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Accelerated Macro Spring 2015 Solutions to HW #2 1 Money demand and the velocity of money ABC Ch. 7 NP #2 Money demand in an economy in which no interest is paid on money is M d P = 500 + 0.2Y - 1000i. a. Suppose that P = 100,Y = 1000, and i =0.10. Find real money demand, nominal money demand, and the velocity of money. Solution: Real money demand is M d P = 500 + 0.2Y - 1000i = 500 + 0.2(1000) - 1000(0.10) = 600 Nominal money demand is M d P P = 600(100) = 60, 000 Velocity of money is V = P Y /M d = 100(1000)/60, 000 = 5/3 b. The price level doubles from P = 100 to P = 200. Find real money demand, nominal money demand, and the velocity of money. Solution: Neither income Y nor the interest rate i have changed, so real money demand is unchanged. Nominal money demand is M d P P = 600(200) = 120, 000 Velocity of money is V = P Y /M d = Y/(M d /P ), and as neither income Y nor real money demand M d P have changed, the velocity of money is unchanged. c. Starting from the values of the variables given in Part (a) and assuming that the money demand function written holds, determine how velocity is affected by an increase in real income, by an increase in the nominal interest rate, and by an increase in the price level. Solution: V = Y M d /P = Y 500+0.2Y -1000i An increase in real income: With i = 0.10, V = Y 500+0.2Y -1000(0.10) = Y 400+0.2Y . dV dY = 10000 (Y +2000) 2 > 0, so when Y increases, the velocity of money increases. An increase in the real interest rate: With Y = 1000, V = 1000 500+0.2(1000)-1000i = 1000 700-1000i . dV di = 100 (7-10x) 2 > 0, so when i increases, the velocity of money increases. An increase in the price level: There is no effect on velocity, since we can write velocity as a function just of Y and i. Nominal money demand changes proportionally with the price level, so that real money demand, and hence velocity, is unchanged. 2 Log-linearization and elasticities Log-linearize the consumption Euler equation you derived in HW #1 Question 5.b. (for the utility form U (c t ,c t+1 )= c 1- 1 σ t 1- 1 σ + β c 1- 1 σ t+1 1- 1 σ ) After log-linearization, one of the percentage deviation terms should have a coefficient. What is the interpretation of this coefficient as an elasticity? Solution: Taking natural logs of our Euler equation, c t = c t+1 (β(1 + r t )) -σ , yields ln(c t )= ln(c t+1 ) - σln(β) - σln(1 + r t ) ⇐⇒ ln(c * t )+ Δct ct = ln(c * t+1 )+ Δct+1 ct+1 - σln(β) - σln(1 + r * t ) - σ Δ1+rt 1+rt ⇐⇒ Δct+1 ct+1 - Δct ct = σ Δ1+rt 1+rt σ is interpreted as the elasticity of intertemporal substitution, which measures how responsive consump- tion growth is to changes in interest rates. 1

Accelerated Macro Spring 2015 Solutions to HW #2 … Solution.pdf · Accelerated Macro Spring 2015 Solutions to HW #2 ... Solution: Neither income Y nor the interest rate i have changed,

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Page 1: Accelerated Macro Spring 2015 Solutions to HW #2 … Solution.pdf · Accelerated Macro Spring 2015 Solutions to HW #2 ... Solution: Neither income Y nor the interest rate i have changed,

Accelerated Macro Spring 2015Solutions to HW #2

1 Money demand and the velocity of moneyABC Ch. 7 NP #2

Money demand in an economy in which no interest is paid on money is Md

P = 500 + 0.2Y − 1000i.

a. Suppose that P = 100, Y = 1000, and i = 0.10. Find real money demand, nominal money demand,and the velocity of money.

Solution: Real money demand is Md

P = 500 + 0.2Y − 1000i = 500 + 0.2(1000)− 1000(0.10) = 600

Nominal money demand is Md

P P = 600(100) = 60, 000

Velocity of money is V = PY/Md = 100(1000)/60, 000 = 5/3

b. The price level doubles from P = 100 to P = 200. Find real money demand, nominal moneydemand, and the velocity of money.

Solution: Neither income Y nor the interest rate i have changed, so real money demand isunchanged.

Nominal money demand is Md

P P = 600(200) = 120, 000

Velocity of money is V = PY/Md = Y/(Md/P ), and as neither income Y nor real money demandMd

P have changed, the velocity of money is unchanged.

c. Starting from the values of the variables given in Part (a) and assuming that the money demandfunction written holds, determine how velocity is affected by an increase in real income, by anincrease in the nominal interest rate, and by an increase in the price level.

Solution: V = YMd/P

= Y500+0.2Y−1000i

• An increase in real income: With i = 0.10, V = Y500+0.2Y−1000(0.10) = Y

400+0.2Y .dVdY = 10000

(Y+2000)2 > 0, so when Y increases, the velocity of money increases.

• An increase in the real interest rate: With Y = 1000, V = 1000500+0.2(1000)−1000i = 1000

700−1000i .dVdi = 100

(7−10x)2 > 0, so when i increases, the velocity of money increases.

• An increase in the price level: There is no effect on velocity, since we can write velocity as afunction just of Y and i. Nominal money demand changes proportionally with the price level,so that real money demand, and hence velocity, is unchanged.

2 Log-linearization and elasticities

Log-linearize the consumption Euler equation you derived in HW #1 Question 5.b.

(for the utility form U(ct, ct+1) =c1− 1

σt

1− 1σ

+ βc1− 1

σt+1

1− 1σ

)

After log-linearization, one of the percentage deviation terms should have a coefficient. What is theinterpretation of this coefficient as an elasticity?

