30
§ 11.3 Geometric Sequences and Series

§ 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Embed Size (px)

Citation preview

Page 1: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

§ 11.3

Geometric Sequences and Series

Page 2: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3

Geometric Sequences

In this section, we will consider another special sequence – the geometric sequence. A sequence is a geometric sequence if each term after the first is obtained by multiplying the preceding term by a fixed nonzero number. The amount by which you multiply each time is called the common ratio r of the sequence.

Consider the following geometric sequence:

1,5,25,125,625…Here, r is 5.

Now consider another geometric sequence:

9,-3, 1, -1/3, 1/9In this case, r is negative. Note that the terms of the sequence are alternating in sign. That tells us that r is negative. Here r is -1/3.

Page 3: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Blitzer, Intermediate Algebra, 5e – Slide #3 Section 11.3

Geometric Sequences

Definition of a Geometric SequenceA geometric sequence is a sequence in which each term after the first is obtained by multiplying the preceding term by a fixed nonzero constant. The amount by which we multiply each time is called the common ratio of the sequence.

Page 4: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Blitzer, Intermediate Algebra, 5e – Slide #4 Section 11.3

Geometric Sequences

EXAMPLEEXAMPLE

SOLUTIONSOLUTION

Write the first five terms of the geometric sequence with the first term and common ratio r = -10.

The first term is -3. The second term is (-3)(-10), or 30. The third term is (30)(-10), or -300. The fourth term is (-300)(-10), or 3000, and so on. The first five terms are

31 a

30, -300, 3000, -30,000, 300,000.

Page 5: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Blitzer, Intermediate Algebra, 5e – Slide #5 Section 11.3

Geometric Sequences

General Term of a Geometric SequenceThe nth term (the general term) of a geometric sequence with first term and common ratio r is1a

.11

nn raa

Page 6: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Blitzer, Intermediate Algebra, 5e – Slide #6 Section 11.3

Geometric Sequences

EXAMPLEEXAMPLE

SOLUTIONSOLUTION

Find the tenth term of the geometric sequence whose first term is 2 and whose common ratio is 4.

To find the tenth term, , we replace n in the formula with 10, with 2, and r with 4.

1a10a

11

nn raa

288,524144,26224242 911010 a

The tenth term is 524,288.

Page 7: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Blitzer, Intermediate Algebra, 5e – Slide #7 Section 11.3

Geometric Sequences in Application

EXAMPLEEXAMPLE

The population of Texas from 1990 through 1997 is shown in the following table.

(a) Divide the population for each year by the population in the preceding year. Round to three decimal places and show that the population of Texas is increasing geometrically.

(b) Write the general term of the geometric sequence describing population growth for Texas n years after 1989.

Year 1990 1991 1992 1993

Population in millions 16.99 17.35 17.71 18.08

Year 1994 1995 1996 1997

Population in millions 18.46 18.85 19.25 19.65

Page 8: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Blitzer, Intermediate Algebra, 5e – Slide #8 Section 11.3

Geometric Sequences in Application

(c) Use your model from part (b) to estimate Texas’s population, in millions, for the year 2000. According to the U.S. Census Bureau, Texas’s population in 2000 was 20.85 million. How well does your geometric sequence model the actual population?

CONTINUECONTINUEDD

SOLUTIONSOLUTION

Years 1991/1990 1992/1991 1993/1992 1994/1993

Quotient of populations 1.021 1.021 1.021 1.021

Years 1995/1994 1996/1995 1997/1996

Quotient of populations 1.021 1.021 1.021

(a) The following table shows each value of the population divided by the preceding population value.

Page 9: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Blitzer, Intermediate Algebra, 5e – Slide #9 Section 11.3

Geometric Sequences in Application

Since all of the quotients are the same, and greater than 1, the sequence is increasing geometrically.

CONTINUECONTINUEDD

(b) Since the first value of the sequence (first population value) is 16.99, Since the common ratio was determined to be 1.021 (in the preceding table), r = 1.021. Therefore, the general term of the geometric sequence that models the population growth of Texas since 1989 is

.99.161 a

1021.199.16 nna

(c) To estimate Texas’s population in the year 2000, using the model from part (b), we determine that n = 2000 – 1989 = 11.

Page 10: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Blitzer, Intermediate Algebra, 5e – Slide #10 Section 11.3

Geometric Sequences in Application

CONTINUECONTINUEDD 1021.199.16 n

na This is the formula for the nth term of this geometric sequence.

11111 021.199.16 a Replace n with 11.

231.199.1611 a Evaluate the exponent.

91.2011 a Multiply.

Therefore, the models estimates that in the year 2000 there were 20.91 million people living in Texas. The census for that year stated that there were 20.85 million people living in Texas that year. The two numbers are relatively close. The geometric sequence models the population of Texas very well.

