A Shear Locking Free Six-node Mindlin Plate Bending Element

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    548

    M. H. VERWOERDnd A. W. M. KOK

    Fig. 1. Rigid pin and midplane deformation.

    The variables E and v are the Youngs modulus

    and Poissons ratio, and k is the shape factor

    k = 5/6).

    Finite element formulation

    For the six-node triangular element the same set of

    shape functions [8] is used to approximate all the

    midplane displacements.

    The displacements, the translations (U , v , w ) and

    the rotations (4, and 4,) are related to the nodal

    displacements II: = [up, up, wp, c ,, &] by shape

    functions a, x, y). The Appendix gives the expression

    for the shape functions of the quadratic triangular

    plate element.

    The strain vectors L, and L, of eqns (2) and (3) are

    now described by:

    or

    c, = B,u

    (5b)

    and

    or

    L, =

    B,u

    (6b)

    Strain energy

    The strain energy of the plate may be written as

    the sum of membrane and transverse shear

    energy.

    aE,= +

    s

    aL;.a,dV+

    s

    ac:.a,dV.

    7)

    v

    Substituting eqns (5b) and (6b) for &, and &,, the

    strain energy is discretized for an element, and given

    by,

    +

    s

    duB;GB,udV. (8)

    For thick plates the usual three-point integration

    rule yields acceptable results. For thin plates, trans-

    verse shear deformations dominate the stiffness

    matrix (shear locking).

    The base of the poor behaviour is found in the

    inhomogeneous composition of the contributing

    terms to the shear strains. The strains in the F.E.M.

    are calculated following the kinematic relations of

    eqn (3).

    Shear locking is assumed to be introduced by the

    obligate quadratic terms of y, vs the linear approxi-

    mation of w,,. The result is an overly stiff element.

    A refined transverse shear strain approximation is

    proposed by the addition of correction terms to the

    displacement field w. The function of these correction

    terms is to neutralize the quadratic contribution of

    f& in yXZ s f#~, n yyZ.

    Correction terms

    Shear strains are obtained by:

    7x1= 4. + w,,

    @a)

    Yyl= - 4, + w

    Y

    For each direction s, the transverse shear strains can

    be written as

    Y,= 9, + w.,,

    (9b)

    where 4 is the quadratic polynomial and w,, the

    linear polynomial. Shear locking is introduced by

    the quadratic terms of 4,. The shear locking of the

    SHELL6 element can be eliminated by addition of

    correction terms, Aw.

    or

    rt=r,+Av,

    (loa)

    Y: = w,, + 4. + Aw,,

    (1W

    The correction term Aw should be taken in such a

    way that rj

    will be linear with respect to every

    direction s.

    The condition of the linear transverse shear strain

    requires that

    Y

    * CO

    s, .7

    for every direction s.

    (11)

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    A shear locking free six-node Mindlin plate bending element

    549

    Using the kinematic relations of eqn (9b) the

    condition to the displacement field is now

    where

    (12a)

    Aw., = Aw,,, cos a + 3Aw,, cos* a sin

    a

    ~Aw,,,,~ os

    a

    sin*

    a

    Aw,, sin a

    (12b)

    d.,, = &,XX os a + (2#5,, - 9,,) cos* a sin a

    + (& YY

    21$,,) cos a sin* a - 4r.yy in a

    (12c)

    for each angle

    a.

    To this condition eqn (12a) is satisfied if:

    The solution Aw is now given by:

    Aw = - i (x*a:, + Zxya:, + y*a;J

    x (x4,, - y ) - aAw*

    (14a)

    with discrete values

    Awi+ =

    -b(xfa:, + 2xiyia~Y+y~a~,,)(xi~Y-yi~X)

    or

    (14b)

    The Appendix gives the expression for a,, aYY, Xv.

    The refined shear strains in the x- and y-directions

    are now given by:

    in which the correction terms Ay, and AyYZare,

    respectively,

    by,, = Aw,, =

    (f

    xya: + iy2a:, - a:P,)

    -(~x2a:X+fxya:Y+~y2a;Y+a:P2)~Y

    (15b)

    and

    Ar,, = Aw,, = (ix2aiX + f xya: +fy2a;,, - a;P,)

    -(ix2a:,+fxya6+a;P2)qbY. (1%)

    The shear strains y$ and y; are

    linearly with respect to x and y.

    now distributed

    NUMERICAL INTEGRATION

    RULES

    For both the SHELL6 element

    SHELL6* element the three-point

    has been applied.

    and the refined

    integration rule

    Numerical test

    A symmetric quadrant of a uniformly loaded,

    simply supported, square plate is idealized by 32

    elements for a thin plate of span/thickness ratio

    L/t =

    50.

