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Chapter 21, Benzeneand and the Concept of
Aromaticity
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Benzene - Kekul
In 1872, August Kekul proposed the following
structure for benzene.
This structure, however, did not account for the
unusual chemical reactivity of benzene.
CH
CH
CH
CHC
H
C
HC
C
CC
C
C
H
HHH
HH
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Benzene - Resonance
We often represent benzene as a hybrid of two
equivalent Kekul structures. Each makes an equal contribution to the hybrid and
thus the C-C bonds are neither double nor single, butsomething in between.
Benzene as a hybrid of two equ ivalen tcontributing structures
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Benzene - Resonance Model
The concepts of hybridization of atomic orbitals
and the theory of resonance, developed in the1930s, provided the first adequate description ofbenzenes structure.
The carbon skeleton is a planar regular hexagon.
All C-C-C and H-C-C bond angles 120.
sp2-sp
2
sp2-1s109 pm
120
120
120
139 pm
C
C
C
C
C
C H
H H
H
H H
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The Pi System of Benzene
(a) The carbon framework with the six 2p orbitals.
(b) Overlap of the parallel 2p orbitals forms one torusabove the plane of the ring and another below it
this orbital represents the lowest-lying pi-bondingmolecular orbital.
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Benzene-Molecular Orbital Model
The molecular orbital representation of the pi
bonding in benzene.
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Orbitals of the pi System of BenzeneNumber ofnodal surfaces
0
1
2
3
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Benzene - Resonance
Resonance energy:The difference in energy
between a resonance hybrid in which theelectrons are delocalized
and
the most stable one of its hypotheticalcontributing structures in which electrons arelocalized on particular atoms and in particularbonds.
One way to estimate the resonance energy of benzeneis to compare the heats of hydrogenation of benzeneand cyclohexene.
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Benzene- Resonance Energy
Experimentaldata
Model
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Concept of Aromaticity
The underlying criteria for aromaticity were
recognized in the early 1930s by Erich Hckel,based on molecular orbital (MO) calculations.
To be aromatic, a compound must
Be cyclic. Have one p orbital on each atom of the ring.
Be planar or nearly planar so that there is continuousor nearly continuous overlap of all p orbitals of the
ring. Have a closed loop of (4n + 2) pi electrons in the cyclic
arrangement of p orbitals.
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Frost Circles
Frost circle: A graphic method for determining
the relative order of pi MOs in planar, fullyconjugated monocyclic compounds.
Inscribe in a circle a polygon of the same number ofsides as the ring to be examined such that one of the
vertices of the polygon is at the bottom of the circle.
The relative energies of the MOs in the ring are givenby where the vertices of the polygon touch the circle.
Those MOs
Below the horizontal line through the center of the ringare bonding MOs.
on the horizontal line are nonbonding MOs.
above the horizontal line are antibonding MOs.
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Frost Circles
Frost circles describing the MOs for monocyclic,
planar, fully conjugated four-, five-, and six-memberedrings.
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Relationship of hexa-1,3,5-triene to benzene
How does the linear triene relate
to benzene?
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Relationship of hexa-1,3,5-triene to benzene
?
R l i hi f h 3 i b
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Relationship of hexa-1,3,5-triene to benzene
?
Look at orbitals 2 and 3.
p2
p3
Curvearound
Antibonding,destabilizing
Bonding,stabilizing
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Aromatic Hydrocarbons
Annulene:A cyclic hydrocarbon with a
continuous alternation of single and doublebonds.
[14]Annulene is aromatic according to Hckels
criteria.
[14]Annulene
(aromatic)
HH
H H
H
H
H
H
HH
H
H
H H
n = 3
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Aromatic Hydrocarbons
[18]Annulene is also aromatic.
[18]Annulene
(aromatic)
H
H
H
H
H
H
H
H
HH
H
H
H
H
H
H
H
H
n = 4
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Aromatic Hydrocarbons
According to Hckels criteria, [10]annulene should be
aromatic; it has been found, however, that it is not. Nonbonded interactions between the two hydrogens
that point inward toward the center of the ring forcethe ring into a nonplanar conformation in which
overlap of the ten 2p orbitals is no longer continuous.
[10]Annulene
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Aromatic Hydrocarbons
What is remarkable relative to [10]annulene is that if
the two hydrogens facing inward toward the center ofthe ring are replaced by a methylene (CH2) group, thering is able to assume a conformation close enough toplanar that it becomes aromatic.
CH2
Bridged [10]annulene
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Antiaromatic Hydrocarbons
Antiaromatic hydrocarbon:A monocyclic, planar,
fully conjugated hydrocarbon with 4n pielectrons (4, 8, 12, 16, 20...).
An antiaromatic hydrocarbon is especially unstablerelative to an open-chain fully conjugated hydrocarbon
of the same number of carbon atoms.
Cyclobutadiene is antiaromatic.
In the ground-state electron configuration of thismolecule, two electrons fill the p
1
bonding MO.
The remaining two electrons lie in the p2 and p3nonbonding MOs.
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Cyclobutadiene
The ground state of planar cyclobutadiene has two
unpaired electrons, which make it highly unstable andreactive.
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Cyclooctatetraene
Cyclooctatetraene, with 8 pi electrons is not aromatic;
it shows reactions typical of alkenes. X-ray studies show that the most stable conformation
is a nonplanar tub conformation.
Although overlap of 2p orbitals occurs to form pi
bonds, there is only minimal overlap between sets of2p orbitals because they are not parallel.
viewed from above viewed through an edge
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Cyclooctatetraene
MO energy diagram for a planar conformation of
cyclooctatetraene.
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Heterocyclic Aromatics
Heterocyclic compound: A compound that
contains more than one kind of atom in a ring. In organic chemistry, the term refers to a ring with one
or more atoms that differ from carbon.
Pyridine and pyrimidine are heterocyclic analogsof benzene; each is aromatic.
Pyridine
N
N
N
Pyrimidine
1
2
3
4
5
6
12
3 4
5
6
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Pyridine
The nitrogen atom of
pyridine is sp2
hybridized.
The unshared pair ofelectrons lies in an sp2
hybrid orbital and is nota part of the six pielectrons of thearomatic system (thearomatic sextet).
Resonance energy ofpyridine is134 kJ (32kcal)/mol.
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Furan and Pyrrole
The oxygen atom of furan is sp2 hybridized.
one unshared pairs of electrons on oxygen lies in anunhybridized 2p orbital and is a part of the aromaticsextet.
The other unshared pair lies in an sp2 hybrid orbital
and is not a part of the aromatic system. The resonance energy of furan is 67 kJ (16 kcal)/mol.
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Other Heterocyclics
Purine
Indole
N
N
NN
N
H
H
N
H
CH2 CH2 NH 2
Serotonin(a neurotransmitter)
HO
Caffeine
N
NN
N
O
O
H3 C
CH3
CH3
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Aromatic Hydrocarbon Ions
Any neutral, monocyclic, unsaturated
hydrocarbon with an odd number of carbonsmust have at least one CH2 group and, therefore,cannot be aromatic.
Cyclopropene, for example, has the correct number of
pi electrons to be aromatic, 4(0) + 2 = 2, but does nothave a closed loop of 2p orbitals.
Cyclopropene Cyclopentadiene Cycloheptatriene
CH2 CH2CH2
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Cyclopropenyl Cation
If, however, the CH2 group of cyclopropene is
transformed into a CH+
group in which carbon