Page 11: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Blitzer, Intermediate Algebra, 5e – Slide #11 Section 11.3

Geometric Sequences

The Sum of the First n Terms of a Geometric Sequence

The sum, , of the first n terms of a geometric sequence is given by

in which is the first term and r is the common ratio

nS

1a

r

raS

n

n

1

11

Page 12: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Blitzer, Intermediate Algebra, 5e – Slide #12 Section 11.3

Geometric Sequences

EXAMPLEEXAMPLE

SOLUTIONSOLUTION

Find the sum of the first 12 terms of the geometric sequence:

3, 6, 12, 24,...

To find the sum of the first 12 terms, , we replace n in the formula with 12.

12S

r

raS

n

n

1

11

r

raS

1

1 121

12

The first term, , is 3. We must find r, the common ratio.1a

Page 13: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Blitzer, Intermediate Algebra, 5e – Slide #13 Section 11.3

Geometric Sequences

We can find the common ratio by dividing the second term of 3, 6, 12, 24,... by the first term.

r

raS

n

n

1

11

Now we are ready to find the sum of the first 12 terms of the sequence.

12 and ,2 ,3 )first term (the 1 nra

CONTINUECONTINUEDD

23

6

1

2 a

ar

Use the formula for the sum of the first n terms of a geometric sequence.

because we want the sum of the first 12 terms.

21

213 12

12

S

Page 14: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Blitzer, Intermediate Algebra, 5e – Slide #14 Section 11.3

Geometric Sequences

285,12

The sum of the first 12 terms is 12,285. Equivalently, this number is the 12th partial sum of the sequence.

CONTINUECONTINUEDD

Use a calculator.

Page 15: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Blitzer, Intermediate Algebra, 5e – Slide #15 Section 11.3

Geometric Sequences

EXAMPLEEXAMPLE

SOLUTIONSOLUTION

Find the following sum:

Let’s write out a few terms in the sum.

.347

1

i

i

Do you see that each term after the first is obtained by multiplying the preceding term by -3? To find the sum of the 7 terms (n = 7), we need to know the first term, , and the common ratio, r. The first term is 4(-3) or -12: . The common ratio is -3: r = -3.

1a

7217

1

34343434

i

i

121 a

Page 16: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Blitzer, Intermediate Algebra, 5e – Slide #16 Section 11.3

Geometric Sequences

31

3112 7

7

S

r

raS

n

n

1

11

Thus

CONTINUECONTINUEDD Use the formula for the sum of the

first n terms of a geometric sequence.

7 and ,3 ,12 )first term (the 1 nrabecause we are adding 7 terms.

6564 Use a calculator.

.6564347

1

i

i

Page 17: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Blitzer, Intermediate Algebra, 5e – Slide #17 Section 11.3

Geometric Sequences in Application

EXAMPLEEXAMPLE

SOLUTIONSOLUTION

A professional basketball player signs a contract with a beginning salary of $3,000,000 for the first year and an annual increase of 4% per year beginning in the second year. That is, beginning in year 2, the athlete’s salary will be 1.04 times what it was in the previous year. What is the sum of the athlete’s salaries for the first 7 years of the contract? Round to the nearest dollar.

The salary for the first year is $3,000,000. With a 4% raise, the second-year salary is computed as follows:

Salary for year 2 = 3,000,000 + 3,000,000(0.04)

= 3,000,000(1 + 0.04) = 3,000,000(1.04).

Page 18: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Blitzer, Intermediate Algebra, 5e – Slide #18 Section 11.3

Geometric Sequences in Application

Each year, the salary is 1.04 times what it was in the previous year. Thus, the salary for year 3 is 1.04 times 3,000,000(1.04), or , and so on. Therefore, since each salary is the preceding salary multiplied by 1.04, r = 1.04. By the same token, the salary in the 7th year will be Since the initial salary is $3,000,000, Since we are interested in determining the sum of the salaries for the first seven years, n = 7.

CONTINUECONTINUEDD

204.1000,000,3

.04.1000,000,3 6

. 00000031 ,, a

r

raS

n

n

1

11

04.11

04.11000,000,3 7

7

S

Page 19: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Blitzer, Intermediate Algebra, 5e – Slide #19 Section 11.3

Geometric Sequences in Application

CONTINUECONTINUEDD

04.0

04.11000,000,3 7

7

S

750,694,237 S

The sum of the salaries for the first 7 years is $23,694,750.

