11 Ohmic Contacts

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    Slide # 1

    Ohmic contacts

    Common techniques to make ohmiccontacts Choose metal so that its work function

    Fmetal is close to that of semiconductorsFsemi (thermal ionic)

    Insert thin layer of narrow bandgapmaterial between metal andsemiconductor

    Increase the doping level near thesemiconductor surface as high aspossible (tunneling assisted)

    Ohmic contacts should be

    Low contact resistance (< 10-6 cm2) Thermally stable (does not degrade at

    elevated temperature or react withoxygen), which requires no phasechange or no phase change leading tohigh resistance

    Smooth morphology

    Compatibility with the whole deviceprocess

    Both semiconductors and metalsources should be CLEAN!

    Michaelson, IBM J. of R&D, 1978

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    Slide # 2

    Common Techniques for Ohmic contacts

    Usually for compound semiconductorsthe ohmic contact by band alignment ishard to realize due to surface states and

    Fermi pinning. For p-type, the problemis caused by unavailability of metalswith large enough work function

    High n-type doping required for ohmiccontacts to n-type semiconductors,

    which can also be realized by interfaciallayer reaction chemistry

    M

    Evac Evac

    EF

    M < +Ec-EF = SFor n-typesemiconductor.

    Reverse for p-type

    (ii) Ohmic contact by high doping

    Electrons from

    conduction band

    can move veryeasily to the

    metal and vice

    versa by

    tunneling

    n+ doped

    (i) Ohmic contact by band alignment

    n doped

    B = S -MEF

    B = band bending

    n-doped

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    Slide # 3

    Ohmic on n-GaN Possible metals: Ag, Nb, Ti, Al, In, Ta, Cr

    Ag: poor adhesion Nb: extremely easy to oxidize thus difficult to

    process Ti: formation of TiN (intermetallic) and high N

    vacancies in GaN -> good! But easy tooxidize need a stable cap like Au

    Al: formation of AlN (not intermetallic) and highN vacancies in GaN -> ok! Also easy tooxidize Au cap is necessary

    In: most popularly used for quick contacts Ta: studied by Qiao et al. 5.7e10-7 cm2 on

    AlGaN/GaN (2001); but others could notreproduce the results

    Others: also studied but not as good as theone below

    As deposited or alloy: generally alloyed unlessdoping near the surface is very high!

    Popular schemes: Ti/Al/Ni/Au

    Ti/Al bilayer: formation of N vacancies, TiN,Al3Ti (thermally very stable ); but ratio of Ti/Alhas to be carefully controlled (~1/2.5)

    Add high conductive and protective layer of Au,but Au diffuses easily

    Add Ni as diffusion barrier (decent, othermetals were tried, Pd and Pt were worse)

    State-of-art: 0.1-0.2 cm2 (~ 10-8 cm2 )

    Lim et al, APL 78, 3797(2001)

    Liu et al, Solid State Electronics, 42, 677(1998)

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    Slide # 4

    Schottky contacts

    Schottky contacts areformed whenDoping in the

    semiconductor is not veryhigh i.e. > ~5x1018 cm-3

    The metal work function isgreater than the n- typesemiconductor workfunction

    The metal work function islower than p-typesemiconductor work

    functionVery high density of

    surface states pinning theFermi level at the surface

    w.r.t. the conduction band(Example: GaAs)

    Schottky contact

    n doped

    Electrons from

    conduction band

    or in the metalfaces barrier to

    free movement,

    and tunneling is

    also not easy

    M

    Evac Evac

    EF

    M > +Ec-EF = SFor n-type semiconductor andreverse for p-type

    s

    Bn =

    M -

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    Slide # 5

    Conduction mechanisms in schottky contacts

    Thermionic emissionElectrons emit over the barrier

    Low probability of direct tunneling

    Valid for low doping (ND < ~ 1017 cm-3)