Solution: Taking natural logs of our Euler equation, ct = ct+1(β(1 + rt))−σ, yields

ln(ct) = ln(ct+1)− σln(β)− σln(1 + rt) ⇐⇒ln(c∗t ) + ∆ct

ct= ln(c∗t+1) + ∆ct+1

ct+1− σln(β)− σln(1 + r∗t )− σ∆1+rt

1+rt⇐⇒

∆ct+1

ct+1− ∆ct

ct= σ∆1+rt

1+rt

σ is interpreted as the elasticity of intertemporal substitution, which measures how responsive consump-tion growth is to changes in interest rates.

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Page 2: Accelerated Macro Spring 2015 Solutions to HW #2 … Solution.pdf · Accelerated Macro Spring 2015 Solutions to HW #2 ... Solution: Neither income Y nor the interest rate i have changed,

3 The Solow model: shocks to the steady stateABC Ch. 6 AP #1

According to the Solow model, how would each of the following affect consumption per worker in thelong run (i.e., in the steady state)? Explain.

a. The destruction of a portion of the nation’s capital stock in a war.

Solution: “The destruction of some of a country’s capital stock in a war would have no effecton the steady state, because there has been no change in s, f(), n, or δ. Instead, k is reducedtemporarily, but equilibrium forces eventually drive k to the same steady state value as before.”

b. A permanent increase in the rate of immigration (which raises the overall population growth rate).

Solution: Immigration raises n, which lowers steady state k, leading to lower steady state outputand thus consumption per worker. (See Figure 6.3.)

c. A permanent increase in energy prices.

Solution: The rise in energy prices reduces the productivity of capital per worker (i.e., reducesTotal Factor Productivity, A). This causes sf(k) to shift downward, resulting in a decline insteady state k. Steady state consumption per worker falls beacuse the decline in productivityreduces output for any fixed factor level, but the steady state k is also reduced, further reducingoutput and consumption. (See Figure 6.4.)

d. A temporary rise in the saving rate.

Solution: “A temporary rise in s has no effect on the steady state equilibrium.”

e. A permanent increase in the fraction of the population in the labor force (the population growthrate in unchanged).

Solution: “The increase in the size of the labor force does not affect the growth rate of the laborforce, so there is no impact on the steady state capital-labor ratio. However, because a largerfraction of the population is working, output and consumption per person increases.”

4 Per-worker production functionBased on ABC Ch. 6 NP #5

An economy has the per-worker production function yt = 3k0.5t where yt is output per worker and kt is

the capital-labor ratio. The depreciation rate is 0.1, and the population growth rate is 0.05. Savings isSt = 0.3Yt, where St is total national savings and Yt is total output.

a. What are the steady state values of the capital-labor ratio, output per worker, and consumptionper worker?

Solution: sf(k) = (n+ δ)k ⇐⇒ 0.3(3k0.5) = (0.05 + 0.1)k ⇐⇒ 6 = k0.5 ⇐⇒ k∗ = 36

y∗ = 3(k∗)0.5 = 3(6) = 18

c∗ = y∗ − (n+ δ)k∗ = 18− (0.15)36 = 12.6

The rest of the problem shows the effects of changes in the three fundemental determinants oflong-run standards of living.

b. Repeat Part (a) for a savings rate of 0.4 instead of 0.3. Explain why the steady state capital-laborratio is changing the way it is.

Solution: sf(k) = (n+ δ)k ⇐⇒ 0.4(3k0.5) = (0.05 + 0.1)k ⇐⇒ 8 = k0.5 ⇐⇒ k∗ = 64

y∗ = 3(k∗)0.5 = 3(8) = 24

c∗ = y∗ − (n+ δ)k∗ = 24− (0.15)64 = 14.4

When the savings rate rises, more capital is accumulated, so K/N ↑; Y/N is increasing in K/N ,so Y/N ↑; C/N is increasing linearly in Y/N , so C/N ↑.

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Page 3: Accelerated Macro Spring 2015 Solutions to HW #2 … Solution.pdf · Accelerated Macro Spring 2015 Solutions to HW #2 ... Solution: Neither income Y nor the interest rate i have changed,

c. Repeat Part (a) for a population growth rate of 0.08 (with a saving rate of 0.3). Explain why thesteady state capital-labor ratio is changing the way it is.

Solution: sf(k) = (n+ δ)k ⇐⇒ 0.3(3k0.5) = (0.08 + 0.1)k ⇐⇒ 5 = k0.5 ⇐⇒ k∗ = 25

y∗ = 3(k∗)0.5 = 3(5) = 15

c∗ = y∗ − (n+ δ)k∗ = 15− (0.18)25 = 10.5

When the population growth rate rises, a larger workforce dilutes the capital stock per worker, soK/N ↓; Y/N is increasing in K/N , so Y/N ↓; C/N is increasing linearly in Y/N , so C/N ↓ .

d. Repeat Part (a) for a per-worker production function yt = 4k0.5t . Assume the saving rate and pop-

ulation rate are at their original values. Explain why the steady state capital-labor ratio is changingthe way it is.

Solution: sf(k) = (n+ δ)k ⇐⇒ 0.3(4k0.5) = (0.05 + 0.1)k ⇐⇒ 8 = k0.5 ⇐⇒ k∗ = 64

y∗ = 4(k∗)0.5 = 4(8) = 32

c∗ = y∗ − (n+ δ)k∗ = 32− (0.15)64 = 22.4

When productivity rises, more output is produced from the given factor levels. Savings and con-sumption are linear function of Y/N , so C/N ↑ and S ↑. The increase in savings will increase thecapital stock per worker, so K/N ↑.

Can you back out the original Cobb-Douglas production function from the given per-worker productionfunction yt?

Solution: yt = 3k0.5t ⇐⇒ Yt

Nt= 3(KtNt )0.5 ⇐⇒ Yt = 3K0.5

t N0.5t

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