Page 20: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Blitzer, Intermediate Algebra, 5e – Slide #20 Section 11.3

Annuities

Value of an Annuity: Interest Compounded n Times Per Year

If P is the deposit made at the end of each compounding period for an annuity at r percent annual interest compounded n times per year, the value, A, of the annuity after t years is

.11

nr

nr

PA

nt

Page 21: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Blitzer, Intermediate Algebra, 5e – Slide #21 Section 11.3

Annuities

EXAMPLEEXAMPLE

SOLUTIONSOLUTION

To save for retirement, you decide to deposit $2500 into an IRA at the end of each year for the next 40 years. If the interest rate is 9% per year compounded annually, find the value of the IRA after 40 years.

The annuity involves 40 year-end deposits of P = $2500. The interest rate is 9%: r = 0.09. Because the deposits are made once a year and the interest is compounded once a year, n = 1. The number of years is 40: t = 40. We replace the variables in the formula for the value of an annuity with these numbers.

Page 22: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Blitzer, Intermediate Algebra, 5e – Slide #22 Section 11.3

Annuities

The value of the IRA at the end of 40 years is approximately $844,706.

CONTINUECONTINUEDD

nr

nr

PA

nt

11

706,844

109.0

1109.0

12500

401

A

Page 23: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Blitzer, Intermediate Algebra, 5e – Slide #23 Section 11.3

Geometric Series

1a

The Sum of an Infinite Geometric SeriesIf -1 < r < 1 (equivalently, |r| < 1), then the sum of the infinite geometric series

in which is the first term and r is the common ratio is given by

If , the infinite series does not have a sum.

31

2111 rararaa

.1

1

r

aS

1r

Page 24: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Blitzer, Intermediate Algebra, 5e – Slide #24 Section 11.3

Geometric Series

EXAMPLEEXAMPLE

SOLUTIONSOLUTION

Find the sum of the infinite geometric series:

Before finding the sum, we must find the common ratio.

9

1

3

113

3

1

3

1

1

2

a

ar

Because r = -1/3, the condition that |r| < 1 is met. Thus, the infinite geometric series has a sum.

r

aS

11 This is the formula for the sum of an

infinite geometric series. Let , and r = -1/3.

31 a

Page 25: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Blitzer, Intermediate Algebra, 5e – Slide #25 Section 11.3

Geometric Series

Thus, the sum of the geometric series is 9/4.

4

9

4

33

343

31

1

3

S

CONTINUECONTINUEDD

Page 26: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Blitzer, Intermediate Algebra, 5e – Slide #26 Section 11.3

Geometric Series

EXAMPLEEXAMPLE

SOLUTIONSOLUTION

Express as a fraction in lowest terms.

Observe that is an infinite geometric series with first term 83/100 and common ratio 1/100. Because r = 1/100, the condition that |r| < 1 is met. Thus, we can use our formula to find the sum. Therefore,

83.0

83.0

000,000,1

83

000,10

83

100

83838383.083.0

Page 27: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Blitzer, Intermediate Algebra, 5e – Slide #27 Section 11.3

Geometric Series

.99

83

99

100

100

83

10099

10083

1001

1

10083

183.0 1

r

a

CONTINUECONTINUEDD

An equivalent fraction for is 83/99.83.0

Page 28: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Blitzer, Intermediate Algebra, 5e – Slide #28 Section 11.3

Geometric Series in Application

EXAMPLEEXAMPLE

SOLUTIONSOLUTION

How much additional spending will be generated by a $10 billion tax rebate if 60% of all income is spent?

The total amount spent is given by the infinite geometric series

000,000,600,3000,000,000,6000,000,000,10

60% of 10 billion

60% of 6 billion

The first term is 10 billion: = 10 billion. The common ratio is 60%, or 0.6: r = 0.6. Because r = 0.6, the condition that |r| < 1 is met. Thus, we can use our formula to find the sum.

1a

Page 29: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Blitzer, Intermediate Algebra, 5e – Slide #29 Section 11.3

Geometric Series in Application

000,000,600,3000,000,000,6000,000,000,10

Therefore,CONTINUECONTINUE

DD

000,000,000,256.01

000,000,000,10

11

r

a

This means that the total amount spent on the $10 billion tax rebate is approximately $25 billion. To determine the additional spending that will be generated, we subtract the initial $10 billion from $25 billion. Hence, the additional spending that will be generated is $25 billion - $10 billion = $15 billion.

Page 30: § 11.3 Geometric Sequences and Series. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 11.3 Geometric Sequences In this section, we will consider

Blitzer, Intermediate Algebra, 5e – Slide #30 Section 11.3

Geometric Sequences and Series

Important to Note…

We’ve looked at sequences and at series now. What is the difference?

In very simple terms, the difference is that a sequence is a list and a series is a sum. In many other ways they are similar – both related to functions of the positive integers.

Just don’t forget the distinction.

Sequence – a list

Series – a sum