    To compare the quality of the refined

    SHELL6* element the same quadrant has been ideal-

    ized by 16 eight-node plate elements (SHELLS) too.

    The exact solution for this class of problems is given

    in [9].

    L=lOrn

    t=0 2m

    E=lON/m

    x

    G lON/m

    VSO

    Fig. 3. Simply supported square plate under uniformly

    distributed load.

    ig. 2. Correction terms A.w.

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    55

    M. H. VERWOERD and A. W. M. KOK

    601

    I

    I

    2

    L

    0

    2

    -x [ml

    -+x hl

    Fig. 4. Moments m?,. and PI,, along line of symmetry y = 0.

    601

    50 -

    30 -

    SHELL6*/SHELLB

    ----x

    [ml

    -60

    SHELL 6

    -60

    i

    I

    I

    I

    1 I

    0

    2 L

    -x [ml

    Fig. 5. Shear forces

    qy

    and

    q_

    along line of symmetry y = 0

    RESULTS REFERENCES

    The computed displacements of SHELL6 and

    SHELL6* are very close to the exact results and are

    not shown here. Results of the moments and the

    shear forces are shown in Figs 4 and 5.

    1.

    2.

    3.

    4.

    5.

    6.

    I.

    8.

    9.

    I. Fried, Shear in C? and C bending finite elements. Inr.

    J. Solids Struct. 9, 449 (1973).

    0. C. Zienkiewicz, R. L. Taylor and J. M. Too,

    Reduced integration techniques in general analysis of

    plates and shells.

    Int. J. Numer. Meth.

    Engng 3,275-290

    (1971).

    T. J. R. Hughes, M. Cohen and M. Haoun, Reduced

    and selective integration techniques in the finite element

    analysis of plates. Nucl. Engng Des. 46, 203 (1978).

    0. C. Zienkiewicz and E. Hinton, Reduced integration,

    function smoothing and non-conformity in finite ele-

    ment analysis (with special reference to thick plates).

    J. Franklin Inst. 302, 443461 1976).

    R. D. Mindlin, Influence of rotary inertia and shear on

    flexural motions of isotropic plates.

    J. uppl. Mech.

    18

    31-38 (1951).

    T. J. R. Hughes and T. E. Tezduyar, Finite elements

    based upon Mindlin plate theory with particular refer-

    ence to the four-node bilinear isoparametric element.

    J. appl. Mech ASME 48, 587-596 1981).

    E. Reissner, The effect of transverse shear deformation

    on the bending of elastic plates.

    J. appt. Mech., Trans.

    ASME 12, A69-A77 (1945).

    C. S. Desai and J. F. Abel,

    Introduction to the Finite

    Element Method. Van Nostrand Reinhold, New York

    (1972).

    S. Timoshenko and S. Woinowky-Kreiger, Theory of

    Plates and Shells,

    2nd Edn. McGraw-Hill, New York

    (1940).

    CONCLUSIONS

    The introduction of transverse shear strain in

    the family of Mindlin element leads to shear

    locking problems with decreasing thickness of

    triangular and quadrilateral plate elements. Re-

    duced or selective integration techniques can

    overcome shear locking for four-node and eight-

    node

    elements. For triangles, reduced inte-

    gration techniques do not solve the shear locking

    problem.

    For triangular plate elements shear locking can be

    effectively eliminated by the introduction of the cor-

    rection terms, Aw. These correction terms neutralize

    the inhomogeneous quadratic terms in the shear

    strain and successively the shear locking effects, This

    new element leads to much more accurate results for

    moments and shear forces.

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    A shear locking free six-node Mindlin plate bending element

    551

    APPENDIX

    The functions qxx, qYYand aLxyare the components of

    the vectors a,, aYY nd axy, respectively,

    The expression of the shape functions a,@, y) in vector a

    are

    L,(2L, - 1)

    L&L, - 1)

    4

    0

    0

    a= L,(ZL,-1)

    0

    4

    0

    4LI L*

    4

    4

    4

    4L, L3

    a,, =

    %v =

    0

    0

    axY=

    4

    4&L, _

    -8

    0

    -4

    whereL,=x;L,=y;L,=l-x-y;O