24993385 Water Waste Water Treatment

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    Water & Wastewater TreatmentWater & Wastewater Treatment

    Objectives:Objectives:

    Define primary, secondary, and tertiary treatmentDefine primary, secondary, and tertiary treatment

    Define BODDefine BOD Describe the activated sludge processDescribe the activated sludge process

    Setup and solve a mass balance for an activatedSetup and solve a mass balance for an activatedsludge systemsludge system

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    SettlingSettling

    Settling velocity:Settling velocity:

    Percent of particles removed: (1Percent of particles removed: (1--CCssss/C/Css,oss,o) x 100%) x 100% Where,Where,

    ReviewReview

    Sorption:Sorption:

    KKdd=C=Css/C/CLL

    CCTT=(1+K=(1+KddCCssss)C)CLL

    Fraction sorbed vs. fraction remaining in waterFraction sorbed vs. fraction remaining in water

    218

    dg

    v wss VV

    Q

    !

    Q

    AvC

    C

    soss

    ss

    !

    1

    1

    ,

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    WellWell--Mixed Settling TankMixed Settling Tank

    Q

    AvC

    C

    soss

    ss

    !

    1

    1

    ,

    Q, Css,o Q, CssCssvs V

    Suspended solids remaining: Define the Overflow Rate:

    A

    Q

    ~ 20 100 m/day in treatment plants

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    Wastewater TreatmentWastewater Treatment

    POTWPOTW Publicly Owned Treatment WorksPublicly Owned Treatment Works

    0.40.4 0.6 m0.6 m33/person/day/person/day

    15 million people in Los Angeles15 million people in Los Angeles

    7.5 x 107.5 x 1066

    mm33

    /day/dayor 2000 MGD (million gallons per day)or 2000 MGD (million gallons per day)

    HyperionHyperion 450 MGD450 MGD

    Clean Water Act (CWA)Clean Water Act (CWA) 19771977 Set effluentSet effluent

    (what is released by treatment plants into the(what is released by treatment plants into theenvironment) standardsenvironment) standards

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    Stages ofWater TreatmentStages ofWater Treatment

    PrimaryPrimary

    ContaminantsContaminants (60% of solids and 35% of BOD removed)(60% of solids and 35% of BOD removed)

    Oil & GreaseOil & Grease

    Total Suspended Solids (CTotal Suspended Solids (Cssss or TSS)or TSS) 60% Removed60% Removed PathogensPathogens

    BODBOD 35% removed35% removed

    ProcessesProcesses

    ScreensScreens

    Grit SettlingGrit Settling

    Scum FlotationScum Flotation

    Primary SettlingPrimary Settling

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    SecondarySecondary

    ContaminantsContaminants

    BODBOD 90% Removed90% Removed

    TSSTSS 90% Removed90% Removed

    ProcessesProcesses

    Trickling FilterTrickling Filter rotating diskrotating disk

    Activated SludgeActivated Sludge Suspended and mixedSuspended and mixed Oxidation pondsOxidation ponds lagoonslagoons

    (promote contact between microbes and contaminants)(promote contact between microbes and contaminants)

    Stages (continued)Stages (continued)

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    Stages (continued)Stages (continued)

    TertiaryTertiary

    ContaminantsContaminants

    NutrientsNutrients

    Dissolved solids (e.g., salt, other ions, etc.)Dissolved solids (e.g., salt, other ions, etc.)

    ProcessesProcesses

    DenitrificationDenitrification bacteriabacteria

    Phosphorus removalPhosphorus removal precipitationprecipitation Other chemicalsOther chemicals adsorption and precipitationadsorption and precipitation

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    Primary Sludge (contd)Primary Sludge (contd)

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    Primary SludgePrimary Sludge

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    Primary SludgePrimary Sludge

    (contd)(contd)

    Given:Given: Q = 4000 mQ = 4000 m33/d/d

    CCss,oss,o = 200 mg/L and C= 200 mg/L and Cssss = 100 mg/L= 100 mg/L

    Sludge density = 0.05 kg/LSludge density = 0.05 kg/L

    Overflow rate of 50 m/dOverflow rate of 50 m/d

    FindFind

    Population of town served by this unitPopulation of town served by this unit Sludge production rateSludge production rate

    Area of settling tankArea of settling tank

    Settling velocity of particlesSettling velocity of particles

    CutCut--off size of particles (find the particle diameter corresponding to thisoff size of particles (find the particle diameter corresponding to thissettling velocity. Assumesettling velocity. Assume VV

    ss

    = 2600 kg/m= 2600 kg/m33. All particles larger than this. All particles larger than thissize will settle)size will settle)

    Q, Css,o Q, Css

    rateproductionsludgems !

