure of each exterior angle of a 100-gon.