    Thermionic-field emissionElectrons use thermal energy to tunnel trough the

    thin barrier in the upper end of the conduction

    band

    Valid for intermediate doping (~ 1017 cm-3 < ND ~ 1018 cm-3); almostohmic

    Leakage currentHigh probability of defect-assisted tunneling and

    simple conduction

    Occurs in poor material/interface quality; dislocations

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    Slide # 6

    Thermionic emission current: Schottky diode

    I-V characteristics

    Schottky diode I-V equation:J = J0 (e

    qV / kT 1), where J0 is the

    saturation current density given by

    Forward bias Reverse biasTypical I-V

    characteristics

    = kT

    qTAJ Bno

    exp2* T = temperature, A* = effective Richardsons constant

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    Slide # 7

    Schottky on n-GaN

    Experimentally shownvery weak surfacepinning

    Surface cleanness hasbeen heavilyinvestigated, however External cleaning is

    generally sufficient toachieve decentSchottky

    Leakage is largely due

    to dislocations Thermal stability is

    IMPORTANT Ni does not react with

    GaN below ~ 600 C

    Pd reacts with GaN at ~

    400-500 C W and Rd ~ 600 C Liu et al, Solid State Electronics, 42, 677(1998)

    The higher the schottky barrier, the lowerthe leakage current

    Using polarization in nitrides i.e.

    GaN/AlGaN/GaN structure, the schottkybarrier can be made larger

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    Slide # 8

    Electrical properties of dislocations in MBE-grown n-GaN(Ed Yu --- UCSD)

    1m

    topography:

    1m

    current:

    Pure screw dislocations can be highly conductive in MBE-grown n-GaN:

    Screw: conducting, uncharged

    Edge: nonconducting , e chargeMixed: nonconducting, e charge

    Edge and mixed dislocations typically contain negative charge in dislocation core:

    high current leakagein Schottky contacts

    scattering, localcarrier depletion

    [B.S. Simpkins, E.T. Yu, P. Waltereit, J.S. Speck, J. Appl. Phys. 94, 1448 (2003).]

    [E. J. Miller, D. M. Schaadt, E. T. Yu, C. Poblenz, C. Elsass, J. Speck, J. Appl. Phys. 91, 9821 (2002).]

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    Slide # 9

    Mitigation of dislocation-induced leakagecurrents in MBE n-GaN (Ed Yu, UCSD)

    1m

    AFM

    1m

    AFM

    1m

    current

    NaOH solution

    pH = 13.1 T= 30C

    AFM

    2m

    current

    ~10A

    AFM

    2m

    current

    ~100pA

    b= 0.800.02V

    n= 1.740.01

    b= 0.860.02V

    n= 1.130.02

    unmodified

    with electrochemicalprocess

    area = 1.2310-4cm2

    V = 30V

    I ~ 1-10mA t= 1000s

    [E. J. Miller, D. M. Schaadt, E. T. Yu, P. Waltereit, C. Poblenz, and J. S. Speck, Appl. Phys. Lett. 82, 1293 (2003).]

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    Slide # 10

    Ohmic to p-GaN

    Similar techniques likeohmic to n-GaN havebeen tried, but:

    rC~ 10-3 cm2

    P-GaN/Ni/Au annealed inair (N2/O2) proved to beone of the best:

    rC~ 10-6 cm2

    Why?

    After annealing, newphases form: NiO, Ni-Ga-O with Au particles,GaN

    NiO is p-semiconductorwith high Ni vacancies

    Continuing challenges: Transparency to visible

    and UV

    Ohmic to p-AlGaN

    Tunneling junctioncontacts

    Ho et al. JAP 85, 4491 (1999)

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    Slide # 11

    Another Contact Metal for p-GaN The absence of a metal with a sufficiently high work function. The band gap of

    GaN is 3.4 eV, and the electron affinity is 4.1 eV, but metal work functions are

    typically ~ 5 eV

    The relatively low hole concentrations in p-GaN due to the deep ionization level of

    the Mg acceptor ~170 meV The tendency for the preferential loss of nitrogen from the GaN surface during

    processing, which may produce surface conversion to n-type conductivity.

    Palladium gallide creates Ga vacancies that

    reduce contact resistances

    Temperature and time of anneal also important

    TEM

    image

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    Slide # 12

    Schottky to p-GaN

    Schottky (Ni) on as grown GaN:Mg (MOCVD) --- quasi-ohmic (higher Mg near the surface?)

