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06/27/22 Perkins AP Calculus AB Day 1 Section 2.1

11/10/2015 Perkins AP Calculus AB Day 1 Section 2.1

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Page 1: 11/10/2015 Perkins AP Calculus AB Day 1 Section 2.1

04/20/23 Perkins

AP Calculus AB

Day 1Section 2.1

Page 2: 11/10/2015 Perkins AP Calculus AB Day 1 Section 2.1

-2 2 4 6 8

4

3

2

1

-1

-2

Find the slope of the tangentline to f(x) at the given point.

x , f x f(x)

x

B

Page 3: 11/10/2015 Perkins AP Calculus AB Day 1 Section 2.1

The Derivative (Definition of the Derivative)

or 0

' limx

f x x f xf x

x

0

' limh

f x h f xf x

h

The Alternative Form of the Definition of the Derivative

' lim

x c

f x f cf c

x c

Gives the numeric value of the derivative at a given point, x = c.

Gives a generic expression into which we can substitute any x to get a numeric value of the derivative at that point.

Page 4: 11/10/2015 Perkins AP Calculus AB Day 1 Section 2.1

1. Find using the definition of the derivative.

f x x

'f x

0

' limx

f x x f xf x

x

0limx

x x x

x

x x x

x x x

0limx

x x x

x x x x

0limx

x

x x x x

0

1limx x x x

1

2 x

Page 5: 11/10/2015 Perkins AP Calculus AB Day 1 Section 2.1

2. Find the equation of the tangent line to at (1,5). Use the alternative form of the definition of the derivative.

23 2f x x

1

1' 1 lim

1x

f x ff

x

2

1

3 2 5lim

1x

x

x

2

1

3 3lim

1x

x

x

1

3 1 1lim

1x

x x

x

1

lim 3 1x

x

6D.S.

165y x

6 1y x

Page 6: 11/10/2015 Perkins AP Calculus AB Day 1 Section 2.1

3. Find the slope of the tangent line to at x = 2. 2f x x

4

2

-2

-4

-5 5

This function has a sharp turn at x = 2.

Functions are not differentiable at

a. Discontinuities

b. Sharp turns

c. Vertical tangents

Therefore the slope of the tangent line at x = 2 does not exist.

Page 7: 11/10/2015 Perkins AP Calculus AB Day 1 Section 2.1

4. Find any values where is not differentiable. 1

3f x

x

This function has a V.A. at x = 3.

Theorem:

If f is differentiable at x = c,

then it must also be continuous at x = c.

Therefore the derivative at x = 3 does not exist.

4

2

-2

-4

-5 5

Page 8: 11/10/2015 Perkins AP Calculus AB Day 1 Section 2.1

Perkins

AP Calculus AB

Day 1Section 2.1

Page 9: 11/10/2015 Perkins AP Calculus AB Day 1 Section 2.1

-2 2 4 6 8

4

3

2

1

-1

-2

Find the slope of the tangentline to f(x) at the given point.

x , f x f(x)

x

B

Page 10: 11/10/2015 Perkins AP Calculus AB Day 1 Section 2.1

The Derivative (Definition of the Derivative)

or 0

' limx

f x x f xf x

x

0

' limh

f x h f xf x

h

The Alternative Form of the Definition of the Derivative

' lim

x c

f x f cf c

x c

Page 11: 11/10/2015 Perkins AP Calculus AB Day 1 Section 2.1

1. Find using the definition of the derivative.

f x x

'f x

Page 12: 11/10/2015 Perkins AP Calculus AB Day 1 Section 2.1

2. Find the equation of the tangent line to at (1,5). Use the alternative form of the definition of the derivative.

23 2f x x

Page 13: 11/10/2015 Perkins AP Calculus AB Day 1 Section 2.1

3. Find the slope of the tangent line to at x = 2. 2f x x

Page 14: 11/10/2015 Perkins AP Calculus AB Day 1 Section 2.1

4. Find any values where is not differentiable. 1

3f x

x