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    Activated SludgeActivated Sludge

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    Activated Sludge ComponentsActivated Sludge Components

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    Activated Sludge ComponentsActivated Sludge Components

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    Activated Sludge (contd)Activated Sludge (contd)

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    Activated Sludge NomenclatureActivated Sludge Nomenclature

    Q, So, Xo

    Q+QR,

    S, XQ-Qs, S

    Qs+QR, Xs

    Qs, Xs

    QR, Xs

    S stands for conc.of substrate (organic matter, waste, etc.) or

    BOD

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    Activated Sludge NomenclatureActivated Sludge Nomenclature

    (co

    ntd)(co

    ntd)Q, So, Xo Q+QR, S, X ~Q, S

    Qs+QR, Xs

    Qs, XsQR, Xs

    Assumptions: Effluent bacteria concentration is 0 Concentration of substrate or BOD in sludge is 0 Sludge flowrate (Q

    s

    ) is much smaller than Q

    Q, V

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    Decay ofBOD and growth ofDecay ofBOD and growth of

    organismsorganisms

    Substrate or BOD (S) decays with rate k:Substrate or BOD (S) decays with rate k:

    Microbes (X) grow at rateMicrobes (X) grow at rate QQ::

    kS

    dt

    dS!

    Xdt

    dXQ!

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    Activated Sludge EquationsActivated Sludge Equations

    The following equations are derived fromThe following equations are derived from

    conducting mass balances over:conducting mass balances over:

    The entire systemThe entire systemThe aeration tankThe aeration tank

    The sedimentation tankThe sedimentation tank

    Any good book on wastewater engineering willAny good book on wastewater engineering willhave the derivations if you are curious!have the derivations if you are curious!

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    Activated Sludge EquationsActivated Sludge Equations

    Biomass (X) balance over entire system:Biomass (X) balance over entire system:

    Substrate (S) balance over entire system:Substrate (S) balance over entire system:

    XVXQm sss Q!!

    kSV

    XV

    consumedBOD

    producedbiomassY

    mXVSSYQ so

    Q

    Q

    !!

    !!

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    More AS equationsMore AS equations

    Mass balance over sedimentation tank:Mass balance over sedimentation tank:

    Other equation(s)/rules of thumb:Other equation(s)/rules of thumb:

    F/M = QSF/M = QSoo/XV/XV -- FoodFood--toto--microbe ratio: 0.3microbe ratio: 0.3 0.7 d0.7 d--11

    QQRR~ 0.25~ 0.25 0.50 x Q0.50 x Q

    X~

    1000X~

    1000 2000 mg/L2000 mg/L Problem types:Problem types:

    Given Q, SGiven Q, Soo, and S (target concentration), and S (target concentration)

    Find QFind QRR, Q, Qss, X,, X, QQ, V, Y, V, Y

    sRR XQXVXQQ ! Q

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    ExampleExample

    Find QFind Qss,, QQ, V, Y, V, Y

    Given:Given: Q = 1000 mQ = 1000 m33/d/d

    SSoo = 150 mg/L= 150 mg/L

    S = 15 mg/LS = 15 mg/L

    QQRR= 240 m= 240 m33/d/d

    F/M = 0.3 dF/M = 0.3 d--11 X = 2000 mg/LX = 2000 mg/L

    XXss = 1% or 10,000 mg/L= 1% or 10,000 mg/L

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    Definition ofBODDefinition ofBOD

    Microorganisms (e.g., bacteria) are responsible for decomposingMicroorganisms (e.g., bacteria) are responsible for decomposingorganic waste. When organic matter such as dead plants, leaves,organic waste. When organic matter such as dead plants, leaves,grass clippings, manure, sewage, or even food waste is present ingrass clippings, manure, sewage, or even food waste is present ina water supply, the bacteria will begin the process of breakinga water supply, the bacteria will begin the process of breakingdown this waste. When this happens, much of the availabledown this waste. When this happens, much of the availabledissolved oxygen is consumed by aerobic bacteria, robbing otherdissolved oxygen is consumed by aerobic bacteria, robbing otheraquatic organisms of the oxygen they need to live. Biologicalaquatic organisms of the oxygen they need to live. BiologicalOxygen Demand (BOD) is a measure of the oxygen used byOxygen Demand (BOD) is a measure of the oxygen used bymicroorganisms to decompose this waste. If there is a largemicroorganisms to decompose this waste. If there is a largequantity of organic waste in the water supply, there will also be aquantity of organic waste in the water supply, there will also be a

    lot of bacteria present working to decompose this waste. In thislot of bacteria present working to decompose this waste. In thiscase, the demand for oxygen will be high (due to all the bacteria)case, the demand for oxygen will be high (due to all the bacteria)so the BOD level will be high. As the waste is consumed orso the BOD level will be high. As the waste is consumed ordispersed through the water, BOD levels will begin to decline.dispersed through the water, BOD levels will begin to decline.