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8/13/2019 10 Fisika Termal Bag 2 Nov 12 Revisi (1)
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FISIKA TERMALBAGIAN 2
8/13/2019 10 Fisika Termal Bag 2 Nov 12 Revisi (1)
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Ekspansi termal dari benda padat dan cair
Fenomena terjadinya peningkatan volume dari suatu materi
karena peningkatan temperatur disebut dengan ekspansi
termal.Ekspansi termal adalah konsekuensi dari perubahan average
separationantar atom dalam suatu materi.
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Benda akan memanjangbila temperaturnyameningkat
Pertambahan panjangproporsional terhadapperubahan temperaturDL/L = a DT atau
DL = a LDT atau
dL
dTaL
L DL
L DL
DL/L = aDT
DL/L = aDT
Ekspansi Linier
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Contoh:
Suatu penggaris besi dikalibrasi pada suhu 20 C. Hitungerror dalam pengukuran jika penggaris tersebut digunakan
untuk mengukur sepanjang 500 mm pada temperatur 45 C.
abesi= 1,2x10-5C-1
DL/L = aDT
DL = L a DT
DL = 500 x10-3m x 1,2 x10-5C-1 x 25 C
DL = 1,5x10-4m = 0,15 mm
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Ekspansi Volume
Setiap sisi panjang berubah dari Lmenjadi L+DL = L + La DT
Volume awal = L3
Volume baru (V+DV)
= (L +DL)3= (L + La DT)3
= (L (1+a DT))3
= L3
(1+ aDT)3
= V [1+3aDT+3(aDT)2 +(aDT)3]
L DL
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Ekspansi Volume (lanjutan)
V+DV = V [1+3aDT+3(aDT)2
+(aDT)3
]DV / V = [3aDT+3(aDT)2 +(aDT)3]
Karena aDT < 1 untuk nilai DT < 100 Cmaka nilai 3(aDT)2 dan (aDt )3dapat
diabaikan. Sehingga:DV / V = 3aDT
DV = 3a V DT
3a b DV = bV DT
L DL
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Unusual Behavior of Water
Cairan umumnya akan meningkat volumenya denganpeningkatan temperatur. Kecuali untuk air dingin sepertiditunjukkan pada gambar.
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Ideal Gas
An ideal gasis an idealized model for real gases that have
sufficiently low densities.
The condition of low density means that the molecules of the
gas are so far apart that they do not interact (except duringcollisions that are effectively elastic).
The ideal gas law expresses the relationship between the
absolute pressure (P), the Kelvintemperature (T), the
volume (V), and the number of moles (n) of the gas.
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Misal gas ideal didalam wadah silinder yang
volumenya dapat divariasikan dengan pistonyang dapat bergerak. Jika diasumsikan sistem
tertutup, maka massa (atau jumlah mol) gas
tetap konstan. Pada sistem tersebut dapat
diperoleh informasi:
Pada temperatur konstan, tekanan berbanding
terbalik dengan volume (Hukum Boyle)
Pada tekanan konstan, volume berbanding
lurus dengan temperatur (Hukum Charles)
Pada volume konstan, tekanan berbandinglurus dengan temperatur (Hukum Gay-Lussac)
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Amount of Gas
Better to describe gas in terms of number of moles.
The number of moles ncontained in any sample is the
number of particles Nin the sample divided by the
number of particles per mole NA(Avogadro's number):
AN
Nn
The number of moles contained in a sample can also be
found from its mass.
M
mn
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Avogadros Constant
One moleof any gas contains
the same number of particles.
This number is called
Avogadros constant and hasthe symbol NA. The value of
NAis 6.02 1023particles per
mole.
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Avogadros Law
nV
The most significant consequence of
Avogadro's law is that the ideal gas
constanthas the same value for all
gases. This means that the constant is
given by:-
constant
22
22
11
11 nT
Vp
nT
Vp
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Deriving Ideal Gas Equation
From Boyles Law:
From CharlessLaw:
From Avogadros Law:
Combining these three:
Rewriting using the gas
constant R:
pV
1
p
nTV
nV
TV
nRTpV
p
nTRV
Therefore:-
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PV Diagram in Thermodynamic Process
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Kinetic Theory of Gases
The pressurethat a gas
exerts is caused by the
impact of its molecules
on the walls of the
container.
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Consider a gas molecule colliding
elastically with the right wall of thecontainer and rebounding from it.
The force on the molecule is obtained
using Newtons second law as follows:
D
D
t
PF
( (
L
mv
vL
mvmvF
2
2
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The force on one of the molecule:
According to Newton's law of actionreaction, the force on
the wall is equal in magnitude to this value, but oppositely
directed.
The force exerted on the wall by one molecule:L
mv 2
( ( L
mv
vL
mvmv 2
2
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If N is the total number of molecules, since these particles
move randomly in three dimensions, one-third of them on theaverage strike the right wall. Therefore, the total force is:
Vrms = root-mean-square velocity.
L
vmNF rms
2
3
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Pressureis forceper unitarea, so the pressure Pacting on a
wall of area L2is
Since the volume of the box is V = L3, the equation above
can be written as
3
2
23 L
vmN
L
FP rms
2
2
1
3
2
rmsvmNPV
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Contoh soal:
1. Berapa banyaknya massa Cl2(gram) yang dapat
disimpan dalam suatu wadah (kontainer) dengan volume
10 L pada suhu 30 C dan tekanan 1000 kPa?
2. Pada suhu 150 C dan tekanan 100 kPa, sebuah
senyawa dengan massa 2,506 gram memiliki volume 1
L. Hitung massa molar senyawa tersebut.3. Berapa vrms dari atom helium yang mengisi sebuah
balon dengan diameter 30 cm pada suhu 20 Cdan
tekanan 1 atm?(diketahui jumlah atom helium dalam
balon sebanyak 3,54 x 1023
dan massa atom helium 6,64x 10-24g)
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TERIMAKASIH