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LAPORAN PERCOBAAN II(MENENTUKAN JARAK FOKUS LENSA TIPIS)
1.HASIL PENGAMATAN1.1 LensaPositif
TabelPengamantan
No. Jarakbenda (d0) JarakBayangan (di) 1/d0 1/d1
1.2.3.4.5.6.
1.2 LensaNegatif
Table pengamatan
No. Jarak Benda (d0) JarakBayangan (d1) 1/d0 1/d1
1.
2.3.
4.
5.6.
2.AnalisisMenghitungJarakFokusLensa
2.1 LensaPositif
a. DenganRumus
f1 = ………………………………………………………………………………………………………………………………………..
f2 = ………………………………………………………………………………………………………………………………………..
f3 = ………………………………………………………………………………………………………………………………………..
f4 = ……………………………………………………………………………………………………………………………………….
f5 = ………………………………………………………………………………………………………………………………………
f6 = ………………………………………………………………………………………………………………………………………
f =
b. Dengan Grafik
f = ………………………………………..
2.2 Lensa Negatif
c. Dengan Rumus
f1 = ………………………………………………………………………………………………………………………………………..
f2 = ………………………………………………………………………………………………………………………………………..
f3 = ………………………………………………………………………………………………………………………………………..
f4 = ……………………………………………………………………………………………………………………………………….
f5 = ………………………………………………………………………………………………………………………………………
f6 = ………………………………………………………………………………………………………………………………………
f = ……………………………………………………………………………………………………………………………..
1 2 3 4 5 60.00
0.02
0.04
0.06
0.08
0.10
0.12
0.14
0.16
0.18
0.11 0.110.10
0.14
0.16
0.13
0.10
0.08
0.11
0.040.03
0.06
1/do1/d1
d. Dengan Grafik
f = ………………………………………………………………………
3.RAMBAT RALATLensaPositif
RambatRalatdaripersamaan f =d0d1d0+d1
∆ f = ………………………………………………………………………………………………………………………………
………………………………………………………………………………………………………………………………
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1 2 3 4 5 60.00
0.20
0.40
0.60
0.80
1.00
1.20
0.01
0.150.20 0.20
1.00
0.090.06 0.05 0.04 0.03
0.15
0.08
1/do1/di
4. MENGHITUNG RAMBAT RALAT
∆ f 1=¿ ……………………………………………………………………………………………………………………………………
…………………………………………………………………………………………………………………………………
∆ f 1f 1
=¿ ……………………………………..........................…………………………………..=……………………………%
∆ f 2=¿ …………………………………………………………………………………………………………………………………..
………………………………………………………………………………………………………………………………....
∆ f 2f 2
=¿ ……………………………………………………………........................…………...=……………………………%
∆ f 3=¿ …………………………………………………………………………………………………………………………………
…………………………………………………………………………………………………………………………….....
∆ f 3f 3
=¿ ………………………………………………………….........................………………=……………………………%
∆ f 4=¿ …………………………………………………………………………………………………………………………………
………………………………………………………………………………………………………………………………..
∆ f 4f 4
=¿ ………………………………………………………………........................…………=…………………………..%
∆ f 5=¿ ……………………………………………………………………………………………………………………………….
………………………………………………………………………………………………………………………………
∆ f 5f 5
=¿ ………………………………………………………………….........................……...=…………………………%
∆ f 6=¿ ………………………………………………………………………………………………………………………………
…………………………………………………………………………………………………………………………….
∆ f 6f 6
=¿ ………………………………………………...................………………………=………………………………..%
∆ f=¿ ……………………………………………………………………………………………………………………………..
= ……………………………………cm.
5.PenulisanHasilEksperimen
f = (………………………..±………………………) cm.
6.kesalahan-kesalahan yang dapatterjadipadapercobaaniniadalah :
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7.Kesimpulan
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PAREPARE, 2010
Asisten Praktikan
NIM
