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This presentation gives you an idea about how the normalization process is being done in JEE by using board percentile as the basis.

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- 1. Presented by Anchit Das 13810010 Ashish Pandey 13810020 Gaurav kumar Gupta 13810030 Kartik Khamesra 13810040 Mohit Chaudhary 13810050 Pawan Arora 13810060 Shashi Kiran Lugun 13810070 Vaibhav Agarwal 13810080
- 2. Adjusting values measured on different scales to notionally common scales. In Indian JEE context: Process for ensuring students are neither advantaged nor disadvantaged by the difficulty of their respective board exams
- 3. Percentile Score: No. of candidates in the group with aggregate marks less than the candidates Total number of Candidate in that group For example, the 20th Percentile is the value (or score) below which 20 Percent of the observations may be found. 100 *
- 4. i) Note down the aggregate marks (A0) obtained by each student in JEE- Main. ii) Compute the percentile (P) of each student on the basis of aggregate marks in his/her own board (B0) computed from the list of five subjects specified (each marked out of 100). The percentile is to be computed among all students of the board whose subject combinations meet the eligibility criteria of JEE-Main. iii) Determine the JEE- Main aggregate marks corresponding to percentile (P) at the All- India level. Regard this as B1. iv) Also, determine the JEE- Main aggregate marks corresponding to percentile (P) among the set of aggregate scores obtained in the JEE- Main by the students of that board. Regard this as B2. The normalized board score of the candidate will be computed as: Bfinal = 0.5 * (B1 + B2)
- 5. Step 1: Calculate Percentile (Pi) of the Candidate with reference to the group of Candidates of Board ABCD who also satisfy the eligibility criteria of JEE (Main).
- 6. Step 2. Arrange JEE (Main) score of all 11.5 lakhs Candidates in ascending order and find out Percentile for each score.
- 7. Step 3. Arrange JEE (Main) score of Candidates from Board ABCD only, in ascending order and find out the Percentile for each score.
- 8. Step 4. 4.i Use Percentile (Pi), 50.07, calculated from step 1 and find out the same Percentile in the Percentile calculated in step 2.
- 9. 4.ii Now, to find B1, find out JEE (Main) score, corresponding to the matched Percentile in 4.i above. This is B1. Here, B1 = 48.
- 10. Step 5. 5.i Use Percentile (Pi), 50.07, calculated from step 1 (Table 2) and find out the same Percentile in the Percentile calculated in step 3 (Table 4).
- 11. 5. ii Now, to find B2, find out JEE (Main) score, corresponding to the matched Percentile in 5.i. above. This is B2. Here B2 = 80. Board Percentage (B0)
- 12. Step 6. Normalised Board mark of the Candidate from Board ABCD who has scored 60% will be Bfinal = 0.5 * (B1 + B2) => Bfinal = 0.5 * (48+80) => Bfinal = 0.5 * (128) => Bfinal = 64
- 13. For the purpose of admission to CFTIs where it has been decided to use the JEE Mains performance and the Normalized Board performance in the 60:40 ratio, the composite score for drawing the merit list will be computed as: C = 0.6 * AO + 0.4 * Bfinal
- 14. Example to support the argument that boards are playing the role of deciding factors whereas the JEE (main) has become almost redundant: Student Name: Karthik Board: CBSE Marks in JEE (main): 99 Board Percentage: 94.6 AIR: 34000 (approximately.) Student Name: Ashish Board: CBSE Marks in JEE (main): 135 Board Percentage: 90 AIR: 60000 (approximately.)
- 15. Example to support the argument that different boards differ radically in terms of their competition levels. Student Name= Gaurav Board= CBSE Board Percentage= 90.2% Marks in JEE (main) = 267 Rank= Beyond 5000 Student Name= Anchit Board= Rajasthan Board Board Percentage= 90% Marks in JEE (main) = 195 Rank= 4400
- 16. Example to explain how major the role played by the boards was Student Name: Vaibhav Board: CBSE Marks in JEE (main): 201 Board Percentage: 88 AIR: 23000 (approximately.) Student Name: Mohit Board: CBSE Marks in JEE (main): 201 Board Percentage: 94 AIR: 9000 (approximately.)