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Algebra II Honors—Day 69

Algebra II Honors—Day 69

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Algebra II Honors—Day 69. Warmup. Solve and check: Find the next four terms of this arithmetic sequence: 207, 194, 181, . . . Find the indicated term of this arithmetic sequence:. Warmup. Check both solutions!!!. -13. -13. -13. -13. Warmup. - PowerPoint PPT Presentation

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Algebra II Honors—Day 69

Warmup

• Solve and check:

• Find the next four terms of this arithmetic sequence:207, 194, 181, . . .

• Find the indicated term of this arithmetic sequence:

1119 xx

21,8,801 nda

Warmup

4or 3

0)4)(3(

0127

12119

)1(119

1119

2

2

2

xx

xx

xx

xxx

xx

xx

416

41127

1)3(11)3(9

Check both solutions!!!

525

51136

1)4(11)4(9

Warmup

• Find the next four terms of this arithmetic sequence:207, 194, 181, . . .

What is the common difference?? (194-207=-13 and 181-194=-13, so d=-13)

207, 194, 181, 168, 155, 142, 129

-13 -13 -13 -13

Warmup

• Find the indicated term of this arithmetic sequence:

21,8,801 nda

dnaan )1(1

8016080

)8)(20(80

)8)(121(80

21

21

21

a

a

a

Today

• Finish up Arithmetic Sequences and Series

• Essential Question/New Material

• Homework

Essential Questions

• What is an arithmetic series and how is it calculated?

• What is a geometric sequence?

• What is a geometric series, and how is it calculated?

B

nn A

a

UPPER BOUND(NUMBER)

LOWER BOUND(NUMBER)

SIGMA(SUM OF TERMS) NTH TERM

(SEQUENCE)

Sigma Notation

n (Index of

summation)

An arithmetic series is a series associated with an arithmetic sequence.

The sum of the first n terms:

12n n

nS a a

1(2 ( 1) )2n

nS a n d

OR

Find the sum of the first 100 natural numbers.

1 + 2 + 3 + 4 + … + 100

12n n

nS a a 1 1a

100na 100n

100

100(1 100)

2S

5050

Find the sum of the first 14 terms of the arithmetic series 2 + 5 + 8 + 11 + 14 + 17 +…

1 2a 3d 14n

1(2 ( 1) )2n

nS a n d

14

14(2(2) (14 1)3)

2S

14 7(3 13(3))S 7(43)301

j

4

1

j 2

21 2 2 3 2 24 18

7

4a

2a 42 2 5 2 6 72 44

n

n 0

4

0.5 2

00.5 2 10.5 2 20.5 2 30.5 2 40.5 2

33.5

Find the sum of the series

13

1

(4 5)n

n

9 13 17 ....

1 9a 4d 13n 1(2 ( 1) )

2n

nS a n d

13

13(2(9) (13 1)4)

2S

13(66)

2 429

12.2 – Geometric Sequences and Series

1, 4, 7,10,13

9,1, 7, 15

6.2, 6.6, 7, 7.4

, 3, 6

Arithmetic Sequences

ADDTo get next term

2, 4, 8,16, 32

9, 3,1, 1/ 3

1,1/ 4,1/16,1/ 64

, 2.5 , 6.25

Geometric Sequences

MULTIPLYTo get next term

Arithmetic Series

Sum of Terms

35

12

27.2

3 9

Geometric Series

Sum of Terms

62

20 / 3

85 / 64

9.75

Vocabulary of Sequences (Universal)

1a First term

na nth term

nS sum of n terms

n number of terms

r common ratio

n 1

n 1

n1

n

nth term of geometric sequence

sum of n terms of geometric sequ

a a r

a r 1S

r 1ence

Recursive Formula:

an+1=an(r)

ExplicitFormula

Find the next three terms of 2, 3, 9/2, ___, ___, ___

3 – 2 vs. 9/2 – 3… not arithmetic

3 9 / 2 31.5 geometric r

2 3 2

3 3 3 3 3 3

2 2 2

92, 3, , , ,

2

9 9 9

2 2 2 2 2 2

92, 3, , ,

27 81 243

4 8,

2 16

1 9

1 2If a , r , find a .

2 3

1a First term

na nth term

nS sum of n terms

n number of terms

r common ratio

1/2

x

9

NA

2/3

n 1n 1a a r

9 11 2

x2 3

8

8

2x

2 3

7

8

2

3 128

6561

Find two geometric means between –2 and 54

-2, ____, ____, 54

1a First term

na nth term

nS sum of n terms

n number of terms

r common ratio

-2

54

4

NA

x

n 1n 1a a r

1454 2 x

327 x 3 x

The two geometric means are 6 and -18, since –2, 6, -18, 54

forms a geometric sequence

2 4 1

2Find a a if a 3 and r

3

-3, ____, ____, ____

2Since r ...

3

4 83, 2, ,

3 9

2 4

8 10a a 2

9 9

9Find a of 2, 2, 2 2,...

1a First term

na nth term

nS sum of n terms

n number of terms

r common ratio

x

9

NA

2

2 2 2r 2

22

n 1n 1a a r

9 1

x 2 2

8

x 2 2

x 16 2

5 2If a 32 2 and r 2, find a

____, , ____,________ ,32 2

1a First term

na nth term

nS sum of n terms

n number of terms

r common ratio

x

5

NA

32 2

2n 1

n 1a a r

5 1

32 2 x 2

4

32 2 x 2

32 2 x4

8 2 x

*** Insert one geometric mean between ¼ and 4***

*** denotes trick question

1,____,4

4

1a First term

na nth term

nS sum of n terms

n number of terms

r common ratio

1/4

3

NA

4

xn 1

n 1a a r

3 114

4r 2r

14

4 216 r 4 r

1,1, 4

4

1, 1, 4

4

7

1 1 1Find S of ...

2 4 8

1a First term

na nth term

nS sum of n terms

n number of terms

r common ratio

1/2

7

x

NA

11184r

1 1 22 4

n1

n

a r 1S

r 1

71 12 2

x12

1

1

71 12 2

12

1

128

127

Section 12.3 – Infinite Series

1, 4, 7, 10, 13, …. Infinite Arithmetic No Sum

3, 7, 11, …, 51 Finite Arithmetic n 1 n

nS a a

2

1, 2, 4, …, 64 Finite Geometric n

1

n

a r 1S

r 1

1, 2, 4, 8, … Infinite Geometricr > 1r < -1

No Sum

1 1 13,1, , , ...

3 9 27Infinite Geometric

-1 < r < 11a

S1 r

Sequence Type Series

Find the sum, if possible: 1 1 1

1 ...2 4 8

1 112 4r

11 22

1 r 1 Yes

1a 1S 2

11 r 12

Find the sum, if possible: 2 2 8 16 2 ...

8 16 2r 2 2

82 2 1 r 1 No

NO SUM

Homework

• Handout on Arithmetic and Geometric Sequences/Series—Due Tuesday for a grade