    Schottky (Ni) on etched GaN:Mg --- rectifying (tunneling and defect-assisted tunneling still

    significant thus it is difficult to extract barrier height and Richardson constant from I-V)

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    Slide # 13

    Schottky contact characterization

    Current-Voltage (IV) measurements

    Capacitance-Voltage (CV) measurements

    So the intercept of 1/C2 vs. V gives the barrier height

    Photoelectric measurements (by photon incidenton the schottky contact; this is very accurate)

    Photocurrent R is related to the barrier height as

    ( )VqNW BnDs

    = 2

    ( )V

    Nq

    CBn

    Ds

    =

    2 ( )VC Bn 21

    BnqhvR ~ So the intercept gives the barrier height

    kT

    q Bn

    eTAJ

    = 2*0

    =

    0

    2*

    ln

    J

    TA

    q

    kTBn. VF vs. J intercept gives J0 and

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    Slide # 14

    Evaporation systems

    Contact Metallization (Ti, Al, Ni, Au etc)

    Metal Electron-Beam Evaporation System

    Rapid Thermal Annealing System

    from 20 oC to 1000 oC in seconds

    Target Metal Sourcewith e-beam

    Sample

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    Slide # 15

    Ohmic contacts: n-type or undoped nitride

    Standard recipe for ohmic contact:

    Ti/Al/Ti/Au or Ti/Al/Ni/Au deposition. Ti/Al thickness ratio is important

    Annealing at 800 900 C for about 1 min for alloying. Alloying temperature

    and alloying time are important factors controlling contact resistance.

    Ti/Al/Ni/Au

    Since TiN and AlN are formed by reaction

    between the nitride layers and Ti or Al, N-

    vacancies are created, which can dope thecontact region and create ohmic contact

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    Slide # 16

    Specific contact resistivity and sheet resistance

    Product of contact resistance Rc and area

    A is called specific contact resistivityc:

    0

    1

    =

    =

    V

    c

    V

    J ( . cm2)

    Semiconductor layer resistivity:

    ne

    1= ( . cm)

    tZ

    ddx

    A

    R

    d

    s

    ==

    0

    1()

    d

    Z

    t

    Sometimes semiconductor resistance is

    expressed in terms of sheet resistance sh

    For any semiconductor device there are two main resistances: Contact resistance

    Semiconductor resistance

    ( ) tnetsh ==

    1(Can also be expressed in terms of . mm)

    The total semiconductor resistance is thengiven by

    (/)

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    Slide # 17

    Ohmic contact characterization:

    Transmission line method (TLM)

    ( )TT LxLx BeAexI // +=

    c

    ZxV

    dx

    dI

    )(=

    Z

    I

    tZ

    I

    dx

    dV shs ==sh

    cTL

    =,)(

    22

    2

    TLxI

    dxId =

    shx/Z

    c/(Zx)

    I

    I(x)

    V(x)

    I(x+x)

    V(x +x)

    where

    The solution forI(x) is given as:

    Now putting the boundary conditionI(x = L) = 0, and finding the

    solution for V(x), we can find the contact resistance as the ratio of the

    input voltage and input current as:

    L

    ( ) ( )00 === xIxVRC

    is called the transfer length.

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    Slide # 18

    Transmission line method (TLM) II

    T

    CC

    ZLR

    =

    Z

    dRRRR

    shcscTot

    +=+= 22

    sh = /t

    d

    Z

    t

    When the following conditions are further

    satisfied, d LT , we have,

    =

    TT

    CC

    LL

    ZLR coth

    ,ZLR Tcc=Putting Rtot = 0, and using the relation

    .2)0( TT LRd ==

    we have,

    So, the transfer length can be found from the

    intercept of the total resistance on the x-axis.

    Note that the contact resistivity is not given by the product of the

    contact resistance and the total contact area, but by the product of

    contact resistance, width Z, and transfer length LT.

    OhmicsL

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    Slide # 19

    Measurement technique

    -2 -1 0 1 2-100

    -50

    0

    50

    100

    B1205 UV LED

    n-TLM

    Curr

    ent,mA

    Voltage, V

    4um

    6um

    8um10um

    12um

    14um

    16um

    0 5 10 15 200

    10

    20

    30

    40

    B1205 UV LED

    n-TLM

    Y =14.51607+1.13839 XR

    c=7.258

    LT=6.373um

    c=6.93*10-5-cm2

    Rsh

    =170.7/sq

    Resistanc

    e,

    Ohm

    gap, um

    Typical measurement set up

    Slope =

    sh/Z

    What is wrong in

    this measurement?

    Plot of total resistance

    vs. distance